TLDR
The nth term test for divergence is a quick check: if the terms of a series do not approach zero, the series diverges. It only proves divergence, so if the terms do go to zero, the test tells you nothing and you need a different test. This is a BC-only topic in AP Calculus.

Why This Matters for the AP Calculus Exam
The nth term test is usually your first move when you see an infinite series on the AP Calculus BC exam. It is fast, and in multiple choice questions it can rule out divergent series in seconds. On free response questions that involve series, you may need to justify why a series diverges, and computing the limit of the general term is a clean way to do that. Knowing exactly what this test can and cannot conclude saves you from wasting time and from writing incorrect justifications.
Key Takeaways
- The test in symbols: if (or the limit does not exist), then diverges.
- If , the test is inconclusive. The series could converge or diverge.
- Terms going to zero is a necessary condition for convergence, not a sufficient one.
- Three steps: write the limit of , evaluate it, then conclude based on whether it equals zero.
- Use this as a preliminary check before reaching for the integral, comparison, ratio, or alternating series tests.
- The harmonic series shows why "terms to zero" is not enough: its terms go to zero, but the series still diverges.
What is the nth Term Test for Divergence?
The nth term test (also called the divergence test or term test) tells you when a series diverges. It states:
If the nth term does not approach 0, the series diverges. If the nth term does approach 0, the test cannot decide anything. The series might converge, or it might still diverge. Everything hinges on whether the general term tends to zero.
This works because of a basic fact about convergent series: if a series converges, its terms must approach zero. The nth term test is the contrapositive of that statement. So passing the divergence test (meaning the terms go to zero) never proves convergence.
If , you cannot say the series converges. You only know the divergence test failed to show divergence.
How to Use This on the AP Calculus Exam
Problem Solving
There are three steps:
- Write the limit of the general term, .
- Evaluate the limit.
- Conclude based on the nth term test.
Determine if the following series diverges.
Step 1: Write the limit.
Step 2: Evaluate. Factor out the highest power of from the top and bottom.
Recall that any finite number divided by is 0.
Step 3: Conclude.
Because the limit of the terms is 5, not 0, the series diverges. You are applying a new test to limit work you already know.
Practice Problems
Try these two yourself.
Solution 1
The limit is , so:
Solution 2
As goes to , approaches .
Since the limit is :
Common Trap
When the limit of the terms is 0, stop and switch tests. Do not write a conclusion about convergence based on the nth term test alone. Reach for the integral test, comparison or limit comparison test, ratio test, or alternating series test instead.
Common Misconceptions
- "If the terms go to zero, the series converges." This is false. The harmonic series has terms that go to zero, yet it diverges. Terms going to zero only means the test is inconclusive.
- "The nth term test can prove convergence." It cannot. It only ever proves divergence. When the limit is 0, the test gives no information.
- "If the limit does not exist, the test fails." Actually, if the limit of does not exist (for example, or ), the terms do not approach 0, so the series diverges.
- "I should always run the nth term test last." Run it first. It is the quickest way to spot an obviously divergent series before doing more work.
- "Limit equals zero means I made a mistake." A limit of zero is normal and common. It just means you need another test to finish the problem.
Related AP Calculus Guides
Vocabulary
The following words are mentioned explicitly in the College Board Course and Exam Description for this topic.Term | Definition |
|---|---|
converges | A series converges when the sequence of partial sums approaches a finite limit as n approaches infinity. |
diverges | A series diverges when the sequence of partial sums does not approach a finite limit as the number of terms increases indefinitely. |
nth term test | A test for divergence that examines whether the limit of the nth term of a series equals zero; if the limit is not zero, the series diverges. |
series | A sum of the terms of a sequence, often written as the sum of infinitely many terms. |
Frequently Asked Questions
How do I use the nth term test for divergence?
You use the nth-term (zero) test to quickly rule out convergence. It says: if lim_{n→∞} a_n ≠ 0 or does not exist, then the series ∑ a_n diverges. So first compute L = lim_{n→∞} a_n. - If L ≠ 0 (for example a_n = 5 for all n, or a_n = (−1)^n), the series diverges. - If L = 0, the test is inconclusive—the series might converge (like a geometric series with |r|<1) or diverge (the harmonic series ∑1/n has terms →0 but still diverges). Remember: the nth-term test is a necessary condition for convergence, not sufficient. On the AP BC exam you’ll use it to eliminate options fast (CED LIM-7.A.5). For a short guide and examples, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). Practice lots of problems at (https://library.fiveable.me/practice/ap-calculus) to get fluent.
What's the formula for the nth term test?
The nth-term (or zero) test says: if the sequence of terms a_n does not approach 0, the series ∑ a_n must diverge. In formula form: - If lim_{n→∞} a_n ≠ 0 or the limit does not exist, then ∑_{n=1}^∞ a_n diverges. - If lim_{n→∞} a_n = 0, the test is inconclusive (the series may converge or diverge). So the necessary condition for convergence is lim a_n = 0, but that alone isn’t enough (e.g., the harmonic series has terms →0 but diverges; a geometric series with |r|<1 converges). This is the very first divergence test you should check on AP BC series problems (CED LIM-7.A.5). For a short study guide on this topic, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For more practice, use the AP Calculus practice bank (https://library.fiveable.me/practice/ap-calculus).
When do I use the nth term test vs other convergence tests?
Use the nth-term (zero) test first as a quick fail-fast check: if lim_{n→∞} a_n ≠ 0 (or doesn’t exist), the series ∑a_n diverges—that’s all the test can prove (CED: LIM-7.A.5). If lim a_n = 0, the test is inconclusive—the series may converge or diverge. When to move to other tests: - If a_n ≈ geometric form → use geometric-series test. - If a_n ~ 1/n^p → use p-series (or comparison). - If terms are positive and come from a nice function → try the integral test. - If you can bound a_n above/below by a known series → comparison or limit comparison. - If terms alternate and decrease to 0 → alternating series test (for conditional convergence). - If factorials/exponentials appear → ratio test. - If partial sums simplify → telescoping. Strategy for AP BC: always do the nth-term test first (fast check). If it’s inconclusive, pick the test that matches the term’s form. For a refresher, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx) and practice problems (https://library.fiveable.me/practice/ap-calculus).
If the limit of an as n approaches infinity equals zero, does that mean the series converges?
No—lim_{n→∞} a_n = 0 is necessary for ∑ a_n to converge, but it’s not sufficient. That’s exactly what the nth-term (divergence) test says: if lim_{n→∞} a_n ≠ 0 (or doesn’t exist), then the series diverges. But if lim_{n→∞} a_n = 0, the test is inconclusive—the series may converge or diverge. Example: a_n = 1/n has lim a_n = 0, but the harmonic series ∑ 1/n diverges. Contrast that with the alternating harmonic series ∑ (-1)^{n+1}/n, which converges (conditionally). So when terms go to 0 you must use other tests (p-series, comparison, integral, alternating series, ratio, etc.) to decide convergence—this is part of LIM-7.A in the CED. For a quick refresher on the divergence test, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For more practice problems across Unit 10, check the unit page (https://library.fiveable.me/ap-calculus/unit-10) or the practice bank (https://library.fiveable.me/practice/ap-calculus).
I'm confused about the nth term test - does it prove convergence or just divergence?
The nth-term test only proves divergence. AP CED (LIM-7.A.5) calls it a divergence test: if lim_{n→∞} a_n ≠ 0 (or the limit doesn’t exist), then the series ∑ a_n must diverge. That’s a necessary condition for convergence—a_n → 0 is required but not enough. So: - If lim a_n ≠ 0 → series diverges (you can conclude divergence). - If lim a_n = 0 → the test is inconclusive; the series might converge (e.g., geometric with |r|<1) or diverge (e.g., harmonic ∑1/n). For more AP-aligned notes and examples, check the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For extra practice problems across Unit 10, use (https://library.fiveable.me/practice/ap-calculus).
Can someone explain step by step how to apply the nth term test?
Use the nth-term (zero) test as a quick divergence check—step by step: 1. Identify a_n, the general term of the series ∑ a_n. 2. Compute L = lim_{n→∞} a_n. (This is a limit of the sequence of terms, not partial sums.) 3. Apply the rule (CED/LIM-7.A.5): - If L ≠ 0 or the limit doesn’t exist, the series diverges. (Necessary condition for convergence: terms must go to 0.) - If L = 0, the test is inconclusive—the series might converge or diverge; use other tests (comparison, integral, alternating, ratio, etc.). 4. Common checks: for a_n = 1/n, L = 0 but harmonic series still diverges (so nth-term test alone fails); for a_n = 1/2^n, L = 0 and geometric test shows convergence. So practically: take the limit; nonzero → immediate “diverges.” Zero → stop and pick a stronger convergence test. For the AP BC topic and examples, see the Fiveable study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For extra practice, use the Unit 10 overview (https://library.fiveable.me/ap-calculus/unit-10) and Fiveable’s practice problems (https://library.fiveable.me/practice/ap-calculus).
What's the difference between the nth term test and the ratio test?
The nth-term (divergence) test and the ratio test do related but different jobs. - nth-term test (zero test): If lim_{n→∞} a_n ≠ 0 (or doesn’t exist) then the series ∑ a_n diverges. It’s a necessary condition for convergence only—if lim a_n = 0 you still don’t know convergence. This is the simple “nonzero term ⇒ divergence” test emphasized in LIM-7.A (Topic 10.3) and is the first quick check you should always do. - Ratio test: Compute L = lim_{n→∞} |a_{n+1}/a_n|. - If L < 1, the series converges absolutely. - If L > 1 (or = ∞), it diverges. - If L = 1, the test is inconclusive. Use the ratio test for factorials, exponentials, or n-th powers (e.g., n!, 2^n, (3/2)^n). It often succeeds where the nth-term test can’t (because nth-term only rules out convergence). Quick strategy for AP BC: always run the nth-term test first (zero test); if lim a_n = 0, try a stronger test—ratio, comparison, integral, alternating series, etc. For the Topic 10.3 study guide see (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For more unit review and practice questions go to (https://library.fiveable.me/ap-calculus/unit-10) and (https://library.fiveable.me/practice/ap-calculus).
How do I find the limit of the nth term when n goes to infinity?
Find the limit of a_n as n → ∞ so you can apply the nth-term (divergence) test: if lim a_n ≠ 0 (or doesn’t exist), the series ∑a_n must diverge. If lim a_n = 0, the test is inconclusive. How to compute lim a_n (quick checklist): - Simplify algebraically (divide numerator & denominator by highest power of n). Example: a_n = n/(n+1) → divide by n → 1/(1+1/n) → limit 1 → series diverges. - Compare growth rates: polynomials vs exponentials. n^p / a^n → 0 if |a|>1. So a_n = 2^n/n! → 0. - Recognize standard limits: 1/n^p → 0 (p>0); r^n → 0 iff |r|<1; (−1)^n oscillates (no limit). - Use L’Hôpital on sequences written as functions f(n) → f(x) then x→∞ when appropriate. - Squeeze theorem if you can bound a_n between two sequences with same limit. Examples: a_n = 1/n → 0 (inconclusive); a_n = (−1)^n → no limit → series diverges by nth-term test; a_n = (3/4)^n → 0 (could converge). For AP BC review of the test and worked examples, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). Practice lots of limits on Fiveable’s practice page (https://library.fiveable.me/practice/ap-calculus)—knowing common patterns will save you time on the exam.
Why does the nth term test only work for proving divergence and not convergence?
The nth-term test is just a “zero test”: if lim_{n→∞} a_n ≠ 0 (or doesn’t exist), the series ∑a_n cannot converge—because the terms don’t shrink to 0, the partial sums keep changing by a nonzero amount, so the series diverges. That’s why the test proves divergence. But lim_{n→∞} a_n = 0 is only a necessary condition, not sufficient. Even when terms go to zero, partial sums can still blow up—e.g., the harmonic series ∑1/n has a_n → 0 but diverges. So the nth-term test can only give a one-way conclusion: nonzero limit ⇒ divergence; zero limit ⇒ inconclusive. For deciding convergence you must use other tests (comparison, integral, ratio, alternating, p-series, etc.). This is exactly what the CED emphasizes for LIM-7.A (nth-term test = divergence test). See the Topic 10.3 study guide for examples and practice (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For more practice, check the unit overview (https://library.fiveable.me/ap-calculus/unit-10) or the practice problems (https://library.fiveable.me/practice/ap-calculus).
If lim n→∞ an ≠ 0, what does that tell me about the series?
If lim_{n→∞} a_n ≠ 0, the series Σ a_n must diverge. This is the nth-term (or divergence/zero) test: a necessary condition for convergence is that the terms go to 0, so if they don’t, the sequence of partial sums cannot settle to a finite limit. Notes that help for AP BC: this test only shows divergence—it can’t prove convergence when lim a_n = 0 (you’ll need other tests). Use the nth-term test early when terms don’t approach 0 (that immediately rules the series out). This is exactly what LIM-7.A.5 in the CED describes. For a refresher, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx) and more unit review (https://library.fiveable.me/ap-calculus/unit-10). For extra practice, try problems at (https://library.fiveable.me/practice/ap-calculus).
I don't understand when the nth term test is inconclusive - can someone explain?
Good question—the nth-term test only tells you when a series definitely diverges, not when it converges. - The test: if lim_{n→∞} a_n ≠ 0 or does not exist, then ∑ a_n diverges. That’s a necessary condition for convergence (zero test). - It’s inconclusive when lim_{n→∞} a_n = 0. Why? Because a_n → 0 is required for convergence but not enough by itself. Examples: - ∑ 1/n (harmonic) has terms → 0 but diverges. - ∑ 1/2^n has terms → 0 and converges (geometric). - Alternating harmonic ∑ (-1)^{n+1}/n has terms → 0 and converges conditionally. So: if the limit isn’t zero, you’re done—divergent. If the limit is zero, you must use other tests (comparison, integral, ratio, alternating series, p-series, etc.) to decide. This is exactly what Topic 10.3 in the CED emphasizes—nth-term test = divergence test, not a convergence test. For the AP review and examples, check the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx) and more unit resources (https://library.fiveable.me/ap-calculus/unit-10). For extra practice, try problems at (https://library.fiveable.me/practice/ap-calculus).
What happens if the limit of the nth term doesn't exist?
If lim_{n→∞} a_n does not exist, the nth-term test (zero test) tells you the series ∑ a_n diverges. The CED’s key idea is that a necessary condition for convergence is that the terms go to 0; if the limit fails to exist (or equals any nonzero number), the series cannot converge. Why: convergence of ∑ a_n implies the sequence of terms a_n → 0 (otherwise partial sums can’t settle). So nonexistence of the limit rules out convergence. Note this is only a divergence test—if lim a_n = 0, the test is inconclusive (you’ll need another test like integral, comparison, ratio, or alternating series). For a quick review, check the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx) and more unit resources (https://library.fiveable.me/ap-calculus/unit-10). For extra practice, use the AP problems at (https://library.fiveable.me/practice/ap-calculus).
How do I know which convergence test to try first on a series problem?
Start with the nth-term (zero) test every time: if lim a_n ≠ 0, the series diverges immediately (fast check). If lim a_n = 0, that just means “maybe”—you need other tests. Quick strategy for what to try next (order of checks you’ll usually follow on the AP BC exam): - Recognize the form: is it geometric? If so, use the geometric-series test. - Look for p-series or something like 1/n^p → use p-series. - Alternating signs with decreasing terms → try the Alternating Series Test (for conditional convergence). - Positive-term rational combos of polynomials → try Limit Comparison with a known p-series. - Exponentials or factorials → try Ratio or Root Test. - Terms coming from an integral-friendly function (decreasing, positive) → Integral Test. - Obvious telescoping sum → compute partial sums. - If you want absolute vs conditional: test absolute convergence with one of the positive-term tests above. Always state why a test applies (conditions from the CED: e.g., monotone decreasing for the integral or alternating tests). For guided practice and examples on Topic 10.3, see the Fiveable study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx). For lots of practice problems, use the AP practice bank (https://library.fiveable.me/practice/ap-calculus).
Can the nth term test be used on any type of series or are there restrictions?
Short answer: the nth-term (or zero) test applies to any infinite series ∑ a_n, but it only tests for divergence—not convergence. If lim_{n→∞} a_n ≠ 0 or doesn’t exist, the series MUST diverge. If lim_{n→∞} a_n = 0, the test is inconclusive: the series might converge (e.g., alternating harmonic) or diverge (e.g., harmonic series). So restrictions to remember: - You may apply it to any series (geometric, p-series, alternating, etc.) to try to prove divergence. - You cannot use it to prove convergence. If the terms go to 0, you must use other tests (ratio, integral, comparison, alternating series, etc.) per the CED LIM-7.A objectives. For a quick refresher, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx) and try practice problems at (https://library.fiveable.me/practice/ap-calculus).
I keep getting confused about whether I'm testing the sequence or the series - what's the difference?
Short answer: a sequence is the list of terms a_n; a series is the sum of those terms (partial sums S_n = a_1 + a_2 + ... + a_n). The nth-term test (zero test) looks at the sequence a_n, not the partial-sum sequence S_n. How to use it (CED language): compute lim_{n→∞} a_n. - If lim a_n ≠ 0 (or doesn’t exist), the series ∑ a_n diverges—nonzero term implies divergence (necessary condition). - If lim a_n = 0, the test is inconclusive: the series might converge (e.g., alternating series) or diverge (e.g., harmonic series ∑ 1/n). Quick examples: a_n = 1/n → lim a_n = 0 but ∑ 1/n diverges. a_n = (–1)^n/n → lim = 0 and ∑ converges conditionally. This is a BC-only divergence test (LIM-7.A.5). For a concise guide and practice, see the Topic 10.3 study guide (https://library.fiveable.me/ap-calculus/unit-10/nth-term-test-for-divergence/study-guide/oEMEbEp7gWXCgxDFyRlx) and more unit review (https://library.fiveable.me/ap-calculus/unit-10). For extra practice questions, try Fiveable’s problem bank (https://library.fiveable.me/practice/ap-calculus).