8.1 Finding the Average Value of a Function on an Interval
Welcome back to AP Calculus with Fiveable! This topic focuses on finding the average value of a continuous function using definite integrals.
๐ข Average Value of a Function
The average value of a function will allow us to solve problems that involve the accumulation of change over an interval, which will later be used to understand more difficult topics of integration.
For questions that require the average value of a function, we are never given a finite number of data points. Therefore, we must use integration to determine what the average value is.
This idea is fairly simple once you memorize a key piece of information: if f is continuous on [a,b], then the average value of f on [a,b] is the following.
Average Value=bโa1โโซabโf(x)dx
Image of average value equation and corresponding graph. Image courtesy of ExamSolutions
๐Average Value of a Function Steps
Here are some steps to help break down the formula!
- Set up the integral so that you integrate f(x) from a to b with respect to x, which will calculate the area under the curve between these two limits.
- Then place the fraction in front of the integral, which is simply the reciprocal of the difference between a and b.
- Evaluating this expression allows you to get the average y-value of this function between [a,b]
โ๏ธ Average Value of a Function Walkthrough
If the formula still seems a little difficult to understand due to its notation, practice questions are the best way to better understand its use!
Consider the function f(x)=2x2โ3x+5 on the interval [1,4]. Find the average value of this function on the interval.
In this case, a=1 and b=4. So we begin by subbing the 1 and 4 into both the denominator of the fraction in front of the integral and the limits of the integral.
Average Value=4โ11โโซ14โ(2x2โ3x+5)dx
Next, take the integral of f(x).
=31โ[32โx3โ23โx2+5x]14โ
Finally, we can sub in the limits and evaluate.
31โ[(32โ(4)3โ23โ(4)2+5(4))โ(32โ(1)3โ23โ(1)2+5(1))]=223โโ
Time for you to practice some questions yourself! โฌ๏ธ
๐ Average Value of a Function Practice Problems
Give each of these problems a try before you move onto the solutions!
- What is the average value of 5x2+4 on the interval 0โคxโค6?
- What is the average value of x3โx2 on the interval 2โคxโค5?
- What is the average value of sin(x)+cos(x) on the interval 0โคxโคฯ?
Average Value of a Function Question Solutions
Question 1 Solution
Average Value=6โ01โโซ06โ(5x2+4)dx
=61โ[35โx3+4x]06โ
61โ[(35โ(6)3+4(6))โ(35โ(0)3+4(0))]=64โ
Question 2 Solution
Average Value=5โ21โโซ25โ(x3โx2)dx
=31โ[41โx4โ31โx3]25โ
31โ[(41โ(5)4โ31โ(5)3)โ(41โ(2)4โ31โ(2)3)]=4151โโ
Question 3 Solution
Average Value=ฯโ01โโซ0ฯโsin(x)+cos(x)dx
=ฯ1โ[โcos(x)+sin(x)]0ฯโ
ฯ1โ[(โcos(ฯ)+sin(ฯ))โ(โcos(0)+sin(0))]=ฯ2โโ
โญ Closing
Great job! This topic often shows up as part (a) of FRQs, so keep this in mind for the AP.