Fiveable
♾️AP Calculus AB/BC
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♾️AP Calculus AB/BC

FRQs – Graphing calculator required
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Unit 1: Limits and Continuity
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Guided Practice

Practice FRQ 1 of 81/8
1. The following functions are defined for this question: g(x)={x2−4x−2x≠24x=2g(x) = \begin{cases} \frac{x^2-4}{x-2} & x ≠ 2 \\ 4 & x = 2 \end{cases}g(x)={x−2x2−4​4​x=2x=2​ k(x)=4k(x) = 4k(x)=4
A temporary channel is built to move water away from a construction site. For x≠2x≠ 2x=2, the function fff defined by f(x)=x2−4x−2f(x)=\frac{x^2-4}{x-2}f(x)=x−2x2−4​ models the flow rate of water, in cubic meters per minute, at position xxx meters along the channel. A graph of y=f(x)y=f(x)y=f(x) is shown in Figure 1.
  • g(x)={x2−4x−2x≠24x=2g(x) = \begin{cases} \frac{x^2-4}{x-2} & x ≠ 2 \\ 4 & x = 2 \end{cases}g(x)={x−2x2−4​4​x=2x=2​
  • k(x)=4k(x) = 4k(x)=4

Figure 1. Graph of y = f(x) for f(x) = (x^2 − 4)/(x − 2), x ≠ 2 (flow rate vs. position).

Single 2D graph on a clean coordinate plane (no grid).

Axes (all required items):
- Horizontal axis labeled exactly: "x (meters)". The x-axis runs from −1 to 5 with tick marks every 1 unit, labeled −1, 0, 1, 2, 3, 4, 5. The origin is labeled "0" at the axes intersection. Put an arrow on the positive end of the x-axis.
- Vertical axis labeled exactly: "f(x) (cubic meters per minute)". The y-axis runs from 0 to 8 with tick marks every 1 unit, labeled 0 through 8. The origin label "0" is at the intersection (shared with x-axis). Put an arrow on the positive end of the y-axis.

Curve shape description (path and key features):
- The graph is a straight line with positive slope everywhere it is drawn, matching the linear rule f(x) = x + 2 for all x-values shown except the single excluded x-value where the hole occurs.
- On the left edge of the window (at x = −1), the line is at y = 1. From there it rises uniformly (constant slope) as x increases.
- The line passes exactly through the y-axis at y = 2 (so the y-intercept is 2).
- The line continues rising through x = 1 at y = 3, then reaches the excluded x-value at x = 2.

Discontinuity (removable hole) with exact numeric placement:
- At x = 2, do NOT draw a filled point. Instead, leave a small gap in the line and draw an open circle exactly on the line directly above the tick labeled 2 on the x-axis.
- The open circle is placed at y = 4 (aligned horizontally with the y-axis tick labeled 4), indicating the value the line would have there.
- The straight line is drawn on both sides of x = 2 as two separate solid segments: one segment from x = −1 up to but not including x = 2, and a second segment starting just to the right of x = 2 through the right edge of the window.

Right-side continuation:
- After the open circle location, the line continues with the same constant slope upward, passing through x = 3 at y = 5, through x = 4 at y = 6, and reaching y = 7 at the right edge x = 5.

Curve behavior summary (segment-by-segment, as required):
- Segment for x < 2: perfectly straight solid line, increasing left-to-right, constant slope; no curvature (neither concave up nor concave down).
- At x = 2: removable discontinuity shown by a single open circle at y = 4 with a visible break in the line; no filled point at that x-value.
- Segment for x > 2: perfectly straight solid line, increasing left-to-right with the same constant slope as the left segment; no curvature.

Styling:
- Draw the line in solid black, medium thickness.
- Draw the open circle in black with a white interior, clearly visible and centered exactly at the intersection of x = 2 and y = 4 alignment.
- No extra annotations, no equation text inside the plotting area, and no legend.
A. Use the definition of average rate of change to find the average rate of change of fff over the interval 1≤x≤31≤ x≤ 31≤x≤3. Show the setup for your calculations.
B. Use average rates of change over intervals containing x=2x=2x=2 to estimate the instantaneous rate of change of fff at x=2x=2x=2. Show the setup for your calculations.
C. Write a limit expression that represents the value of f(x)f(x)f(x) as xxx approaches 222, and evaluate the limit.
The function ggg matches fff for all x≠2x≠ 2x=2 but assigns the value kkk at x=2x=2x=2 to remove the discontinuity.
D. A new function ggg is defined by g(x)={f(x),x≠2k,x=2g(x)=\begin{cases}f(x),&x≠ 2\\k,&x=2\end{cases}g(x)={f(x),k,​x=2x=2​, where kkk is a constant. Find the value of kkk such that ggg is continuous at x=2x=2x=2. Justify your answer.






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