Fiveable

♾️AP Calculus AB/BC Unit 1 Review

QR code for AP Calculus AB/BC practice questions

1.2 Defining Limits and Using Limit Notation

1.2 Defining Limits and Using Limit Notation

Written by the Fiveable Content Team • Last updated June 2026
Verified for the 2027 exam
Verified for the 2027 examWritten by the Fiveable Content Team • Last updated June 2026
♾️AP Calculus AB/BC
Unit & Topic Study Guides

AP Cram Sessions 2021

Pep mascot

TLDR

A limit describes the value a function gets close to as xx approaches a number, even if the function never actually reaches that value there. In AP Calculus, you write this as limxcf(x)=R\lim\limits_{x \to c} f(x) = R, and you can express the same idea graphically, numerically, or analytically.

Why This Matters for the AP Calculus Exam

Limits are the foundation for almost everything that comes later: derivatives, integrals, and (for BC) infinite series all build on the limit idea. On the AP Calculus exam, you may see limit questions in both multiple-choice and free-response form, with some sections that allow a calculator and some that do not.

This topic focuses on two skills: writing limits with correct notation and reading what a limit in notation is telling you. Clear, correct notation is important for showing your work in a way graders can follow. Getting comfortable with translating between graphs, tables, and analytic expressions sets you up for the rest of Unit 1 and beyond.

Key Takeaways

  • A limit is the single value f(x)f(x) approaches as xx gets arbitrarily close to cc, but not necessarily the value at cc itself.
  • The standard notation is limxcf(x)=R\lim\limits_{x \to c} f(x) = R, read as "the limit of f(x)f(x) as xx approaches cc equals RR."
  • The same limit can be shown three ways: graphically, numerically (a table), and analytically (an expression).
  • f(c)f(c) and limxcf(x)\lim\limits_{x \to c} f(x) are not always the same; a function can have a hole at cc but still have a limit there.
  • When a function is continuous at cc, you can find the limit by direct substitution.
  • One-sided notation, limxcf(x)\lim\limits_{x \to c^-} f(x) and limxc+f(x)\lim\limits_{x \to c^+} f(x), lets you describe behavior from each side separately.

Defining a Limit

A limit is the yy-value a function f(x)f(x) heads toward as xx approaches some number. You write it as:

limxcf(x)=R\lim\limits_{x \to c} f(x) = R

This is read as "the limit of f(x)f(x) as xx approaches cc." More precisely, the limit equals a real number RR if f(x)f(x) can be made arbitrarily close to RR by taking xx sufficiently close to cc, but not equal to cc.

That last part matters. The limit is about what happens near cc, not necessarily at cc. The function might not even be defined at cc, and the limit can still exist.

You do not need the epsilon-delta definition of a limit for the AP exam. The "arbitrarily close" idea above is the version you will use.

Representing Limits Numerically and Graphically

A limit can be expressed in multiple ways, including graphically, numerically, and analytically. Being able to move between these representations is a core Unit 1 skill.

Representing Limits Numerically

Consider this function:

f(x)=x21x1f(x)=\frac{x^2-1}{x-1}

We want the limit as xx approaches 11. Notice that plugging in x=1x=1 gives 00\frac{0}{0}, which is undefined, so we cannot just substitute. Instead, build a table of xx-values approaching 11 from both sides:

Approaching from the left (x1x \to 1^-)Approaching from the right (x1+x \to 1^+)
0.91.1
0.991.01
0.9991.001
0.99991.0001

Now calculate f(x)f(x) for each value.

Viewing the Limit from the Left Side

For x1x \to 1^-:

f(0.9)=0.9210.91=0.8110.1=0.190.1=1.9f(0.9) =\frac{0.9^2 - 1}{0.9 - 1} = \frac{0.81 - 1}{-0.1} = \frac{-0.19}{-0.1} = 1.9

f(0.99)=0.99210.991=0.980110.01=0.01990.01=1.99f(0.99) = \frac{0.99^2 - 1}{0.99 - 1} = \frac{0.9801 - 1}{-0.01} = \frac{-0.0199}{-0.01} = 1.99

f(0.999)=0.999210.9991=0.99800110.001=0.0019990.001=1.999f(0.999) = \frac{0.999^2 - 1}{0.999 - 1} = \frac{0.998001 - 1}{-0.001} = \frac{-0.001999}{-0.001} = 1.999

f(0.9999)=0.9999210.99991=0.9998000110.0001=0.000199990.0001=1.9999f(0.9999) = \frac{0.9999^2 - 1}{0.9999 - 1} = \frac{0.99980001 - 1}{-0.0001} = \frac{-0.00019999}{-0.0001} = 1.9999

As xx gets closer to 11 from the left, f(x)f(x) approaches 22.

Viewing the Limit from the Right Side

For x1+x \to 1^+:

f(1.1)=1.1211.11=1.2110.1=0.210.1=2.1f(1.1) = \frac{1.1^2 - 1}{1.1 - 1} = \frac{1.21 - 1}{0.1} = \frac{0.21}{0.1} = 2.1

f(1.01)=1.01211.011=1.020110.01=0.02010.01=2.01f(1.01) = \frac{1.01^2 - 1}{1.01 - 1} = \frac{1.0201 - 1}{0.01} = \frac{0.0201}{0.01} = 2.01

f(1.001)=1.001211.0011=1.00200110.001=0.0020010.001=2.001f(1.001) = \frac{1.001^2 - 1}{1.001 - 1} = \frac{1.002001 - 1}{0.001} = \frac{0.002001}{0.001} = 2.001

f(1.0001)=1.0001211.00011=1.0002000110.0001=0.000200010.0001=2.0001f(1.0001) = \frac{1.0001^2 - 1}{1.0001 - 1} = \frac{1.00020001 - 1}{0.0001} = \frac{0.00020001}{0.0001} = 2.0001

From the right side, f(x)f(x) also approaches 22. Since both sides head to the same value:

limx1x21x1=2\lim\limits_{x \to 1}\frac{x^2-1}{x-1} = 2

This is a good example of a limit existing even though f(1)f(1) itself is undefined. There is a hole in the graph at x=1x=1, but the function still approaches 22 from both sides.

You can go deeper on estimating limit values from tables in Topic 1.4.

Representing Limits Graphically

Now take the linear function f(x)=2x+3f(x)=2x+3 and find limx1(2x+3)\lim\limits_{x \to 1}(2x+3).

As xx approaches 11 from the left (x1x \to 1^-) and from the right (x1+x \to 1^+), the function values move smoothly along the line toward the same yy-value. Both sides converge, so:

limx1(2x+3)=5\lim\limits_{x \to 1}(2x+3) = 5

Because this function is continuous everywhere, the graph has no break at x=1x=1, and the limit equals the function value there.

You can go deeper on estimating limits from graphs in Topic 1.3.

Limits are not just numbers; they describe how a function behaves near a point, not only at the point itself.

How to Use This on the AP Calculus Exam

MCQ

Many limit questions can be answered by direct substitution when the function is continuous at the point. Plug in the value and evaluate. If substitution gives a real number, that is usually your answer.

Watch for forms like 00\frac{0}{0}. That signals you cannot just substitute and need another approach, such as factoring or a table, which you will practice in later topics.

Problem Solving

  1. Substitute the value into the limit.
  2. Evaluate. If you get a real number, that is the limit. If you get 00\frac{0}{0}, the function may have a hole, so try a table or algebraic simplification.

Common Trap

Use correct notation throughout. Keep the limxc\lim\limits_{x \to c} written until you actually substitute the value. Writing clean notation helps graders follow your reasoning on free-response work.

Defining Limits: Practice Problems

When you work these, follow two steps:

  1. Substitute the value into the limit.

  2. Evaluate the limit.

  3. Consider the function f(x)=3x1f(x)=3x-1. What is the value of limx2f(x)\lim\limits_{x \to 2}f(x)?

    A. 3

    B. 5

    C. 6

    D. 7

  4. Consider the function f(x)=x5f(x)=x-5. What is the value of limx3f(x)\lim\limits_{x \to -3}f(x)?

    A. -8

    B. 8

    C. 9

    D. 1

Defining Limits: Solutions to Practice Problems

  1. Both steps:

    1. Substitute: limx2f(x)=limx2(3x1)\lim\limits_{x \to 2}f(x) = \lim\limits_{x \to 2}(3x-1)
    2. Evaluate: 3(2)1=61=53(2)-1 = 6-1 = 5

    The correct answer is B) 5. This works by direct substitution because 3x13x-1 is continuous everywhere.

  2. Both steps:

    1. Substitute: limx3f(x)=limx3(x5)\lim\limits_{x \to -3}f(x) = \lim\limits_{x \to -3}(x-5)
    2. Evaluate: (3)5=8(-3)-5 = -8

    The correct answer is A) -8.

Common Misconceptions

  • A limit equals the function value at that point. Not always. The limit is what f(x)f(x) approaches near cc. The function might be undefined at cc or defined as a different value, and the limit can still exist.
  • If f(c)f(c) is undefined, the limit must not exist. False. The x21x1\frac{x^2-1}{x-1} example above is undefined at x=1x=1, but the limit there is 22.
  • You can always find a limit by plugging in. Direct substitution only works when the function is continuous at that point. When you get 00\frac{0}{0}, you need another method.
  • The notation limxcf(x)\lim\limits_{x \to c} f(x) and f(c)f(c) mean the same thing. They are different ideas. One is about approaching behavior; the other is the actual output at cc.
  • A two-sided limit exists no matter what the sides do. For a two-sided limit to exist, the left-hand and right-hand limits must approach the same value.

Vocabulary

The following words are mentioned explicitly in the College Board Course and Exam Description for this topic.

Term

Definition

analytic notation

The symbolic mathematical representation of a limit, typically written as lim(x→a) f(x) = L.

approaches

In the context of limits, the behavior of a function's output as the input gets arbitrarily close to a specific value.

function

A mathematical relationship that assigns exactly one output value to each input value of an independent variable.

limit

The value that a function approaches as the input approaches some value, which may or may not equal the function's value at that point.

limit notation

The symbolic representation of a limit, written as lim[x→c] f(x) = R, indicating that f(x) approaches R as x approaches c.

Frequently Asked Questions

What is AP Calculus 1.2 about?

AP Calculus 1.2 is about defining limits and using correct limit notation. You learn that a limit describes what $f(x)$ approaches as $x$ gets close to a value, and you interpret that idea analytically, graphically, and numerically.

How do I write limit notation correctly?

The standard notation is $\lim_{x\to c} f(x)=R$, which means the values of $f(x)$ approach the real number $R$ as $x$ gets close to $c$. The expression is about behavior near $c$, not necessarily the value at $c$.

What does a limit mean in plain language?

A limit is the value a function gets close to as the input gets close to a specific number. The function does not have to equal that value at the input, and it may not even be defined there.

Can a limit exist if the function is undefined?

Yes. A limit can exist even if the function is undefined at the exact input value, because the limit depends on nearby behavior. A removable discontinuity, or hole, is the classic example.

What is one-sided limit notation?

One-sided limit notation uses $x\to c^-$ for approaching from the left and $x\to c^+$ for approaching from the right. A two-sided limit exists only when the left-hand and right-hand limits approach the same value.

How does limit notation show up on the AP Calculus exam?

You may need to interpret limit notation from an equation, graph, or table, then explain what value the function approaches. Use correct notation and remember that the AP exam does not assess the formal epsilon-delta definition.

Pep mascot
Upgrade your Fiveable account to print any study guide

Download study guides as beautiful PDFs See example

Print or share PDFs with your students

Always prints our latest, updated content

Mark up and annotate as you study

Click below to go to billing portal → update your plan → choose Yearly→ and select "Fiveable Share Plan". Only pay the difference

Plan is open to all students, teachers, parents, etc
Pep mascot
Upgrade your Fiveable account to export vocabulary

Download study guides as beautiful PDFs See example

Print or share PDFs with your students

Always prints our latest, updated content

Mark up and annotate as you study

Plan is open to all students, teachers, parents, etc
report an error
description

screenshots help us find and fix the issue faster (optional)

add screenshot

2,589 studying →