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5.3 Determining Intervals on Which a Function is Increasing or Decreasing

5.3 Determining Intervals on Which a Function is Increasing or Decreasing

Written by the Fiveable Content Team • Last updated June 2026
Verified for the 2027 exam
Verified for the 2027 examWritten by the Fiveable Content Team • Last updated June 2026
♾️AP Calculus AB/BC
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A function is increasing where its first derivative is positive and decreasing where the first derivative is negative. To find these intervals, locate the critical points (where f(x)=0f'(x)=0 or ff' is undefined) plus any points where the function itself is undefined, split the domain at those points, then test the sign of ff' in each piece. For AP Calculus, justify each interval with the sign of ff'.

Why This Matters for the AP Calculus Exam

This topic is the backbone of analyzing function behavior with derivatives, which shows up across Unit 5. On the AP Calculus exam you will use sign analysis of ff' to justify where a function increases or decreases, and that same skill leads directly into finding relative extrema, locating absolute extrema, and sketching graphs of ff from information about ff'.

These questions appear in both multiple-choice and free-response settings. Strong justifications matter here: when you claim a function is increasing, you need to point to the sign of the derivative, not just say "the graph goes up." Refer to ff, ff', and ff'' by name so your reasoning is clear.

Key Takeaways

  • f(x)>0f'(x) > 0 means ff is increasing; f(x)<0f'(x) < 0 means ff is decreasing.
  • A function can only switch between increasing and decreasing at critical points (where f(x)=0f'(x)=0 or ff' is undefined) or where ff itself is undefined.
  • Split the domain at those points, then test the sign of ff' at one sample point inside each interval.
  • Report your answer in interval notation using open intervals.
  • Justify with the sign of ff', not vague phrases like "it's going up."
  • Always name ff, ff', or ff'' so the reader knows which function you mean.

When Does a Function Increase or Decrease?

The derivative of a function gives its rate of change at a point, so the sign of the derivative tells you which direction the function is heading.

  1. If ff' is positive at a point, ff is increasing there.
  2. If ff' is negative at a point, ff is decreasing there.

The graph below shows this pattern. The gray line is the function ff, and the black line is its derivative ff'.

Graph of a function and its derivative

A function can only change direction (from increasing to decreasing or the reverse) at its critical points, where the derivative equals 00 or is undefined, and at points where the function itself is undefined.

So for each interval between those points, pick one sample xx-value, plug it into ff', and check the sign. Positive means increasing on that interval; negative means decreasing. The sign stays the same across an interval because the function cannot switch direction without passing through a critical point.

Worked Example

Let hh be a function defined for all real numbers except 00, with derivative h(x)=(x+7)x2h'(x)=\frac{(x+7)}{x^2}. On which intervals is hh increasing?

Find where hh can change direction. Set h(x)=0h'(x)=0:

h(x)=(x+7)x2h'(x)=\frac{(x+7)}{x^2}

0=(x+7)x20=\frac{(x+7)}{x^2}

This gives h=0h'=0 at x=7x=-7, so that is a critical point. The function is also undefined at x=0x=0, as stated. These two points split the number line into three intervals:

(,7),(7,0),(0,)(-\infty,-7),(-7,0),(0,\infty)

Test a sample xx-value in each interval. Here we use x=8x=-8, x=1x=-1, and x=1x=1.

Intervalxxh(x)h'(x)Verdict
(,7)(-\infty,-7)x=8x=-8h(8)=164<0h'(-8)=-\frac{1}{64} <0hh is decreasing
(7,0)(-7,0)x=1x=-1h(1)=6>0h'(-1)=6 > 0hh is increasing
(0,)(0,\infty)x=1x=1h(1)=8>0h'(1)=8>0hh is increasing

So hh is increasing on (7,0)(-7,0) and (0,)(0,\infty).

Steps to Determine Function Behavior

  1. Find the critical points, where f(x)f'(x) equals zero or is undefined.
  2. Split the domain into intervals at those critical points (and any points where ff is undefined).
  3. Choose a test point inside each interval.
  4. Evaluate ff' at each test point.
  5. Read the sign: positive means ff is increasing on that interval, negative means ff is decreasing.

How to Use This on the AP Calculus Exam

Problem Solving

Use the sign chart of ff' as your main tool. Find critical points, split the domain, test each interval, and translate the sign of ff' into increasing or decreasing behavior of ff.

Free Response

When a question says "Justify your answer," anchor your justification to the sign of the derivative. Write something like "ff is increasing on (7,0)(-7,0) because f(x)>0f'(x)>0 on that interval." Naming ff and ff' specifically keeps your reasoning clear and easy to follow, which is important for clean exam work.

Common Trap

If you are given the graph of ff' instead of an equation, read where the graph is above the xx-axis (positive, so ff is increasing) and below it (negative, so ff is decreasing). Do not treat the height of the ff' graph as the height of ff.

Practice Problems

Question 1

Let f(x)=x327xf(x)=x^3-27x. On which interval(s) is ff decreasing?

Question 2

Let f(x)=x42x2f(x)=x^{4}-2x^{2}. On which interval(s) is ff increasing?

Answers and Solutions

Question 1

The answer is (3,3)(-3,3).

Look for where ff' is negative. The derivative is f(x)=3x227f'(x)=3x^2-27, which equals 00 at x=3x=-3 and x=3x=3, so these are the only points where ff can change direction. They split the number line into three intervals: (,3),(3,3),(3,)(-\infty,-3),(-3,3),(3,\infty).

Intervalxxf(x)f'(x)Verdict
(,3)(-\infty,-3)x=4x=-4f(4)=21>0f'(-4)=21>0ff is increasing
(3,3)(-3,3)x=0x=0f(0)=27<0f'(0)=-27<0ff is decreasing
(3,)(3,\infty)x=4x=4f(4)=21>0f'(4)=21>0ff is increasing

So ff is decreasing on (3,3)(-3,3).

Question 2

The answer is (1,0)(-1,0) and (1,)(1,\infty).

Look for where ff' is positive. The derivative is f(x)=4x34xf'(x)=4x^3-4x, which factors as 4x(x+1)(x1)4x(x+1)(x-1). It equals 00 at x=1x=-1, x=0x=0, and x=1x=1, so these are the only points where ff can change direction. They split the number line into four intervals: (,1),(1,0),(0,1),(1,)(-\infty,-1),(-1,0),(0,1),(1,\infty).

Intervalxxf(x)f'(x)Verdict
(,1)(-\infty,-1)x=2x=-2f(2)=24<0f'(-2)=-24<0ff is decreasing
(1,0)(-1,0)x=0.5x=-0.5f(0.5)=1.5>0f'(-0.5)=1.5>0ff is increasing
(0,1)(0,1)x=0.5x=0.5f(0.5)=1.5<0f'(0.5)=-1.5<0ff is decreasing
(1,)(1,\infty)x=2x=2f(2)=24>0f'(2)=24>0ff is increasing

So ff is increasing on (1,0)(-1,0) and (1,)(1,\infty).

Common Misconceptions

  • Reading the ff' graph as if it were ff. A high point on the graph of ff' does not mean ff is large; it means ff is increasing quickly. Use the sign of ff', not its height.
  • Justifying with "it's going up." On free-response questions you need to cite the sign of the derivative, such as "f(x)>0f'(x)>0 on this interval," not a casual description.
  • Forgetting points where ff is undefined. The function can only change direction at critical points and at points outside its domain, so include both when you split the number line.
  • Saying f=0f'=0 always means a max or min. A zero of ff' marks a possible change in direction, but ff might keep increasing or decreasing through it if the sign does not switch.
  • Using closed intervals carelessly. Report intervals of increase and decrease as open intervals between the critical points.
  • Writing "it" instead of naming the function. Always refer to ff, ff', and ff'' by name so your reasoning is unambiguous.

Vocabulary

The following words are mentioned explicitly in the College Board Course and Exam Description for this topic.

Term

Definition

decreasing

An interval on which a function's output values are getting smaller as the input values increase, corresponding to where the first derivative is negative.

first derivative

The derivative of a function, denoted f', which describes the rate of change and indicates where a function is increasing or decreasing.

increasing

An interval on which a function's output values are getting larger as the input values increase, corresponding to where the first derivative is positive.

Frequently Asked Questions

How do you find increasing and decreasing intervals in AP Calculus?

Find where f'(x)=0, where f' is undefined, and where f is undefined. Use those points to split the domain, test the sign of f' on each interval, then report where f'(x)>0 as increasing and where f'(x)<0 as decreasing.

What does f'(x) > 0 mean?

If f'(x)>0 on an interval, then f is increasing on that interval. On the AP exam, justify the claim by naming the derivative and the interval, not just by saying the graph goes up.

What points split the sign chart for increasing and decreasing intervals?

Use critical points where f'(x)=0 or f' is undefined, plus any points where f itself is undefined. Those values divide the domain into intervals where you can test the sign of the derivative.

Why do you use open intervals for increasing and decreasing?

Increasing and decreasing behavior is described on intervals between critical points or domain breaks. The endpoints are usually excluded because they are where the derivative is zero, undefined, or where the function is not defined.

How do you use the graph of f' to find where f is increasing?

Look for where the graph of f' is above the x-axis. That means f'(x)>0, so f is increasing. Where the graph of f' is below the x-axis, f'(x)<0 and f is decreasing.

What is a common AP Calc 5.3 mistake?

A common mistake is mixing up f and f'. If the question gives a graph of f', points above the x-axis show where f is increasing; they do not show the height of f itself.

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