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Unit 8

8.12 Volume with Washer Method: Revolving Around Other Axes

2 min readโ€ขjune 11, 2020

anusha

Anusha Tekumulla


AP Calculus AB/BCย โ™พ๏ธ

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This topic is similar to topic 8.11 except we will be revolving our shape around other axes instead of just the x- or y-axis. These axes can be lines like x = 1, y = -2, or even y = x. This can get a bit confusing but weโ€™ll simplify it for you with an example problem.ย 

๐Ÿ” Example Problem: Finding the Volume Using the Washer Method Around Other Axes

Suppose we have the region bounded by y = โˆšx on top and y = x on the bottom. We are asked to find the volume of the figure if the region is revolved around the y = -1. This is the same region we used in example for topic 8.11. As you read through this consider the similarities and differences between the two procedures.ย 
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreenshot%20(686).png?alt=media&token=adedc196-0e28-4570-85f9-683f80f1b6f2
The first step of this is to find inner and outer radii. The outer radius will be the top function, which is โˆšx, plus 1. We add one because we revolve around the line y = -1.ย  The inner radius will be the bottom function, which is x, plus 1.
Now we can calculate the area of the cross section. This is as simple as subtracting the area of the smaller disc from the larger one. If the outer radius is (โˆšx) + 1 and inner radius is x + 1, then the area of the washer is ฯ€((โˆšx) + 1)2 -ย  ฯ€(x + 1)2. Now all we have to do is find the intersections of the functions to get the endpoints for the integral. To find the intersection, set the two functions equal to each other and solve for x. In this example, the intersections would be at x = 0 and x = 1. The final step is to integrate to find the volume:ย 
https://firebasestorage.googleapis.com/v0/b/fiveable-92889.appspot.com/o/images%2FScreenshot%20(687).png?alt=media&token=93d8ab65-8786-49ee-aed3-bfcdcd2f67fe

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