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🧪AP Chemistry Unit 4 Review

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4.9 Oxidation-Reduction (Redox) Reactions

🧪AP Chemistry
Unit 4 Review

4.9 Oxidation-Reduction (Redox) Reactions

Written by the Fiveable Content Team • Last updated September 2025
Verified for the 2026 exam
Verified for the 2026 examWritten by the Fiveable Content Team • Last updated September 2025
🧪AP Chemistry
Unit & Topic Study Guides
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This is the last reaction to learn for this unit! Before moving on to the rest of the study guide, be sure to review both precipitation and acid-base reactions.

What is a Redox Reaction?

The last type of reaction in this unit is oxidation-reduction reactions, commonly called redox. These reactions deal with the transferring of electrons, which causes molecules to change oxidation states. 

An oxidation state is a measure of the degree of oxidation of an atom in a chemical compound. It is represented by a positive or negative number that expresses the number of electrons that an atom has gained or lost in a compound relative to its elemental state on the periodic table.

When a molecule loses an electron, it’s oxidized, and its oxidation number increases. When a molecule gains an electron, it’s reduced, and its oxidation number decreases. Electrons travel from the oxidized species to the reduced species. Okay, wait...that was a lot of information in three sentences. Here is a quick recap of what you should understand about redox reactions so far:

  • Redox reactions involve the transfer of electrons from one atom to another.
  • Oxidation is the process of losing electrons or increasing the oxidation state of an atom.
  • Reduction is the process of gaining electrons or decreasing the oxidation state of an atom.
  • Acids donate hydrogen ions to bases in acid-base reactions, but here, the substance that is oxidized "donates" electrons to the substance that is reduced.

Writing out the chemical equation of redox reactions reveals which species are oxidized and which are reduced by illustrating the transfer of electrons between molecules.

💡 Mnemonic Device Time! There are two different ones, use the one that seems the most catchy to you:

  • OIL RIG = "oxidation is loss" and "reduction is gain"
  • LEO says GER "loss of electrons = oxidation" and "gain of electrons = reduced"
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Assigning Oxidation Numbers

How do we know the oxidation state of an atom? Here are a few rules that you should remember and familiarize yourself with:

  1. Free elements (ex. Br₂, Na, P₄) have an oxidation number of 0.
  2. Neutral molecules also have oxidation numbers of 0, so their elements’ oxidation numbers must sum to 01. In the compound IF₆, let x = the oxidation number for iodine and y = the oxidation number for fluorine. The following must be true since IF₆ is a neutral molecule: x + 6y = 0
  3. Monatomic ions have an oxidation number equal to their charge (ex. Na⁺ has an oxidation number of +1, Ba²⁺ has an oxidation number of +2, Cl⁻ has an oxidation number of -1, and Al⁺³ has an oxidation number of +3).
  4. Oxygen is -2, except in hydrogen peroxide (H₂O₂) and peroxide ion (O₂⁻²), where it’s -1
  5. Hydrogen is +1, except in metal hydrides (ex. LiH, BaH₂), where it’s -1
  6. Fluorine is -1. Other halogens are usually -1, but they vary (ex. Br₂O₃)
  7. Oxidation numbers can be fractions, but it’s very rare (ex. superoxide, O₂⁻ = -½)

Redox Practice Problem

Redox reactions are important in a variety of chemical processes, including the production of electricity, the corrosion of metals, and the metabolism of cells. The scope of redox reactions in this unit is understanding how to balance their chemical equations. We come back to redox in the very final unit of this course: applications of thermodynamics.

On the AP examination, you may be given a redox reaction and be asked to either balance it in an acidic or basic solution. Let's go over both scenarios.

Balancing Redox in an Acidic Solution

2Mg (s) + O₂ (g) → 2MgO (s)

Step 1

First, assign oxidation numbers to all atoms that take part in the reaction. Mg and O₂ are both neutral molecules, so they must have oxidation states of 0. MgO is made up of an ionic bond between Mg²⁺ and O²⁻, and we know their oxidation numbers have to sum to 0 since MgO is a neutral compound. Since oxygen typically has an oxidation number of 2-, we know that Mg will have an oxidation state of 2+ in this compound.

With this information, we can write half-reactions for each reactant. A half-reaction just shows the transfer of electrons for each molecule specifically, showing either the oxidation or reduction process.

Step 2

Start writing the half-reaction equations by illustrating the change in oxidation numbers. Neutral 2 moles of Mg becomes 2 moles of Mg²⁺, and 1 mole of neutral O₂ becomes 2 moles of O²⁻:

2Mg → 2Mg²⁺

O₂ → 2O²⁻

However, just like any other equation, we need to balance the products and reactants. We’re dealing with the change in charge, so not only do we need to ensure the conservation of mass, but we need to conserve charge❗❗

Step 3

We can conserve charge by adding electrons, negative subatomic particles, to the appropriate side. In the first half-reaction equation, the reactants have a charge of 0, but the products have a charge of +4 (2 moles of 2+ ions). We need to add a charge of -4 (or 4 electrons) to the products to make it so that both sides have 0:

2Mg → 2Mg²⁺ + 4e⁻

In the second equation, the reactants also have a charge of 0, but the products have a charge of -4. Thus, we need a way to add a charge of +4 to balance the products out. However, we can only add electrons. The way around this is to add a charge of -4 (or 4 electrons) to the neutral side. Now, both sides have an equal charge of -4.

O₂+ 4e⁻ → 2O²⁻

Step 4

Since both of our half-reactions conserve both mass and charge, and we can see the transfer of electrons, we can add the two. Adding the two half-reactions allows us to see the full balanced redox reaction: 2Mg + O₂ + 4e⁻ → 2Mg²⁺ + 2O²⁻ + 4e⁻

Wait...but there are four electrons on both sides of the equation! When we have similar terms, we can cancel them out.

2Mg + O₂ → 2Mg²⁺ + 2O²⁻

Congratulations! You made a redox reaction! 🥳

However, we’re not done yet. In ionic bonds, electrons are transferred completely from one element to another. MgO is an example of an ionic bond. Alternatively, in non-ionic bonds, electrons are shared between molecules. HCl and BrNO₃ are some examples. 

Scientists decided to deal with this caveat by giving molecules with non-ionic bonds oxidation numbers instead of ionic charges. These oxidation numbers reflect the maximum number of electrons a molecule would give or accept if they were in an ionic bond.

Balancing Redox in a Basic Solution

Above, we balanced a really easy equation in an acidic solution. You could also be asked to balance redox in a basic solution. Balancing in a basic solution follows the same steps, BUT there is an additional step at the end since OH⁻ ions are present. That extra step is to form H₂O with the present H⁺ ions and oxygen atoms, and then add that mass onto the other side with OH⁻.

Steps for Balancing Redox

⬇️ Here are the general rules for making redox equations: 

  1. Assign oxidation numbers and determine which element is being oxidized and which element is being reduced.
  2. Write the half-reactions for the oxidation and reduction processes.
  3. Balance elements in the half-reactions other than O and H.
  4. Balance the oxygen atoms by adding the appropriate atoms of water molecules.
  5. Balance the hydrogen atoms by adding hydrogen ions.
  6. Balance the half-reactions for charge by adding electrons as necessary. Most of the time, the hydrogen ion is on the same side as the electrons.
  7. Combine the half-reactions by adding them together and canceling out any species that appear on both sides of the equation.
  8. If the reaction is being balanced in a basic solution, add the appropriate number of hydroxide ions to neutralize all hydrogen ions and convert them to water molecules. Remember, whatever you add to one side, you must add to the other as well.
  9. Check your work by making sure the number of atoms of each element is balanced on both sides of the equation, and that the total charge on the reactant side is equal to the total charge on the product side.

🎥 Watch AP Chemistry teacher Wes Winter review the different types of reactions, including oxidation-reduction reactions.

Vocabulary

The following words are mentioned explicitly in the College Board Course and Exam Description for this topic.

TermDefinition
balanced redox reaction equationA chemical equation for an oxidation-reduction reaction where the number of electrons lost equals the number of electrons gained, and all atoms and charges are balanced.
half-reactionSeparate equations showing either the oxidation process (loss of electrons) or the reduction process (gain of electrons) in a redox reaction.

Frequently Asked Questions

What is a redox reaction and how do I know when one is happening?

A redox reaction is any chemical reaction where electrons are transferred—one species loses electrons (oxidation) and another gains them (reduction). On the AP, you’ll show these with oxidation and reduction half-reactions (CED LO 4.9.A). The quickest way to tell a redox reaction is happening: assign oxidation states to each element before and after the reaction. If any element’s oxidation number changes, electrons moved and it’s redox. The species that’s oxidized is the reducing agent; the species reduced is the oxidizing agent. For full AP-style work, write separate half-reactions, balance mass and charge (add H+, H2O in acidic or OH– and H2O in basic), and balance electrons between half-reactions before combining. On electrochemistry problems, connect reduction potentials to identify anode (oxidation) and cathode (reduction). For more step-by-step examples and practice, see the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and lots of practice problems (https://library.fiveable.me/practice/ap-chemistry).

How do I figure out which element is getting oxidized and which is getting reduced?

Quick method you can use every time: 1. Assign oxidation numbers to each element in the reactants and products (use rules: free elements 0, O usually –2, H usually +1, ions equal charge, etc.). 2. Compare numbers: the element whose oxidation number increases is oxidized (lost electrons); the one whose oxidation number decreases is reduced (gained electrons). 3. Identify agents: the species that’s reduced is the oxidizing agent; the species that’s oxidized is the reducing agent. 4. To write half-reactions (CED 4.9.A): separate the oxidation and reduction half-reactions, balance atoms (H2O, H+, OH–) and charge by adding electrons, then multiply to cancel electrons and combine. For acidic vs basic solutions, balance with H+ or add OH– as needed. This is exactly what AP asks you to do on redox problems—practice doing oxidation-state changes and writing balanced half-reactions (see the Topic 4.9 study guide for step-by-step examples: https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa). For extra practice, try the many AP-style problems at https://library.fiveable.me/practice/ap-chemistry.

What's the difference between oxidation and reduction - I always mix them up?

Oxidation = loss of electrons; reduction = gain of electrons. Quick ways to keep them straight: think “OIL RIG” (Oxidation Is Loss; Reduction Is Gain) or “LEO the lion says GER” (Loss Electrons = Oxidation, Gain Electrons = Reduction). In redox, the species that’s oxidized increases its oxidation state and is the reducing agent (it gives e−). The species that’s reduced decreases its oxidation state and is the oxidizing agent (it accepts e−). On the AP, you must be able to split a reaction into oxidation and reduction half-reactions, balance mass and charge (add e−, H+, H2O in acidic or add OH− in basic), and combine them so electrons cancel (CED LO 4.9.A). In electrochemical cells, reduction happens at the cathode and oxidation at the anode. Want step-by-step practice and examples? Check the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and use Fiveable’s AP practice problems (https://library.fiveable.me/practice/ap-chemistry).

Can someone explain half-reactions in simple terms because I'm totally lost?

Think of a half-reaction as one side of a tug-of-war for electrons—it shows only the oxidation part (loss of e–) or the reduction part (gain of e–). To use them on the AP exam (LO 4.9.A), you: 1) split the overall redox into two half-reactions (one oxidation, one reduction); 2) balance atoms (add H2O, H+ in acidic solution or add OH– in basic); 3) balance charge by adding electrons; and 4) multiply so the electrons lost = electrons gained, then add the half-reactions and cancel common species. Remember: the species that’s reduced is the oxidizing agent, the one oxidized is the reducing agent; reduction happens at the cathode and oxidation at the anode. Practice balancing electrons and mass/charge—that’s what AP free-response often checks. For a step-by-step guide and examples, see the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa). More unit review and 1000+ practice problems are at (https://library.fiveable.me/ap-chemistry/unit-4) and (https://library.fiveable.me/practice/ap-chemistry).

How do I balance redox equations using the half-reaction method step by step?

Step-by-step half-reaction method (good for AP 4.9.A): 1. Identify oxidation and reduction changes by assigning oxidation states. 2. Split the overall reaction into two half-reactions (one oxidation, one reduction). 3. For each half-reaction, balance all atoms except H and O. 4. Balance O by adding H2O; balance H by adding H+ (acidic). For basic solutions, add OH- to both sides to neutralize H+. 5. Balance charge by adding electrons (e-) to the more positive side so charge is equal. 6. Multiply each half-reaction by an integer so the total electrons gained = electrons lost. 7. Add the half-reactions, cancel identical species (including e-), then simplify (combine waters, H+, OH-). 8. Check mass and charge balance and that oxidation numbers changed appropriately. On the AP exam, show your half-reactions, electron balancing, and final mass/charge check (CED 4.9.A.1). For extra practice, review the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and do problems at (https://library.fiveable.me/practice/ap-chemistry).

Why do we need to separate redox reactions into half-reactions instead of just balancing normally?

You separate redox reactions into half-reactions because redox is about electron transfer, not just atoms. Writing an oxidation half-reaction (loss of e-) and a reduction half-reaction (gain of e-) lets you balance mass and charge separately, then combine them so electrons cancel. That ensures charge conservation and shows exactly how many electrons move—which species is the reducing agent and which is the oxidizing agent. Half-reaction method also handles acidic vs. basic media cleanly (add H+, OH−, and H2O as needed) and works when different atoms change oxidation states by different numbers of electrons. The AP CED explicitly expects you to “represent a balanced redox reaction equation using half-reactions” (4.9.A), so practicing this method is required for exam problems. Want guided walkthroughs and practice? Check the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa), the unit overview (https://library.fiveable.me/ap-chemistry/unit-4), and Fiveable’s AP Chem practice problems (https://library.fiveable.me/practice/ap-chemistry).

What does it mean when they say electrons are transferred in redox reactions?

Saying “electrons are transferred” means one species loses electrons (oxidation) and another gains them (reduction). In practice that means you can split a redox reaction into two half-reactions: an oxidation half (shows electrons as products) and a reduction half (shows electrons as reactants). The substance that loses electrons is the reducing agent (it’s oxidized); the one that gains electrons is the oxidizing agent (it’s reduced). You track these changes by assigning oxidation states and making sure electrons lost = electrons gained when you balance the half-reactions (mass and charge balanced; add H+, OH−, H2O as needed in acid or base). On the AP exam you’re expected to represent balanced redox equations using half-reactions (CED 4.9.A). If you want step-by-step practice and worked examples, check the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and other Unit 4 resources (https://library.fiveable.me/ap-chemistry/unit-4)—Fiveable also has 1000+ practice questions (https://library.fiveable.me/practice/ap-chemistry) to help you master balancing electrons.

I'm confused about oxidation numbers - how do I assign them and what do they tell me?

Think of oxidation numbers as bookkeeping for electrons so you can spot electron transfer in redox. Quick rules: - Free elements = 0 (O2, Fe(s) = 0). - Monatomic ion = its charge (Na+ = +1, S2- = -2). - H is usually +1 (except with metals/hydrides), O is usually -2 (except in peroxides where it’s -1). - Sum of oxidation numbers in a neutral compound = 0; in a polyatomic ion = ion charge. What they tell you: - If an element’s oxidation number increases → it’s oxidized (loses electrons) and is the reducing agent. - If it decreases → it’s reduced (gains electrons) and is the oxidizing agent. On the AP exam you’ll use these to write oxidation and reduction half-reactions, balance mass and charge (add H2O, H+, and e−; in basic solution add OH−), and make sure electrons cancel before combining (CED keywords: half-reaction, electron transfer, balance electrons, acidic/basic balancing, oxidizing/reducing agent, cathode/anode). For a short refresher and practice, see the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and the AP Chem practice problems (https://library.fiveable.me/practice/ap-chemistry).

How do I know which half-reaction is the oxidation and which is the reduction?

Look at electron flow. Oxidation is the half-reaction where electrons are produced (lost by a species); reduction is the half-reaction where electrons are consumed (gained by a species). Quick steps you can use on AP problems: - Assign oxidation states to each element. The element whose oxidation number increases is oxidized; the one whose oxidation number decreases is reduced. - Write two half-reactions: one showing electrons on the product side (oxidation) and one with electrons on the reactant side (reduction). - Balance mass and charge by adding H2O, H+ (acidic) or OH– (basic), and electrons so the electrons lost = electrons gained (CED 4.9.A). - For electrochemical cells, the half-reaction with the more positive standard reduction potential is the one that will be reduced (cathode); the other is oxidized (anode). Review worked examples in the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and practice many problems (https://library.fiveable.me/practice/ap-chemistry)—AP free-response often asks you to represent balanced redox by half-reactions, so get fluent at identifying electrons and balancing charge.

What's the deal with adding water and H+ ions when balancing redox equations in acidic solution?

When you balance redox reactions in acidic solution you use half-reactions and two simple moves: add H2O to fix oxygen atoms and add H+ to fix hydrogen atoms. Why? Each half-reaction must be balanced for mass (atoms) and charge. If O is missing, add H2O so oxygen atoms match; that introduces extra H, so add H+ to balance the hydrogens. Then add electrons to balance charge. (In basic solution you’d neutralize H+ with OH− instead.) This is exactly what the CED expects for Topic 4.9: construct balanced redox equations from half-reactions (4.9.A). Practice doing the steps: split into oxidation/reduction, balance atoms (O with H2O, H with H+), balance charge with e−, then multiply and combine so electrons cancel. For step-by-step examples and practice, check the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and the AP Chem practice sets (https://library.fiveable.me/practice/ap-chemistry).

Why do some redox equations need to be balanced differently in acidic vs basic solutions?

You balance redox reactions the same way (split into oxidation and reduction half-reactions, balance atoms and electrons), but the solvent gives you different bookkeeping tools. In acidic solution you may add H2O and H+ to balance O and H; in basic solution you can’t introduce free H+—instead you add OH− and H2O. Practically you balance as if acidic, then neutralize H+ by adding OH− to both sides (H+ + OH− → H2O). That changes where H2O and OH− appear and can change coefficients, so the final balanced equation looks different even though electron transfer is the same. For AP Chem, show balanced half-reactions with mass and charge balanced and note whether you used acidic or basic conditions (CED 4.9.A). For a step-by-step example, check the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa). More practice problems are at (https://library.fiveable.me/practice/ap-chemistry).

How do I remember that LEO the lion says GER for oxidation and reduction?

Think of LEO = Loss of Electrons → Oxidation, and GER = Gain of Electrons → Reduction. Memorize it as: when a species loses electrons its oxidation number increases (it’s oxidized) and it’s the reducing agent; when a species gains electrons its oxidation number decreases (it’s reduced) and it’s the oxidizing agent. On AP Chem problems (half-reactions, balancing electrons, acid/basic solutions) always label which side loses/gains electrons, then balance mass and charge—that tells you anode (oxidation) vs cathode (reduction) and which agent does the oxidizing/reducing (CED keywords: oxidation half-reaction, reduction half-reaction, electron transfer, oxidizing/reducing agent). For quick practice and review, use the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and Unit 4 overview (https://library.fiveable.me/ap-chemistry/unit-4). For lots of problems, see Fiveable practice (https://library.fiveable.me/practice/ap-chemistry).

What happens to the electrons in a redox reaction and where do they actually go?

In a redox reaction electrons are transferred from one chemical species to another—they don’t vanish. The species that loses electrons is oxidized (the reducing agent) and the species that gains electrons is reduced (the oxidizing agent). We represent this with half-reactions: an oxidation half shows electrons as products, a reduction half shows electrons as reactants; you balance the overall equation by making the electrons cancel (CED keywords: oxidation half-reaction, reduction half-reaction, balance electrons). In solution those electrons are taken up by the oxidizing species (for example Ag+ + e– → Ag). In an electrochemical cell the electrons physically travel through an external wire from the anode (where oxidation occurs) to the cathode (where reduction occurs); ions in the salt bridge complete the charge balance. For AP tasks you’ll often write half-reactions, balance mass and charge, and identify oxidizing/reducing agents (Topic 4.9; useful practice: the Unit 4 redox study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and 1000+ practice problems (https://library.fiveable.me/practice/ap-chemistry)).

Can you give me a real world example of a redox reaction that I might actually see?

See a simple one in action: a copper–zinc “galvanic” reaction (like in a classic voltaic cell). Overall: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s). Half-reactions: - Oxidation (anode): Zn(s) → Zn2+(aq) + 2 e− - Reduction (cathode): Cu2+(aq) + 2 e− → Cu(s) Zn is the reducing agent (it’s oxidized, loses electrons); Cu2+ is the oxidizing agent (it’s reduced, gains electrons). You balance electrons between half-reactions (here both transfer 2 e−), then combine to give a mass-and-charge balanced equation—exactly the skill AP wants in 4.9.A. Where you might see it: a simple electroplating demo, a homemade lemon battery, or the chemistry inside AA batteries (different metals but same redox idea). For practice writing and balancing half-reactions and more real examples, check the Topic 4.9 study guide (https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa) and the AP Chem practice problems (https://library.fiveable.me/practice/ap-chemistry).

How do I balance this redox equation if both half-reactions have different numbers of electrons?

Do the usual half-reaction method: make each half-reaction mass-and-charge balanced, then multiply whole half-reactions so the electrons lost = electrons gained, and add them so electrons cancel. Steps (short): 1. Write oxidation and reduction half-reactions and balance atoms except H and O. 2. Balance O with H2O and H with H+ (if basic, add OH– to both sides after). 3. Balance charge by adding electrons. 4. Multiply one or both half-reactions by integers so the number of electrons is the same. 5. Add the half-reactions and cancel identical species (including electrons). Quick example: Fe2+ → Fe3+ + e– and Cu2+ + 2 e– → Cu. Multiply the Fe half by 2 so 2 e– cancel: 2 Fe2+ → 2 Fe3+ + 2 e–; add to Cu half → balanced overall. On the AP exam you’ll be asked to “represent a balanced redox reaction using half-reactions” (CED LO 4.9.A; see Topic 4.9 study guide for examples: https://library.fiveable.me/ap-chemistry/unit-4/oxidation-reduction-redox-reactions/study-guide/43xfitnkAe6lhVeXtDXa). For extra practice, Fiveable has many practice problems (https://library.fiveable.me/practice/ap-chemistry).