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AP Chem Unit 8 Review: Acids & Bases

Review AP Chem Unit 8 to build fluency with acid-base equilibria, pH and pOH calculations, buffer systems, titration curves, and the Henderson-Hasselbalch equation. This unit carries 11-15% of the exam and connects directly to the equilibrium reasoning from Unit 7.

Use the topic guides, key terms, and available practice questions to work through every concept from Kw and Ka to buffer capacity and pH-dependent solubility.

What is AP Chem unit 8?

Acids and bases are central to aqueous chemistry, and Unit 8 gives you the tools to quantify their behavior. You will calculate pH from strong and weak acid concentrations, set up equilibrium expressions for partial ionization, explain how buffers resist pH change, and interpret titration curves for both monoprotic and polyprotic systems.

Unit 8 is about predicting and calculating pH in acid-base systems. Strong acids and bases ionize completely, so pH follows directly from concentration. Weak acids and bases require Ka or Kb and an ICE table. Buffers use the Henderson-Hasselbalch equation, and titration curves reveal equivalence points, half-equivalence points, and pKa values.

pH, pOH, and Kw

Water autoionizes: Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25 degrees C. pH = -log[H3O+] and pOH = -log[OH-], and pH + pOH = 14 at 25 degrees C. Strong acids and bases ionize completely, so [H3O+] or [OH-] equals the starting concentration directly.

Weak Acid and Base Equilibria

Weak acids and bases only partially ionize. Use Ka = [H3O+][A-]/[HA] or Kb = [OH-][HB+]/[B] with an ICE table to find equilibrium concentrations. The small-x approximation works when Ka is much smaller than the initial concentration, and Ka x Kb = Kw links conjugate pairs.

Buffers and Titrations

A buffer contains both members of a conjugate acid-base pair. pH = pKa + log([A-]/[HA]) gives the buffer pH. At the half-equivalence point in a titration, pH = pKa. Buffer capacity increases with higher component concentrations, and the titration curve shape depends on whether the acid or base is strong or weak.

Equilibrium drives all acid-base chemistry

Every calculation in Unit 8 is an equilibrium problem. Whether you are finding the pH of a weak acid, explaining why a buffer resists pH change, or reading a titration curve, you are applying the same Le Chatelier and equilibrium constant logic from Unit 7 to proton-transfer reactions. Recognizing that connection makes the entire unit more manageable.

AP Chem unit 8 topics

8.1

Introduction to Acids and Bases

Water autoionizes to give Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25 degrees C. pH = -log[H3O+] and pOH = -log[OH-]; pH + pOH = 14. Neutral means [H3O+] = [OH-], which is pH 7 only at 25 degrees C.

open guide
8.2

pH and pOH of Strong Acids and Bases

Strong acids (HCl, HBr, HI, HClO4, HNO3, H2SO4) and strong bases (group I and II hydroxides) ionize completely. [H3O+] equals the acid concentration; [OH-] equals the base concentration (doubled for group II hydroxides).

open guide
8.3

Weak Acid and Base Equilibria

Weak acids and bases partially ionize. Use Ka = [H3O+][A-]/[HA] or Kb = [OH-][HB+]/[B] with an ICE table. Apply the small-x approximation when justified. Ka x Kb = Kw for conjugate pairs.

open guide
8.4

Acid-Base Reactions and Buffers

Start with moles when mixing acids and bases. Strong-strong neutralization leaves excess H3O+ or OH-. Weak acid plus strong base can form a buffer (if weak acid is in excess) or leave only A- (equimolar). Use Henderson-Hasselbalch for buffer regions.

open guide
8.5

Acid-Base Titrations

Titration curves plot pH versus volume of titrant. At the equivalence point, moles titrant equal moles analyte. At the half-equivalence point, pH = pKa. Curve shape and equivalence point pH differ for strong-strong versus weak-strong titrations.

open guide
8.6

Molecular Structure of Acids and Bases

Acid strength depends on conjugate base stability. Electronegativity, inductive effects, and resonance all stabilize conjugate bases and increase acid strength. Carboxylic acids are common weak acids; group I and II hydroxides are strong bases.

open guide
8.7

pH and pKa

When pH is less than pKa, HA dominates. When pH is greater than pKa, A- dominates. When pH = pKa, concentrations are equal. Acid-base indicators change color near their own pKa; choose indicators with pKa near the equivalence point pH.

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8.8

Properties of Buffers

A buffer contains significant amounts of both HA and A-. The conjugate acid neutralizes added base; the conjugate base neutralizes added acid. Both components must be present in large enough amounts to resist pH change.

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8.9

Henderson-Hasselbalch Equation

pH = pKa + log([A-]/[HA]). When [A-] = [HA], pH = pKa. Use this equation only when a buffer exists. Derivation and computation of pH change after acid or base addition are not assessed on the AP exam.

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8.10

Buffer Capacity

Buffer capacity increases when total buffer component concentrations increase, even if the pH stays the same. A buffer with more HA has greater capacity for added base; a buffer with more A- has greater capacity for added acid.

open guide
8.11

pH and Solubility

Salts with basic anions (CO3^2-, F-, OH-) are more soluble in acidic solution because H3O+ consumes the anion, shifting dissolution equilibrium right by Le Chatelier's principle. Only qualitative reasoning is required on the AP exam.

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practice snapshot

Hardest AP Chemistry unit 8 topics

This snapshot uses Fiveable practice activity to show where students tend to miss questions and which review moves are worth prioritizing first.

58%average MCQ accuracy

Across 13k multiple-choice practice attempts for this unit.

13kMCQ attempts

Practice activity included in this snapshot.

44%average FRQ score

Across 43 scored free-response attempts for this unit.

Hardest topics in unit 8

MCQ miss rate
8.6

Review Molecular Structure of Acids and Bases with attention to how the concept appears in AP-style source and evidence questions.

45%1,245 tries
8.3

Review Weak Acid and Base Equilibria with attention to how the concept appears in AP-style source and evidence questions.

45%233 tries
8.2

Review pH and pOH of Strong Acids and Bases with attention to how the concept appears in AP-style source and evidence questions.

44%1,486 tries
8.5

Review Acid-Base Titrations with attention to how the concept appears in AP-style source and evidence questions.

41%2,044 tries

Unit 8 review notes

8.1

pH, pOH, Kw, and Strong Acids and Bases

Water autoionizes to produce H3O+ and OH-, described by Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25 degrees C. pH and pOH are the negative base-10 logarithms of those concentrations, and they always sum to 14 at 25 degrees C. Strong acids (HCl, HBr, HI, HClO4, HNO3, H2SO4) and strong bases (group I and II hydroxides) ionize completely, so you read [H3O+] or [OH-] directly from the starting concentration. Group II hydroxides like Ca(OH)2 release two OH- per formula unit, so [OH-] = 2 x [Ca(OH)2].

  • Kw: Ion product of water, equal to [H3O+][OH-] = 1.0 x 10^-14 at 25 degrees C; temperature dependent, so neutral pH is not always 7.
  • pH = -log[H3O+]: Converts hydronium concentration to the pH scale; reversible as [H3O+] = 10^(-pH).
  • pH + pOH = 14: Holds at 25 degrees C; use this to convert between pH and pOH after finding one of them.
  • Complete ionization: Strong acids and bases dissociate 100% in water, so no equilibrium calculation is needed to find [H3O+] or [OH-].
  • Group II hydroxides: Release two OH- per formula unit; [OH-] = 2 x initial molarity of the base.
Given 0.025 M HCl, what is the pH? Given 0.010 M Ca(OH)2, what is the pOH and then the pH?
SpeciesIonizationFinding [H3O+] or [OH-]Example
Strong acidComplete[H3O+] = initial acid concentration0.10 M HCl: [H3O+] = 0.10 M
Strong base (group I)Complete[OH-] = initial base concentration0.10 M NaOH: [OH-] = 0.10 M
Strong base (group II)Complete[OH-] = 2 x initial base concentration0.10 M Ca(OH)2: [OH-] = 0.20 M
8.3

Weak Acid and Base Equilibria

Weak acids and bases only partially ionize, so you must set up an ICE table and solve the Ka or Kb expression to find equilibrium concentrations. For a weak acid HA: Ka = [H3O+][A-]/[HA]. For a weak base B: Kb = [OH-][HB+]/[B]. The small-x approximation ([HA]eq is approximately equal to [HA]initial) is valid when Ka is much smaller than the initial concentration, typically less than 5% ionization. Percent ionization = ([H3O+]eq / [HA]initial) x 100. The relationship Ka x Kb = Kw connects any conjugate acid-base pair.

  • Ka: Acid dissociation constant; larger Ka means stronger weak acid and more ionization at equilibrium.
  • ICE table: Organizes Initial, Change, and Equilibrium concentrations for solving weak acid or base equilibrium problems.
  • Small-x approximation: Assumes x is negligible compared to initial concentration; valid when percent ionization is less than about 5%.
  • Percent ionization: ([H3O+]eq / [HA]initial) x 100; increases as initial concentration decreases for a given Ka.
  • Ka x Kb = Kw: For any conjugate acid-base pair at 25 degrees C; use this to find Kb from Ka or vice versa.
A 0.10 M solution of acetic acid has Ka = 1.8 x 10^-5. Set up the ICE table, apply the small-x approximation, and calculate pH.
SystemEquilibrium expressionSolve forThen find
Weak acid HAKa = [H3O+][A-]/[HA][H3O+] = xpH = -log(x)
Weak base BKb = [OH-][HB+]/[B][OH-] = xpOH = -log(x), then pH = 14 - pOH
8.4

Acid-Base Reactions and Buffers

When you mix an acid and a base, start with moles, not molarity. Strong acid plus strong base reacts completely: H+(aq) + OH-(aq) forms H2O(l). The pH comes from the excess reagent and total volume. When a weak acid reacts with a strong base, the product is the conjugate base A-. If weak acid is in excess, a buffer forms and you use Henderson-Hasselbalch. If strong base is in excess, use moles of excess OH- and total volume. At the equimolar point, only A- remains and the solution is slightly basic because A- hydrolyzes: A-(aq) + H2O(l) forms HA(aq) + OH-(aq).

  • Neutralization stoichiometry: Convert all species to moles before comparing; the limiting reagent determines what remains after reaction.
  • Buffer formation: Occurs when both HA and A- are present in significant amounts after a weak acid-strong base or weak base-strong acid reaction.
  • Excess strong base: After all weak acid is consumed, pH is set by moles of excess OH- divided by total volume.
  • Hydrolysis at equimolar point: When weak acid and strong base are equimolar, only A- remains; A- acts as a weak base, giving a slightly basic pH.
  • Excess reagent: The species remaining after a quantitative neutralization reaction; determines the pH calculation method.
You mix 25.0 mL of 0.10 M acetic acid with 15.0 mL of 0.10 M NaOH. Identify the major species after reaction and explain whether a buffer forms.
Mixture resultMajor species presentpH method
Strong acid excessH3O+pH = -log([H3O+]excess)
Strong base excessOH-pOH = -log([OH-]excess), then pH = 14 - pOH
Weak acid excess after partial neutralizationHA and A-Henderson-Hasselbalch
Equimolar weak acid + strong baseA- onlyKb of A-, ICE table for hydrolysis
8.5

Acid-Base Titrations

A titration curve plots pH versus volume of titrant added. At the equivalence point, moles of titrant equal moles of analyte, and this relationship gives you the analyte concentration. For a weak acid titrated with strong base, the half-equivalence point occurs at exactly half the equivalence volume, where [HA] = [A-] and pH = pKa. The buffer region spans roughly one pH unit on either side of the pKa. For polyprotic acids, each ionizable proton produces a separate equivalence point and half-equivalence point on the curve. Indicator selection matters: choose an indicator whose pKa is close to the pH at the equivalence point.

  • Equivalence point: Moles of titrant added equals moles of analyte; for strong acid-strong base titrations, pH = 7; for weak acid-strong base, pH is greater than 7.
  • Half-equivalence point: Volume of titrant is half the equivalence volume; pH = pKa for weak acid titrations, making it the easiest way to read pKa from a curve.
  • Titration curve shape: Strong acid-strong base curves have a steep vertical jump at equivalence near pH 7; weak acid-strong base curves have a buffer region and equivalence above pH 7.
  • Indicator selection: Choose an indicator with a pKa close to the equivalence point pH so the color change coincides with the endpoint.
  • Polyprotic acids: Show multiple equivalence points and half-equivalence points; each step corresponds to one ionizable proton.
Sketch the titration curve for a weak acid titrated with strong base. Label the buffer region, half-equivalence point, and equivalence point, and explain what the pH at the half-equivalence point tells you.
Titration typepH at equivalenceHalf-equivalence pointCurve shape
Strong acid + strong base7.0Not meaningful for pKaSteep jump at pH 7
Weak acid + strong baseGreater than 7pH = pKa of weak acidBuffer region, gentler rise, jump above 7
Weak base + strong acidLess than 7pOH = pKb of weak baseBuffer region, jump below 7
8.6

Molecular Structure and Acid-Base Strength

Acid strength depends on how stable the conjugate base is after proton transfer. Three structural factors stabilize conjugate bases: electronegativity (more electronegative atoms pull electron density away from the O-H or other bond, weakening it), inductive effects (electron-withdrawing groups near the acidic proton increase acidity), and resonance (delocalization of negative charge over multiple atoms stabilizes the conjugate base). Carboxylic acids are common weak acids because their carboxylate conjugate base is resonance-stabilized. Strong acids like HClO4, HNO3, and H2SO4 have conjugate bases stabilized by all three factors. Strong bases like group I and II hydroxides have very weak conjugate acids.

  • Conjugate base stability: The more stable the conjugate base, the stronger the acid; stability comes from electronegativity, inductive effects, and resonance.
  • Electronegativity effect: More electronegative atoms bonded near the acidic proton withdraw electron density, weakening the bond and increasing acid strength.
  • Resonance stabilization: Delocalization of negative charge across multiple atoms in the conjugate base lowers its energy and increases acid strength.
  • Inductive effect: Electron-withdrawing substituents (such as halogens) near the acidic site increase acidity by stabilizing the conjugate base through bond polarity.
  • Carboxylic acids: Common class of weak acids; the carboxylate conjugate base is resonance-stabilized across the two oxygen atoms.
Rank CH3COOH, CCl3COOH, and CF3COOH in order of increasing acid strength and explain using inductive effects.
Structural featureEffect on conjugate baseEffect on acid strength
High electronegativity of bonded atomStabilizes by pulling electron densityIncreases
Resonance delocalizationSpreads negative charge over multiple atomsIncreases
Electron-withdrawing inductive groupsFurther stabilizes conjugate baseIncreases
Electron-donating groupsDestabilizes conjugate baseDecreases
8.7

pH vs. pKa and Indicator Choice

Comparing solution pH to the pKa of a weak acid tells you which form dominates in solution. When pH is less than pKa, the protonated form HA is more concentrated. When pH is greater than pKa, the deprotonated form A- is more concentrated. When pH equals pKa, [HA] = [A-]. This logic applies directly to acid-base indicators, which are themselves weak acids with different colors in their HA and A- forms. For accurate titration results, choose an indicator whose pKa is close to the pH at the equivalence point so the color change occurs at the right moment.

  • Protonation state: The relative amounts of HA and A- in solution; determined by comparing pH to pKa.
  • pH less than pKa: Acid form HA predominates; solution is more acidic than the pKa of the weak acid.
  • pH greater than pKa: Conjugate base A- predominates; solution is more basic than the pKa.
  • Acid-base indicator: A weak acid whose protonated and deprotonated forms have different colors; changes color near its own pKa.
  • Indicator selection: Choose an indicator with pKa close to the equivalence point pH to minimize titration error.
A solution has pH = 4.2 and you add a weak acid indicator with pKa = 5.8. Which color form of the indicator dominates, and why?
8.8

Buffer Properties, Henderson-Hasselbalch, and Buffer Capacity

A buffer contains significant amounts of both a weak acid (HA) and its conjugate base (A-). Added strong acid reacts with A-, and added strong base reacts with HA, so pH changes very little. The Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]), gives the buffer pH directly from the pKa and the concentration ratio. When [A-] = [HA], pH = pKa. Buffer capacity is the amount of acid or base a buffer can absorb before large pH changes occur. Increasing the total concentration of buffer components (while keeping the ratio constant) raises capacity without changing pH. A buffer with more HA than A- has greater capacity to neutralize added base; a buffer with more A- than HA has greater capacity to neutralize added acid.

  • Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]); applies when both buffer components are present in significant amounts.
  • Buffer action: Conjugate base A- neutralizes added strong acid; conjugate acid HA neutralizes added strong base.
  • Buffer capacity: The moles of strong acid or base a buffer can absorb before pH changes significantly; increases with higher component concentrations.
  • Concentration ratio effect: Changing [A-]/[HA] shifts pH; equal concentrations give pH = pKa.
  • Asymmetric capacity: A buffer with excess HA resists base addition better; a buffer with excess A- resists acid addition better.
A buffer contains 0.20 M CH3COOH and 0.10 M CH3COO- with pKa = 4.74. Calculate the pH using Henderson-Hasselbalch and predict which direction the pH shifts if a small amount of NaOH is added.
Buffer compositionpH relative to pKaGreater capacity for
[HA] greater than [A-]pH less than pKaNeutralizing added base
[HA] = [A-]pH = pKaEqual capacity for acid and base
[A-] greater than [HA]pH greater than pKaNeutralizing added acid
8.11

pH and Solubility

The solubility of a salt is pH-sensitive when one of its ions is a weak acid, a weak base, or the hydroxide ion. Lowering pH (adding acid) increases the solubility of salts with basic anions such as CO3^2-, F-, or OH- because H3O+ reacts with the anion, shifting the dissolution equilibrium to the right by Le Chatelier's principle. For example, CaCO3 dissolves more readily in acidic solution because H3O+ consumes CO3^2-, pulling the equilibrium toward dissolution. Raising pH increases the solubility of salts with acidic cations. Note: the AP exam tests this concept qualitatively only; numerical Ksp calculations as a function of pH are not required.

  • Le Chatelier's principle: Removing a product or reactant shifts equilibrium to replace it; adding H3O+ consumes basic anions and drives dissolution.
  • Basic anion solubility: Salts with anions that are weak bases (CO3^2-, F-, OH-) dissolve more in acidic solution because the anion is protonated.
  • Hydroxide precipitation: Metal hydroxides precipitate in basic solution and dissolve in acidic solution because OH- is consumed by added acid.
  • Qualitative reasoning: AP exam requires only directional predictions (more or less soluble) using Le Chatelier; no Ksp-pH calculations are assessed.
Explain qualitatively why Mg(OH)2 dissolves more readily in a solution of pH 2 than in pure water. Name the equilibrium principle you are applying.

Practice AP Chem unit 8 questions

Try stimulus-based AP practice questions and written prompts after you review the notes.

Example stimulus-based MCQs

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Stimulus-based practice question

A weak acid-conjugate base system has pKa=3.80pK_a = 3.80. The figure shows the concentrations of HAHA and AA^- in four buffer mixtures.

Question

Which buffer mixture will have a pH of 2.80?

Buffer A, because [HA][HA] is one-tenth of [A][A^-]

Buffer B, because [HA][HA] equals [A][A^-]

Buffer C, because [A][A^-] is one-tenth of [HA][HA]

Buffer D, because [HA]+[A]=1.0 M[HA] + [A^-] = 1.0\ \text{M}

graph

Stimulus-based practice question

A buffer contains equal moles of HCNHCN and CNCN^-, so the initial pH is 9.2. Adding HClHCl lowers the pH to 8.0 before the buffer is tested with added base.

Question

Which of the following best explains the effect on resistance to added base?

It increases because added HClHCl converts CNCN^- to HCNHCN, increasing the amount of acid available to neutralize base.

It decreases because added HClHCl lowers the amount of CNCN^- available to neutralize added base.

It has no effect because the total amount of the conjugate acid-base pair remains unchanged.

It increases because adding HClHCl increases the equilibrium constant for the buffer system.

Example FRQs

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FRQ

Weak acid titration and pH calculations

1. Answer the following questions about hypochlorous acid, HClO. Figure 1 shows the titration curve for the reaction with NaOH.

Hypochlorous acid, HClO, is a weak acid with an acid dissociation constant, KaK_a, of 3.5×1083.5 × 10^{-8} at 25°C. Hypobromous acid, HBrO, has a KaK_a of 2.3×1092.3 × 10^{-9} at 25°C.

Figure 1. Titration curve of hypochlorous acid, HClO(aq), with 0.100 M NaOH(aq)

Figure 1
A.
i.

Identify the stronger acid between HClO and HBrO.

ii.

Explain why the acid you identified in part A(i) is stronger, in terms of chemical bonding and atomic structure.

B.

Calculate the pH of a 0.150 M solution of HClO.

A student titrates a 25.00 mL sample of 0.150 M HClO(aq) with 0.100 M NaOH(aq).

C.

Write the balanced net ionic equation for the reaction that occurs when HClO(aq) is titrated with NaOH(aq).

The titration curve for the reaction is shown in Figure 1.

D.

Using the information provided, calculate the volume of 0.100 M NaOH(aq) required to reach the equivalence point.

E.

At the equivalence point, the solution is basic.

i.

Calculate the value of the equilibrium constant, KbK_b, for the reaction ClO(aq)+H2O(l)HClO(aq)+OH(aq)ClO^-(aq) + H_2O(l) \rightleftharpoons HClO(aq) + OH^-(aq).

ii.

Calculate the pH of the solution at the equivalence point.

In a separate experiment, the student prepares a solution by combining 25.00 mL of 0.150 M HClO(aq) with 25.00 mL of 0.075 M NaOH(aq). A particle representation of the major species in the resulting solution is shown in Figure 2.

Figure 2. Particle representation of a solution containing equal amounts of HClO and ClO⁻ (water and Na⁺ omitted)

Figure 2
F.
i.

Using the particle diagram in Figure 2 and the data provided, calculate the pH of the solution formed in this experiment.

ii.

The student adds 1.0 mL of 0.100 M HCl to the solution in Figure 2. Predict whether the pH will change significantly. Justify your answer.

SAQ

Methylamine nitrogen hybridization and hydrogen bonding

4. A student is investigating the chemical properties of methylamine, CH3NH2CH_3NH_2. The student generates the Lewis electron-dot diagrams shown in Figure 1 and collects the physical data shown in Table 1.

Table 1. Properties of Methylamine

Substance

Molar Mass (g/mol)

Base Dissociation Constant, KbK_b (at 25°C)

Methylamine, CH3NH2CH_3NH_2

31.06

4.4×1044.4 × 10^{-4}

Figure 1. Lewis electron-dot diagrams of methylamine (CH3NH2) and water (H2O), positioned to allow a single N···H hydrogen-bond dashed line to be added.

Figure 1
A.

Identify the hybridization of the nitrogen atom in the CH3NH2CH_3NH_2 molecule shown in Figure 1.

B.

In Figure 1, draw a SINGLE dashed line (----) to represent a strong hydrogen-bonding attraction between the nitrogen atom of the CH3NH2CH_3NH_2 molecule and a hydrogen atom of the H2OH_2O molecule.

Table 2. Acid-Base Indicators

Indicator

pKapK_a

Methyl Red

5.1

Phenolphthalein

9.3

C.

The student prepares a 0.20 M aqueous solution of methylamine (CH3NH2CH_3NH_2). The student plans to titrate 25.0 mL of this solution with 0.20 M HClHCl and considers the two acid-base indicators listed in Table 2.

i.

Propose which indicator from Table 2 is most appropriate for determining the equivalence point of the titration.

ii.

Calculate the pH of the 0.20 M CH3NH2CH_3NH_2 solution before any HClHCl is added.

SAQ

Buffer solution equilibrium and pH calculations

6. A scientist investigates the properties of a buffer solution containing nitrous acid, HNO2HNO_2, and potassium nitrite, KNO2KNO_2. The scientist generates the particle diagram in Figure 1 to represent the species in the solution. Water molecules and K+K^+ ions are omitted for clarity. Table 1 provides acid dissociation constants for several weak acids at 25°C.

Table 1. Acid Dissociation Constants

Acid

KaK_a at 25°C

HNO2HNO_2

4.5×1044.5 × 10^{-4}

HFHF

6.8×1046.8 × 10^{-4}

HC2H3O2HC_2H_3O_2

1.8×1051.8 × 10^{-5}

HCNHCN

6.2×10106.2 × 10^{-10}

Figure 1. Particle diagram of a buffer solution containing HNO2(aq) and NO2−(aq). Water molecules and K+ ions are intentionally omitted.

Figure 1
A.

Write the balanced net ionic equation for the reaction that occurs when a small amount of strong base (NaOH) is added to the buffer solution represented in Figure 1.

B.

Using the particle count in Figure 1 and the data in Table 1, calculate the pH of the buffer solution.

C.

Calculate the value of the base dissociation constant, KbK_b, for the nitrite ion, NO2NO_2^-, at 25°C.

D.

If the scientist uses acetic acid, HC2H3O2HC_2H_3O_2, to prepare the buffer, calculate the ratio of [C2H3O2]/[HC2H3O2][C_2H_3O_2^-]/[HC_2H_3O_2] required to achieve a pH of 4.50. The scientist plans to prepare a new buffer with a pH of 4.50 using one of the acids listed in Table 1.

Key terms

TermDefinition
KwIon product of water; Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25 degrees C. Temperature dependent, so neutral pH is not always 7.
Hydronium IonH3O+(aq), the aqueous hydrogen ion formed when H+ associates with water; its concentration determines pH.
Strong AcidAn acid that ionizes completely in water (HCl, HBr, HI, HClO4, HNO3, H2SO4); [H3O+] equals the initial acid concentration.
Strong BaseA base that dissociates completely in water (group I and II hydroxides); [OH-] equals the initial concentration, doubled for group II.
KₐAcid dissociation constant; Ka = [H3O+][A-]/[HA]. Larger Ka means stronger weak acid and greater ionization at equilibrium.
Weak AcidsAcids that only partially ionize in water; pH requires an ICE table and Ka expression, not just the initial concentration.
percent ionization([H3O+]eq / [HA]initial) x 100; increases as initial concentration decreases for a given Ka.
Conjugate BaseWhat remains of an acid after it donates its proton; its stability (via electronegativity, resonance, or inductive effects) determines acid strength.
Equivalence PointPoint in a titration where moles of titrant equal moles of analyte; pH depends on whether the acid and base are strong or weak.
Half-Equivalence PointPoint in a weak acid-strong base titration where [HA] = [A-] and pH = pKa; used to read pKa directly from a titration curve.
protonation stateThe relative concentrations of HA and A- in solution; when pH is less than pKa, HA dominates; when pH is greater than pKa, A- dominates.
Acid-Base IndicatorA weak acid whose protonated and deprotonated forms have different colors; changes color near its pKa, which should be close to the equivalence point pH.
neutralizationReaction between an acid and a base; strong acid plus strong base gives water and a neutral salt; weak acid plus strong base gives the conjugate base.
excess reagentThe species remaining after a quantitative neutralization; its moles and the total volume determine the pH after reaction.

Common unit 8 mistakes

Using pH = 7 as the universal definition of neutral

Neutral means [H3O+] = [OH-], not pH = 7. At temperatures other than 25 degrees C, Kw changes and the neutral pH shifts. On the exam, state the neutral condition in terms of equal ion concentrations.

Forgetting to double [OH-] for group II hydroxides

Ca(OH)2, Sr(OH)2, and Ba(OH)2 each release two OH- per formula unit. If you use the molarity of the base directly without multiplying by 2, your pOH and pH will be wrong.

Applying Henderson-Hasselbalch when no buffer exists

Henderson-Hasselbalch requires both HA and A- to be present in significant amounts. If one component is essentially zero (for example, after complete neutralization), use the excess reagent or hydrolysis approach instead.

Confusing the equivalence point pH with pH = 7

Only strong acid-strong base titrations reach equivalence at pH 7. Weak acid-strong base equivalence points are above 7 because the conjugate base A- hydrolyzes. Weak base-strong acid equivalence points are below 7.

Skipping stoichiometry before an equilibrium calculation

In mixture and titration problems, always convert to moles and complete the neutralization reaction first. Jumping straight to Ka or Henderson-Hasselbalch without accounting for what reacted leads to incorrect concentrations.

How this unit shows up on the AP exam

Quantitative pH calculations requiring multi-step reasoning

AP Chemistry free-response questions frequently ask you to calculate pH at multiple stages: before a reaction, after partial neutralization, at the equivalence point, and after adding excess titrant. Each stage requires a different method (direct calculation, ICE table, Henderson-Hasselbalch, or hydrolysis), so identifying the major species present after each step is the critical first move.

Justifying claims about acid strength or buffer behavior with structural or conceptual evidence

The exam regularly asks you to explain rather than just calculate. For acid strength comparisons, you must cite electronegativity, resonance, or inductive effects as structural evidence. For buffer questions, you must name which component reacts with added acid or base and explain why pH changes only slightly. Vague answers without chemical reasoning do not earn full credit.

Reading and interpreting titration curves

Titration curve interpretation is a recurring task type. You may be asked to identify the equivalence point, determine pKa from the half-equivalence point, select an appropriate indicator, compare curves for strong versus weak acid titrations, or explain the shape of the buffer region. Connecting curve features to the underlying equilibrium chemistry is the expected level of reasoning.

Final unit 8 review checklist

  • Calculate pH and pOH for strong acids and basesUse complete ionization: [H3O+] equals the strong acid concentration; [OH-] equals the strong base concentration (doubled for group II hydroxides). Apply pH + pOH = 14 at 25 degrees C.
  • Set up ICE tables for weak acid and base equilibriaWrite the Ka or Kb expression, fill in the ICE table, apply the small-x approximation when valid (less than 5% ionization), and solve for [H3O+] or [OH-] to find pH.
  • Identify mixture type and choose the correct pH methodAfter a neutralization reaction, determine whether the result is excess strong acid or base, a buffer (both HA and A- present), or a solution of only the conjugate species. Each case uses a different calculation approach.
  • Apply Henderson-Hasselbalch to buffer problemsUse pH = pKa + log([A-]/[HA]) when both buffer components are present. Recognize that pH = pKa at the half-equivalence point and that adding small amounts of strong acid or base does not significantly change the ratio.
  • Read and interpret titration curvesLocate the equivalence point (moles titrant equal moles analyte), half-equivalence point (pH = pKa), and buffer region. Distinguish strong-strong curves (equivalence at pH 7) from weak-strong curves (equivalence above or below pH 7).
  • Explain acid strength using molecular structureSupport strength comparisons with electronegativity, inductive effects, or resonance stabilization of the conjugate base. Do not rely on memorized labels alone.
  • Apply Le Chatelier's principle to pH and solubilityPredict qualitatively whether a salt dissolves more or less in acidic or basic solution based on whether its ions are weak acids, weak bases, or hydroxide. No numerical Ksp-pH calculations are required.

How to study unit 8

Step 1: Build fluency with pH, pOH, and strong acid-base calculationsReview Kw, the pH and pOH formulas, and complete ionization for strong acids and group I and II hydroxides. Practice converting between concentration and pH in both directions. Use the topic guides for 8.1 and 8.2 to check your understanding of Kw temperature dependence and group II stoichiometry.
Step 2: Work through weak acid and base equilibria with ICE tablesSet up ICE tables for Ka and Kb problems, practice the small-x approximation, and calculate percent ionization. Use the Ka x Kb = Kw relationship to move between conjugate pairs. The topic guide for 8.3 walks through these calculations step by step.
Step 3: Practice acid-base mixture and buffer problemsFor 8.4, start every problem by converting to moles and identifying the limiting reagent. Determine whether the result is excess strong acid or base, a buffer, or a hydrolysis problem. Then apply Henderson-Hasselbalch (8.9) for buffer cases and review buffer capacity concepts from 8.10.
Step 4: Interpret titration curves and connect to pKaSketch titration curves for strong-strong and weak-strong systems. Practice locating the equivalence point, half-equivalence point, and buffer region. Use the pH vs. pKa logic from 8.7 to explain indicator selection and protonation state at any point on the curve.
Step 5: Review molecular structure and pH-solubility connectionsFor 8.6, practice ranking acid strength using electronegativity, inductive effects, and resonance with structural evidence. For 8.11, apply Le Chatelier's principle qualitatively to predict how pH affects the solubility of salts with basic anions or hydroxide ions.

More ways to review

Topic study guides

Open the individual guides for Unit 8 when you want a closer review of one topic.

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FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

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Cram archive videos

Watch past review streams filtered to Unit 8 when you want a video walkthrough.

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Cheatsheets

Use unit cheatsheets for a quick visual review after you work through the notes.

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Score calculator

Estimate your broader AP score goal after you review the course and exam format.

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Frequently Asked Questions

What topics are covered in AP Chem Unit 8?

AP Chem Unit 8 covers 11 topics in acids and bases: Introduction to Acids and Bases, pH and pOH of Strong Acids and Bases, Weak Acid and Base Equilibria, Acid-Base Reactions and Buffers, Acid-Base Titrations, Molecular Structure of Acids and Bases, pH and pKa, Properties of Buffers, the Henderson-Hasselbalch Equation, Buffer Capacity, and pH and Solubility. The unit ties acid-base chemistry directly to chemical equilibrium. You'll work through strong and weak acids, buffer systems, titration curves, and how solubility connects to pH. See all 11 topics at /ap-chem/unit-8.

How much of the AP Chem exam is Unit 8?

AP Chem Unit 8 makes up 11-15% of the AP exam, making acids and bases one of the heavier-weighted units you'll see on test day. That means you can expect a solid handful of multiple-choice questions and a real chance of an FRQ covering topics like buffers, titrations, weak acid equilibria, and pH and solubility. Given that weight, it's worth spending serious time here. Check out /ap-chem/unit-8 for topic-by-topic practice.

What's on the AP Chem Unit 8 progress check (MCQ and FRQ)?

The AP Chem Unit 8 progress check includes both MCQ and FRQ parts drawn from all 11 acids and bases topics. The MCQ section tests concepts like pH and pOH calculations, weak acid and base equilibria, molecular structure of acids and bases, and the Henderson-Hasselbalch Equation. The FRQ part typically asks you to analyze a buffer system, interpret a titration curve, or explain how pH affects solubility. For the progress check FRQ, expect to show your reasoning clearly, not just plug in numbers. Topics like Buffer Capacity (8.10) and Acid-Base Titrations (8.5) are especially common targets. Practice with matched questions at /ap-chem/unit-8 before submitting in AP Classroom.

How do I practice AP Chem Unit 8 FRQs?

AP Chem Unit 8 FRQs most often focus on buffers, acid-base titrations, and weak acid or base equilibria, so those three topics are your highest-priority practice targets. A typical question gives you a titration scenario or a buffer system and asks you to calculate pH, explain the buffer's resistance to pH change, or identify the equivalence point. To practice effectively, work through problems that require you to set up ICE tables, apply the Henderson-Hasselbalch Equation, and connect pH to solubility. Write out your reasoning in full sentences, since AP graders award points for justification, not just correct numbers. Find FRQ-style practice problems at /ap-chem/unit-8.

Where can I find AP Chem Unit 8 practice questions?

The best place to find AP Chem Unit 8 practice questions, including multiple-choice and practice test sets, is /ap-chem/unit-8. You'll find MCQ and FRQ practice covering all 11 acids and bases topics, from pH and pOH of strong acids to buffers, the Henderson-Hasselbalch Equation, and pH and solubility. For a solid practice test experience, work through questions topic by topic rather than all at once. Start with Weak Acid and Base Equilibria (8.3) and Acid-Base Titrations (8.5), since those show up most on the AP exam. Then layer in Buffer Capacity (8.10) and solubility (8.11) once the core equilibrium concepts feel solid.

How should I study AP Chem Unit 8?

Start AP Chem Unit 8 by building a strong foundation in acid-base equilibrium before moving to buffers and titrations, since almost every topic in this unit builds on the one before it. Weak Acid and Base Equilibria (8.3) is the pivot point: if ICE tables and Ka/Kb calculations feel shaky, slow down there before moving on. Here's a practical study sequence: 1. Lock in pH and pOH calculations for strong acids and bases (8.2) first since those are the fastest points on the exam. 2. Work through Weak Acid and Base Equilibria (8.3) with ICE tables until it's automatic. 3. Study buffers across 8.4, 8.8, 8.9, and 8.10 together. The Henderson-Hasselbalch Equation connects them all. 4. Practice full Acid-Base Titration problems (8.5), including sketching titration curves and identifying equivalence points. 5. Finish with pH and Solubility (8.11), which ties solubility back to the equilibrium concepts you already know. Unit 8 is 11-15% of the AP exam, so it rewards focused practice. Use /ap-chem/unit-8 to test yourself on each topic as you go.

Ready to review Unit 8?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.