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8.13 Reaction Stereochemistry: Addition of H2O to a Chiral Alkene

8.13 Reaction Stereochemistry: Addition of H2O to a Chiral Alkene

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
🥼Organic Chemistry
Unit & Topic Study Guides

Reaction Stereochemistry: Addition of H₂O to a Chiral Alkene

Stereochemistry of alkene hydration

Acid-catalyzed hydration of an alkene adds water across the double bond following Markovnikov's rule: the H atom bonds to the less substituted carbon, and the OH group bonds to the more substituted carbon. The reaction proceeds through a carbocation intermediate that forms at the more substituted position, where hyperconjugation and inductive effects provide greater stabilization.

The key stereochemical point is what happens at that carbocation. A carbocation is sp²-hybridized and planar, so water can attack from either face with equal probability. That means the new stereogenic center forms as a racemic mixture (50:50 of both configurations). The existing chiral center in the starting alkene has no significant influence over which face gets attacked.

Stereochemistry of alkene hydration, 4.4. Molecules with multiple chiral centers | Organic Chemistry 1: An open textbook

Reactant chirality and the new stereogenic center

You might expect the existing chiral center to bias the incoming nucleophile toward one face of the carbocation. In practice, for most substrates at this level, the two faces are treated as equally accessible.

Here's why:

  1. The double bond reacts with H+\text{H}^+ to form a planar carbocation at the more substituted carbon.
  2. The original chiral center, sitting elsewhere in the molecule, retains its configuration throughout. It is not involved in bond-breaking or bond-forming.
  3. Water attacks the flat carbocation from the top or bottom face with roughly equal probability, generating both possible configurations at the new stereocenter.

The result: the original stereocenter is preserved with its original configuration, while the new stereocenter is racemic.

Clarification on diastereomers vs. enantiomers: The two products are not enantiomers of each other. They share the same configuration at the original chiral center but differ at the new one. That makes them diastereomers. They'll be produced in approximately equal amounts, but because they're diastereomers (not enantiomers), their physical properties differ slightly.

Stereochemistry of alkene hydration, 4.5. Stereochemistry of reactions | Organic Chemistry 1: An open textbook

Optical activity of the product mixture

The product contains two stereogenic centers:

  • The original chiral center, which keeps its configuration and contributes to optical activity.
  • The newly formed stereogenic center, which is racemic (equal R and S).

Because the new center is racemic, the product is a roughly 50:50 mixture of two diastereomers. Each diastereomer rotates plane-polarized light, but by different amounts and potentially in different directions. The observed optical rotation of the mixture will therefore be reduced compared to a single pure diastereomer, though it won't necessarily be zero (unlike a racemic mixture of enantiomers, which always gives zero net rotation).

Reaction Considerations

  • Regioselectivity is governed by Markovnikov's rule: OH ends up on the more substituted carbon.
  • Stereospecificity refers to whether the stereochemistry of the reactant dictates the stereochemistry of the product. This reaction is not stereospecific at the new center because the planar carbocation allows attack from both faces.
  • Carbocation rearrangements (hydride shifts or alkyl shifts) can occur if a more stable carbocation is accessible. Always check whether a 1,2-shift could produce a more substituted (more stable) carbocation before predicting the final product.