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🥼Organic Chemistry Unit 19 Review

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19.14 Spectroscopy of Aldehydes and Ketones

19.14 Spectroscopy of Aldehydes and Ketones

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
🥼Organic Chemistry
Unit & Topic Study Guides

Spectroscopic Analysis of Aldehydes and Ketones

Interpretation of IR spectra

The carbonyl group produces one of the most recognizable absorptions in all of IR spectroscopy. Because the C=O bond is both strong and polar, it gives a sharp, intense peak that's hard to miss.

  • Aldehydes show a strong C=O stretch at 1720–1740 cm1^{-1} (e.g., formaldehyde, acetaldehyde)
  • Ketones absorb at a slightly lower frequency, around 1705–1720 cm1^{-1} (e.g., acetone, cyclohexanone)

The frequency difference comes down to electronic effects. Ketones have two electron-donating alkyl groups on the carbonyl carbon, which increases electron density in the C=O bond and lowers the stretching frequency slightly.

Aldehydes have one additional diagnostic feature: two weak C–H stretches between 2700–2850 cm1^{-1} from the aldehyde proton. These often appear as a pair of bands (sometimes called "Fermi doublet") and are unique to aldehydes. If you see a carbonyl stretch plus those two bands in the 2700–2850 region, you're almost certainly looking at an aldehyde.

Conjugation with a C=C bond or aromatic ring lowers the C=O stretching frequency by roughly 20–40 cm1^{-1}. So a conjugated aldehyde might absorb closer to 1680–1700 cm1^{-1}, and a conjugated ketone even lower.

Interpretation of IR spectra, Aldehydes, Ketones, Carboxylic Acids, and Esters | General Chemistry

Analysis of NMR spectra

NMR is where you can really pin down the structure of an aldehyde or ketone.

1^1H NMR:

  • The aldehyde proton (R–CHO) resonates far downfield at 9–10 ppm. This is a distinctive signal that immediately tells you an aldehyde is present.
  • That aldehyde proton can couple to neighboring protons on the α\alpha-carbon, though the coupling constant is small (J23J \approx 2{-}3 Hz). In simple cases like acetaldehyde (no α\alpha-neighbors besides the methyl), you'll see it as a singlet or a slightly split peak.
  • α\alpha-Protons (on the carbon directly next to C=O) are deshielded by the electron-withdrawing carbonyl and typically appear around 2.0–2.5 ppm, noticeably downfield from ordinary alkyl protons.

13^{13}C NMR:

  • Aldehyde carbonyls resonate around 190–205 ppm
  • Ketone carbonyls appear at 195–220 ppm

These are the most downfield signals in a typical 13^{13}C spectrum, making them easy to spot.

Substituent effects matter here too. Electron-withdrawing groups (halogens, nitro groups) shift signals further downfield, while electron-donating groups (alkyl, alkoxy) cause slight upfield shifts. For example, 4-chlorobenzaldehyde has a more downfield carbonyl signal than 4-methoxybenzaldehyde.

Interpretation of IR spectra, Chemical Bonding introduction

Mass spectrometry for isomer identification

Mass spectrometry reveals fragmentation patterns that help distinguish between isomeric aldehydes and ketones.

α\alpha-Cleavage is the most common fragmentation:

  1. The bond between the carbonyl carbon and an α\alpha-carbon breaks
  2. This produces an acylium ion (RCO+RCO^+), which is resonance-stabilized and gives a prominent peak
  3. For ketones, cleavage can occur on either side of the carbonyl, so you may see two different acylium ions (e.g., 2-pentanone gives fragments at m/z = 43 from CH3CO+CH_3CO^+ and m/z = 71 from CH3CH2CH2CO+CH_3CH_2CH_2CO^+)

McLafferty rearrangement occurs when a γ\gamma-hydrogen is available (at least 3 carbons away from the carbonyl):

  1. The γ\gamma-hydrogen transfers to the carbonyl oxygen through a six-membered cyclic transition state

  2. The bond between the α\alpha- and β\beta-carbons breaks

  3. This produces an enol radical cation and a neutral alkene that leaves the molecule

For example, pentanal (MW = 86) undergoes McLafferty rearrangement to give an enol fragment at m/z = 44.

Molecular ion peak (M+M^+): Usually observable for aldehydes and ketones, though aldehyde M+M^+ peaks tend to be weaker than ketone M+M^+ peaks. Aromatic carbonyl compounds like benzaldehyde and acetophenone give relatively strong molecular ion peaks due to the stability of the aromatic ring system.

Isotope peaks (M+1, M+2) help determine molecular formulas. The M+1 peak intensity reflects the number of carbons (each 13^{13}C contributes about 1.1% per carbon), while a significant M+2 peak suggests the presence of elements like chlorine or bromine.

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