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8.5 Polar Form of Complex Numbers

8.5 Polar Form of Complex Numbers

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐Ÿ“Honors Pre-Calculus
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Complex Numbers in Polar Form

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Complex numbers in the plane

Complex numbers live on a 2D coordinate system called the complex plane. The horizontal axis represents real numbers, and the vertical axis represents imaginary numbers.

A complex number z=a+biz = a + bi gets plotted at the point (a,b)(a, b). So 3+4i3 + 4i sits at (3,4)(3, 4), just like plotting a point in the coordinate plane you already know.

  • The absolute value (or modulus) of z=a+biz = a + bi is the distance from the origin to (a,b)(a, b):

โˆฃzโˆฃ=a2+b2|z| = \sqrt{a^2 + b^2}

This comes straight from the Pythagorean theorem. For z=3+4iz = 3 + 4i, the modulus is 9+16=5\sqrt{9 + 16} = 5.

  • You can also think of complex numbers as vectors from the origin to the point (a,b)(a, b). This vector interpretation is what makes polar form so natural.

Rectangular vs polar forms

Rectangular form describes a complex number by its horizontal and vertical components:

z=a+biz = a + bi

where aa is the real part and bb is the imaginary part.

Polar form describes the same number by how far it is from the origin and what angle it makes:

z=r(cosโกฮธ+isinโกฮธ)z = r(\cos\theta + i\sin\theta)

This is often shortened to z=rโ€‰cisโ€‰ฮธz = r \, \text{cis} \, \theta. Here, rr is the modulus and ฮธ\theta is the argument (the angle measured from the positive real axis).

Converting rectangular to polar:

  1. Find the modulus: r=a2+b2r = \sqrt{a^2 + b^2}
  2. Find the argument: ฮธ=tanโกโˆ’1(ba)\theta = \tan^{-1}\left(\frac{b}{a}\right)
  3. Check the quadrant. If a<0a < 0, you need to add ฯ€\pi to the angle from your calculator, since tanโกโˆ’1\tan^{-1} only returns values in Quadrants I and IV.

Converting polar to rectangular:

  1. Find the real part: a=rcosโกฮธa = r\cos\theta
  2. Find the imaginary part: b=rsinโกฮธb = r\sin\theta
  3. Write as z=a+biz = a + bi

For example, z=4โ€‰cisโ€‰ฯ€3z = 4 \, \text{cis} \, \frac{\pi}{3} converts to z=4cosโกฯ€3+4isinโกฯ€3=2+23โ€‰iz = 4\cos\frac{\pi}{3} + 4i\sin\frac{\pi}{3} = 2 + 2\sqrt{3}\,i.

Complex numbers in the plane, Polar Form of Complex Numbers ยท Algebra and Trigonometry

Multiplication and division in polar form

This is where polar form really pays off. Multiplying and dividing complex numbers in rectangular form involves messy FOIL-ing and rationalizing denominators. In polar form, the rules are clean:

  • Multiplication: Multiply the moduli, add the arguments.

z1z2=r1r2โ€‰cis(ฮธ1+ฮธ2)z_1 z_2 = r_1 r_2 \, \text{cis}(\theta_1 + \theta_2)

  • Division: Divide the moduli, subtract the arguments.

z1z2=r1r2โ€‰cis(ฮธ1โˆ’ฮธ2)\frac{z_1}{z_2} = \frac{r_1}{r_2} \, \text{cis}(\theta_1 - \theta_2)

Geometrically, multiplying by a complex number scales the distance from the origin (by r2r_2) and rotates the point (by ฮธ2\theta_2). This is a big conceptual takeaway.

Powers and roots of complex numbers

Powers follow directly from the multiplication rule. If you multiply zz by itself nn times, you raise the modulus to the nnth power and multiply the angle by nn:

zn=rnโ€‰cis(nฮธ)z^n = r^n \, \text{cis}(n\theta)

This result is called De Moivre's Theorem, and it works for any positive integer nn.

Roots go the other direction. The nnth roots of z=rโ€‰cisโ€‰ฮธz = r \, \text{cis} \, \theta are:

zn=rnโ€‰cis(ฮธ+2kฯ€n),k=0,1,2,โ€ฆ,nโˆ’1\sqrt[n]{z} = \sqrt[n]{r} \, \text{cis}\left(\frac{\theta + 2k\pi}{n}\right), \quad k = 0, 1, 2, \ldots, n-1

Steps for finding nnth roots:

  1. Take the nnth root of the modulus: rn\sqrt[n]{r}
  2. Divide the argument by nn to get the first root (k=0k = 0)
  3. Add 2ฯ€n\frac{2\pi}{n} to get each successive root
  4. Stop after nn roots total

All nn roots have the same modulus, so they sit equally spaced on a circle of radius rn\sqrt[n]{r}. For instance, the three cube roots of 88 are spaced 2ฯ€3\frac{2\pi}{3} apart (120ยฐ) on a circle of radius 2.

Complex numbers in the plane, Polar Form of Complex Numbers | Precalculus II

Applications of De Moivre's Theorem

De Moivre's Theorem states:

(cosโกฮธ+isinโกฮธ)n=cosโก(nฮธ)+isinโก(nฮธ)(\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta)

Beyond computing powers and roots, this theorem is useful for:

  • Solving equations like z4=โˆ’16z^4 = -16 by converting to polar form and applying the root formula
  • Deriving trig identities by expanding the left side using the binomial theorem and matching real and imaginary parts

For example, expanding (cosโกฮธ+isinโกฮธ)2(\cos\theta + i\sin\theta)^2 and equating real parts gives you the double angle formula cosโก(2ฮธ)=cosโก2ฮธโˆ’sinโก2ฮธ\cos(2\theta) = \cos^2\theta - \sin^2\theta.

Geometry of polar complex numbers

The polar form makes geometric meaning visible:

  • Modulus rr = distance from the origin
  • Argument ฮธ\theta = angle with the positive real axis
  • Multiplying by a complex number = rotating and scaling
  • nnth roots = nn equally spaced points on a circle
  • The unit circle (r=1r = 1) is a special case where every point has the form cisโ€‰ฮธ\text{cis} \, \theta, connecting directly to the trig values you already know

Polar form and trigonometry connections

Polar form ties complex numbers back to trigonometry in a deep way. The most famous connection is Euler's formula:

eiฮธ=cosโกฮธ+isinโกฮธe^{i\theta} = \cos\theta + i\sin\theta

This means the polar form z=r(cosโกฮธ+isinโกฮธ)z = r(\cos\theta + i\sin\theta) can also be written as:

z=reiฮธz = re^{i\theta}

You may not use the exponential form heavily in this course, but it's worth knowing it exists. It's the reason the multiplication and division rules work so neatly: when you multiply exponentials, you add exponents.

Euler's formula also provides an elegant way to derive trig identities. Multiplying eiฮฑโ‹…eiฮฒ=ei(ฮฑ+ฮฒ)e^{i\alpha} \cdot e^{i\beta} = e^{i(\alpha+\beta)} and expanding both sides gives you the angle addition formulas:

cosโก(ฮฑ+ฮฒ)=cosโกฮฑcosโกฮฒโˆ’sinโกฮฑsinโกฮฒ\cos(\alpha + \beta) = \cos\alpha\cos\beta - \sin\alpha\sin\beta

sinโก(ฮฑ+ฮฒ)=sinโกฮฑcosโกฮฒ+cosโกฮฑsinโกฮฒ\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta