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๐Ÿ“Honors Pre-Calculus Unit 12 Review

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12.3 Continuity

12.3 Continuity

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐Ÿ“Honors Pre-Calculus
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Continuity

Continuity describes whether a function has smooth, unbroken behavior at a point or across an interval. A continuous function is one you could draw without lifting your pencil. Understanding continuity matters because it's a foundational requirement for the calculus concepts you're building toward, especially derivatives and integrals.

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Points of continuity and discontinuity

A function is continuous at a point x=ax = a only if it satisfies all three of these conditions:

  1. f(a)f(a) is defined โ€” the function actually has a value at x=ax = a (no holes or gaps in the domain).
  2. limโกxโ†’af(x)\lim_{x \to a} f(x) exists โ€” the limit from the left and the limit from the right both converge to the same single value.
  3. limโกxโ†’af(x)=f(a)\lim_{x \to a} f(x) = f(a) โ€” the limit equals the actual function value (no jumps or mismatches).

If any one of these fails, the function is discontinuous at that point.

When you're scanning a function for potential discontinuities, focus on these trouble spots:

  • Domain restrictions โ€” places where you'd divide by zero, or take an even root of a negative number
  • Piecewise definitions โ€” wherever the formula changes, check that the pieces connect smoothly
  • Endpoints of intervals โ€” here you can only check one-sided continuity (from the left or from the right, not both)
Points of continuity and discontinuity, Continuity ยท Precalculus

Evaluating continuity at specific values

To determine whether a function is continuous at a specific point x=ax = a, follow these steps:

  1. Check that f(a)f(a) is defined. Plug aa into the function. If aa isn't in the domain (e.g., it causes division by zero), stop here โ€” the function is discontinuous.

  2. Evaluate the left-hand and right-hand limits.

    • Find limโกxโ†’aโˆ’f(x)\lim_{x \to a^-} f(x) and limโกxโ†’a+f(x)\lim_{x \to a^+} f(x).
    • If both one-sided limits exist and are equal, then limโกxโ†’af(x)\lim_{x \to a} f(x) exists. If they differ, the overall limit does not exist, and the function is discontinuous.
  3. Compare the limit to the function value. If limโกxโ†’af(x)=f(a)\lim_{x \to a} f(x) = f(a), the function is continuous at x=ax = a. If they don't match, it's discontinuous.

Note: The parenthetical reference to the "sandwich theorem" in step 2 is a common mix-up. The Squeeze (Sandwich) Theorem is a technique for evaluating tricky limits, not the rule that says equal one-sided limits imply the overall limit exists. That's just the definition of a two-sided limit.

Points of continuity and discontinuity, Derivatives ยท Precalculus

Types of function discontinuities

There are four main types of discontinuity you should be able to identify.

Removable discontinuity (hole) โ€” The limit exists at x=ax = a, but either f(a)f(a) is undefined or f(a)f(a) doesn't equal the limit. You can "fix" this by redefining f(a)f(a) to match the limit.

  • Example: f(x)=x2โˆ’1xโˆ’1f(x) = \frac{x^2 - 1}{x - 1}. Factor the numerator to get (xโˆ’1)(x+1)xโˆ’1\frac{(x-1)(x+1)}{x-1}, which simplifies to x+1x + 1 for all xโ‰ 1x \neq 1. So limโกxโ†’1f(x)=2\lim_{x \to 1} f(x) = 2, but f(1)f(1) is undefined. There's a hole at (1,2)(1, 2).

Jump discontinuity โ€” The left-hand and right-hand limits both exist but aren't equal. The function "jumps" from one value to another.

  • Example: f(x)={1,x<02,xโ‰ฅ0f(x) = \begin{cases} 1, & x < 0 \\ 2, & x \geq 0 \end{cases} has a jump at x=0x = 0 because limโกxโ†’0โˆ’f(x)=1\lim_{x \to 0^-} f(x) = 1 while limโกxโ†’0+f(x)=2\lim_{x \to 0^+} f(x) = 2.

Infinite discontinuity (vertical asymptote) โ€” The function blows up toward +โˆž+\infty or โˆ’โˆž-\infty as xx approaches aa from one or both sides.

  • Example: f(x)=1xf(x) = \frac{1}{x} at x=0x = 0. From the right the function heads to +โˆž+\infty, and from the left it heads to โˆ’โˆž-\infty. The limit doesn't exist as a finite number.

Oscillating discontinuity โ€” The function bounces between values near x=ax = a so rapidly that no single limit is approached.

  • Example: f(x)=sinโกโ€‰โฃ(1x)f(x) = \sin\!\left(\frac{1}{x}\right) at x=0x = 0. As xx gets closer to 0, the function oscillates between โˆ’1-1 and 11 faster and faster, so neither one-sided limit exists.

Continuity and Differentiability

These two concepts are closely linked, but the relationship only goes one direction.

  • Differentiability implies continuity. If a function is differentiable at a point, it must be continuous there. A function can't have a well-defined slope at a point where it has a gap or jump.
  • Continuity does NOT imply differentiability. A function can be continuous at a point but still fail to be differentiable there. The classic example is f(x)=โˆฃxโˆฃf(x) = |x| at x=0x = 0: the function is continuous (no breaks), but it has a sharp corner, so no single tangent line exists.

This is a distinction that shows up frequently on tests: every differentiable function is continuous, but not every continuous function is differentiable.