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8.6 Parametric Equations

8.6 Parametric Equations

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐Ÿ“Honors Pre-Calculus
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Parametric Equations

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Parametric to rectangular conversion

Parametric equations define a curve using two separate equations, x(t)x(t) and y(t)y(t), where tt is the parameter that links them together. Instead of writing yy directly as a function of xx, you let both coordinates depend on a third variable. This is especially useful for curves that fail the vertical line test or for describing motion over time.

Converting parametric โ†’ rectangular means eliminating the parameter tt so you're left with a single equation in xx and yy:

  1. Pick whichever parametric equation is easier to solve for tt
  2. Solve that equation for tt
  3. Substitute the result into the other equation

For example, given x(t)=t2x(t) = t^2 and y(t)=t3y(t) = t^3:

  • Solve for tt: since x=t2x = t^2, you get t=x1/2t = x^{1/2} (assuming tโ‰ฅ0t \geq 0)
  • Substitute into y(t)y(t): y=(x1/2)3=x3/2y = (x^{1/2})^3 = x^{3/2}

For parametric equations involving trig, use identities instead of solving for tt directly. If x(t)=cosโก(t)x(t) = \cos(t) and y(t)=sinโก(t)y(t) = \sin(t), square both and add them: x2+y2=cosโก2(t)+sinโก2(t)=1x^2 + y^2 = \cos^2(t) + \sin^2(t) = 1. That gives you the rectangular equation of a circle.

Converting rectangular โ†’ parametric means introducing a parameter tt. The simplest approach: let x(t)=tx(t) = t, then rewrite yy in terms of tt. For y=x2y = x^2, you'd write x(t)=tx(t) = t and y(t)=t2y(t) = t^2. Note that parametric representations aren't unique; you could also use x(t)=2tx(t) = 2t and y(t)=4t2y(t) = 4t^2 for the same parabola.

Parametric to rectangular conversion, Parametric Equations | Precalculus

Modeling with parametric equations

Parametric equations are a natural fit for modeling 2D motion, where x(t)x(t) and y(t)y(t) give the horizontal and vertical position at time tt.

Projectile motion is the classic example. An object launched with initial speed vv at angle ฮธ\theta from the ground follows:

x(t)=vcosโก(ฮธ)โ‹…tx(t) = v\cos(\theta) \cdot t

y(t)=vsinโก(ฮธ)โ‹…tโˆ’12gt2y(t) = v\sin(\theta) \cdot t - \frac{1}{2}gt^2

Here gg is the acceleration due to gravity (approximately 9.8ย m/s29.8 \text{ m/s}^2 or 32ย ft/s232 \text{ ft/s}^2). The horizontal component has constant velocity, while the vertical component is affected by gravity, which is why these are easier to handle as two separate equations rather than one rectangular equation.

Modeling curves and shapes is another major use. A cycloid, the path traced by a point on the rim of a rolling circle of radius rr, has the parametric form:

x(t)=r(tโˆ’sinโก(t))x(t) = r(t - \sin(t))

y(t)=r(1โˆ’cosโก(t))y(t) = r(1 - \cos(t))

This curve would be extremely difficult to express as a single rectangular equation, which is exactly why parametric form is so valuable.

Parametric to rectangular conversion, Parametric Equations: Graphs ยท Precalculus

Calculus of parametric curves

Note: Depending on your course, this section may be preview material for AP Calculus BC. Check with your instructor on how much depth you need here.

The derivatives of x(t)x(t) and y(t)y(t) with respect to tt give you velocity components:

  • dxdt\frac{dx}{dt} is the horizontal velocity
  • dydt\frac{dy}{dt} is the vertical velocity

To find the slope of the tangent line to a parametric curve at a given point, use the chain rule:

dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}

This works as long as dxdtโ‰ 0\frac{dx}{dt} \neq 0 at that point.

The arc length of a parametric curve from t=at = a to t=bt = b is:

L=โˆซab(dxdt)2+(dydt)2โ€‰dtL = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt

Think of this as adding up tiny distances along the curve, where each small piece has a horizontal component dxdx and a vertical component dydy.

Geometric interpretation of parameters

What tt actually represents depends on the context:

  • In motion problems, tt is usually time
  • In shape problems, tt might represent an angle (like for circles and ellipses) or a proportion along the curve

The domain of tt controls which portion of the curve you trace out. For the unit circle x(t)=cosโก(t)x(t) = \cos(t), y(t)=sinโก(t)y(t) = \sin(t):

  • 0โ‰คtโ‰ค2ฯ€0 \leq t \leq 2\pi traces exactly one full revolution
  • 0โ‰คtโ‰คฯ€0 \leq t \leq \pi traces only the upper semicircle
  • 0โ‰คtโ‰ค4ฯ€0 \leq t \leq 4\pi traces the circle twice

Changing constants in the parametric equations affects the curve's size and shape. In the cycloid equations, increasing rr produces a larger cycloid. For an ellipse written as x(t)=acosโก(t)x(t) = a\cos(t), y(t)=bsinโก(t)y(t) = b\sin(t), the values of aa and bb control the width and height.

Advanced parametric representations

Polar-to-parametric conversion: Any polar equation r=f(ฮธ)r = f(\theta) can be written parametrically by using ฮธ\theta as the parameter:

x(ฮธ)=r(ฮธ)cosโก(ฮธ),y(ฮธ)=r(ฮธ)sinโก(ฮธ)x(\theta) = r(\theta)\cos(\theta), \quad y(\theta) = r(\theta)\sin(\theta)

This is useful when you need to apply rectangular-coordinate techniques (like finding tangent lines) to polar curves.

Parametric surfaces extend the idea to three dimensions. Instead of one parameter, you use two (uu and vv) to define a surface with three equations: x(u,v)x(u,v), y(u,v)y(u,v), and z(u,v)z(u,v). This is a concept you'll encounter more in multivariable calculus, but it's worth knowing that parametric thinking scales beyond 2D.