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Calculus IV Unit 23 Review

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23.1 Surface integrals of scalar fields

23.1 Surface integrals of scalar fields

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
Calculus IV
Unit & Topic Study Guides

Surface Integrals and Scalar Fields

Surface integrals of scalar fields extend the idea of single-variable integration to curved surfaces in 3D. Just as you can integrate a function along a curve (a line integral), you can integrate a scalar field over a surface to accumulate quantities like mass, charge, or total heat across that surface.

Definition and Components

A scalar field assigns a single number to each point in space. Think of temperature T(x,y,z)T(x,y,z) at every point in a room, or mass density ρ(x,y,z)\rho(x,y,z) across a thin shell.

A surface integral of a scalar field adds up the values of that field over every point on a surface SS:

Sf(x,y,z)dS\iint_S f(x,y,z)\, dS

The key pieces you need:

  • A surface SS in R3\mathbb{R}^3, described by a parametrization r(u,v)\vec{r}(u,v)
  • A scalar field f(x,y,z)f(x,y,z) defined on that surface
  • The differential area element dSdS, which accounts for how the surface stretches and curves

How to Compute a Surface Integral

Here's the process, step by step:

  1. Parametrize the surface. Write r(u,v)=(x(u,v),y(u,v),z(u,v))\vec{r}(u,v) = \big(x(u,v),\, y(u,v),\, z(u,v)\big) and identify the parameter domain DD in the uvuv-plane.

  2. Compute the partial derivatives ru=ru\vec{r}_u = \frac{\partial \vec{r}}{\partial u} and rv=rv\vec{r}_v = \frac{\partial \vec{r}}{\partial v}.

  3. Take their cross product ru×rv\vec{r}_u \times \vec{r}_v and find its magnitude ru×rv|\vec{r}_u \times \vec{r}_v|. This magnitude is the area distortion factor that converts dudvdu\,dv in parameter space into actual surface area dSdS.

  4. Substitute the parametrization into ff. Replace x,y,zx, y, z with their expressions in uu and vv so that f(x,y,z)f(x,y,z) becomes a function of uu and vv.

  5. Evaluate the double integral over the parameter domain:

SfdS=Df(x(u,v),y(u,v),z(u,v))ru×rvdudv\iint_S f\, dS = \iint_D f\big(x(u,v),\, y(u,v),\, z(u,v)\big)\, |\vec{r}_u \times \vec{r}_v|\, du\, dv

Definition and Components, HartleyMath - Surface Integrals

Applications

  • Mass of a thin shell: If ρ(x,y,z)\rho(x,y,z) is the surface mass density (mass per unit area), then SρdS\iint_S \rho\, dS gives the total mass.
  • Average value: The average of ff over SS is 1Area(S)SfdS\frac{1}{\text{Area}(S)} \iint_S f\, dS.
  • Total heat or charge: Any quantity distributed over a surface can be totaled this way.

Parametrization and Surface Area

Definition and Components, Surface Integrals · Calculus

Parametrizing Surfaces

The parametrization r(u,v)\vec{r}(u,v) maps a flat region DD in the uvuv-plane onto the curved surface in 3D. Choosing a good parametrization makes the integral much easier.

Common examples:

  • Sphere of radius aa: Use r(θ,ϕ)=(asinϕcosθ,asinϕsinθ,acosϕ)\vec{r}(\theta, \phi) = (a\sin\phi\cos\theta,\, a\sin\phi\sin\theta,\, a\cos\phi) with θ[0,2π)\theta \in [0, 2\pi) and ϕ[0,π]\phi \in [0, \pi].
  • Cylinder of radius RR: Use r(θ,z)=(Rcosθ,Rsinθ,z)\vec{r}(\theta, z) = (R\cos\theta,\, R\sin\theta,\, z).
  • Graph surface z=g(x,y)z = g(x,y): Use r(x,y)=(x,y,g(x,y))\vec{r}(x,y) = (x,\, y,\, g(x,y)). This is often the simplest option when the surface is given explicitly.

Surface Area Calculation

The total surface area of SS is the special case where f=1f = 1:

Area(S)=Dru×rvdudv\text{Area}(S) = \iint_D |\vec{r}_u \times \vec{r}_v|\, du\, dv

For the common case of a graph surface z=g(x,y)z = g(x,y), this simplifies nicely. The partial derivatives are rx=(1,0,gx)\vec{r}_x = (1, 0, g_x) and ry=(0,1,gy)\vec{r}_y = (0, 1, g_y), so:

rx×ry=1+gx2+gy2|\vec{r}_x \times \vec{r}_y| = \sqrt{1 + g_x^2 + g_y^2}

This means dS=1+gx2+gy2dxdydS = \sqrt{1 + g_x^2 + g_y^2}\, dx\, dy, a formula worth memorizing.

Watch out: The choice of parametrization doesn't change the value of the integral, but a poor choice can make the computation far harder. Always look for symmetry in the surface before picking coordinates.

Flux (Preview)

This topic (23.1) focuses on scalar field surface integrals, but it's worth seeing how they connect to flux integrals, which you'll study in depth soon.

Flux measures the flow of a vector field F\vec{F} through a surface. The integral looks different:

SFndS=DF(r(u,v))(ru×rv)dudv\iint_S \vec{F} \cdot \vec{n}\, dS = \iint_D \vec{F}\big(\vec{r}(u,v)\big) \cdot (\vec{r}_u \times \vec{r}_v)\, du\, dv

Here n\vec{n} is the unit outward normal to the surface. Notice that the scalar surface integral uses ru×rv|\vec{r}_u \times \vec{r}_v| (the magnitude), while the flux integral uses the cross product vector ru×rv\vec{r}_u \times \vec{r}_v itself (via the dot product with F\vec{F}). That distinction matters.

Key differences at a glance:

  • Scalar integral SfdS\iint_S f\, dS: integrates a scalar field, result is a scalar, surface orientation doesn't matter.
  • Flux integral SFndS\iint_S \vec{F} \cdot \vec{n}\, dS: integrates a vector field, result is a scalar, surface orientation does matter (flipping the normal flips the sign).

Flux shows up in Gauss's Law (electric flux through a closed surface), fluid dynamics (volume flow rate through a pipe cross-section), and Faraday's Law (magnetic flux through a loop). You'll need the scalar surface integral machinery from this section to handle all of those.