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2.6 Other Types of Equations

2.6 Other Types of Equations

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
📈College Algebra
Unit & Topic Study Guides

Solving Equations with Special Properties

Rational exponents and radicals

A rational exponent expresses roots and powers in a single notation: amn=amna^{\frac{m}{n}} = \sqrt[n]{a^m}. The denominator of the exponent is the root, and the numerator is the power.

To solve an equation involving a rational exponent, raise both sides to the reciprocal exponent to isolate the variable. For example, if x23=9x^{\frac{2}{3}} = 9, raise both sides to the 32\frac{3}{2} power: x=932=27x = 9^{\frac{3}{2}} = 27.

For radical equations, follow these steps:

  1. Isolate the radical term on one side of the equation (e.g., x+1=3\sqrt{x+1} = 3)
  2. Raise both sides to the power of the radical's index to eliminate it: (x+1)2=32(\sqrt{x+1})^2 = 3^2
  3. Simplify and solve the resulting equation: x+1=9x+1 = 9, so x=8x = 8
  4. Check your answer in the original equation. Squaring (or raising to any even power) can introduce extraneous solutions that don't actually work. Also consider domain restrictions; for instance, the expression under an even root must be non-negative.

Factoring for polynomial equations

To solve a polynomial equation by factoring, you rewrite it as a product of simpler expressions, then use the zero-product property: if AB=0AB = 0, then A=0A = 0 or B=0B = 0.

Here are the main factoring patterns to know:

  • Greatest common factor (GCF): Pull out the largest factor shared by all terms. 6x2+18x=6x(x+3)6x^2 + 18x = 6x(x+3)
  • Difference of squares: a2b2=(a+b)(ab)a^2 - b^2 = (a+b)(a-b). For example, x225=(x+5)(x5)x^2 - 25 = (x+5)(x-5)
  • Sum or difference of cubes: a3±b3=(a±b)(a2ab+b2)a^3 \pm b^3 = (a \pm b)(a^2 \mp ab + b^2). For example, x38=(x2)(x2+2x+4)x^3 - 8 = (x-2)(x^2 + 2x + 4)
  • Trinomials: ax2+bx+cax^2 + bx + c factors into two binomials. For example, 2x2+7x+3=(2x+1)(x+3)2x^2 + 7x + 3 = (2x+1)(x+3)

After factoring, set each factor equal to zero and solve. Those values are the roots of the polynomial.

Rational exponents and radicals, OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Solving Radical Equations

Absolute value equation solutions

The absolute value x|x| gives the distance of xx from zero, so it's always non-negative. That fact drives the entire solving process.

  1. Isolate the absolute value expression on one side (e.g., 2x3=7|2x-3| = 7)

  2. Split into two cases, since the expression inside could be positive or negative:

    • 2x3=72x - 3 = 7x=5x = 5
    • 2x3=72x - 3 = -7x=2x = -2
  3. Check for impossible setups. If the absolute value equals a negative number (like 2x3=7|2x-3| = -7), there is no solution, because absolute value can never be negative.

  4. Combine your solutions. For 2x3=7|2x-3| = 7, the solution set is x=5x = 5 or x=2x = -2.

Solving Equations with Logarithms and Exponentials

Rational exponents and radicals, OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Solving Radical Equations

Logarithmic and exponential equations

Logarithmic equations often require you to combine or simplify log terms before solving. The three key properties are:

  • Product property: logb(MN)=logb(M)+logb(N)\log_b(MN) = \log_b(M) + \log_b(N)
  • Quotient property: logb(MN)=logb(M)logb(N)\log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N)
  • Power property: logb(Mn)=nlogb(M)\log_b(M^n) = n\log_b(M)

Once you've condensed the equation to a single logarithm, convert to exponential form to solve. For example:

log2(x)+log2(x1)=3\log_2(x) + \log_2(x-1) = 3log2(x(x1))=3\log_2(x(x-1)) = 3x(x1)=23=8x(x-1) = 2^3 = 8

Then solve the resulting equation x2x8=0x^2 - x - 8 = 0 and check that your solutions keep the arguments of every logarithm positive (since you can't take the log of zero or a negative number).

Exponential equations are solved by applying logarithms:

  1. Isolate the exponential expression: 3e2x=753e^{2x} = 75e2x=25e^{2x} = 25
  2. Take the natural log of both sides: 2x=ln(25)2x = \ln(25)
  3. Solve for the variable: x=ln(25)2x = \frac{\ln(25)}{2}

If the equation has different bases (like 2x=7x12^x = 7^{x-1}), take a logarithm of both sides and use the change of base formula: logb(x)=loga(x)loga(b)\log_b(x) = \frac{\log_a(x)}{\log_a(b)}.

Multiple solution methods

Many equations can be solved in more than one way. Picking the most efficient method saves time:

  • Factorable quadratics (like x2+5x+6=0x^2 + 5x + 6 = 0) → factor directly
  • Non-factorable quadratics (like 2x23x2=02x^2 - 3x - 2 = 0) → quadratic formula or completing the square
  • Exponential equations (like 5e3x=205e^{3x} = 20) → logarithms
  • Absolute value equations → split into two cases as described above

Regardless of which method you use, always verify your solutions in the original equation. This catches extraneous solutions and arithmetic errors.

Advanced Equation Solving Techniques

Equation types and solution strategies

Beyond the specific methods above, a few general strategies come up repeatedly:

  • Algebraic manipulation: Rearranging terms and applying operations to isolate the variable. This is the foundation of every solving technique.
  • Substitution: Replacing a complicated expression with a single variable to simplify the equation. For example, if you have x45x2+4=0x^4 - 5x^2 + 4 = 0, let u=x2u = x^2 to get u25u+4=0u^2 - 5u + 4 = 0, which is a standard quadratic. Solve for uu, then back-substitute to find xx.
  • Graphical solutions: Graphing both sides of an equation as separate functions and finding where they intersect. This is especially useful for equations that are difficult to solve algebraically.
  • Inverse functions: Applying the inverse operation to "undo" what's been done to the variable. Logarithms undo exponentials, squaring undoes square roots, and so on.