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2.7 Linear Inequalities and Absolute Value Inequalities

2.7 Linear Inequalities and Absolute Value Inequalities

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
📈College Algebra
Unit & Topic Study Guides

Linear Inequalities

Linear inequalities compare expressions using symbols like <<, >>, \leq, or \geq instead of an equals sign. Solving them works a lot like solving equations, with one critical difference: multiplying or dividing by a negative number flips the inequality sign. The solution isn't a single number but a whole range of values, which you'll represent using interval notation and number line graphs.

Properties of Inequality Solutions

Three rules govern how you can manipulate inequalities:

  • Addition/Subtraction Property: Adding or subtracting the same value on both sides keeps the inequality direction the same. If x<5x < 5, then x+3<8x + 3 < 8.
  • Multiplication/Division by a Positive: Multiplying or dividing both sides by a positive number keeps the inequality direction the same. If 2x>102x > 10, then x>5x > 5.
  • Multiplication/Division by a Negative (the tricky one): Multiplying or dividing both sides by a negative number reverses the inequality. If 3x<9-3x < 9, dividing both sides by 3-3 gives x>3x > -3. The << flipped to >>.

That third rule is where most mistakes happen. Every time you divide or multiply by a negative, flip the sign.

Solving a Linear Inequality Step-by-Step

Solve 2x5<72x - 5 < 7:

  1. Add 5 to both sides: 2x<122x < 12
  2. Divide both sides by 2 (positive, so no flip): x<6x < 6

The solution is every real number less than 6.

Interval notation for inequalities, OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Introduction to Inequalities and ...

Interval Notation

Interval notation is a compact way to write solution sets. It uses:

  • Parentheses ()( \, ) for endpoints that are not included (strict inequalities << or >>)
  • Brackets [][ \, ] for endpoints that are included (non-strict inequalities \leq or \geq)
  • \infty and -\infty always get parentheses, since infinity isn't a reachable number
InequalityInterval Notation
x<5x < 5(,5)(-\infty, 5)
x2x \geq -2[2,)[-2, \infty)
3<x4-3 < x \leq 4(3,4](-3, 4]
Notice that last example mixes a parenthesis on the left (3-3 is excluded) with a bracket on the right (44 is included).

Graphing on a Number Line

To graph an inequality on a number line:

  1. Find the boundary value by solving the inequality.
  2. Draw an open circle (○) for strict inequalities (<< or >>), or a closed circle (●) for non-strict inequalities (\leq or \geq).
  3. Shade the direction that satisfies the inequality. For x<6x < 6, shade to the left of 6. For x2x \geq -2, shade to the right of 2-2.
Interval notation for inequalities, OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Introduction to Inequalities and ...

Absolute Value Inequalities

The absolute value x|x| measures distance from zero on the number line. So absolute value inequalities are really asking: how far from zero (or some other point) can this expression be?

The key skill here is rewriting an absolute value inequality as a compound inequality without absolute value signs, then solving it like a regular inequality.

Rewriting Rules

There are two cases, and they work differently:

"Less than" type (x<a|x| < a or xa|x| \leq a): The expression inside is trapped between a-a and aa. This gives you one connected interval.

x<a|x| < a becomes a<x<a-a < x < a

xa|x| \leq a becomes axa-a \leq x \leq a

"Greater than" type (x>a|x| > a or xa|x| \geq a): The expression is outside the range from a-a to aa. This gives you two separate regions.

x>a|x| > a becomes x<ax < -a or x>ax > a

xa|x| \geq a becomes xax \leq -a or xax \geq a

A quick way to remember: less than = "and" (between), greater than = "or" (outside).

Solving an Absolute Value Inequality Step-by-Step

Solve 2x3<5|2x - 3| < 5:

  1. Identify the type: this is a "less than" inequality, so rewrite as a compound inequality: 5<2x3<5-5 < 2x - 3 < 5

  2. Add 3 to all three parts: 2<2x<8-2 < 2x < 8

  3. Divide all three parts by 2: 1<x<4-1 < x < 4

  4. Write in interval notation: (1,4)(-1, 4)

Solve x+13|x + 1| \geq 3:

  1. Identify the type: this is a "greater than or equal to" inequality, so split into two: x+13x + 1 \leq -3 or x+13x + 1 \geq 3
  2. Solve each separately: x4x \leq -4 or x2x \geq 2
  3. Write in interval notation: (,4][2,)(-\infty, -4] \cup [2, \infty)

The \cup symbol means "union," combining both separate solution regions.

Special Cases to Watch For

  • x<0|x| < 0 has no solution, since absolute value can never be negative.
  • x0|x| \geq 0 is true for all real numbers, since absolute value is always zero or positive.
  • x>5|x| > -5 is also true for all real numbers (same reasoning).

If you get a result that seems too simple, check whether the inequality is comparing absolute value to a negative number. That's usually what's going on.