Fiveable

📈College Algebra Unit 2 Review

QR code for College Algebra practice questions

2.7 Linear Inequalities and Absolute Value Inequalities

2.7 Linear Inequalities and Absolute Value Inequalities

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
📈College Algebra
Unit & Topic Study Guides

Linear Inequalities

Linear inequalities compare expressions using symbols like <<, >>, \leq, or \geq instead of an equals sign. Solving them works a lot like solving equations, with one critical difference: multiplying or dividing by a negative number flips the inequality sign. The solution isn't a single number but a whole range of values, which you'll represent using interval notation and number line graphs.

Properties of Inequality Solutions

Three rules govern how you can manipulate inequalities:

  • Addition/Subtraction Property: Adding or subtracting the same value on both sides keeps the inequality direction the same. If x<5x < 5, then x+3<8x + 3 < 8.
  • Multiplication/Division by a Positive: Multiplying or dividing both sides by a positive number keeps the inequality direction the same. If 2x>102x > 10, then x>5x > 5.
  • Multiplication/Division by a Negative (the tricky one): Multiplying or dividing both sides by a negative number reverses the inequality. If 3x<9-3x < 9, dividing both sides by 3-3 gives x>3x > -3. The << flipped to >>.

That third rule is where most mistakes happen. Every time you divide or multiply by a negative, flip the sign.

Solving a Linear Inequality Step-by-Step

Solve 2x5<72x - 5 < 7:

  1. Add 5 to both sides: 2x<122x < 12
  2. Divide both sides by 2 (positive, so no flip): x<6x < 6

The solution is every real number less than 6.

Interval notation for inequalities, OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Introduction to Inequalities and ...

Interval Notation

Interval notation is a compact way to write solution sets. It uses:

  • Parentheses ()( \, ) for endpoints that are not included (strict inequalities << or >>)
  • Brackets [][ \, ] for endpoints that are included (non-strict inequalities \leq or \geq)
  • \infty and -\infty always get parentheses, since infinity isn't a reachable number
InequalityInterval Notation
x<5x < 5(,5)(-\infty, 5)
x2x \geq -2[2,)[-2, \infty)
3<x4-3 < x \leq 4(3,4](-3, 4]
Notice that last example mixes a parenthesis on the left (3-3 is excluded) with a bracket on the right (44 is included).

Graphing on a Number Line

To graph an inequality on a number line:

  1. Find the boundary value by solving the inequality.
  2. Draw an open circle (○) for strict inequalities (<< or >>), or a closed circle (●) for non-strict inequalities (\leq or \geq).
  3. Shade the direction that satisfies the inequality. For x<6x < 6, shade to the left of 6. For x2x \geq -2, shade to the right of 2-2.
Interval notation for inequalities, OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Introduction to Inequalities and ...

Absolute Value Inequalities

The absolute value x|x| measures distance from zero on the number line. So absolute value inequalities are really asking: how far from zero (or some other point) can this expression be?

The key skill here is rewriting an absolute value inequality as a compound inequality without absolute value signs, then solving it like a regular inequality.

Rewriting Rules

There are two cases, and they work differently:

"Less than" type (x<a|x| < a or xa|x| \leq a): The expression inside is trapped between a-a and aa. This gives you one connected interval.

x<a|x| < a becomes a<x<a-a < x < a

xa|x| \leq a becomes axa-a \leq x \leq a

"Greater than" type (x>a|x| > a or xa|x| \geq a): The expression is outside the range from a-a to aa. This gives you two separate regions.

x>a|x| > a becomes x<ax < -a or x>ax > a

xa|x| \geq a becomes xax \leq -a or xax \geq a

A quick way to remember: less than = "and" (between), greater than = "or" (outside).

Solving an Absolute Value Inequality Step-by-Step

Solve 2x3<5|2x - 3| < 5:

  1. Identify the type: this is a "less than" inequality, so rewrite as a compound inequality: 5<2x3<5-5 < 2x - 3 < 5

  2. Add 3 to all three parts: 2<2x<8-2 < 2x < 8

  3. Divide all three parts by 2: 1<x<4-1 < x < 4

  4. Write in interval notation: (1,4)(-1, 4)

Solve x+13|x + 1| \geq 3:

  1. Identify the type: this is a "greater than or equal to" inequality, so split into two: x+13x + 1 \leq -3 or x+13x + 1 \geq 3
  2. Solve each separately: x4x \leq -4 or x2x \geq 2
  3. Write in interval notation: (,4][2,)(-\infty, -4] \cup [2, \infty)

The \cup symbol means "union," combining both separate solution regions.

Special Cases to Watch For

  • x<0|x| < 0 has no solution, since absolute value can never be negative.
  • x0|x| \geq 0 is true for all real numbers, since absolute value is always zero or positive.
  • x>5|x| > -5 is also true for all real numbers (same reasoning).

If you get a result that seems too simple, check whether the inequality is comparing absolute value to a negative number. That's usually what's going on.

Pep mascot
Upgrade your Fiveable account to print any study guide

Download study guides as beautiful PDFs See example

Print or share PDFs with your students

Always prints our latest, updated content

Mark up and annotate as you study

Click below to go to billing portal → update your plan → choose Yearly → and select "Fiveable Share Plan". Only pay the difference

Plan is open to all students, teachers, parents, etc
Pep mascot
Upgrade your Fiveable account to export vocabulary

Download study guides as beautiful PDFs See example

Print or share PDFs with your students

Always prints our latest, updated content

Mark up and annotate as you study

Plan is open to all students, teachers, parents, etc
report an error
description

screenshots help us find and fix the issue faster (optional)

add screenshot

2,589 studying →