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AP Physics 1 Unit 5 Review: Torque and Rotational Dynamics

  • 10–15% of AP multiple choice
  • 6 topics
  • AP exam review verified for 2027

Torque and rotational dynamics describe how forces cause or prevent rotation. Torque depends on force magnitude, distance from the axis, and the angle of application. Rotational inertia resists changes in spinning motion. When net torque is zero, angular velocity stays constant. When net torque is nonzero, angular acceleration results according to α = τ_net / I.

Fiveable's AP Physics 1 Unit 5 review covers 6 topics, with guided practice questions for the unit.

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AP Physics 1 unit 5 topics

5.1

Rotational Kinematics

Describes rotation using angular displacement Δθ, angular velocity ω, and angular acceleration α. Under constant α, rotational kinematic equations parallel the linear equations from Unit 1. All points in a rigid system share the same ω and α.

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5.2

Connecting Linear and Rotational Motion

Links angular and linear quantities for any point at distance r from the axis: s = rθ, v = rω, and a_T = rα. Points farther from the axis have greater tangential speed and acceleration even though ω and α are the same for the whole rigid system.

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5.3

Torque

Torque is the rotational effect of a force, calculated as τ = rF sinθ. Only the force component perpendicular to the position vector from the axis contributes. The lever arm is the perpendicular distance from the axis to the line of action of the force.

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5.4

Rotational Inertia

Rotational inertia I = mr² measures resistance to changes in rotation. For discrete systems, I_total = Σmᵢrᵢ². Mass farther from the axis increases I more. The parallel axis theorem I' = I_cm + Md² applies when the axis does not pass through the center of mass.

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5.6

Newton's Second Law in Rotational Form

A nonzero net torque produces angular acceleration: α = τ_net / I. Angular acceleration is proportional to net torque and inversely proportional to rotational inertia. Systems with both linear and rotational motion require separate analyses connected by a = rα.

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Practice AP Physics 1 unit 5 questions

Try AP-style questions on unit 5, then use the review notes below for anything you miss.

Example stimulus-based MCQs

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schematic

Stimulus-based practice question

A satellite, modeled as a uniform rod of length LL, is initially at rest. Two thrusters apply constant forces of magnitude FF and 2F2F perpendicular to the rod at the positions shown in the figure.

Question

Which claim correctly describes the angular velocity of the satellite while the thrusters are firing?

It increases at a constant rate because the net force exerted on the satellite is 3F3F.

It increases at a constant rate because the force 2F2F is greater in magnitude than the force FF.

It remains constant at zero because the net torque exerted on the satellite is zero.

It increases at a constant rate because the forces are applied at different distances from the center of mass.

setup_diagram

Stimulus-based practice question

Wheel A rolls without slipping at a constant speed along a horizontal surface. Wheel B rolls without slipping down an inclined plane, increasing in speed as it moves.

Question

How do the magnitudes of the net torques about the center of mass for Wheel A and Wheel B compare, and what does this indicate about their rotational equilibrium?

τA<τB\tau_A < \tau_B; neither wheel is in rotational equilibrium because both are moving.

τA=τB\tau_A = \tau_B; both wheels are in rotational equilibrium because they roll without slipping.

τA>τB\tau_A > \tau_B; Wheel A requires a greater net torque to maintain a constant speed on a horizontal surface.

τA<τB\tau_A < \tau_B; Wheel A is in rotational equilibrium, while Wheel B is not.

Example FRQs

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FRQ

Angular acceleration of rotating disk-pulley system

3. Students are investigating how torque affects the angular acceleration of a rotating system.

Figure 1. Disk-pulley apparatus for angular acceleration

Figure 1

Figure 2. Grid for linearized relationship plot

Figure 2

Table 1. Hanging mass and angular acceleration data

Figure 3
A.

Describe an experimental procedure the students could use to determine the angular acceleration α of the disk when a hanging mass m is released from rest. Include the measurements to be made, how the measurements are used to determine α using angular kinematics, and one method to reduce experimental uncertainty.

B.

The students model the system as follows. The hanging mass m accelerates downward with linear acceleration a while the disk-and-pulley rotate with angular acceleration α. The string does not slip on the pulley, so a = αR. The torque on the rotating system due to the string is τ = TR, where T is the string tension. The net torque about the axle is related to angular acceleration by τ = Iα. Using Newton’s second law for the hanging mass and the relationships above, the students determine that

α = (m g R) / (I + mR^2)

Describe how the students could use measurements of α for different values of m to create a linear graph and how the slope of that graph could be used to determine the rotational inertia I. Clearly identify what quantities are plotted on each axis and how the slope is related to I.

m (kg)

α (rad/s^2)

0.050

1.45

0.070

1.96

0.090

2.44

0.110

2.88

0.130

3.33

C.

The students perform five trials using different hanging masses m. For each trial, the students release the system from rest and measure the time Δt for the disk to rotate through an angular displacement of Δθ = 6.00 rad. The students use rotational kinematics (Δθ = (1/2)α(Δt)^2) to determine α for each trial. The values of m and the calculated α are shown in Table 1.

The students decide to graph 1/m on the horizontal axis.

i.

Indicate what measured or calculated quantity could be plotted on the vertical axis to yield a linear graph whose slope can be used to calculate an experimental value for the rotational inertia I.

Vertical axis: Horizontal axis: 1/m

ii.

On the blank grid provided, create a graph of the quantities indicated in part C(i) that can be used to determine I.

•

Use Table 2 to record the data points or calculated quantities that you will plot.

•

Clearly label the vertical axis, including units as appropriate.

•

Plot the points you recorded in Table 2.

iii.

Draw a straight best-fit line for the data graphed in part C(ii).

D.

Using the best-fit line that you drew in part C(iii), calculate an experimental value for the rotational inertia I of the disk-and-pulley system. Use g = 9.80 m/s^2 and R = 0.0250 m.

FRQ

Rotational torque and angular acceleration comparison

4. A solid disk of mass M = 2, as shown in Figure 2.0 kg and radius R = 0.50 m is mounted on a horizontal axle through its center, as shown in Figure 1. The disk has rotational inertia I = (1/2)MR² about the axle. The axle is supported by a low-friction bearing, and all frictional effects are negligible.

Figure 1. Scenario 1: String pulled at outer rim

Figure 1

Figure 2. Scenario 2: String pulled at inner hub

Figure 2
A.

Indicate whether α₁ is greater than, less than, or equal to α₂ by writing one of the following in your answer booklet.

• α₁ > α₂
• α₁ < α₂
• α₁ = α₂

Justify your answer in terms of ALL torques exerted on the disk in each scenario and the relationship between torque and angular acceleration. Use qualitative reasoning beyond referencing equations.

B.

Starting with Newton's second law for rotation, derive an expression for the angular acceleration α of the disk. Express your answer in terms of F, d, I, and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information. Consider the general case where a string is wrapped around a disk or hub at distance d from the axis of rotation and pulled with a constant horizontal force of magnitude F. The disk has rotational inertia I about the axle.

C.

Indicate whether the expression for the angular acceleration α you derived in part B is or is not consistent with the comparison made in part A. Briefly justify your answer by referencing your derivation in part B.

FRQ

Rotational dynamics of disk-block system

1. A uniform solid disk of mass M=2.00 kgM=2.00\ \text{kg} and radius R=0.200 mR=0.200\ \text{m} can rotate about a fixed, frictionless axle through its center, as shown in Figure 1. A light, inextensible string is wrapped around the rim of the disk and attached to a small hanging block of mass m=0.500 kgm=0.500\ \text{kg}. The block is released from rest at time t=0t=0 and falls vertically. The string does not slip on the disk, and the disk starts from rest.

Figure 1. Uniform solid disk with string and hanging block; positive directions indicated.

Figure 1

Figure 2. Axes for angular velocity ω of the disk versus time t.

Figure 2
A.
i.

On the axes shown in Figure 2, sketch a graph of the angular velocity ω\omega of the disk as a function of time tt from t=0t=0 until t>t2t>t_2.

ii.

Derive an expression for the magnitude of the angular acceleration α\alpha of the disk while the block is falling (before t=t2t=t_2) in terms of mm, MM, RR, gg, and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

iii.

Derive an expression for the angular speed ω1\omega_1 of the disk at time t=t1t=t_1 in terms of mm, MM, RR, gg, and the given distance yy. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

B.

Indicate whether the net torque about the axle on the disk is zero or nonzero while the block is falling. Consider the torques exerted on the disk while the block is falling and the string is taut. The tension in the string is TT. The weight of the disk is MgMg and the axle exerts a force on the disk at its center.

Zero
Nonzero
Justify your response by identifying all forces that can exert a torque about the axle and explaining which contribute to the net torque.

AP Physics 1 unit 5 practice test

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Unit 5 review notes

5.1

Describing Rotation Over Time

Rotational kinematics uses angular displacement Δθ (in radians), angular velocity ω (rad/s), and angular acceleration α (rad/s²) to describe how a rigid system rotates. These quantities follow the same relationships as linear kinematics, so under constant angular acceleration the same equation structure applies. Counterclockwise is typically positive by convention. A rigid system holds its shape, meaning all points share the same ω and α even though they travel different linear distances.

  • Angular displacement Δθ: The angle in radians through which a point on a rigid system rotates about a specified axis; Δθ = θ - θ₀.
  • Average angular velocity ω_avg: Change in angular displacement divided by elapsed time: ω_avg = Δθ / Δt.
  • Average angular acceleration α_avg: Change in angular velocity divided by elapsed time: α_avg = Δω / Δt.
  • Constant angular acceleration equations: ω = ω₀ + αt and θ = θ₀ + ω₀t + ½αt² apply when α is uniform, directly paralleling the linear kinematic equations from Unit 1.
  • Sign convention: One direction of rotation (usually counterclockwise) is defined as positive; the opposite direction is negative. Consistency within a problem is required.

A wheel starts from rest and reaches ω = 12 rad/s in 4 s under constant angular acceleration. What is α, and how many radians does it rotate through?

Linear quantitySymbolRotational equivalentSymbol
DisplacementΔxAngular displacementΔθ
VelocityvAngular velocityω
AccelerationaAngular accelerationα
v = v₀ + atω = ω₀ + αt
5.2

Linking Angular and Linear Quantities

For any point at distance r from a fixed axis, linear and angular quantities are connected by three key equations: arc length s = rθ, tangential speed v = rω, and tangential acceleration a_T = rα. Because all points in a rigid system share the same ω and α, a point farther from the axis moves faster and accelerates more than a point closer to the axis. This relationship is essential for analyzing wheels, gears, and rolling objects.

  • Arc length s = rθ: The linear distance a point travels along its circular path equals the radius times the angular displacement in radians.
  • Tangential speed v = rω: The instantaneous linear speed of a point on a rotating rigid system; larger r means faster linear speed for the same ω.
  • Tangential acceleration a_T = rα: The component of linear acceleration tangent to the circular path; equals radius times angular acceleration.
  • Same ω and α for all points: Every point in a rigid system rotates with identical angular velocity and angular acceleration, regardless of its distance from the axis.
  • Rolling without slipping: For an object rolling without slipping, the contact point is instantaneously at rest and v_cm = rω relates the center-of-mass speed to the angular velocity.

A disk of radius 0.5 m rotates at ω = 6 rad/s. What is the tangential speed of a point on the rim, and what is the tangential speed of a point 0.25 m from the center?

EquationRelatesKey point
s = rθArc length to angular displacementθ must be in radians
v = rωTangential speed to angular velocityLarger r gives larger v
a_T = rαTangential acceleration to angular accelerationDistinct from centripetal acceleration
5.3

Torque: Force That Causes Rotation

Torque measures how effectively a force rotates a rigid system about an axis. Only the component of force perpendicular to the position vector from the axis to the point of application produces torque. The magnitude is τ = rF sinθ = rF⊥, where θ is the angle between the force vector and the position vector. The lever arm is the perpendicular distance from the axis to the line of action of the force. Force diagrams, similar to free-body diagrams, show force magnitudes, directions, and points of application relative to the axis.

  • Torque τ = rF sinθ: The magnitude of torque equals the distance from the axis to the point of force application times the force magnitude times the sine of the angle between them.
  • Lever arm: The perpendicular distance from the axis of rotation to the line of action of the force; a longer lever arm produces greater torque for the same force.
  • Perpendicular force component F⊥: Only the component of force perpendicular to the position vector contributes to torque; the parallel component produces no rotation.
  • Force diagram: A diagram used to analyze torques on a rigid system, showing force magnitudes, directions, and locations of application relative to the axis of rotation.
  • Sign of torque: Torques that tend to rotate the system counterclockwise are typically positive; clockwise torques are negative. Consistency within a problem is required.

A 20 N force is applied at 0.4 m from a pivot at an angle of 30° to the position vector. What is the magnitude of the torque?

ScenarioLever armTorque effect
Force perpendicular to r (θ = 90°)rMaximum torque: τ = rF
Force at angle θ to rr sinθReduced torque: τ = rF sinθ
Force parallel to r (θ = 0°)0Zero torque
5.4

Rotational Inertia: Resistance to Spinning

Rotational inertia I is the rotational analog of mass. It measures how strongly a rigid system resists changes in its rotation and depends on both the total mass and how that mass is distributed relative to the axis. For a point mass, I = mr². For a collection of objects, I_total = Σmᵢrᵢ². Mass farther from the axis contributes more to I, which is why a hoop has greater rotational inertia than a solid disk of the same mass and radius. The parallel axis theorem I' = I_cm + Md² gives the rotational inertia about any axis parallel to one through the center of mass.

  • I = mr²: Rotational inertia of a single point mass m at perpendicular distance r from the axis of rotation.
  • I_total = Σmᵢrᵢ²: Total rotational inertia of a system of discrete masses is the sum of each mass times the square of its distance from the axis.
  • Mass distribution effect: Rotational inertia is greater when mass is concentrated farther from the axis; moving mass outward increases I even if total mass stays the same.
  • Parallel axis theorem: I' = I_cm + Md², where d is the perpendicular distance between the new axis and the center-of-mass axis; rotational inertia is minimum when the axis passes through the center of mass.
  • Extended object formulas: Formulas for hoops, disks, and rods are provided on the exam; students need qualitative understanding of why shape and axis placement affect I.

Two 2 kg masses are placed 0.3 m and 0.6 m from an axis. What is the total rotational inertia of the system? Which mass contributes more, and why?

ObjectAxis locationRelative rotational inertia
Hoop (mass M, radius R)Through centerLarger (all mass at R)
Solid disk (mass M, radius R)Through centerSmaller (mass distributed from 0 to R)
Rod (mass M, length L)Through centerSmaller than through end
Rod (mass M, length L)Through endLarger (mass farther on average)
5.5

Rotational Equilibrium and Constant Angular Velocity

A system is in rotational equilibrium when the net torque on it is zero (Στᵢ = 0), meaning its angular velocity remains constant. This is the rotational form of Newton's first law. A system can be in rotational equilibrium without being in translational equilibrium, and vice versa. To solve balance problems, choose a convenient pivot point, identify all torques with their signs, and set the sum equal to zero. Force diagrams show both the forces and their points of application relative to the chosen axis.

  • Rotational equilibrium condition: Στᵢ = 0; the net torque about any axis is zero, so angular velocity does not change.
  • Rotational form of Newton's first law: A system maintains constant angular velocity (including ω = 0) unless a nonzero net torque acts on it.
  • Independent of translational equilibrium: A system can spin at constant ω while its center of mass accelerates, or be stationary while experiencing unbalanced torques.
  • Pivot point choice: You can choose any point as the axis for torque calculations; choosing a point where an unknown force acts eliminates that force from the torque equation.
  • Force diagram for equilibrium: Shows all forces, their magnitudes, directions, and positions relative to the axis, enabling identification of clockwise and counterclockwise torques.

A uniform 4 m beam of mass 10 kg is supported at one end. A 30 N downward force is applied 1 m from the free end. What upward force at the free end keeps the beam in rotational equilibrium about the supported end?

ConditionNet forceNet torqueResult
Full static equilibriumZeroZeroNo linear or angular acceleration
Rotational equilibrium onlyNonzeroZeroLinear acceleration, constant ω
Translational equilibrium onlyZeroNonzeroAngular acceleration, constant v_cm
Neither equilibriumNonzeroNonzeroBoth linear and angular acceleration
5.6

Newton's Second Law for Rotating Systems

When the net torque on a rigid system is not zero, the system undergoes angular acceleration. The rotational form of Newton's second law is α_sys = τ_net / I_sys. Angular acceleration is directly proportional to net torque and inversely proportional to rotational inertia. For systems that involve both linear and rotational motion, such as a mass hanging from a pulley, you must perform separate linear and rotational analyses and connect them through the constraint equations from Topic 5.2.

  • α_sys = τ_net / I_sys: The angular acceleration of a rigid system equals the net torque divided by the rotational inertia; the rotational analog of a = F_net / m.
  • Nonzero net torque causes angular acceleration: If Στ ≠ 0, angular velocity must be changing; the direction of α matches the direction of τ_net.
  • Proportionality relationships: Doubling τ_net doubles α; doubling I_sys halves α for the same net torque. These functional dependence relationships are commonly tested.
  • Combined linear and rotational analysis: For systems like a block on a string wrapped around a pulley, apply F_net = ma to the block and τ_net = Iα to the pulley separately, then use a = rα to connect them.
  • Internal torques cancel: Only external torques contribute to the net torque that changes a system's angular velocity; internal torques between parts of the system cancel in pairs.

A pulley of rotational inertia 0.2 kg·m² has a net torque of 0.8 N·m applied to it. What is its angular acceleration? If the net torque doubles and I stays the same, what happens to α?

Linear (Unit 2)Rotational (Unit 5)
F_net = maτ_net = Iα
a = F_net / mα = τ_net / I
Larger m resists accelerationLarger I resists angular acceleration
ΣF = 0 means constant vΣτ = 0 means constant ω

Key terms

TermDefinition
axis of rotationThe specified line about which a rigid system rotates; the reference point for measuring torque, lever arm, and rotational inertia.
rigid systemA system that holds its shape during rotation, with all points sharing the same angular velocity and angular acceleration even though they travel different linear distances.
constant angular accelerationA condition in which angular velocity changes at a uniform rate, allowing the use of rotational kinematic equations analogous to constant linear acceleration equations from Unit 1.
Δs = r ΔθThe arc length a point travels equals its distance from the axis times the angular displacement in radians; the foundation for v = rω and a_T = rα.
lever armThe perpendicular distance from the axis of rotation to the line of action of an applied force; a longer lever arm produces greater torque for the same force magnitude.
moment armThe perpendicular distance from the axis of rotation to the line of action of a force, used interchangeably with lever arm to calculate torque as τ = rF sinθ.
force diagramA diagram similar to a free-body diagram used to analyze torques on a rigid system, showing force magnitudes, directions, and points of application relative to the axis of rotation.
parallel axis theoremI' = I_cm + Md²; gives the rotational inertia about any axis parallel to one through the center of mass, where d is the perpendicular distance between the two axes. Rotational inertia is minimum when the axis passes through the center of mass.

How to review unit 5

Topics students miss most

Miss rates come from Fiveable multiple-choice practice.

5.3
50%1,456 tries
5.4
47%2,012 tries

Common unit 5 mistakes

Using degrees instead of radians

All rotational kinematic equations and the arc length formula s = rθ require θ in radians. Converting to degrees before calculating will give wrong answers. Always check your units before substituting.

Using the full force instead of the perpendicular component for torque

Only the component of force perpendicular to the position vector from the axis causes rotation. If a force is applied at an angle, you must use τ = rF sinθ, not τ = rF. Forgetting the sinθ factor is one of the most common torque errors.

Treating rotational inertia like mass in torque problems

Rotational inertia depends on both mass and the square of the distance from the axis. Doubling the distance from the axis quadruples I, not doubles it. Always square the radius when calculating I = mr².

Assuming rotational and translational equilibrium always occur together

A system can have zero net torque (constant ω) while its center of mass accelerates, or zero net force (constant v_cm) while angular velocity changes. These conditions are independent and must be checked separately.

Forgetting to connect linear and rotational analyses with a = rα

In problems with a hanging mass and a pulley, students often write separate equations but forget to use a = rα to link the linear acceleration of the mass to the angular acceleration of the pulley. Without this constraint, the system is underdetermined.

How this unit shows up on the AP exam

Functional dependence and proportional reasoning

The AP Physics 1 exam frequently asks how angular acceleration changes when net torque or rotational inertia changes by a given factor. You should be able to use α = τ_net / I to explain, without numbers, that doubling I halves α for the same torque, or that tripling τ_net triples α for the same I. Written justification of these proportional relationships is a core skill tested in both multiple-choice and free-response questions.

Combined linear and rotational system analysis

Free-response questions in this unit often involve systems where a hanging mass drives a rotating pulley or a force causes both translation and rotation. You are expected to write separate Newton's second law equations for the linear and rotational components, then connect them using the constraint a = rα. Clearly labeling which equation applies to which part of the system and showing the connection step is essential for full credit.

Rotational equilibrium and torque balance problems

Questions may present a beam, rod, or lever with multiple forces and ask you to find an unknown force or distance that maintains rotational equilibrium. The skill is setting up Στ = 0 about a strategically chosen pivot, correctly computing each torque with its sign, and solving algebraically. You may also need to explain why a system is or is not in rotational equilibrium based on a described or diagrammed scenario.

More ways to review

Topic study guides

Open the individual guides for Unit 5 when you want a closer review of one topic.

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Practice questions

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FRQ practice

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Official unit cheatsheet

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Frequently Asked Questions

What's on the AP Physics 1 Unit 5 progress check (MCQ and FRQ)?

The AP Physics 1 Unit 5 progress check in AP Classroom includes both MCQ and FRQ parts drawn from all six unit topics: rotational kinematics, connecting linear and rotational motion, torque, rotational inertia, rotational equilibrium, and Newton's Second Law in rotational form. The MCQ section tests conceptual understanding and quantitative reasoning across these topics, while the FRQ part typically asks you to apply Newton's laws in rotational form or analyze a system in rotational equilibrium. For matched practice that mirrors the progress check format, check out /ap-physics-1-revised/unit-5.

How do I practice AP Physics 1 Unit 5 FRQs?

AP Physics 1 Unit 5 FRQs most often focus on torque, rotational inertia, and Newton's Second Law in rotational form, asking you to set up equations, justify reasoning, or analyze a physical scenario involving rotational equilibrium. To practice effectively, work through problems where you draw extended free-body diagrams, identify the pivot point, and write out net torque equations step by step. Good habits: always define your sign convention for rotation, show your algebra clearly, and connect back to the physical situation in your explanation. You can find FRQ-style practice problems at /ap-physics-1-revised/unit-5.

Where can I find AP Physics 1 Unit 5 practice questions?

The best place to find AP Physics 1 Unit 5 practice questions, including multiple-choice and practice test problems on torque and rotational dynamics, is /ap-physics-1-revised/unit-5. There you'll find MCQ practice covering all six topics, from rotational kinematics and rotational inertia to rotational equilibrium and Newton's Second Law in rotational form. For the most targeted prep, focus your MCQ practice on problems that ask you to compare rotational inertia for different mass distributions and apply torque to find angular acceleration.

How should I study AP Physics 1 Unit 5?

Start AP Physics 1 Unit 5 by locking in rotational kinematics (5.1) and the connections to linear motion (5.2), since those relationships, like angular velocity linking to linear velocity, show up throughout the rest of the unit. Then build toward torque and rotational inertia before tackling Newton's laws in rotational form. Here's a concrete study sequence:
1. Review rotational kinematics equations alongside their linear counterparts so the patterns stick.
2. Practice drawing extended free-body diagrams to identify torques and pivot points.
3. Work problems on rotational inertia for different object shapes, since the mass distribution matters.
4. Apply Newton's Second Law in rotational form to systems with multiple torques.
5. Test yourself with mixed MCQ and FRQ practice at /ap-physics-1-revised/unit-5. Since this unit is 10-15% of the exam, even a few focused study sessions here can meaningfully move your score.

Ready to review Unit 5?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.