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AP Physics 1 Unit 5 practice questions

Try 10 multiple-choice questions from Unit 5 here. Pick an answer to see why it's right or wrong, then take the timed test above for a full AP-style set.

  1. Question 1

    A flywheel initially rotating at 12.0 rad/s12.0 \text{ rad/s} slows down with a constant angular acceleration of −2.0 rad/s2-2.0 \text{ rad/s}^2. What is the total angular displacement of the flywheel from the moment it begins to slow down until it comes to a complete stop?

    6.0 rad6.0 \text{ rad}

    36 rad36 \text{ rad}

    72 rad72 \text{ rad}

    144 rad144 \text{ rad}

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    Answer: (B)

    Using ω2=ω02+2αΔθ\omega^2 = \omega_0^2 + 2\alpha\Delta\theta, substitute values: 0=(12)2+2(−2)Δθ0 = (12)^2 + 2(-2)\Delta\theta. Solving gives 144=4Δθ144 = 4\Delta\theta, so Δθ=36 rad\Delta\theta = 36 \text{ rad}.

  2. Question 2

    A car with tires of radius 0.25 m0.25 \text{ m} accelerates from rest with a constant linear acceleration of 2.0 m/s22.0 \text{ m/s}^2. Assuming the tires roll without slipping, what is their angular velocity after 4.0 s4.0 \text{ s}?

    2.0 rad/s2.0 \text{ rad/s}

    8.0 rad/s8.0 \text{ rad/s}

    16 rad/s16 \text{ rad/s}

    32 rad/s32 \text{ rad/s}

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    Answer: (D)

    First, find linear velocity: v=at=2(4)=8 m/sv = at = 2(4) = 8 \text{ m/s}. Then convert to angular velocity using v=rωv = r\omega: ω=8/0.25=32 rad/s\omega = 8 / 0.25 = 32 \text{ rad/s}.

  3. Question 3

    A fan blade accelerates from rest with a constant angular acceleration of π rad/s2\pi \text{ rad/s}^2. How many revolutions does the blade complete in the first 4.0 s4.0 \text{ s} of motion?

    2.0 revolutions2.0 \text{ revolutions}

    4.0 revolutions4.0 \text{ revolutions}

    8.0 revolutions8.0 \text{ revolutions}

    16 revolutions16 \text{ revolutions}

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    Answer: (B)

    Calculate displacement in radians: Δθ=12αt2=0.5(π)(16)=8π rad\Delta\theta = \frac{1}{2}\alpha t^2 = 0.5(\pi)(16) = 8\pi \text{ rad}. Convert to revolutions: 8π/2π=4.0 revolutions8\pi / 2\pi = 4.0 \text{ revolutions}.

  4. Question 4

    A disk rotating at 4.0 rad/s4.0 \text{ rad/s} accelerates constantly to 12 rad/s12 \text{ rad/s} while rotating through an angular displacement of 32 rad32 \text{ rad}. What is the angular acceleration of the disk?

    1.0 rad/s21.0 \text{ rad/s}^2

    2.0 rad/s22.0 \text{ rad/s}^2

    4.0 rad/s24.0 \text{ rad/s}^2

    8.0 rad/s28.0 \text{ rad/s}^2

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    Answer: (B)

    Use ω2=ω02+2αΔθ\omega^2 = \omega_0^2 + 2\alpha\Delta\theta: 144=16+2α(32)144 = 16 + 2\alpha(32). Simplify to 128=64α128 = 64\alpha, so α=2.0 rad/s2\alpha = 2.0 \text{ rad/s}^2.

  5. Question 5

    A string is wrapped around a pulley of radius 0.20 m0.20 \text{ m}. A block attached to the string falls from rest, causing the pulley to rotate. If the block falls 5.0 m5.0 \text{ m} in 2.0 s2.0 \text{ s}, what is the average angular acceleration of the pulley?

    2.5 rad/s22.5 \text{ rad/s}^2

    6.25 rad/s26.25 \text{ rad/s}^2

    12.5 rad/s212.5 \text{ rad/s}^2

    25 rad/s225 \text{ rad/s}^2

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    Answer: (C)

    First find linear acceleration: y=12at2→5=0.5a(4)→a=2.5 m/s2y = \frac{1}{2}at^2 \rightarrow 5 = 0.5a(4) \rightarrow a = 2.5 \text{ m/s}^2. Then convert: α=a/r=2.5/0.2=12.5 rad/s2\alpha = a/r = 2.5/0.2 = 12.5 \text{ rad/s}^2.

  6. Question 6

    A rotor starts from rest and accelerates at 3.0 rad/s23.0 \text{ rad/s}^2 for 4.0 s4.0 \text{ s}, then continues at constant angular velocity for another 4.0 s4.0 \text{ s}. What is the total angular displacement?

    48 rad48 \text{ rad}

    72 rad72 \text{ rad}

    96 rad96 \text{ rad}

    144 rad144 \text{ rad}

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    Answer: (B)

    Phase 1: θ1=0.5(3)(42)=24 rad\theta_1 = 0.5(3)(4^2) = 24 \text{ rad}. Final speed ω=3(4)=12 rad/s\omega = 3(4) = 12 \text{ rad/s}. Phase 2: θ2=12(4)=48 rad\theta_2 = 12(4) = 48 \text{ rad}. Total = 24+48=72 rad24 + 48 = 72 \text{ rad}.

  7. Question 7

    A wheel is initially rotating counterclockwise at 8.0 rad/s8.0 \text{ rad/s}. It is subjected to a constant clockwise angular acceleration of 2.0 rad/s22.0 \text{ rad/s}^2. What is the angular displacement of the wheel after 5.0 s5.0 \text{ s}?

    15 rad15 \text{ rad}

    25 rad25 \text{ rad}

    40 rad40 \text{ rad}

    65 rad65 \text{ rad}

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    Answer: (A)

    Define CCW as positive. θ=ω0t+12αt2\theta = \omega_0 t + \frac{1}{2}\alpha t^2. Substitute: 8(5)+0.5(−2)(25)=40−25=15 rad8(5) + 0.5(-2)(25) = 40 - 25 = 15 \text{ rad}.

  8. Question 8

    An object's angular velocity as a function of time is given by ω(t)=4.0+2.0t\omega(t) = 4.0 + 2.0t, where ω\omega is in rad/s and tt is in seconds. What is the angular displacement of the object from t=0t=0 to t=3.0 st=3.0 \text{ s}?

    10 rad10 \text{ rad}

    15 rad15 \text{ rad}

    21 rad21 \text{ rad}

    30 rad30 \text{ rad}

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    Answer: (C)

    Displacement is the area under the ω−t\omega-t graph (trapezoid). ω0=4\omega_0=4, ω3=10\omega_3=10. Area = 4+102×3=7×3=21 rad\frac{4+10}{2} \times 3 = 7 \times 3 = 21 \text{ rad}.

  9. Question 9

    A turbine starts from rest with constant angular acceleration. It rotates through an angle θ\theta in the first second. What is the total angle rotated through in the first 3.0 s3.0 \text{ s}?

    3θ3\theta

    4θ4\theta

    6θ6\theta

    9θ9\theta

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    Answer: (D)

    From rest, Δθ=12αt2\Delta\theta = \frac{1}{2}\alpha t^2, so Δθ∝t2\Delta\theta \propto t^2. If time triples (1→31 \rightarrow 3), displacement increases by a factor of 32=93^2 = 9.

  10. Question 10

    A merry-go-round of radius 2.0 m2.0 \text{ m} starts from rest and accelerates such that a point on the rim has a tangential acceleration of 1.0 m/s21.0 \text{ m/s}^2. What is the angular velocity of the merry-go-round after 6.0 s6.0 \text{ s}?

    0.50 rad/s0.50 \text{ rad/s}

    3.0 rad/s3.0 \text{ rad/s}

    6.0 rad/s6.0 \text{ rad/s}

    12 rad/s12 \text{ rad/s}

    Show answer

    Answer: (B)

    Find angular acceleration: α=at/r=1.0/2.0=0.5 rad/s2\alpha = a_t / r = 1.0 / 2.0 = 0.5 \text{ rad/s}^2. Then find velocity: ω=αt=0.5(6)=3.0 rad/s\omega = \alpha t = 0.5(6) = 3.0 \text{ rad/s}.

What's on the AP Physics 1 Unit 5 practice test

The standard version takes about 88 minutes and follows the timing and directions of the AP exam, sized to one unit:

  • 20 Multiple Choice Questions (40 minutes)
  • 1 FRQ – FRQ 1 – Mathematical Routines (24 minutes)
  • 1 FRQ – FRQ 2 – Translation Between Representations (24 minutes)

Questions are drawn from 1934 multiple-choice questions and 30 FRQs written for Unit 5, Torque and Rotational Dynamics.

Practice AP Physics 1 Unit 5 FRQs

Answer the unit's free-response questions one at a time and get a score on every part.

Review Unit 5 before you start

Other AP Physics 1 unit tests