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🎡AP Physics 1
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🎡AP Physics 1

FRQ 1 – Mathematical Routines
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Unit 1: Kinematics
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Practice FRQ 1 of 141/14

1. A drone travels at constant altitude above a straight road. An observer O stands at rest on the ground next to the road, while an observer O′ rides in a truck moving along the road at constant speed. The positive x-direction is east, and the positive y-direction is north, as shown in Figure 1.

Figure 1. Top-down reference frame: drone motion relative to ground observer O and truck observer O′.

Figure 1

Figure 2. Axes for sketching x-position versus time for the drone as measured by observer O.

Figure 2
A.
i.

On the axes shown in Figure 2, sketch a graph of the drone’s x-position xxx as a function of time ttt from t=0t=0t=0 until t=t2t=t_2t=t2​ as measured by observer O.

ii.

Derive expressions for the drone’s displacement components Δx\Delta xΔx and Δy\Delta yΔy from t=0t=0t=0 to t=t2t=t_2t=t2​ as measured by observer O in terms of vxv_xvx​, vyv_yvy​, and t2t_2t2​. Begin your derivation by writing a fundamental equation from the reference information.

iii.

Derive an expression for the magnitude of the drone’s displacement ∣Δr⃗∣|\Delta \vec r|∣Δr∣ from t=0t=0t=0 to t=t2t=t_2t=t2​ as measured by observer O in terms of vxv_xvx​, vyv_yvy​, and t2t_2t2​. Begin your derivation by writing an equation that relates the magnitude of a vector to its perpendicular components.

B.

Indicate whether the x-component of the drone’s average velocity as measured by observer O′ is greater than, less than, or equal to the x-component of the drone’s average velocity as measured by observer O. Observer O′ in the truck moves east with constant speed vT=6.0 m/sv_T = 6.0\ \text{m/s}vT​=6.0 m/s relative to observer O. The truck’s motion is along the +x direction only. The drone’s velocity relative to observer O remains constant at v⃗=(12 m/s) ı^+(5.0 m/s) ȷ^\vec v = (12\ \text{m/s})\,\hat\imath + (5.0\ \text{m/s})\,\hat\jmathv=(12 m/s)^+(5.0 m/s)^​. Consider the interval from t=0t=0t=0 to t=t2=8.0 st=t_2 = 8.0\ \text{s}t=t2​=8.0 s.

Greater than
Less than
Equal to
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Free Response Question Practice

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