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6.2 Parallelograms and their properties

6.2 Parallelograms and their properties

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
๐Ÿ”ทHonors Geometry
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Parallelogram Definition and Properties

A parallelogram is a quadrilateral with two pairs of parallel sides. Its properties give you a reliable set of relationships between sides, angles, and diagonals that you can use to solve for unknowns, write proofs, and classify shapes. This section covers those core properties, the theorems behind them, and how to apply them.

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Properties of Parallelograms

In any parallelogram ABCDABCD, the following properties always hold:

  • Opposite sides are parallel. ABโ€พโˆฅCDโ€พ\overline{AB} \parallel \overline{CD} and BCโ€พโˆฅADโ€พ\overline{BC} \parallel \overline{AD}. This is the defining property.
  • Opposite sides are congruent. AB=CDAB = CD and BC=ADBC = AD.
  • Opposite angles are congruent. โˆ Aโ‰…โˆ C\angle A \cong \angle C and โˆ Bโ‰…โˆ D\angle B \cong \angle D.
  • Consecutive angles are supplementary. Any two angles that share a side add to 180ยฐ180ยฐ. For example, โˆ A+โˆ B=180ยฐ\angle A + \angle B = 180ยฐ. This follows directly from the parallel sides: ABโ€พโˆฅCDโ€พ\overline{AB} \parallel \overline{CD} with transversal BCโ€พ\overline{BC} makes โˆ B\angle B and โˆ C\angle C co-interior (same-side interior) angles.
  • Diagonals bisect each other. If diagonals ACโ€พ\overline{AC} and BDโ€พ\overline{BD} intersect at point MM, then AM=MCAM = MC and BM=MDBM = MD. The diagonals themselves don't have to be equal in length; they just cut each other in half.

One thing worth remembering: knowing any one of these properties (besides the definition itself) isn't enough to prove a shape is a parallelogram. You'll see the converse theorems in the next section, but for now, these properties are consequences of already knowing the shape is a parallelogram.

Properties of parallelograms, Parallelogram - Wikipedia

Theorems and Their Proofs

These properties aren't just observations. They're proven from the definition using triangle congruence. Both proofs below rely on the same core idea: draw a diagonal to split the parallelogram into triangles, then use alternate interior angles.

Theorem: Opposite sides of a parallelogram are congruent.

  1. Start with parallelogram ABCDABCD. Draw diagonal ACโ€พ\overline{AC}, splitting it into two triangles: โ–ณABC\triangle ABC and โ–ณCDA\triangle CDA.
  2. Because ABโ€พโˆฅCDโ€พ\overline{AB} \parallel \overline{CD}, the diagonal acts as a transversal. By the Alternate Interior Angles Theorem, โˆ BACโ‰…โˆ DCA\angle BAC \cong \angle DCA.
  3. Similarly, because BCโ€พโˆฅADโ€พ\overline{BC} \parallel \overline{AD}, we get โˆ BCAโ‰…โˆ DAC\angle BCA \cong \angle DAC.
  4. Side ACโ€พ\overline{AC} is shared by both triangles (Reflexive Property).
  5. By ASA, โ–ณABCโ‰…โ–ณCDA\triangle ABC \cong \triangle CDA. Therefore AB=CDAB = CD and BC=ADBC = AD by CPCTC.

Notice that this same congruence also proves opposite angles are congruent: โˆ Bโ‰…โˆ D\angle B \cong \angle D follows from CPCTC. Drawing the other diagonal proves โˆ Aโ‰…โˆ C\angle A \cong \angle C.

Theorem: Diagonals of a parallelogram bisect each other.

  1. Draw both diagonals ACโ€พ\overline{AC} and BDโ€พ\overline{BD}, intersecting at point MM.
  2. In โ–ณABM\triangle ABM and โ–ณCDM\triangle CDM: we already know AB=CDAB = CD (opposite sides). The alternate interior angles give us โˆ ABMโ‰…โˆ CDM\angle ABM \cong \angle CDM and โˆ BAMโ‰…โˆ DCM\angle BAM \cong \angle DCM.
  3. By ASA, โ–ณABMโ‰…โ–ณCDM\triangle ABM \cong \triangle CDM. So AM=CMAM = CM and BM=DMBM = DM by CPCTC.
Properties of parallelograms, trigonometry - parallelogram diagonals in a relationship with basic geometry - Mathematics Stack ...

Applying Parallelogram Properties

These properties let you set up equations to find unknown measurements. Here are the main strategies:

Finding side lengths: If you know one side, the opposite side is equal. If AB=5AB = 5 cm, then CD=5CD = 5 cm. If a side is given as an expression, set opposite sides equal and solve.

Example: In parallelogram PQRSPQRS, PQ=3x+2PQ = 3x + 2 and SR=5xโˆ’6SR = 5x - 6. Since opposite sides are congruent:

3x+2=5xโˆ’63x + 2 = 5x - 6

8=2x8 = 2x x=4x = 4, so PQ=SR=14PQ = SR = 14

Finding angle measures: If you know one angle, the opposite angle is equal, and each consecutive angle is its supplement. If โˆ A=70ยฐ\angle A = 70ยฐ, then โˆ C=70ยฐ\angle C = 70ยฐ and โˆ B=โˆ D=110ยฐ\angle B = \angle D = 110ยฐ. So knowing just one angle determines all four.

Example: In parallelogram ABCDABCD, โˆ A=(2x+10)ยฐ\angle A = (2x + 10)ยฐ and โˆ B=(3x)ยฐ\angle B = (3x)ยฐ. Since consecutive angles are supplementary: (2x+10)+3x=180(2x + 10) + 3x = 180 5x+10=1805x + 10 = 180 x=34x = 34, so โˆ A=78ยฐ\angle A = 78ยฐ, โˆ B=102ยฐ\angle B = 102ยฐ, โˆ C=78ยฐ\angle C = 78ยฐ, โˆ D=102ยฐ\angle D = 102ยฐ

Using diagonals: If diagonal ACโ€พ\overline{AC} has total length 12 cm, then AM=MC=6AM = MC = 6 cm. When you're given diagonal segments as expressions, set the two halves equal and solve.

Example: In parallelogram JKLMJKLM, diagonals intersect at NN. If JN=2x+1JN = 2x + 1 and NL=4xโˆ’5NL = 4x - 5, then:

2x+1=4xโˆ’52x + 1 = 4x - 5

6=2x6 = 2x x=3x = 3, so JN=NL=7JN = NL = 7 and the full diagonal JL=14JL = 14

The diagonals create two pairs of congruent triangles (โ–ณABMโ‰…โ–ณCDM\triangle ABM \cong \triangle CDM and โ–ณBCMโ‰…โ–ณDAM\triangle BCM \cong \triangle DAM), which is useful in proofs. Be careful: the four triangles formed are not all congruent to each other unless the parallelogram happens to be a rectangle.

Constructing a Parallelogram

You can construct a parallelogram given any of these sets of information:

  1. Two adjacent side lengths and the included angle
  2. Two adjacent side lengths and a diagonal length
  3. One side and two adjacent angles

Steps for construction (given two sides and the included angle):

  1. Draw side ABโ€พ\overline{AB} with the given length.
  2. At point AA, construct the given angle using a protractor or compass-and-straightedge method.
  3. Along the ray from AA, mark point DD at the second given side length.
  4. From BB, construct a line parallel to ADโ€พ\overline{AD}. You can do this by copying โˆ DAB\angle DAB at point BB on the opposite side of ABโ€พ\overline{AB}, or by setting your compass to length ADAD and drawing an arc from BB.
  5. From DD, set your compass to length ABAB and draw an arc that intersects the line from step 4. Label this intersection CC.
  6. Connect DD to CC to complete the parallelogram.
  7. Verify your result: check that opposite sides are congruent and diagonals bisect each other.