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2.3 Techniques for evaluating limits

Updated March 2026Fiveable Content Team
Fiveable

Differential Calculus Unit 2 Review

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2.3 Techniques for evaluating limits

Limits are the foundation of calculus, allowing us to understand function behavior near specific points. They're crucial for defining derivatives and continuity, which we'll explore later in the course.

Evaluating limits involves various techniques, from direct substitution to algebraic manipulation and trigonometric identities. Mastering these methods is essential for solving complex limit problems and understanding function behavior.

Evaluating Limits

Direct substitution for limits

  • Simplest method for finding limits substitutes limiting value directly into function
  • Works when function is continuous at limiting value meaning limit equals function value at that point (polynomial functions)
  • Fails when function is undefined or indeterminate at limiting value resulting in forms like 00\frac{0}{0}, \frac{\infty}{\infty}, 00 \cdot \infty, \infty - \infty, 000^0, 11^\infty, 0\infty^0
Direct substitution for limits, Graphing Polynomial Functions | College Algebra

Algebraic techniques in limit simplification

  • Factoring simplifies rational functions and cancels common factors eliminating indeterminate forms like 00\frac{0}{0} (factoring x21x1\frac{x^2-1}{x-1} to (x+1)(x1)x1\frac{(x+1)(x-1)}{x-1})
  • Rationalization simplifies limits with roots by multiplying numerator and denominator by conjugate of denominator eliminating 00\frac{0}{0} or \frac{\infty}{\infty} (rationalizing x1x1\frac{\sqrt{x}-1}{x-1} to x1x1x+1x+1\frac{\sqrt{x}-1}{x-1} \cdot \frac{\sqrt{x}+1}{\sqrt{x}+1})
  • Multiplying by cleverly chosen form of 1 like xx\frac{x}{x}, xnxn\frac{x^n}{x^n}, exex\frac{e^x}{e^x}, lnxlnx\frac{\ln x}{\ln x} reveals limit when direct substitution fails
Direct substitution for limits, Indeterminate form - Wikipedia, the free encyclopedia

Trigonometric identities in limit evaluation

  • Trigonometric identities simplify limits with trigonometric functions using sin2x+cos2x=1\sin^2 x + \cos^2 x = 1, tanx=sinxcosx\tan x = \frac{\sin x}{\cos x}, secx=1cosx\sec x = \frac{1}{\cos x}
  • Squeeze theorem finds limits of trigonometric functions bounded by simpler functions with equal limits (sinx\sin x squeezed between xx and tanx\tan x as x0x \to 0)
  • Special trigonometric limits:
    • limx0sinxx=1\lim_{x \to 0} \frac{\sin x}{x} = 1
    • limx01cosxx=0\lim_{x \to 0} \frac{1 - \cos x}{x} = 0
    • limx01cosxx2=12\lim_{x \to 0} \frac{1 - \cos x}{x^2} = \frac{1}{2}

Sandwich theorem for bounded functions

  • Squeeze Theorem states if f(x)g(x)h(x)f(x) \leq g(x) \leq h(x) near aa and limxaf(x)=limxah(x)=L\lim_{x \to a} f(x) = \lim_{x \to a} h(x) = L, then limxag(x)=L\lim_{x \to a} g(x) = L
  • To apply:
    1. Find simpler bounding functions f(x)f(x) and h(x)h(x) near limiting value
    2. Evaluate limits of f(x)f(x) and h(x)h(x)
    3. If bounding limits are equal, squeezed limit exists and equals same value
  • Useful for limits involving absolute values, trigonometric functions, or complex expressions (sinx|\sin x| squeezed between 00 and x|x| as x0x \to 0)