Fiveable

โˆฌDifferential Calculus Unit 3 Review

QR code for Differential Calculus practice questions

3.3 Intermediate Value Theorem

3.3 Intermediate Value Theorem

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
โˆฌDifferential Calculus
Unit & Topic Study Guides

The Intermediate Value Theorem is a powerful tool in calculus, guaranteeing that continuous functions take on all values between their endpoints. It's like a bridge connecting the dots of a function, ensuring no gaps or jumps exist.

This theorem helps us prove the existence of solutions to equations and approximate roots. It's super useful in real-world applications, from finding equilibrium prices in economics to predicting object collisions in physics.

The Intermediate Value Theorem

Intermediate Value Theorem statement

  • States if a function ff is continuous on a closed interval [a,b][a, b] and f(a)โ‰ f(b)f(a) \neq f(b), then for any value yy between f(a)f(a) and f(b)f(b), there exists a value cc in the open interval (a,b)(a, b) such that f(c)=yf(c) = y
  • Intuitively means a continuous function takes on all values between its endpoints without any gaps or jumps
  • Applies to real-valued functions that are continuous on a closed interval
  • Examples:
    • If a continuous function has values of -1 and 5 at the endpoints of [0,2][0, 2], it must also take on the values 0, 1, 2, 3, and 4 somewhere within the interval
    • The function f(x)=x3โˆ’xf(x) = x^3 - x on the interval [โˆ’1,1][-1, 1] satisfies the conditions of the IVT
Intermediate Value Theorem statement, Continuity ยท Calculus

Proving equation solutions

  • To prove an equation f(x)=yf(x) = y has a solution using the IVT:
    • Identify an interval [a,b][a, b] where the function ff is continuous
    • Verify that f(a)f(a) and f(b)f(b) lie on opposite sides of the target value yy
      • Either f(a)<y<f(b)f(a) < y < f(b) or f(b)<y<f(a)f(b) < y < f(a)
    • The IVT guarantees the existence of a value cโˆˆ(a,b)c \in (a, b) such that f(c)=yf(c) = y, proving the equation has at least one solution
  • Examples:
    • To show x3โˆ’xโˆ’1=0x^3 - x - 1 = 0 has a solution between 1 and 2, note f(1)=โˆ’1<0f(1) = -1 < 0 and f(2)=5>0f(2) = 5 > 0
    • Proving sinโก(x)=0.5\sin(x) = 0.5 has a solution on [0,ฯ€][0, \pi] since sinโก(0)=0<0.5<1=sinโก(ฯ€/2)\sin(0) = 0 < 0.5 < 1 = \sin(\pi/2)
Intermediate Value Theorem statement, Intermediate value theorem - Wikipedia

Root approximation with IVT

  • To approximate a root of a continuous function ff on an interval [a,b][a, b]:
    • Confirm f(a)f(a) and f(b)f(b) have opposite signs, ensuring the existence of a root by the IVT
    • Bisect the interval at the midpoint m=a+b2m = \frac{a + b}{2} and evaluate f(m)f(m)
      • If f(m)=0f(m) = 0, then mm is the exact root
      • If f(m)f(m) has the same sign as f(a)f(a), the root lies in the right half-interval [m,b][m, b]
      • If f(m)f(m) has the same sign as f(b)f(b), the root lies in the left half-interval [a,m][a, m]
    • Iteratively repeat the bisection process with the new, smaller interval until the desired precision is achieved
  • This method is known as the bisection method or binary search
  • Examples:
    • Approximating a root of f(x)=x2โˆ’2f(x) = x^2 - 2 on [1,2][1, 2] since f(1)<0f(1) < 0 and f(2)>0f(2) > 0
    • Finding a solution to cosโก(x)=x\cos(x) = x on [0,1][0, 1] as cosโก(0)>0\cos(0) > 0 and cosโก(1)<1\cos(1) < 1

Applications of Intermediate Value Theorem

  • The IVT has numerous real-world applications in fields such as physics, engineering, and economics, where continuous functions model various phenomena
    • Proving the existence of solutions to equations describing physical systems
      • Demonstrating the existence of a time when a projectile reaches a specific height
      • Showing two objects must collide or meet at some point in time
    • Approximating zeros or roots of continuous functions representing physical quantities
      • Finding the equilibrium price that balances supply and demand in a market
      • Locating the neutral buoyancy depth of a submarine
  • Steps to solve application problems using the IVT:
    1. Recognize the continuous function ff and the target value yy in the context of the problem
    2. Establish a closed interval [a,b][a, b] where ff is continuous and f(a)f(a) and f(b)f(b) fall on opposite sides of yy
    3. Conclude the existence of a solution or approximate the solution using the bisection method
  • Examples:
    • A ball thrown upward must reach a height of 5 meters at some point if its initial height is 0 meters and its peak height is 10 meters
    • The temperature in a room must equal the thermostat setting at some point if the room starts cooler than the setting and later becomes warmer than the setting