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Differential Calculus Unit 2 Review

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2.2 One-sided limits and limit laws

2.2 One-sided limits and limit laws

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
Differential Calculus
Unit & Topic Study Guides

Limits help us understand how functions behave near specific points. One-sided limits focus on approaching from the left or right, while limit laws and theorems provide tools for evaluating complex limits.

These concepts are crucial for grasping function behavior and continuity. By mastering limits, you'll be better equipped to tackle more advanced calculus topics like derivatives and integrals.

One-Sided Limits

Left-hand vs right-hand limits

  • Left-hand limit limxaf(x)\lim_{x \to a^-} f(x) considers function values as xx approaches aa from the left (smaller values)
  • Right-hand limit limxa+f(x)\lim_{x \to a^+} f(x) considers function values as xx approaches aa from the right (larger values)
  • Limit exists only if both left-hand and right-hand limits exist and are equal (limxaf(x)=limxa+f(x)\lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x))
    • Example: f(x)=xf(x) = |x| at x=0x = 0, left-hand limit is 0, right-hand limit is 0, so the limit exists and equals 0
    • Example: f(x)=1xf(x) = \frac{1}{x} at x=0x = 0, left-hand limit is -\infty, right-hand limit is ++\infty, so the limit does not exist
Left-hand vs right-hand limits, Finding Limits: Numerical and Graphical Approaches · Precalculus

Evaluation of one-sided limits

  • Tables: Create a table with xx values approaching the point from left and right, observe function value trends
    • Example: f(x)=x21x1f(x) = \frac{x^2 - 1}{x - 1} at x=1x = 1, table shows left-hand and right-hand limits both approach 2
  • Graphs: Visually inspect the graph near the point, determine yy-values the function approaches from left and right
    • Example: f(x)={x2x<0xx0f(x) = \begin{cases} x^2 & x < 0 \\ x & x \geq 0 \end{cases} at x=0x = 0, graph shows left-hand limit is 0 and right-hand limit is 0
  • Algebraic manipulation: Simplify the function, factor and cancel terms, substitute the point to evaluate the limit
    • Example: limx2x24x2=limx2(x+2)=4\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = \lim_{x \to 2} (x + 2) = 4, factoring and canceling (x2)(x - 2) allows direct substitution
Left-hand vs right-hand limits, Finding Limits: Numerical and Graphical Approaches | Precalculus

Limit Laws and Theorems

Limit laws for function operations

  • Sum rule: limxa[f(x)+g(x)]=limxaf(x)+limxag(x)\lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x)
  • Difference rule: limxa[f(x)g(x)]=limxaf(x)limxag(x)\lim_{x \to a} [f(x) - g(x)] = \lim_{x \to a} f(x) - \lim_{x \to a} g(x)
  • Product rule: limxa[f(x)g(x)]=limxaf(x)limxag(x)\lim_{x \to a} [f(x) \cdot g(x)] = \lim_{x \to a} f(x) \cdot \lim_{x \to a} g(x)
  • Quotient rule: limxaf(x)g(x)=limxaf(x)limxag(x)\lim_{x \to a} \frac{f(x)}{g(x)} = \frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)}, provided limxag(x)0\lim_{x \to a} g(x) \neq 0
  • Constant multiple rule: limxa[cf(x)]=climxaf(x)\lim_{x \to a} [c \cdot f(x)] = c \cdot \lim_{x \to a} f(x), where cc is a constant
  • Power rule: limxa[f(x)]n=[limxaf(x)]n\lim_{x \to a} [f(x)]^n = [\lim_{x \to a} f(x)]^n, where nn is a constant
    • Example: limx2(3x2+2x1)=3limx2x2+2limx2xlimx21=34+221=15\lim_{x \to 2} (3x^2 + 2x - 1) = 3 \cdot \lim_{x \to 2} x^2 + 2 \cdot \lim_{x \to 2} x - \lim_{x \to 2} 1 = 3 \cdot 4 + 2 \cdot 2 - 1 = 15

Theorems for limit evaluation

  • Squeeze Theorem (Sandwich Theorem): If f(x)g(x)h(x)f(x) \leq g(x) \leq h(x) near aa (except possibly at aa) and limxaf(x)=limxah(x)=L\lim_{x \to a} f(x) = \lim_{x \to a} h(x) = L, then limxag(x)=L\lim_{x \to a} g(x) = L
    • Useful for finding limits of functions "squeezed" between two other functions with known limits
    • Example: 0sinxx10 \leq \frac{\sin x}{x} \leq 1 for x>0x > 0, and limx0+0=limx0+1=0\lim_{x \to 0^+} 0 = \lim_{x \to 0^+} 1 = 0, so limx0+sinxx=0\lim_{x \to 0^+} \frac{\sin x}{x} = 0
  • Limit Comparison Test: Compares the behavior of two functions near a point
    1. If limxaf(x)g(x)=L\lim_{x \to a} \frac{f(x)}{g(x)} = L, where LL is a finite positive number, then limxaf(x)\lim_{x \to a} f(x) and limxag(x)\lim_{x \to a} g(x) either both exist or both diverge
    2. If limxaf(x)g(x)=0\lim_{x \to a} \frac{f(x)}{g(x)} = 0 and limxag(x)\lim_{x \to a} g(x) exists, then limxaf(x)=0\lim_{x \to a} f(x) = 0
    • Example: To find limx2x+13x2\lim_{x \to \infty} \frac{2x + 1}{3x - 2}, compare with limx1x\lim_{x \to \infty} \frac{1}{x}. Since limx2x+13x21x=23\lim_{x \to \infty} \frac{\frac{2x + 1}{3x - 2}}{\frac{1}{x}} = \frac{2}{3}, both limits exist, and limx2x+13x2=23\lim_{x \to \infty} \frac{2x + 1}{3x - 2} = \frac{2}{3}