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โˆฌDifferential Calculus Unit 2 Review

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2.2 One-sided limits and limit laws

2.2 One-sided limits and limit laws

Written by the Fiveable Content Team โ€ข Last updated August 2025
Written by the Fiveable Content Team โ€ข Last updated August 2025
โˆฌDifferential Calculus
Unit & Topic Study Guides

Product, Quotient Rules & Higher-Order Derivatives

Limits help us understand how functions behave near specific points. One-sided limits focus on approaching from the left or right, while limit laws and theorems provide tools for evaluating complex limits.

These concepts are crucial for grasping function behavior and continuity. By mastering limits, you'll be better equipped to tackle more advanced calculus topics like derivatives and integrals.

One-Sided Limits

Left-hand vs right-hand limits

  • Left-hand limit limโกxโ†’aโˆ’f(x)\lim_{x \to a^-} f(x) considers function values as xx approaches aa from the left (smaller values)
  • Right-hand limit limโกxโ†’a+f(x)\lim_{x \to a^+} f(x) considers function values as xx approaches aa from the right (larger values)
  • Limit exists only if both left-hand and right-hand limits exist and are equal (limโกxโ†’aโˆ’f(x)=limโกxโ†’a+f(x)\lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x))
    • Example: f(x)=โˆฃxโˆฃf(x) = |x| at x=0x = 0, left-hand limit is 0, right-hand limit is 0, so the limit exists and equals 0
    • Example: f(x)=1xf(x) = \frac{1}{x} at x=0x = 0, left-hand limit is โˆ’โˆž-\infty, right-hand limit is +โˆž+\infty, so the limit does not exist
Left-hand vs right-hand limits, Finding Limits: Numerical and Graphical Approaches ยท Precalculus

Evaluation of one-sided limits

  • Tables: Create a table with xx values approaching the point from left and right, observe function value trends
    • Example: f(x)=x2โˆ’1xโˆ’1f(x) = \frac{x^2 - 1}{x - 1} at x=1x = 1, table shows left-hand and right-hand limits both approach 2
  • Graphs: Visually inspect the graph near the point, determine yy-values the function approaches from left and right
    • Example: f(x)={x2x<0xxโ‰ฅ0f(x) = \begin{cases} x^2 & x < 0 \\ x & x \geq 0 \end{cases} at x=0x = 0, graph shows left-hand limit is 0 and right-hand limit is 0
  • Algebraic manipulation: Simplify the function, factor and cancel terms, substitute the point to evaluate the limit
    • Example: limโกxโ†’2x2โˆ’4xโˆ’2=limโกxโ†’2(x+2)=4\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = \lim_{x \to 2} (x + 2) = 4, factoring and canceling (xโˆ’2)(x - 2) allows direct substitution
Left-hand vs right-hand limits, Finding Limits: Numerical and Graphical Approaches | Precalculus

Limit Laws and Theorems

Limit laws for function operations

  • Sum rule: limโกxโ†’a[f(x)+g(x)]=limโกxโ†’af(x)+limโกxโ†’ag(x)\lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x)
  • Difference rule: limโกxโ†’a[f(x)โˆ’g(x)]=limโกxโ†’af(x)โˆ’limโกxโ†’ag(x)\lim_{x \to a} [f(x) - g(x)] = \lim_{x \to a} f(x) - \lim_{x \to a} g(x)
  • Product rule: limโกxโ†’a[f(x)โ‹…g(x)]=limโกxโ†’af(x)โ‹…limโกxโ†’ag(x)\lim_{x \to a} [f(x) \cdot g(x)] = \lim_{x \to a} f(x) \cdot \lim_{x \to a} g(x)
  • Quotient rule: limโกxโ†’af(x)g(x)=limโกxโ†’af(x)limโกxโ†’ag(x)\lim_{x \to a} \frac{f(x)}{g(x)} = \frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)}, provided limโกxโ†’ag(x)โ‰ 0\lim_{x \to a} g(x) \neq 0
  • Constant multiple rule: limโกxโ†’a[cโ‹…f(x)]=cโ‹…limโกxโ†’af(x)\lim_{x \to a} [c \cdot f(x)] = c \cdot \lim_{x \to a} f(x), where cc is a constant
  • Power rule: limโกxโ†’a[f(x)]n=[limโกxโ†’af(x)]n\lim_{x \to a} [f(x)]^n = [\lim_{x \to a} f(x)]^n, where nn is a constant
    • Example: limโกxโ†’2(3x2+2xโˆ’1)=3โ‹…limโกxโ†’2x2+2โ‹…limโกxโ†’2xโˆ’limโกxโ†’21=3โ‹…4+2โ‹…2โˆ’1=15\lim_{x \to 2} (3x^2 + 2x - 1) = 3 \cdot \lim_{x \to 2} x^2 + 2 \cdot \lim_{x \to 2} x - \lim_{x \to 2} 1 = 3 \cdot 4 + 2 \cdot 2 - 1 = 15

Theorems for limit evaluation

  • Squeeze Theorem (Sandwich Theorem): If f(x)โ‰คg(x)โ‰คh(x)f(x) \leq g(x) \leq h(x) near aa (except possibly at aa) and limโกxโ†’af(x)=limโกxโ†’ah(x)=L\lim_{x \to a} f(x) = \lim_{x \to a} h(x) = L, then limโกxโ†’ag(x)=L\lim_{x \to a} g(x) = L
    • Useful for finding limits of functions "squeezed" between two other functions with known limits
    • Example: 0โ‰คsinโกxxโ‰ค10 \leq \frac{\sin x}{x} \leq 1 for x>0x > 0, and limโกxโ†’0+0=limโกxโ†’0+1=0\lim_{x \to 0^+} 0 = \lim_{x \to 0^+} 1 = 0, so limโกxโ†’0+sinโกxx=0\lim_{x \to 0^+} \frac{\sin x}{x} = 0
  • Limit Comparison Test: Compares the behavior of two functions near a point
    1. If limโกxโ†’af(x)g(x)=L\lim_{x \to a} \frac{f(x)}{g(x)} = L, where LL is a finite positive number, then limโกxโ†’af(x)\lim_{x \to a} f(x) and limโกxโ†’ag(x)\lim_{x \to a} g(x) either both exist or both diverge
    2. If limโกxโ†’af(x)g(x)=0\lim_{x \to a} \frac{f(x)}{g(x)} = 0 and limโกxโ†’ag(x)\lim_{x \to a} g(x) exists, then limโกxโ†’af(x)=0\lim_{x \to a} f(x) = 0
    • Example: To find limโกxโ†’โˆž2x+13xโˆ’2\lim_{x \to \infty} \frac{2x + 1}{3x - 2}, compare with limโกxโ†’โˆž1x\lim_{x \to \infty} \frac{1}{x}. Since limโกxโ†’โˆž2x+13xโˆ’21x=23\lim_{x \to \infty} \frac{\frac{2x + 1}{3x - 2}}{\frac{1}{x}} = \frac{2}{3}, both limits exist, and limโกxโ†’โˆž2x+13xโˆ’2=23\lim_{x \to \infty} \frac{2x + 1}{3x - 2} = \frac{2}{3}
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