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AP Physics 2 Unit 14 Review: Waves, Sound, and Physical Optics

Review AP Physics 2 Unit 14 to build a complete picture of how waves carry energy, interact at boundaries, interfere, diffract, and produce observable patterns in light and sound. This unit covers everything from basic wave properties and the electromagnetic spectrum to thin-film interference and diffraction gratings.

Use the topic guides, key terms, and practice questions available for this unit to work through all nine topics before exam day.

What is AP Physics 2 unit 14?

Unit 14 is the wave and optics unit of AP Physics 2. It builds from the basic idea that waves transfer energy without transferring matter, then develops the tools needed to analyze how waves behave at boundaries, how they interfere constructively and destructively, and how those interference effects produce the bright and dark patterns seen in diffraction and thin-film problems.

Unit 14 covers wave properties, periodic waves, boundary behavior, polarization, electromagnetic waves, the Doppler effect, interference, standing waves, single-slit diffraction, double-slit interference, diffraction gratings, and thin-film interference. It accounts for 12-15% of the AP Physics 2 exam.

Wave fundamentals

Waves transfer energy without transferring matter. Mechanical waves need a medium; electromagnetic waves do not. Key quantities are amplitude, wavelength, frequency, period, and wave speed, connected by v = f lambda and T = 1/f. Transverse and longitudinal waves differ in the direction of the disturbance relative to propagation.

Interference and diffraction

When waves overlap, superposition determines the net displacement. Constructive interference occurs when path length difference equals m lambda; destructive when it equals (m + 1/2) lambda. Single-slit dark fringes follow a sin theta = m lambda. Double-slit bright fringes follow d sin theta = m lambda. Standing waves form when waves reflect and overlap in a confined region.

Thin-film interference

Light reflecting off the two surfaces of a thin film interferes based on film thickness t, index of refraction n, and phase shifts at each boundary. A 180-degree phase shift occurs when reflecting from a medium with a higher index. The optical path difference is 2nt, and whether that produces constructive or destructive interference depends on how many phase inversions occur.

Light as a wave explains observable patterns

The central thread of Unit 14 is that treating light and sound as waves with well-defined wavelength and frequency explains a wide range of phenomena: why soap bubbles show color, why a siren changes pitch as it passes, why a narrow slit produces a spread-out pattern of bright and dark bands, and why antireflection coatings work. Every major topic in the unit is an application of wave superposition and the conditions for constructive or destructive interference.

AP Physics 2 unit 14 topics

14.1

Properties of Wave Pulses and Waves

Waves transfer energy without transferring matter. Mechanical waves need a medium; EM waves do not. Wave speed on a string depends on tension and mass per length. Key quantities: amplitude, wavelength, frequency, and wave speed.

open guide
14.2

Periodic Waves

Periodic waves repeat with well-defined period T, frequency f, wavelength lambda, and amplitude A. Core equations: T = 1/f and v = f lambda. Amplitude is independent of frequency; wave energy increases with frequency.

open guide
14.3

Boundary Behavior of Waves and Polarization

At a boundary, waves partially reflect and partially transmit. Reflected waves invert when moving into a slower medium. Frequency is conserved across boundaries. Only transverse waves can be polarized.

open guide
14.4

Electromagnetic Waves

EM waves have perpendicular oscillating E and B fields, require no medium, and all travel at c = 3.00 x 10^8 m/s in vacuum. The EM spectrum runs from radio (longest lambda) to gamma rays (shortest lambda).

open guide
14.5

The Doppler Effect

Relative motion between source and observer shifts the observed frequency. Approaching increases observed frequency; receding decreases it. AP Physics 2 requires qualitative reasoning only, no Doppler formula.

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14.6

Wave Interference and Standing Waves

Superposition adds wave displacements. Constructive interference: path difference = m lambda. Destructive: path difference = (m+1/2) lambda. Standing waves in confined regions produce harmonics with fixed nodes and antinodes.

open guide
14.7

Diffraction

Diffraction is most pronounced when opening width a is close to lambda. Single-slit dark fringes: a sin theta = m lambda. The central bright fringe is the widest. Narrower slits or longer wavelengths widen the pattern.

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14.8

Double-Slit Interference and Diffraction Gratings

Bright fringes from two slits: d sin theta = m lambda. Fringe spacing y = lambda L / d. Diffraction gratings use the same condition but produce sharper maxima and separate wavelengths more effectively.

open guide
14.9

Thin-Film Interference

Interference between light reflected from the top and bottom of a thin film depends on optical path difference 2nt and phase shifts at each boundary. One phase inversion flips the constructive/destructive conditions relative to two or zero inversions.

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practice snapshot

Hardest AP Physics 2 unit 14 topics

This snapshot uses Fiveable practice activity to show where students tend to miss questions and which review moves are worth prioritizing first.

62%average MCQ accuracy

Across 947 multiple-choice practice attempts for this unit.

947MCQ attempts

Practice activity included in this snapshot.

100%average FRQ score

Across 1 scored free-response attempts for this unit.

Hardest topics in unit 14

MCQ miss rate
14.9

Review Thin-Film Interference with attention to how the concept appears in AP-style source and evidence questions.

63%65 tries
14.3

Review Boundary Behavior of Waves and Polarization with attention to how the concept appears in AP-style source and evidence questions.

40%108 tries
14.8

Review Double-Slit Interference and Diffraction Gratings with attention to how the concept appears in AP-style source and evidence questions.

39%88 tries
14.1

Review Properties of Wave Pulses and Waves with attention to how the concept appears in AP-style source and evidence questions.

36%182 tries

Unit 14 review notes

14.1

Wave Properties and Periodic Waves

A wave pulse is a single disturbance; a periodic wave is a continuous, repeating disturbance described by wavelength lambda, frequency f, period T, and amplitude A. Wave speed depends on the medium: for a string, v = sqrt(F_T / (m/L)); for all EM waves in vacuum, c = 3.00 x 10^8 m/s. The fundamental relationships are T = 1/f and v = f lambda. Amplitude is independent of frequency; wave energy increases with frequency.

  • Transverse vs. longitudinal: In transverse waves the disturbance is perpendicular to propagation (strings, EM waves); in longitudinal waves it is parallel (sound, compressions and rarefactions).
  • v = f lambda: Wave speed equals frequency times wavelength. Speed is set by the medium; changing medium changes wavelength but not frequency.
  • T = 1/f: Period and frequency are reciprocals. A 440 Hz sound wave has a period of about 2.27 ms.
  • Amplitude and energy: Amplitude measures maximum displacement from equilibrium. Louder sound has greater pressure amplitude; higher-frequency waves carry more energy.
  • Mechanical vs. EM waves: Mechanical waves (sound, string waves) require a medium. Electromagnetic waves propagate through vacuum at c.
Given a wave with f = 500 Hz traveling at 340 m/s in air, what is its wavelength? (lambda = v/f = 0.68 m)
PropertyMechanical waveElectromagnetic wave
Requires mediumYesNo
ExampleSound in airVisible light
Speed in vacuumN/Ac = 3.00 x 10^8 m/s
Wave typeTransverse or longitudinalTransverse only
14.3

Boundary Behavior and Polarization

When a wave reaches a boundary between two media, it partially reflects and partially transmits. The key rule for reflection inversion: if the wave slows down in the new medium, the reflected wave is inverted (phase shift of 180 degrees); if it speeds up, the reflected wave is not inverted. Frequency never changes at a boundary; wavelength changes because speed changes. Only transverse waves can be polarized; longitudinal waves cannot.

  • Inversion rule: Reflected wave inverts when moving from a faster medium to a slower one (analogous to a fixed-end reflection on a string).
  • Frequency conservation: Frequency is set by the source and does not change when a wave crosses a boundary. Wavelength adjusts via lambda = v/f.
  • Polarization: A polarized transverse wave oscillates in a single plane. Passing unpolarized light through a polarizer reduces intensity by half.
  • Polarization methods: Transverse waves can be polarized by reflection, refraction, or passing through a polarizing filter. Longitudinal waves (sound) cannot be polarized.
A wave on a light string hits a junction with a heavier string. Is the reflected pulse inverted or not? (Inverted, because the wave slows down in the heavier string.)
ScenarioReflected wave inverted?
Wave moves from fast to slow mediumYes
Wave moves from slow to fast mediumNo
Fixed end of stringYes
Free end of stringNo
14.4

Electroma­gnetic Waves

Electromagnetic waves consist of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of propagation, making them transverse waves. They require no medium and all travel at c = 3.00 x 10^8 m/s in vacuum. The EM spectrum is ordered by wavelength from longest to shortest: radio, microwave, infrared, visible (red to violet), ultraviolet, X-ray, gamma ray. Higher frequency means shorter wavelength and more energy per photon.

  • E and B orientation: The electric field E, magnetic field B, and propagation direction k are mutually perpendicular. E and B oscillate in phase.
  • EM spectrum order: Radio (longest lambda) > microwave > infrared > visible > ultraviolet > X-ray > gamma ray (shortest lambda, highest f).
  • Visible light: Within visible light, red has the longest wavelength (~700 nm) and violet the shortest (~400 nm). ROYGBV in decreasing wavelength order.
  • c = f lambda: All EM waves in vacuum satisfy c = f lambda. A 600 nm orange photon has f = c/lambda = 5.0 x 10^14 Hz.
Which EM wave carries more energy per photon: a microwave or an X-ray? (X-ray, because it has higher frequency.)
RegionApproximate wavelength range
Radio> 1 mm
Visible400-700 nm
X-ray0.01-10 nm
Gamma ray< 0.01 nm
14.5

The Doppler Effect

The Doppler effect is the change in observed frequency when a source and observer move relative to each other. AP Physics 2 requires only qualitative reasoning: no Doppler formula calculations. When source and observer approach each other, observed frequency is higher than the rest frequency. When they move apart, observed frequency is lower. If they move together at the same velocity, observed frequency equals rest frequency.

  • Approaching: f_obs > f_rest: Wavefronts bunch together in the direction of approach, so the observer detects more cycles per second. Example: ambulance siren pitch rises as it approaches.
  • Receding: f_obs < f_rest: Wavefronts spread out behind the source, so the observer detects fewer cycles per second. Example: siren pitch drops as the ambulance passes.
  • No relative motion: f_obs = f_rest: If source and observer move at the same velocity in the same direction, no Doppler shift occurs.
  • Applications: Doppler radar measures vehicle speed; medical ultrasound uses Doppler shifts to measure blood flow; astronomical redshift indicates galaxies receding from Earth.
A fire truck moves away from a stationary listener. Is the observed pitch higher, lower, or equal to the emitted frequency? (Lower, because the source is receding.)
Relative motionObserved frequency vs. rest frequency
Source approaches observerHigher
Source recedes from observerLower
Source and observer move togetherEqual
Observer approaches stationary sourceHigher
14.6

Wave Interference and Standing Waves

Superposition states that overlapping waves add their displacements. Constructive interference occurs when path difference = m lambda (waves in phase); destructive when path difference = (m + 1/2) lambda (waves out of phase). Beats arise when two slightly different frequencies interfere: f_beat = |f1 - f2|. Standing waves form when two identical waves travel in opposite directions in a confined region, producing fixed nodes (zero amplitude) and antinodes (maximum amplitude). Only specific wavelengths fit the boundary conditions, giving a harmonic series.

  • Superposition: Net displacement at any point equals the sum of individual wave displacements at that point.
  • Nodes and antinodes: Nodes are points of permanent zero displacement; antinodes are points of maximum displacement. Adjacent nodes are separated by lambda/2.
  • Fixed-fixed string harmonics: f_n = nv / 2L for n = 1, 2, 3, ... The fundamental (n=1) has one antinode; each higher harmonic adds one more.
  • Open-closed pipe harmonics: f_n = nv / 4L for odd n only (1, 3, 5, ...). A closed end is a node; an open end is an antinode.
  • Beats: Two sources at 440 Hz and 444 Hz produce beats at f_beat = 4 Hz, heard as a pulsing amplitude variation.
A string of length 0.80 m has wave speed 320 m/s. What is the fundamental frequency? (f1 = v/2L = 320/(1.6) = 200 Hz)
Boundary typeHarmonic seriesFormula
Fixed-fixed string or open-open pipeAll harmonicsf_n = nv/2L
Open-closed pipeOdd harmonics onlyf_n = nv/4L (odd n)
14.7

Single-Slit Diffraction

Diffraction is the spreading of a wave around edges or through an opening. It is most pronounced when the opening width a is comparable to the wavelength lambda. For single-slit diffraction, dark fringes (minima) occur where a sin theta = m lambda (m = +/-1, +/-2, ...). The central bright fringe is the widest and brightest band; secondary maxima are much dimmer. Using the small-angle approximation, the position of the mth dark fringe on a screen at distance L is y_min = m lambda L / a.

  • Diffraction condition: Spreading is most significant when a is close to lambda. Very large openings produce little diffraction; very small openings spread the wave widely.
  • Single-slit dark fringe: a sin theta = m lambda gives the angles of destructive interference for m = +/-1, +/-2, ...
  • Central maximum width: The central bright fringe spans from the m = -1 to m = +1 dark fringes, making it twice as wide as secondary maxima.
  • Effect of changing a or lambda: Narrower slit (smaller a) or longer wavelength produces a wider diffraction pattern. Wider slit or shorter wavelength narrows the pattern.
Light of wavelength 500 nm passes through a 0.10 mm slit onto a screen 2.0 m away. Where is the first dark fringe? (y = lambda L / a = (500e-9)(2.0)/(0.10e-3) = 0.010 m = 1.0 cm)
14.8

Double-Slit Interference and Diffraction Gratings

In Young's double-slit experiment, two slits separated by distance d produce an interference pattern. Bright fringes occur where d sin theta = m lambda; dark fringes where d sin theta = (m + 1/2) lambda. For small angles, fringe spacing is y = lambda L / d. A diffraction grating has many slits and produces sharper, more widely spaced bright maxima using the same equation d sin theta = m lambda, where d is the grating spacing. Gratings separate wavelengths more effectively than double slits.

  • Path length difference: Delta D = d sin theta. When Delta D = m lambda, waves arrive in phase (bright fringe). When Delta D = (m+1/2) lambda, waves cancel (dark fringe).
  • Fringe spacing: y = lambda L / d for small angles. Larger slit separation d produces more closely spaced fringes; longer lambda spreads them out.
  • Diffraction grating: Many parallel slits with spacing d. Same condition d sin theta = m lambda applies, but maxima are much sharper and brighter than in double-slit patterns.
  • White light through a grating: Different wavelengths diffract at different angles, spreading white light into a spectrum. Longer wavelengths (red) diffract more than shorter ones (violet).
Double slits with d = 0.20 mm are illuminated by 600 nm light. The screen is 1.5 m away. What is the fringe spacing? (y = lambda L / d = (600e-9)(1.5)/(0.20e-3) = 4.5 mm)
FeatureDouble slitDiffraction grating
Number of slits2Hundreds to thousands
Bright fringe sharpnessBroadVery sharp
Condition for maximad sin theta = m lambdad sin theta = m lambda
Best useDemonstrating interferenceSeparating wavelengths precisely
14.9

Thin-Film Interference

Thin-film interference occurs when light reflects off the top and bottom surfaces of a film whose thickness t is comparable to the wavelength of light. The two reflected rays interfere based on: (1) the optical path difference 2nt, where n is the film's index of refraction, and (2) any 180-degree phase shifts at each reflection. A phase shift occurs when reflecting from a medium with a higher index of refraction; no phase shift occurs when reflecting from a lower index. Counting the number of phase inversions determines whether 2nt = m lambda gives constructive or destructive interference.

  • Phase shift rule: Reflection from a higher-n medium causes a 180-degree phase shift. Reflection from a lower-n medium causes no phase shift.
  • Optical path difference: The extra distance traveled by the ray reflecting off the bottom surface is 2nt, where n is the film index and t is the film thickness.
  • One phase inversion (e.g., air-soap-air): Only the top surface reflection inverts. Constructive: 2nt = (m + 1/2) lambda; destructive: 2nt = m lambda.
  • Two phase inversions (e.g., air-film-glass with n_film < n_glass): Both surfaces invert, so inversions cancel. Constructive: 2nt = m lambda; destructive: 2nt = (m + 1/2) lambda.
  • Antireflection coating: A coating with index between air and glass causes one phase inversion. Thickness t = lambda / (4n) produces destructive interference in reflection, minimizing glare.
A soap film (n = 1.33) in air has one phase inversion at the top surface. What minimum thickness gives constructive reflection for 532 nm light? (2nt = lambda/2, so t = lambda/(4n) = 532/(4 x 1.33) = 100 nm)
Phase inversionsConstructive conditionDestructive conditionExample
One (air-film-air)2nt = (m+1/2) lambda2nt = m lambdaSoap bubble
Two (air-film-glass, n_film < n_glass)2nt = m lambda2nt = (m+1/2) lambdaAntireflection coating
Zero (film on lower-n substrate)2nt = m lambda2nt = (m+1/2) lambdaOil on water (rare geometry)

Practice AP Physics 2 unit 14 questions

Try stimulus-based AP practice questions and written prompts after you review the notes.

Example stimulus-based MCQs

open all practice
graph

Stimulus-based practice question

A graph shows the observed frequency of a sound source as a function of time as recorded by a stationary observer. The source moves along a straight road that passes directly by the observer. The source emits sound at a constant rest frequency f₀, indicated by a dashed line on the graph.

Question

Which of the following correctly compares the observed frequency at time t₁ (before the source passes) to the observed frequency at time t₃ (after the source passes), and explains what occurs at time t₂?

f(t₁) > f₀ > f(t₃); at t₂ the source is at the point of closest approach and the observed frequency rapidly shifts from above f₀ to below f₀.

f(t₁) < f₀ < f(t₃); at t₂ the source is at the point of closest approach and the observed frequency rapidly shifts from below f₀ to above f₀.

f(t₁) > f₀ > f(t₃); at t₂ the observed frequency equals zero because the source is moving perpendicular to the observer.

f(t₁) = f(t₃) = f₀; at t₂ the observed frequency is at its maximum because the source is closest to the observer.

diagram

Stimulus-based practice question

A thin film of oil (n = 1.45) floats on water (n = 1.33). The figure shows the cross-section of the film with incident light rays and the two reflected rays labeled R1 and R2. The film thickness is t.

Question

Which of the following correctly describes the phase shifts experienced by rays R1 and R2 at their respective interfaces, and what does this imply about the condition for constructive interference?

R1 undergoes a 180° phase shift; R2 undergoes no phase shift. Constructive interference requires 2t = (m + ½)λ_film.

R1 undergoes no phase shift; R2 undergoes a 180° phase shift. Constructive interference requires 2t = mλ_film.

Both R1 and R2 undergo 180° phase shifts. Constructive interference requires 2t = mλ_film.

Neither R1 nor R2 undergoes a phase shift. Constructive interference requires 2t = (m + ½)λ_film.

Example FRQs

open all FRQs
FRQ

Thin film interference and light wavelength reflection

4. A uniform, transparent soap film of thickness t=450 nmt = 450\ \text{nm} and index of refraction nf=1.33n_f = 1.33 is suspended in air, as shown in Figure 1. Monochromatic light in air is incident normally on the film. The reflected light from the top surface of the film and the reflected light from the bottom surface of the film interfere and determine whether the film appears bright or dark in reflection for a given wavelength. Assume the film is nonabsorbing and that the index of refraction of air is na=1.00n_a = 1.00.

Figure 1. Normal-incidence reflection from a uniform soap film in air showing the two reflected rays (top-surface reflection and bottom-surface reflection after a round trip inside the film).

Figure 1
A.

A student claims that, for the film described, reflected light of wavelength λ1=600 nm\lambda_1 = 600\ \text{nm} in air is more likely to be bright than reflected light of wavelength λ2=450 nm\lambda_2 = 450\ \text{nm} in air.

Indicate whether the student's claim is correct or incorrect. Without manipulating equations, justify your answer by referencing (i) the relative phase changes that occur upon reflection at each boundary and (ii) the relative number of wavelengths that fit into the round-trip path inside the film for each wavelength.

B.

Derive an expression for the wavelengths λbright\lambda_{\text{bright}} in air that produce constructive interference (maximum brightness) in the reflected light for the film described. Express your answer in terms of tt, nfn_f, and an integer mm, and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

C.

Indicate whether the expression you derived in part B is or is not consistent with your answer from part A. Briefly justify your answer by using the functional dependence of λbright\lambda_{\text{bright}} on mm and explaining which of 600 nm600\ \text{nm} or 450 nm450\ \text{nm} is closer to satisfying the constructive-interference condition for the given tt and nfn_f.

FRQ

Double-slit interference patterns and wavelength determination

3. In Experiment 1, a student uses a laser pointer to produce an interference pattern on a screen with a double-slit. The student is asked to design an experiment to determine the wavelength of the laser light and then use that wavelength to predict the appearance of reflected light from a thin soap film.

A.

Describe a procedure for collecting data that would allow the student to determine the wavelength λ\lambda of the laser light using the double-slit apparatus. In your description, include the measurements to be made. Include any steps necessary to reduce experimental uncertainty.

B.

Describe how the collected data could be analyzed to determine λ\lambda. Include references to appropriate equations and to relationships between measured and known quantities.

Figure 1. Double-slit interference setup for measuring laser wavelength

Figure 1

Figure 2. Graph grid for linear plot to determine laser wavelength

Figure 2

Fringe order, m

Distance from central bright fringe to mth bright fringe, y (m)

1

0.0060

2

0.0121

3

0.0181

4

0.0242

5

0.0302

C.

In a set of trials, the student fixes the distance from the slits to the screen at L=2.50 mL = 2.50\ \text{m} and measures the distances yy from the central bright fringe to several bright fringes of order mm. The student records the data in Table 1.

i.

Indicate two quantities, either measured quantities from Table 1 or additional calculated quantities, that could be graphed to produce a straight line that could be used to determine λ\lambda.

Vertical axis: Horizontal axis:

ii.

On Figure 2, create a graph of the quantities indicated in part C(i) that can be used to determine λ\lambda.

Use Table 2 to record the data points or calculated quantities that you will plot.

Clearly label the axes, including units as appropriate.

Plot the points you recorded in Table 2.

iii.

Draw a best-fit line for the data graphed in part C(ii).

D.

Using the best-fit line information provided, calculate the wavelength λ\lambda of the laser light. Then determine whether the reflected light from the soap film is most nearly a maximum (bright) or a minimum (dark). In Experiment 2, the student uses the wavelength determined from Experiment 1 to analyze a thin soap film in air. The film has index of refraction n=1.33n = 1.33 and uniform thickness t=220 nmt = 220\ \text{nm}. Monochromatic laser light is incident nearly perpendicular to the film. The reflected light from the top surface (air to soap) undergoes a phase shift of π\pi, and the reflected light from the bottom surface (soap to air) undergoes no phase shift. Using the best-fit line from part C(iii), the student obtains the slope s=6.04×103 m per fringe orders = 6.04× 10^{-3}\ \text{m per fringe order} for a graph of yy versus mm, and uses d=0.250 mmd = 0.250\ \text{mm} and L=2.50 mL = 2.50\ \text{m}.

FRQ

Wave reflection at fixed and free boundaries

2. A student investigates wave behavior using a ripple tank and a monochromatic laser. A mechanical wave in the ripple tank travels across the surface of water toward boundaries and openings. The student can also shine a laser through an adjustable slit and onto a screen. In a later trial, the student places a thin, transparent soap film directly over the slit opening so the laser light passes through the film immediately after passing through the slit. The laser has vacuum wavelength λ0=532 nm\lambda_0 = 532\ \text{nm}.

Figure 1. Ripple-tank pulse reflection at two boundary types and a laser single-slit setup (with optional soap film over the slit).

Figure 1
A.

A single upward wave pulse on the water surface travels to the right and reaches a boundary.

(i) On Figure 1, consider the rigid wall (fixed end). Draw the reflected pulse on the left side of the wall at an instant just after reflection.

(ii) On Figure 1, consider the flexible absorbing barrier that behaves like a free end for the surface disturbance. Draw the reflected pulse on the left side of the barrier at an instant just after reflection.

In each case, your drawing must indicate the direction of motion of the reflected pulse and the pulse orientation (inverted or not inverted).

Figure 2. Snapshot of a periodic transverse surface wave: displacement versus position, with wavelength and amplitude labeled.

Figure 2
B.

The wave generator produces a periodic wave whose snapshot is shown in Figure 2. The wave speed in the tank is v=0.40 m/sv = 0.40\ \text{m/s}.

Derive an expression for the period TT of the wave in terms of vv and the wavelength λ\lambda, and then determine the numerical value of TT using the data in Figure 2. Begin your derivation by writing a fundamental relationship for periodic waves.

Figure 3. Axes for sketching single-slit diffraction intensity I(y) on a screen; y = 0 at the central maximum.

Figure 3
C.

On the axes in Figure 3, sketch the relative intensity pattern I(y)I(y) on the screen. Then determine the positions y1y_1 of the first minima on both sides of the central maximum. The student uses the laser and slit shown in Figure 1. The slit is uncovered (no soap film). The slit width is a=0.20 mma = 0.20\ \text{mm} and the screen is L=2.0 mL = 2.0\ \text{m} from the slit. The student observes a single-slit diffraction pattern.

Use the small-angle approximation and the single-slit minimum condition. Clearly indicate y=0y = 0 and the locations of the first minima on your sketch.

D.

Indicate whether the light reflected from the top and bottom surfaces of the film produces constructive interference or destructive interference in reflection. The student now places a soap film directly over the slit opening, so the laser light passes through the film immediately after passing through the slit. The film has index of refraction n=1.33n = 1.33 and uniform thickness t=420 nmt = 420\ \text{nm}. The film is surrounded by air on both sides. The laser wavelength in vacuum is λ0=532 nm\lambda_0 = 532\ \text{nm}.

Constructive in reflection
Destructive in reflection

Briefly justify your answer by using the phase changes upon reflection and the path difference through the film. If you use a condition for interference, state it clearly.

Key terms

TermDefinition
mechanical waveA wave that requires a medium in which to propagate, such as sound in air or a wave on a string. Electromagnetic waves do not require a medium.
periodThe time required for one complete oscillation of a wave, related to frequency by T = 1/f.
wavelength-frequency relationshipThe relationship v = f lambda (or c = f lambda for EM waves in vacuum), expressing that wave speed equals frequency times wavelength.
superpositionThe principle that when two or more waves overlap, the net displacement at any point equals the sum of the individual displacements at that point.
fundamental frequencyThe lowest-frequency standing wave mode in a confined region, corresponding to the longest wavelength that fits the boundary conditions.
path length differenceThe difference in distance traveled by two wavefronts, denoted Delta D. Constructive interference occurs when Delta D = m lambda; destructive when Delta D = (m + 1/2) lambda.
central bright fringeThe brightest, widest band at the center of a single-slit diffraction pattern, located at theta = 0 between the first-order dark fringes on each side.
wavefrontA surface connecting all points of equal phase in a wave. Plane waves have flat wavefronts perpendicular to the direction of propagation.
phase shiftA 180-degree change in the phase of a wave that occurs when light reflects from a medium with a higher index of refraction. This affects whether thin-film interference is constructive or destructive.
antireflection coatingA thin film with index of refraction between air and the substrate, designed so that one phase inversion and a film thickness of lambda/(4n) produce destructive interference in reflection, reducing glare.
intensityThe average power transferred per unit area by a wave. Intensity increases with amplitude squared and is reduced when a polarizer transmits only one plane of oscillation.
Fringe separationThe distance between adjacent bright or dark fringes in an interference pattern, given by y = lambda L / d for double-slit setups with small angles.
transmissionThe passage of a wave into a new medium at a boundary. At every boundary, energy is split between the reflected and transmitted waves; frequency is unchanged.

Common unit 14 mistakes

Confusing inversion rules at boundaries

Students often invert the rule: a reflected wave inverts when the wave moves into a slower medium (like a string wave hitting a heavier string or a fixed end), not when it moves into a faster medium. Tie the rule to wave speed, not to which medium is denser in general.

Mixing up single-slit and double-slit equations

For single-slit diffraction, a sin theta = m lambda gives dark fringes (minima). For double-slit interference, d sin theta = m lambda gives bright fringes (maxima). The same form of equation gives opposite results depending on which setup you are analyzing.

Forgetting to count phase inversions in thin-film problems

Whether 2nt = m lambda is constructive or destructive depends entirely on how many 180-degree phase shifts occur. With one inversion, 2nt = m lambda is destructive; with zero or two inversions, it is constructive. Skipping the phase-shift count leads to the wrong answer every time.

Assuming frequency changes when a wave crosses a boundary

Frequency is set by the source and never changes at a boundary. Only wavelength changes because wave speed changes in the new medium. Students who change frequency when changing medium will get incorrect wavelength and speed values.

Applying a Doppler formula when only qualitative reasoning is needed

AP Physics 2 requires only qualitative Doppler analysis. Focus on the direction of relative motion and whether observed frequency is higher or lower than rest frequency. Writing a quantitative formula is not required and can introduce errors if the formula is misremembered.

How this unit shows up on the AP exam

Diagram analysis and wave sketching

AP Physics 2 frequently asks students to interpret or draw wave diagrams: identifying nodes and antinodes in standing waves, sketching reflected pulses with correct inversion, labeling wavelength and amplitude on a sinusoidal wave, or drawing the diffraction pattern expected from a given slit width. Being able to translate between a physical setup and a wave diagram is a core skill tested across multiple topics in this unit.

Quantitative reasoning with interference and diffraction equations

Free-response questions in this unit often require applying d sin theta = m lambda, a sin theta = m lambda, or the thin-film condition 2nt = m lambda (with correct phase-shift analysis) to find fringe positions, film thickness, or wavelength. The small-angle approximation y = m lambda L / d is frequently needed to convert angles to screen positions. Students should be prepared to set up these equations from a diagram description and solve for an unknown.

Qualitative explanation of wave phenomena

Many questions ask students to explain why a phenomenon occurs rather than just calculate a result. Common tasks include explaining why a soap bubble shows color (thin-film interference), why a siren changes pitch (Doppler effect), why a narrower slit produces a wider diffraction pattern, or why only odd harmonics appear in an open-closed pipe. These explanations require connecting the physical setup to the underlying wave principle in clear, precise language.

Final unit 14 review checklist

  • Unit 14 final review checklistUse this list to confirm you can handle every major skill in Unit 14 before the exam.
  • Apply v = f lambda and T = 1/fGiven any two of wave speed, frequency, wavelength, or period, calculate the third. Identify whether a wave is mechanical or electromagnetic and whether it is transverse or longitudinal.
  • Predict boundary behaviorDetermine whether a reflected wave is inverted based on whether the wave speeds up or slows down in the new medium. Explain why frequency is conserved but wavelength changes at a boundary.
  • Reason qualitatively about the Doppler effectExplain whether observed frequency is higher or lower than rest frequency based on the direction of relative motion between source and observer. Apply this to sound, light, and radar examples.
  • Analyze standing waves and harmonicsIdentify nodes and antinodes in a standing wave diagram. Calculate harmonic frequencies for fixed-fixed strings (f_n = nv/2L) and open-closed pipes (f_n = nv/4L, odd n only). Explain why only certain wavelengths fit.
  • Use diffraction and interference equationsApply a sin theta = m lambda for single-slit dark fringes and d sin theta = m lambda for double-slit bright fringes. Use the small-angle approximation y = m lambda L / d or y = m lambda L / a to find fringe positions on a screen.
  • Solve thin-film interference problemsCount phase inversions at each boundary, determine the optical path difference 2nt, and write the correct constructive or destructive condition. Apply this to soap films, oil slicks, and antireflection coatings.

How to study unit 14

Step 1: Build wave vocabulary and equations (14.1-14.2)Read the topic guides for 14.1 and 14.2. Practice calculating wave speed, frequency, wavelength, and period using v = f lambda and T = 1/f. Draw and label a transverse wave identifying amplitude, wavelength, crest, and trough. Distinguish mechanical from electromagnetic waves and transverse from longitudinal.
Step 2: Work through boundary behavior, polarization, and EM waves (14.3-14.4)Use the topic guides for 14.3 and 14.4. Practice the inversion rule by sketching reflected pulses at fixed and free ends. Memorize the EM spectrum order by wavelength. Confirm you can explain why only transverse waves polarize and why frequency is conserved at boundaries.
Step 3: Practice Doppler reasoning and interference (14.5-14.6)Review the topic guides for 14.5 and 14.6. For Doppler, write out the three cases (approaching, receding, same velocity) and connect each to a real example. For interference and standing waves, practice drawing standing wave diagrams for strings and pipes, identifying harmonics, and applying f_n = nv/2L and f_n = nv/4L.
Step 4: Apply diffraction and interference equations (14.7-14.8)Work through the topic guides for 14.7 and 14.8. Practice using a sin theta = m lambda for single-slit minima and d sin theta = m lambda for double-slit maxima. Use the small-angle approximation to find fringe positions. Compare single-slit and double-slit patterns side by side to keep the equations straight.
Step 5: Understand thin-film interference and review the full unit (14.9)Study the topic guide for 14.9. Practice counting phase inversions for different film configurations and writing the correct constructive or destructive condition. Then review all nine topics using the key terms and available practice questions. Use the AP score calculator to estimate your score range and identify which topics need more attention.

More ways to review

Topic study guides

Open the individual guides for Unit 14 when you want a closer review of one topic.

browse guides

FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

practice FRQs

Cheatsheets

Use unit cheatsheets for a quick visual review after you work through the notes.

open cheatsheets

Score calculator

Estimate your broader AP score goal after you review the course and exam format.

open calculator

Frequently Asked Questions

What topics are covered in AP Physics 2 Unit 14?

AP Physics 2 Unit 14 covers waves, sound, and physical optics across 9 topics: Properties of Wave Pulses and Waves, Periodic Waves, Boundary Behavior of Waves and Polarization, Electromagnetic Waves, the Doppler Effect, Wave Interference and Standing Waves, Diffraction, Double-Slit Interference and Diffraction Gratings, and Thin-Film Interference. The unit builds from basic wave properties up through light behavior, so the topics connect tightly. You'll use concepts from early topics (like how waves reflect and transmit at boundaries) to make sense of later ones (like why thin films produce colorful patterns). See the full topic breakdown at /ap-physics-2-revised/unit-14.

How much of the AP Physics 2 exam is Unit 14?

AP Physics 2 Unit 14 makes up 12-15% of the AP exam, making it one of the more heavily tested units. That weight covers waves and their properties, the Doppler effect, interference, diffraction, and physical optics topics like double-slit patterns and thin-film interference. With that kind of exam weight, it's worth spending real time here. A few percentage points of your score can shift your final grade, and the wave concepts in this unit also connect to quantum ideas that appear elsewhere on the exam.

What's on the AP Physics 2 Unit 14 progress check (MCQ and FRQ)?

The AP Physics 2 Unit 14 progress check includes both MCQ and FRQ parts drawn from all 9 topics in the unit, with a focus on waves, the Doppler effect, interference, and diffraction. The MCQ section tests conceptual understanding and quantitative reasoning across topics like periodic waves, boundary behavior, and electromagnetic waves. The FRQ part typically asks you to analyze wave phenomena, explain patterns from double-slit or diffraction grating setups, or reason through thin-film interference scenarios. The progress check is College Board's built-in checkpoint, so it closely mirrors the style and difficulty of actual exam questions. Practicing with questions matched to each topic before you attempt it helps a lot. You can find topic-aligned practice at /ap-physics-2-revised/unit-14.

How do I practice AP Physics 2 Unit 14 FRQs?

To practice AP Physics 2 Unit 14 FRQs, focus on the topics that generate the most free-response questions: wave interference and standing waves, diffraction and double-slit setups, the Doppler effect, and thin-film interference. FRQs in this unit typically ask you to derive or apply a relationship, sketch or interpret a wave pattern, or explain a physical phenomenon using wave principles. The best approach is to write out full solutions, not just circle answers. Show your reasoning for each step, because AP Physics 2 FRQ scoring rewards clear justification. After solving, check whether your explanation connects the math to the physical situation. Topic-specific practice questions are available at /ap-physics-2-revised/unit-14.

Where can I find AP Physics 2 Unit 14 practice questions?

You can find AP Physics 2 Unit 14 practice questions, including multiple-choice and FRQ-style problems, at /ap-physics-2-revised/unit-14. The page organizes practice by topic, so you can target specific areas like the Doppler effect, diffraction, interference, or thin-film interference rather than reviewing everything at once. For MCQ practice, look for questions that test conceptual reasoning about wave behavior alongside quantitative problems. For a practice test experience, work through questions from all 9 topics in sequence to simulate the variety you'll see on the real exam.

How should I study AP Physics 2 Unit 14?

Start AP Physics 2 Unit 14 by building a solid foundation in wave properties before moving to the more complex optics topics. Waves, interference, and diffraction are all connected, so gaps in early topics will slow you down later. Here's a concrete plan: - **Topics 14.1-14.3 first.** Nail wave pulse properties, periodic wave equations, and boundary behavior. These show up everywhere else in the unit. - **Topic 14.5 next.** The Doppler effect has a clean formula and appears often on the exam. Practice applying it to both sound and light scenarios. - **Topics 14.6-14.8 together.** Wave interference, standing waves, diffraction, and double-slit patterns share the same core logic. Study them as a group and sketch diagrams for each setup. - **Topic 14.9 last.** Thin-film interference trips up a lot of students because of the phase-shift rules. Give it extra time and work through several examples. Use the topic pages at /ap-physics-2-revised/unit-14 to practice each section before moving on.

Ready to review Unit 14?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.