Magnetic forces on conductors in magnetic fields are a key concept in electromagnetism. When a conductor moves through a magnetic field or experiences a changing magnetic field, currents are induced. These induced currents then interact with the original magnetic field, creating forces that affect the conductor's motion.
The strength of these forces depends on factors like loop size, magnetic field strength, and relative velocity. Understanding these interactions is crucial for analyzing the motion of conducting loops in magnetic fields and applying Newton's second law to predict their behavior.
Force on conductors in magnetic fields

Magnetic force on induced currents
When conductors move through magnetic fields, induced currents flow through them. These currents then experience forces from the same magnetic fields that created them.
- The magnetic force on a current-carrying conductor can be calculated using:
where:
- is the magnetic force vector
- is the induced current
- is the infinitesimal displacement vector along the conductor
- is the magnetic field vector
- This force follows the right-hand rule: if you point your fingers in the direction of the current and curl them toward the magnetic field, your thumb points in the direction of the force.
- Only portions of the conducting loop within the external magnetic field experience these forces, which can cause:
- Translational acceleration (linear movement)
- Rotational acceleration (spinning motion)
Partial field interactions
The interaction between a conductor and a magnetic field depends on how much of the conductor is within the field. This partial interaction creates interesting dynamics.
- The magnitude of force on a conducting loop depends on:
- The induced current in the loop (determined by the rate of change of magnetic flux)
- The resistance of the loop material (higher resistance means lower current)
- The velocity of the loop relative to the magnetic field (faster movement creates more rapid flux change)
- As a loop enters a magnetic field, the changing flux induces a current that creates a force opposing the entry.
- Similarly, as a loop exits a magnetic field, the changing flux induces a current that creates a force opposing the exit.
This opposition to both entry and exit is a manifestation of Lenz's law, which states that induced effects oppose the cause that created them.
Factors affecting loop force
Several physical characteristics determine how strongly a loop will be affected by magnetic forces.
- Loop geometry matters significantly:
- Larger loops intercept more magnetic field lines, experiencing greater flux changes
- Loops with multiple turns effectively multiply the induced current and resulting force
- The shape of the loop affects how the magnetic field lines intersect it
- The external magnetic field properties directly impact the forces:
- Stronger magnetic fields produce larger induced currents and forces
- Non-uniform magnetic fields create complex force distributions across the loop
- The direction of the field relative to the loop's motion determines the force direction
- The loop's physical properties also play a role:
- Conductivity affects the magnitude of induced current
- The loop's mass determines how much acceleration results from a given force
- Rigidity of the loop affects whether it deforms under magnetic forces
Newton's second law application
To analyze the motion of conducting loops in magnetic fields, we apply Newton's second law to connect forces with resulting motion.
-
The net force on a loop equals its mass times acceleration:
-
This net force includes:
- Magnetic forces from induced currents
- Gravitational force
- Any other external forces (tension, normal forces, etc.)
-
The resulting acceleration can be used with kinematic equations to predict motion:
-
The motion is often complex because:
- The induced current depends on the loop's velocity
- The magnetic force depends on the induced current
- This creates a feedback loop where motion affects force and force affects motion
Practice Problem 1: Conductor Moving Through Magnetic Field
A rectangular conducting loop with width 10 cm, height 5 cm, and mass 20 g moves with a velocity of 2 m/s perpendicular to a uniform magnetic field of 0.5 T. If the loop has a resistance of 0.1 Ω, calculate the magnetic force on the loop as it enters the field.
Solution
First, we need to find the induced current in the loop as it enters the magnetic field.
The rate of change of magnetic flux is:
Where:
- T is the magnetic field strength
- m is the width of the loop
- m/s is the velocity
The induced current is:
The magnetic force on the entering side of the loop is:
This force is directed opposite to the motion of the loop, following Lenz's law.
Practice Problem 2: Acceleration of a Conducting Loop
A square conducting loop with side length 5 cm, resistance 0.2 Ω, and mass 15 g is initially at rest at the edge of a region with a uniform magnetic field of 0.8 T perpendicular to the loop. If the loop is released, what is its initial acceleration?
Solution
To find the initial acceleration, we need to determine the magnetic force on the loop and apply Newton's second law.
When the loop begins to enter the magnetic field, the rate of change of flux is:
Where:
- T is the magnetic field
- m is the side length
- is the initial velocity (which is zero)
Since the initial velocity is zero, the initial rate of change of flux is zero, meaning no current is induced yet.
However, as soon as the loop starts moving due to other forces (like gravity if the setup is vertical), a current will be induced. Let's assume the loop has just started moving at a very small velocity .
The induced current would be:
The magnetic force on the portion of the loop in the field is:
According to Newton's second law:
Therefore:
This gives us:
Since the force opposes the motion (Lenz's law), the loop experiences a damping effect, with acceleration proportional to velocity but in the opposite direction.
Vocabulary
The following words are mentioned explicitly in the College Board Course and Exam Description for this topic.
| Term | Definition |
|---|---|
| electromagnetic waves | Waves consisting of oscillating electric and magnetic fields that propagate through space at a constant speed in free space. |
| Faraday's law | The principle that describes the relationship between a changing magnetic flux and the induced emf in a system, expressed as Δ = -âΊB/ât. |
| induced electric potential difference | The voltage generated in a conductor or circuit due to a change in magnetic flux through it. |
| induced emf | The electromotive force generated in a conductor or circuit as a result of a change in magnetic flux. |
| Lenz's law | The principle that states an induced emf generates a current that creates a magnetic field opposing the change in magnetic flux. |
| magnetic flux | The measure of the total magnetic field passing through a surface, calculated as the dot product of the magnetic field vector and the area vector. |
| Maxwell's equations | A collection of four fundamental equations that fully describe electromagnetism and the behavior of electric and magnetic fields. |
| right-hand rule | A method for determining the direction of the magnetic field produced by a moving charged object by pointing the thumb in the direction of velocity and curling fingers to show the field direction. |
| solenoid | A coil of wire wound in a tight, helical pattern that produces a uniform magnetic field when current flows through it. |
Frequently Asked Questions
What is electromagnetic induction and how does it actually work?
Electromagnetic induction is how a changing magnetic flux through a loop creates an emf (voltage) andâif the loopâs closedâan induced current. Faradayâs law quantifies it: Δ = âdΊB/dt, where ΊB = B·A (or sum for N loops: |Δsol| = N|dΊB/dt|). Flux can change if B changes, the loopâs area or orientation changes, or you move the loop. Lenzâs law (the minus sign) tells the induced currentâs direction: it produces a B-field that opposes the flux changeâuse the right-hand rule to get the current sense. Physically, a changing B induces a nonconservative electric field (MaxwellâFaraday: âźE·dâ = âdΊB/dt), so charges feel an electric force and move (current) or a motional emf appears in moving conductors. Youâll need these ideas and the equations for AP Topic 13.2 (see the study guide: https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW; unit overview: https://library.fiveable.me/ap-physics-c-e-m/unit-13). For extra practice, use the 1000+ problems at (https://library.fiveable.me/practice/ap-physics-c-e-m).
Why does Faraday's law have a negative sign in the equation?
The negative sign in Faradayâs law, đ = âdΊB/dt, encodes Lenzâs law: an induced emf (and any induced current) always acts to oppose the change in magnetic flux that produced it. Physically thatâs required by energy conservationâthe induced current creates its own magnetic field which resists the flux change, so you must do work (or lose energy) to change the flux. Mathematically the minus also comes from the orientation convention: ΊB = â«B·dA uses an area (normal) vector; if ΊB is increasing, the induced electric field around the loop gives a current whose magnetic field points to reduce that increase, so the sign is negative. In Maxwellâs form, âźE·dl = âdΊB/dt, the minus simply relates the direction of the line integral of E to the direction of changing flux (use the right-hand rule to connect current direction and flux). For AP review, focus on Lenzâs law for direction questions and the Faraday/Maxwell equations for quantitative work (see the Topic 13.2 study guide on Fiveable: https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW). For extra practice, use the AP practice problems at https://library.fiveable.me/practice/ap-physics-c-e-m.
I'm confused about magnetic flux - is it just B times A or is there more to it?
Short answer: magnetic flux isnât always just B times Aâitâs the dot product of the magnetic field and the area vector: ΊB = â« B · dA. What that means in practice: - If B is uniform and the surface is flat, ΊB = B A cosΞ (Ξ is the angle between B and the area normal), so B·A reduces to B·A only when B is perpendicular (cosΞ = 1). - If B varies over the surface or the surface is curved, you must integrate: ΊB = â« B·dA. - For N turns, flux linkage is NΊB, and Faradayâs law gives emf: Δ = âdΊB/dt (and Lenzâs law sets the sign/direction). This is exactly what the CED covers for Topic 13.2 (Faradayâs law, area vector, flux linkage). For worked examples and practice problems, see the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW), the unit overview (https://library.fiveable.me/ap-physics-c-e-m/unit-13), and lots of practice sets (https://library.fiveable.me/practice/ap-physics-c-e-m).
What's the difference between Faraday's law and Lenz's law?
Faradayâs law gives you the math: a changing magnetic flux through a loop produces an emf. Symbolically E = âdΊB/dt (or â° = âd( B·A )/dt), and you use it to calculate the magnitude of the induced emf (including N loops for a solenoid). Lenzâs law tells you the direction: the minus sign in Faradayâs law means the induced current produces a magnetic field that opposes the change in flux. Practically, use Faraday to get |â°| and Lenz (with the right-hand rule) to pick the currentâs direction so the induced B-field fights the flux change. On the AP exam youâll be asked to compute magnitudes (13.2.A.1) and justify directions (13.2.A.2)âso show the derivative for â° and state how the induced field opposes the change. For a quick review, see the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and practice problems (https://library.fiveable.me/practice/ap-physics-c-e-m).
How do I use the right-hand rule for electromagnetic induction problems?
Right-hand rule for induction is just a tool to apply Lenzâs law (CED 13.2.A.2): the induced current makes a magnetic field that opposes the change in magnetic flux (Faradayâs law 13.2.A.1). Quick steps you can use on every problem: 1. Decide how the magnetic flux through the loop is changing (is B getting bigger/smaller, or is area/orientation changing?). 2. Use Lenzâs law: if flux into page is increasing, the induced B must point out of the page; if flux into page is decreasing, induced B must point into the page. 3. Use the right-hand rule for loops: point your thumb in the direction of the induced B (the field the induced current must create). Curl your fingersâthe finger curl shows the direction of induced current (clockwise or counterclockwise). 4. If asked for emf sign or magnitude, use Faraday: E = âdΊB/dt (and for N turns multiply by N). Example: B into the page and increasing â induced B out â thumb out of page â fingers curl counterclockwise â induced current is CCW. This exactly matches CED skills for Topic 13.2. For more worked examples and practice problems, check the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and the general unit page (https://library.fiveable.me/ap-physics-c-e-m/unit-13).
Can someone explain Lenz's law in simple terms - why does the induced current oppose the change?
Lenzâs law says the induced emf (and any induced current) always acts to oppose the change in magnetic flux that produced it. Think of it like a âreactionâ: if the magnetic flux through a loop tries to increase, the induced current creates its own magnetic field that points the opposite way to reduce that increase; if flux tries to decrease, the induced field boosts it. Mathematically Faradayâs law shows this: Δ = âdΊB/dtâthe minus sign is Lenzâs law built in. Use the right-hand rule to get the induced field direction from the current direction (and the right-hand curl to find current given an induced B). Physically this arises from conservation of energy: the induced current resists change so you must do work to change the flux (that work becomes Joule heat or stored energy). For AP E&M, practice applying Faradayâs law + Lenzâs sign rule and the right-hand rule (see the Topic 13.2 study guide on Fiveable (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and try practice problems at (https://library.fiveable.me/practice/ap-physics-c-e-m)).
When do I use the solenoid equation versus the regular Faraday's law equation?
Use Faradayâs law (general form) any time you need the induced emf from a changing magnetic flux: E = âdΊB/dt = âd(B·A)/dt (or the loop integral form E = âźE·dâ = âdΊB/dt). That covers cases where B changes, A changes (motional emf), the loop rotates, or the shape/orientation matters (CED 13.2.A.1 and 13.2.A.1.iâii). Use the âsolenoid equationâ (emf for a long solenoid with N turns) when the changing flux comes from many identical loops stacked into a long solenoidâthen total emf = N·(emf per loop) = âN dΊB/dt (CED 13.2.A.1.iii). Practically: if you have a long solenoid with n turns per length and a small coil/loop inside it, substitute Binside = ÎŒ0 n I and multiply flux by the number of turns (or use N when youâre given total turns). If youâre unsure on the exam, start with Faradayâs law and then include N (or n and loop area) when the problem states multiple turns/solenoid (see the Topic 13.2 study guide for worked examples: https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW). For extra practice, try AP-style problems at (https://library.fiveable.me/practice/ap-physics-c-e-m).
How does changing the area of a loop create an induced emf if the magnetic field stays constant?
Magnetic flux is ΊB = B · A (more precisely B·A·cosΞ). If B is constant but the loopâs area A changes, ΊB still changes because ΊB depends on A. By Faradayâs law, an emf is induced whenever dΊB/dt â 0: Δ = âdΊB/dt = âB (dA/dt) (if B and the loopâs orientation are constant). So changing the loopâs size (sliding part of the loop, stretching it, or pulling it out of a uniform-B region) changes A over time, gives a nonzero dA/dt, and produces an emf. Lenzâs law then tells you the induced currentâs direction: it will create a magnetic field that opposes the change in flux (i.e., opposes the increase or decrease of ΊB). This is exactly what the CED expects you to use (Faradayâs law 13.2.A.1 and Lenzâs law 13.2.A.2). For a quick review and practice problems on this topic, see the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and the AP practice question bank (https://library.fiveable.me/practice/ap-physics-c-e-m).
What happens when both the magnetic field and the area are changing at the same time?
Use Faradayâs law: emf = âdΊB/dt = âd( B · A )/dt. If both the magnetic field and the area (or orientation) are changing, the total induced emf is the sum of the contributions from each change: emf = â[ A (dB/dt) + B (dA/dt) ] (for B and A perpendicular; more generally use the dot product and take its time derivative). If you have N loops, multiply that result by N (flux linkage). Direction: use Lenzâs lawâthe induced current produces a magnetic field that opposes the net change of flux (i.e., opposes the combined effect of dB/dt and dA/dt). For AP-style problems, set up ΊB(t) explicitly, differentiate, and use signs to get direction. For practice and worked examples, see the Topic 13.2 study guide on Fiveable (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and more practice at (https://library.fiveable.me/practice/ap-physics-c-e-m).
Why do we need to know about Maxwell's equations for AP Physics C?
You need Maxwellâs equations in AP Physics C because theyâre the compact set of laws that explain everything you study in Topic 13.2: Faradayâs law (Maxwellâs third equation) is exactly the statement that a changing magnetic flux produces an induced emf (E = âźE·dâ = âdΊB/dt). Knowing Maxwellâs equations ties Faradayâs law to Lenzâs law, motional emf, and how induced electric fields behave in circuits and solenoidsâall tested on the exam. They also show (conceptually) that E and B fields satisfy wave equations and predict the constant speed c = 1/â(Δ0ÎŒ0) in free space (you donât have to derive that on the AP). For targeted review, see the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and practice problems at (https://library.fiveable.me/practice/ap-physics-c-e-m) to drill Faraday/Lenz setups and induced-emf calculations.
How do I tell which direction the induced current flows in a circuit?
Quick checklist you can use on any problem: 1) Identify how magnetic flux is changing (is B getting stronger/weaker, into or out of the page? or is the loop area changing?). Use ΊB = B·A and Faradayâs law (Δ = âdΊB/dt) to tell if the induced emf is nonzero. 2) Use Lenzâs law: the induced magnetic field from the induced current will oppose the change in flux. If flux into the page is increasing, the induced B must come out of the page; if flux out is decreasing, the induced B must come out to replace it, etc. (That minus sign in Faradayâs law encodes Lenzâs law.) 3) Use the right-hand rule to get current direction: point your thumb in the induced-B direction, your curled fingers show the direction of induced current (counterclockwise vs clockwise as seen from your viewpoint). Practice this sequence on a few diagramsâthe AP C exam expects you to use Lenzâs law + the right-hand rule (Topic 13.2). For more worked examples, see the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and try practice problems at (https://library.fiveable.me/practice/ap-physics-c-e-m).
What's the connection between electromagnetic induction and how generators work?
Generators are just real-world applications of Faradayâs law and Lenzâs law. Faraday: E = âdΊB/dt, so any device that makes the magnetic flux through a coil change will produce an induced emf. In a typical AC generator a loop (or many turns, N) rotates in a (nearly) constant B-field, so ΊB = B A cosΞ and Ξ = Ït. That gives an emf E(t) = N B A Ï sin(Ït)âan alternating voltage whose frequency is f = Ï/2Ï. Lenzâs law tells you the direction of the induced current: it creates a magnetic field opposing the change in flux (this is why you feel mechanical resistance when you turn a generator). Motional emf (v Ă B) on moving conductors is the same idea for simple rod-on-rails setups. For AP exam work, you should be able to derive and use E = âdΊB/dt, apply Lenzâs rule, and handle N-turn coils (13.2.A.1â2). Review Topic 13.2 on Fiveable (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and try practice problems (https://library.fiveable.me/practice/ap-physics-c-e-m).
I don't understand how a changing magnetic flux creates an electric field - can someone explain?
Think of a changing magnetic flux as the cause, and an induced electric field as the effectâFaradayâs law gives the exact link. In integral form (the AP CED expects this): âź E · dâ = âdΊB/dt. That means if the magnetic flux through any loop changes with time, the line integral of E around that loop is nonzeroâthere must be an electric field circulating around the region. Physically: a time-changing B-field produces a nonconservative electric field whose field lines form closed loops (often circular around the changing B). Lenzâs law sets the direction: the induced E (and any induced current in a conductor) works to oppose the change in flux. For moving conductors you can also get a motional emf from v Ă B, but thatâs a different viewpoint that still matches Faradayâs law. You should be ready to use âźE·dâ = âdΊB/dt and Lenzâs law on the exam. For a quick refresher and practice problems, see the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and the AP Physics C practice set (https://library.fiveable.me/practice/ap-physics-c-e-m).
How do I solve problems where a conducting rod moves through a magnetic field?
Short recipe for rod-through-field problems: 1) Draw B, v, and rod length â. Identify area swept per time: dA/dt = â v (if rod moves perpendicular to B and along rails). 2) Use Faraday: Δ = âdΊB/dt. For constant B this gives motional emf Δ = B â v (magnitude). Thatâs the AP C 13.2.A idea: emf from changing flux. 3) If the rod closes a circuit with resistance R, get current I = Δ/R. Use Lenzâs law/right-hand rule to pick the current direction so its B opposes the flux change (CED 13.2.A.2). 4) Magnetic force on charges (and rod): F = I â B (direction opposes motion). If you need acceleration, apply Newtonâs 2nd law: ma = Fnet (include applied forces). Power/energy: electrical power P = IΔ = I^2R and mechanical power lost = F v. On the exam, explicitly cite Faradayâs law and Lenzâs law in your setup. For more worked examples and practice, see the Topic 13.2 study guide (Fiveable) here: (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and thousands of practice problems at (https://library.fiveable.me/practice/ap-physics-c-e-m).
What's the relationship between the speed of light and electromagnetic waves in Maxwell's equations?
Maxwellâs equations show that changing electric and magnetic fields produce each other (Faradayâs law and the MaxwellâAmpĂšre law), which leads to wave equations for E and B. Those wave equations have solutions that are electromagnetic waves traveling through free space at a single, constant speed c, where c = 1 / sqrt(Δ0 ÎŒ0). So the speed of light is not just an empirical numberâitâs the natural propagation speed of E and B fields predicted by Maxwellâs laws. In those waves E and B are transverse, perpendicular to each other and to the direction of travel, and their magnitudes are linked by the vacuum impedance (â(ÎŒ0/Δ0)). You donât need to derive this for APâthe CED notes that Maxwellâs equations can be used to show EM fields obey wave equations and that c = 1/â(Δ0ÎŒ0) (see Topic 13.2). For review, check the Topic 13.2 study guide (https://library.fiveable.me/ap-physics-c-e-m/unit-6/2-electromagnetic-induction/study-guide/b2D8zUgtWmPcdNoW) and more unit resources (https://library.fiveable.me/ap-physics-c-e-m/unit-13).