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AP Physics C: Electricity and Magnetism Unit 13 Review: Electromagnetic Induction

Review AP Physics C: E&M Unit 13 to build fluency with magnetic flux, Faraday's law, Lenz's law, inductance, and the transient and oscillatory behavior of LR and LC circuits. This unit connects the magnetic field concepts from Unit 12 to real circuit behavior and carries up to 20% of the exam.

Fiveable's AP Physics C: Electricity and Magnetism Unit 13 review covers 6 topics, with guided practice questions for the unit.

Use the topic guides, practice questions, FRQ practice, and score calculator available for this unit to work through every concept before exam day.

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What is AP Physics C: Electricity and Magnetism unit 13?

Electromagnetic induction is the mechanism behind electric generators, transformers, wireless charging, and Wi-Fi. Unit 13 gives you the mathematical tools to quantify how changing magnetic flux produces electric potential differences and how inductors store and release energy in circuits.

Unit 13 covers how a changing magnetic flux induces an emf (Faraday's law), how the direction of that emf is determined (Lenz's law), how inductors behave as circuit elements, and how LR and LC circuits evolve over time.

Flux and Faraday's law

Magnetic flux Φ_B = ∫ B · dA is the foundation. Faraday's law states that any change in flux through a loop induces an emf equal to -dΦ_B/dt. The negative sign encodes Lenz's law: the induced current opposes the flux change that caused it.

Inductance and energy storage

An inductor opposes changes in current. Its inductance L_sol = μ_core N² A / ℓ depends on geometry and core material. Energy stored is U_L = (1/2)LI², and any change in current produces a back emf of -L dI/dt.

LR and LC circuit dynamics

In an LR circuit, current grows or decays exponentially with time constant τ = L/R. In an LC circuit with no resistance, energy oscillates between the capacitor and inductor at angular frequency ω = 1/√(LC), analogous to simple harmonic motion.

Why electromagnetic induction unifies the unit

Every topic in Unit 13 follows from one principle: a changing magnetic flux drives an electric effect. Flux (13.1) defines what changes. Faraday's and Lenz's laws (13.2) quantify the induced emf. Forces on induced currents (13.3) show the mechanical consequences. Inductance (13.4) describes how a conductor's own changing current creates flux. LR circuits (13.5) and LC circuits (13.6) show how that inductance shapes time-dependent circuit behavior.

AP Physics C: Electricity and Magnetism unit 13 topics

13.1

Magnetic Flux

Define and calculate Φ_B = ∫ B · dA. Understand the area vector orientation, the role of the dot product in determining sign, and when to use the integral form versus the simple BA cos θ formula.

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13.2

Electromagnetic Induction

Apply Faraday's law emf = -dΦ_B/dt to find induced emf when B, A, or the angle between them changes. Use Lenz's law to determine the direction of the induced current. Handle the solenoid case with N turns.

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13.3

Induced Currents and Magnetic Forces

Calculate the induced current using I = emf/R, then find the magnetic force on current-carrying segments via F_B = ∫ I(dℓ × B). Apply Newton's second law to determine translational or rotational acceleration of the loop.

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13.4

Inductance

Calculate solenoid inductance with L_sol = μ_core N² A / ℓ. Find the back emf using emf_L = -L(dI/dt) and the stored energy using U_L = (1/2)LI². Understand how each physical parameter of the solenoid affects L.

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Hardest AP Physics C: Electricity and Magnetism unit 13 topics

This snapshot uses Fiveable practice activity to show where students tend to miss questions and which review moves are worth prioritizing first.

54%average MCQ accuracy

Across 839 multiple-choice practice attempts for this unit.

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0%average FRQ score

Across 1 scored free-response attempts for this unit.

Hardest topics in unit 13

MCQ miss rate
13.4

Review Inductance with attention to how the concept appears in AP-style source and evidence questions.

54%104 tries
13.3

Review Induced Currents and Magnetic Forces with attention to how the concept appears in AP-style source and evidence questions.

49%177 tries
13.5

Review Circuits with Resistors and Inductors (LR Circuits) with attention to how the concept appears in AP-style source and evidence questions.

48%219 tries
13.1

Review Magnetic Flux with attention to how the concept appears in AP-style source and evidence questions.

38%157 tries

Unit 13 review notes

13.1

Magnetic Flux

Magnetic flux Φ_B measures how much magnetic field passes through a surface. For a uniform field, Φ_B = B · A = BA cos θ, where θ is the angle between the field vector and the area vector. For a nonuniform field or curved surface, you must use the surface integral Φ_B = ∫ B · dA. The area vector points perpendicular to the surface and outward for a closed surface. The sign of flux is determined by the dot product: flux is positive when B and the area vector point in the same general direction and negative when they oppose.

  • Φ_B = B · A: Flux for a uniform field over a flat surface; equals BA cos θ where θ is the angle between B and the area vector.
  • Φ_B = ∫ B · dA: General surface integral form used when the field varies across the surface or the surface is curved.
  • Area vector: A vector perpendicular to the surface with magnitude equal to the area; for a closed surface it points outward.
  • Sign of flux: Positive when B and the area vector have a component in the same direction; negative when they oppose; zero when perpendicular.

A flat circular loop of area 0.05 m² sits in a uniform 2 T field at 30° to the plane of the loop. What is the magnetic flux through the loop?

SituationFormula to useKey variable
Uniform B, flat surfaceΦ_B = BA cos θAngle θ between B and area vector
Nonuniform B or curved surfaceΦ_B = ∫ B · dADifferential area element dA
13.2

Electroma­gnetic Induction: Faraday's Law and Lenz's Law

Faraday's law states that the induced emf in a loop equals the negative rate of change of magnetic flux: emf = -dΦ_B/dt. If the area is constant, emf = -A(dB_perp/dt). If the field is constant but the area changes, emf = -B(dA_perp/dt). For a solenoid with N turns, the total induced emf is |emf_sol| = N|dΦ_B/dt|. Lenz's law gives the direction: the induced current flows in the direction that opposes the change in flux. A loop entering a region of increasing flux will have an induced current that creates a field opposing the increase.

  • emf = -dΦ_B/dt: Faraday's law: the magnitude of the induced emf equals the rate of flux change; the negative sign indicates Lenz's law direction.
  • Lenz's law: The induced current flows in the direction that opposes the flux change causing it; determines the sign of the induced emf.
  • |emf_sol| = N|dΦ_B/dt|: For a solenoid, the total induced emf is N times the single-loop emf because flux links all N turns.
  • Motional emf: When a conductor of length ℓ moves at velocity v perpendicular to field B, the induced emf is emf = Bℓv.

A square loop of side 0.1 m is in a region where B increases at 3 T/s perpendicular to the loop. What is the magnitude of the induced emf, and in which direction does the induced current flow?

What changesInduced emf expressionExample
Magnetic field B (constant area)emf = -A(dB/dt)Loop in a time-varying solenoid field
Area A (constant field)emf = -B(dA/dt)Conducting rod sliding on rails
Both B and A changeemf = -d(BA cos θ)/dtRotating loop in a uniform field
13.3

Induced Currents and Magnetic Forces

When flux through a conducting loop changes, an induced current I = emf/R flows. That current-carrying loop sits in the external magnetic field, so the field exerts a force on it via F_B = ∫ I(dℓ × B). Only the segments of the loop actually inside the external field experience a net force. The result can be translational acceleration (a loop entering or exiting a field region) or rotational acceleration (a loop in a torque-producing geometry). By Lenz's law, the net magnetic force always opposes the motion that caused the flux change, which is the basis of magnetic braking and eddy current damping.

  • F_B = ∫ I(dℓ × B): Magnetic force on a current-carrying conductor segment; only segments inside the external field contribute to the net force on the loop.
  • Induced current I = emf/R: Ohm's law applied to the loop: the induced emf drives a current inversely proportional to the loop's resistance.
  • Magnetic braking: The opposing force on a loop moving through a field region; arises because the induced current experiences a retarding magnetic force.
  • Newton's second law application: The net magnetic force on the loop equals ma, allowing calculation of translational or rotational acceleration of the loop.

A rectangular loop of resistance R moves at constant velocity into a uniform field B. Identify which segments carry induced current, which experience a magnetic force, and in what direction the net force acts.

Motion typeRelevant equationPhysical effect
Translational (loop entering field)F = BIℓ = B²ℓ²v/RRetarding force opposing entry
Rotational (loop in torque geometry)τ = μ × B = IAB sin θAngular acceleration of the loop
13.4

Inductance

Inductance L is the property of a conductor that opposes changes in current by generating a back emf: emf_L = -L(dI/dt). For a solenoid, L_sol = μ_core N² A / ℓ, so inductance increases with more turns, larger cross-sectional area, shorter length, and higher core permeability. Straight wires are modeled as having zero inductance. An inductor stores energy in its magnetic field: U_L = (1/2)LI². That stored energy can later be dissipated through a resistor or transferred to a capacitor.

  • L_sol = μ_core N² A / ℓ: Solenoid inductance depends on core permeability, number of turns squared, cross-sectional area, and inverse of length.
  • emf_L = -L(dI/dt): Back emf produced by an inductor; opposes the change in current through it.
  • U_L = (1/2)LI²: Energy stored in the magnetic field of an inductor carrying current I.
  • dI/dt: Rate of change of current; determines the magnitude of the back emf across an inductor.

A solenoid has 500 turns, length 0.2 m, cross-sectional area 4 × 10⁻⁴ m², and an air core. Calculate its inductance and the energy stored when 2 A flows through it.

Physical change to solenoidEffect on L
Double the number of turns NL increases by factor of 4 (L ∝ N²)
Double the length ℓL decreases by factor of 2 (L ∝ 1/ℓ)
Double the cross-sectional area AL increases by factor of 2 (L ∝ A)
Replace air core with ferrite coreL increases proportional to μ_core
13.5

LR Circuits

Applying Kirchhoff's loop rule to a series LR circuit with battery emf gives the differential equation emf = L(dI/dt) + IR. The solution is an exponential function with time constant τ = L/R_eq. When the switch closes, current grows as I(t) = (emf/R)(1 - e^(-t/τ)). When the battery is removed, current decays as I(t) = I_0 e^(-t/τ). At steady state (t >> τ), the inductor acts like a short circuit (zero voltage drop across an ideal inductor) and current equals emf/R. At t = τ, the current has reached about 63% of its final value during growth or dropped to about 37% during decay.

  • τ = L/R_eq: LR time constant; larger L or smaller R means slower approach to steady state.
  • I(t) = (emf/R)(1 - e^(-t/τ)): Current growth after switch closes; starts at zero and approaches emf/R asymptotically.
  • I(t) = I_0 e^(-t/τ): Current decay after battery is removed; starts at I_0 and decays to zero.
  • Steady state: After many time constants, dI/dt = 0, so the inductor has no voltage drop and current is constant at emf/R.
  • emf = L(dI/dt) + IR: Kirchhoff's loop rule for a series LR circuit; the first-order linear ODE whose solution gives the transient behavior.

An LR circuit has emf = 12 V, R = 4 Ω, and L = 0.2 H. Find τ, the steady-state current, and the current at t = τ after the switch closes.

QuantityAt t = 0At t = τAt t >> τ (steady state)
Current I0 (switch just closed)0.63 × (emf/R)emf/R
Voltage across Lemf0.37 × emf0
Voltage across R00.63 × emfemf
13.6

LC Circuits

An ideal LC circuit with no resistance allows energy to oscillate indefinitely between the electric field of the capacitor and the magnetic field of the inductor. Applying Kirchhoff's loop rule gives the differential equation d²q/dt² = -(1/LC)q, which has the same form as simple harmonic motion. The angular frequency of oscillation is ω = 1/√(LC). The maximum current occurs when the capacitor is fully discharged, and conservation of energy gives I_max = Q_0/√(LC). Charge and current are 90° out of phase: when charge on the capacitor is maximum, current is zero, and vice versa.

  • d²q/dt² = -(1/LC)q: Governing equation for charge in an LC circuit; identical in form to the SHM equation d²x/dt² = -(k/m)x.
  • ω = 1/√(LC): Angular frequency of LC oscillation; depends only on inductance and capacitance, not on initial conditions.
  • I_max = Q_0/√(LC): Maximum current in the inductor, found by setting initial capacitor energy equal to maximum inductor energy.
  • Energy exchange: Total energy U = (1/2)CV² + (1/2)LI² is constant; energy shifts between capacitor and inductor each quarter cycle.
  • Simple harmonic motion analogy: Charge q maps to displacement x, current I maps to velocity v, L maps to mass m, and 1/C maps to spring constant k.

An LC circuit has L = 0.1 H and C = 10 μF. Find ω, the period T, and the maximum current if the capacitor is initially charged to Q_0 = 2 × 10⁻³ C.

LC circuit quantitySHM analogyFormula
Charge qDisplacement xq(t) = Q_0 cos(ωt)
Current I = dq/dtVelocity v = dx/dtI(t) = -Q_0 ω sin(ωt)
Inductance LMass mOpposes change
1/C (inverse capacitance)Spring constant kRestoring tendency
Angular frequency ωω = √(k/m)ω = 1/√(LC)

Practice AP Physics C: Electricity and Magnetism unit 13 questions

Try AP-style multiple-choice questions and written prompts after you review the notes.

Example AP-style MCQs

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MCQ

AP-style practice question

Question

An LC circuit contains a 50 mH50\ \text{mH} inductor. If the maximum current observed in the circuit is 4.0 A4.0\ \text{A}, what is the maximum energy stored in the capacitor during the oscillation cycle?

0.10 J0.10\ \text{J}

0.20 J0.20\ \text{J}

0.40 J0.40\ \text{J}

0.80 J0.80\ \text{J}

MCQ

AP-style practice question

Question

A series LR circuit with time constant τ\tau is connected to a DC battery at t=0t=0. At what time tt is the magnitude of the potential difference across the resistor equal to the magnitude of the potential difference across the inductor?

The magnitude of the voltages is equal when time tt reaches τ/2\tau / 2

The magnitude of the voltages is equal when time tt reaches τln⁡2\tau \ln 2

The magnitude of the voltages is equal when time tt reaches τ\tau

The magnitude of the voltages is equal when time tt reaches 2τ2\tau

Example FRQs

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FRQ

Motional EMF in moving conductor bars

4. A U-shaped conducting track lies in the plane of the page, as shown in Figure 1. The rails are separated by a distance L=0.30 mL = 0.30\ \text{m} and are connected by a resistor of resistance R=2.0 ΩR = 2.0\ \Omega at the left end. A conducting bar of negligible resistance makes sliding contact with the rails and is pulled to the right at constant speed. A uniform magnetic field of magnitude B=0.80 TB = 0.80\ \text{T} is directed into the page over the entire region shown. The bar is at a distance xx from the resistor, where xx increases as the bar moves to the right. Gravitational effects and friction are negligible.

Figure 1. Sliding conducting bar on parallel rails in a uniform magnetic field (into the page).

Figure 1
A.

At the instant shown in Figure 1, the bar is pulled to the right with speed v1=1.5 m/sv_1 = 1.5\ \text{m/s}. The induced potential difference across the resistor is ΔV1\Delta V_1. Later, the bar is pulled to the right with a greater speed v2=3.0 m/sv_2 = 3.0\ \text{m/s} while all other quantities remain the same, and the induced potential difference across the resistor is ΔV2\Delta V_2.

Indicate whether ΔV2\Delta V_2 is greater than, less than, or equal to ΔV1\Delta V_1 by writing one of the following.

  • ΔV2>ΔV1\Delta V_2 > \Delta V_1
  • ΔV2<ΔV1\Delta V_2 < \Delta V_1
  • ΔV2=ΔV1\Delta V_2 = \Delta V_1

Justify your answer.

B.

Derive an expression for the magnitude of the induced potential difference ΔV\Delta V across the resistor in Figure 1 in terms of BB, LL, and the bar speed vv. Begin your derivation by writing a fundamental physics principle or an equation from the reference information. Your derivation must explicitly relate magnetic flux through the loop to the induced emf.

Figure 2. Same rails and sliding bar, with a series RL element (ideal inductor and resistor) at the left end; current direction shown.

Figure 2
C.

Indicate whether the magnitude of the pulling force required to keep the bar moving at constant speed is greater at the instant immediately after the bar begins moving from rest or greater after a long time, by writing one of the following. The circuit is modified as shown in Figure 2 by placing an ideal inductor of inductance Lind=0.50 HL_{\text{ind}} = 0.50\ \text{H} in series with the resistor R=2.0 ΩR = 2.0\ \Omega. The bar continues to be pulled to the right at constant speed v1=1.5 m/sv_1 = 1.5\ \text{m/s} in the same magnetic field. Immediately after the bar begins moving from rest, the current in the circuit is very small. After a long time, the circuit reaches a steady state with a constant current.

  • Finitial>FlongF_{\text{initial}} > F_{\text{long}}
  • Finitial<FlongF_{\text{initial}} < F_{\text{long}}
  • Finitial=FlongF_{\text{initial}} = F_{\text{long}}

Briefly justify your answer by referencing your derivation in part B and the physical/electrical properties of an inductor in an RLRL circuit.

FRQ

Electromagnetic induction in moving conductor systems

1. A conducting rail system consists of two parallel horizontal rails separated by a distance 2=0.30 m2 = 0.30\ \text{m} and connected on the left by a resistor of resistance R=2.0 ΩR = 2.0\ \Omega, as shown in Figure 1. A conducting bar of negligible resistance and mass m=0.20 kgm = 0.20\ \text{kg} makes contact with both rails and can slide to the right without friction. A uniform magnetic field of magnitude B=0.80 TB = 0.80\ \text{T} is directed into the page throughout the region that includes the rails and bar. The rails and bar form a rectangular conducting loop. The bar is pulled to the right by an external agent so that the speed of the bar is constant at v=3.0 m/sv = 3.0\ \text{m/s}. The bar remains perpendicular to the rails at all times.

Figure 1. Conducting rails with sliding bar in a uniform magnetic field (into the page).

Figure 1

Figure 2. Axes for graph of induced emf magnitude |ε| versus time t.

Figure 2
A.
i.

The bar is at position x(t)x(t) from the left resistor, so that the loop area is A(t)=ℓ x(t)A(t) = \ell\,x(t). Using the definition of magnetic flux, derive an expression for the magnetic flux ΦB(t)\Phi_B(t) through the loop in terms of BB, ℓ\ell, and x(t)x(t). Clearly indicate the sign of ΦB\Phi_B based on the field direction into the page.

ii.

Using Faraday's law, derive an expression for the induced electric potential difference (emf) ε\varepsilon around the loop while the bar moves at constant speed vv. Express your answer in terms of BB, ℓ\ell, and vv, and indicate the direction of the induced current through the resistor (clockwise or counterclockwise) as viewed in Figure 1.

iii.

On the axes shown in Figure 2, sketch a graph of the magnitude of the induced emf, ∣ε∣|\varepsilon|, as a function of time tt for t≥0t ≥ 0. Label at least one numerical value on each axis using the given quantities.

Figure 3. Same rails and sliding bar, with a series inductor L and capacitor C replacing the resistor on the left side.

Figure 3
B.

Derive a differential equation for the loop current I(t)I(t) for t>0t > 0 and then calculate the angular frequency ω0\omega_0 of the resulting oscillations. Express ω0\omega_0 in rad/s\text{rad/s}. Your derivation must use the defining relationships for an inductor and a capacitor (in terms of current, charge, and potential difference) and the induced emf from part A. The resistor is replaced by an inductor and capacitor in series, as shown in Figure 3. The inductor has inductance L=0.50 HL = 0.50\ \text{H} and negligible resistance. The capacitor has capacitance C=200 μFC = 200\ \mu\text{F} and is initially uncharged. At t=0t = 0 the bar begins moving to the right at constant speed v=3.0 m/sv = 3.0\ \text{m/s} in the same field B=0.80 TB = 0.80\ \text{T}, and the bar maintains contact with the rails.

Given values: ℓ=0.30 m\ell = 0.30\ \text{m}, B=0.80 TB = 0.80\ \text{T}, v=3.0 m/sv = 3.0\ \text{m/s}, L=0.50 HL = 0.50\ \text{H}, C=200 μFC = 200\ \mu\text{F}.

FRQ

Magnetic energy density in solenoids with and without cores

2. A long solenoid of length 0.40 m has 800 turns of wire and a circular cross-sectional area of 3.0e-4 m^2, as shown in Figure 1. The solenoid is connected to a variable current supply so that the current I in the windings can be set between 0 A and 2.0 A.

Figure 1. Long solenoid with core

Figure 1

Figure 2. Magnetic energy density

Figure 2
A.

In Figure 2, draw a bar to represent the magnetic energy density u in the solenoid at I = 2.0 A after the core (mu_r = 250) is inserted. Use the given air-core bar as a reference. If the bar would be off-scale, draw it to the top of the axis and write the numerical value above the bar. The solenoid current is set to I = 2.0 A and held constant. Figure 2 shows a bar for the magnetic energy density u in the air-core solenoid at I = 2.0 A.

B.

Derive an expression for the magnetic energy density u inside the solenoid as a function of current I for (i) the air-core solenoid and (ii) the solenoid with the inserted core. Express your final answers in terms of mu_0, mu_r, N, L, and I only. Begin your derivation by writing a fundamental physics principle or an equation from the reference information, and show the intermediate steps needed to obtain u(I).

Figure 3. Energy density vs. current

Figure 3
C.

On the axes shown in Figure 3, sketch graphs of u versus I for both the air-core solenoid and the solenoid with the inserted core, for 0 <= I <= 2.0 A. Label each curve. The curves should be consistent with the value represented by the given bar in Figure 2. A student wants a representation of how the magnetic energy density depends on current for both cases (air core and with core).

D.

Indicate whether the relative height of the bar you drew in part A is or is not consistent with the two curves you sketched in part C. Briefly justify your answer by referencing a specific functional dependence between u and I and explaining how inserting a material with permeability mu = mu_r mu_0 changes that dependence at the same current.

AP Physics C: Electricity and Magnetism unit 13 practice test

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Key terms

TermDefinition
area vectorA vector perpendicular to the plane of a surface with magnitude equal to the area; for a closed surface it points outward. Used in Φ_B = B · A to determine both the magnitude and sign of magnetic flux.
dot productThe scalar product B · A = BA cos θ that determines the component of B perpendicular to the surface; sets both the magnitude and sign of magnetic flux.
dI/dtRate of change of current with respect to time; the back emf across an inductor is emf_L = -L(dI/dt), so a rapidly changing current produces a large opposing voltage.
energy stored in an inductorU_L = (1/2)LI²; the energy held in the magnetic field of an inductor carrying current I. This energy can be dissipated through a resistor or transferred to a capacitor.
ideal inductorAn inductor with negligible resistance. At steady state in an LR circuit, an ideal inductor has zero potential difference across it and acts like a short circuit.
steady stateThe condition in an LR circuit after many time constants when dI/dt = 0, the inductor voltage is zero, and current equals emf/R.
RL circuitA series circuit containing a resistor and inductor governed by emf = L(dI/dt) + IR. Current changes exponentially with time constant τ = L/R.
LC circuitA circuit containing only a capacitor and an inductor. Energy oscillates between electric energy in the capacitor and magnetic energy in the inductor at angular frequency ω = 1/√(LC).
angular frequencyω = 1/√(LC) for an LC circuit; the rate of charge oscillation in radians per second, determined entirely by the values of L and C.
simple harmonic motionThe oscillatory behavior described by d²q/dt² = -(1/LC)q in an LC circuit. Charge q plays the role of displacement, L plays the role of mass, and 1/C plays the role of spring constant.
Maximum emfThe peak induced emf in a rotating loop, emf_max = NBAω, occurring when the plane of the loop is parallel to the field and the rate of flux change is greatest.
Sinusoidal emfThe time-varying emf produced by a loop rotating at constant angular speed in a uniform field: emf(t) = emf_max sin(ωt), a direct consequence of Faraday's law.
F_B = ∫I(dℓ × B)The magnetic force on a current-carrying conductor; in Topic 13.3, this force acts on the segments of an induced-current loop that lie within the external magnetic field.

Common unit 13 mistakes

Ignoring the angle in flux calculations

Φ_B = BA cos θ uses the angle between B and the area vector, not the angle between B and the plane of the loop. If B is parallel to the plane, θ = 90° and flux is zero. Confusing these two angles is a frequent error.

Forgetting the negative sign in Faraday's law

The negative sign is Lenz's law in mathematical form. Dropping it means you get the magnitude of the induced emf but assign the wrong direction to the induced current, which affects force and torque calculations in Topic 13.3.

Treating the inductor as a resistor at t = 0

At the instant a switch closes, an inductor with zero initial current acts like an open circuit (infinite opposition to current change), not a short circuit. At steady state it acts like a wire. Mixing these two limits is a common LR circuit error.

Using the wrong N dependence for solenoid inductance

L_sol scales as N², not N. Doubling the number of turns quadruples the inductance. Students often write L ∝ N and underestimate the effect of adding turns.

Confusing the LC angular frequency with the LR time constant

ω = 1/√(LC) is an angular frequency in rad/s for oscillation; τ = L/R is a time constant in seconds for exponential decay. They are different quantities with different units and should not be substituted for each other.

How this unit shows up on the AP exam

Deriving and solving differential equations

AP Physics C: E&M free-response questions frequently ask you to apply Kirchhoff's loop rule to an LR or LC circuit, write the resulting differential equation, and either solve it or verify that a given exponential or sinusoidal function is a solution. You should be comfortable showing that I(t) = (emf/R)(1 - e^(-t/τ)) satisfies emf = L(dI/dt) + IR and that q(t) = Q_0 cos(ωt) satisfies d²q/dt² = -(1/LC)q.

Multi-step flux and force problems

A common exam task chains together several Unit 13 skills: calculate the flux through a moving or rotating loop, apply Faraday's law to find the induced emf, use Ohm's law to find the induced current, then apply F_B = ∫ I(dℓ × B) to find the retarding force and Newton's second law to find acceleration. Each step must be shown clearly with correct sign conventions.

Energy conservation and graphical analysis

Exam questions on LC circuits often ask you to use conservation of energy to find I_max or the voltage across each element at a given moment, then sketch graphs of q(t), I(t), U_C(t), and U_L(t) over one full cycle. For LR circuits, you may need to read or sketch I vs. t graphs and identify τ from the graph. Connecting the mathematical solution to a correctly labeled quantitative graph is a tested skill.

Final unit 13 review checklist

  • Unit 13 final review checklist

    Use this list to confirm you can handle every major skill in the unit before exam day.

  • Calculate magnetic flux

    Compute Φ_B = BA cos θ for uniform fields and set up Φ_B = ∫ B · dA for nonuniform or curved-surface cases. Correctly orient the area vector and determine the sign of flux.

  • Apply Faraday's and Lenz's laws

    Use emf = -dΦ_B/dt to find induced emf when B, A, or θ changes. Determine the direction of the induced current using Lenz's law and the right-hand rule.

  • Analyze forces on induced currents

    Find the induced current with I = emf/R, identify which loop segments are in the field, compute the magnetic force via F_B = ∫ I(dℓ × B), and apply Newton's second law to find acceleration.

  • Work with inductance formulas

    Calculate L_sol = μ_core N² A / ℓ, find the back emf emf_L = -L(dI/dt), and compute stored energy U_L = (1/2)LI². Predict how changing N, A, ℓ, or core material affects L.

  • Solve LR circuit transients

    Write and solve the Kirchhoff loop equation for an LR circuit. Use τ = L/R to find the time constant, write I(t) for growth and decay, and identify voltages across L and R at t = 0, t = τ, and steady state.

  • Describe LC circuit oscillations

    Identify the SHM analogy, calculate ω = 1/√(LC) and period T = 2π√(LC), use energy conservation to find I_max = Q_0/√(LC), and describe the phase relationship between q(t) and I(t).

How to study unit 13

Step 1: Build fluency with flux (Topic 13.1)

Read the Topic 13.1 guide and practice computing Φ_B = BA cos θ for loops at various angles. Then set up the integral form for a nonuniform field. Sketch diagrams showing the area vector and field vector to confirm sign conventions before moving on.

Step 2: Work through Faraday's and Lenz's laws (Topic 13.2)

Read the Topic 13.2 guide. Practice differentiating Φ_B with respect to time for cases where B changes, A changes, and the loop rotates. For each scenario, use Lenz's law to determine current direction before checking with the formula.

Step 3: Connect flux changes to forces (Topic 13.3)

Read the Topic 13.3 guide. Work problems involving a rectangular loop entering or exiting a field region: find the induced emf, the induced current, the force on each segment, and the net force. Apply Newton's second law to find acceleration.

Step 4: Understand inductance and energy storage (Topic 13.4)

Read the Topic 13.4 guide. Practice calculating L_sol for solenoids with different parameters and finding U_L = (1/2)LI². Make sure you can derive the back emf emf_L = -L(dI/dt) from Faraday's law applied to the solenoid's own flux.

Step 5: Solve LR and LC circuit problems (Topics 13.5-13.6)

Read the Topic 13.5 and 13.6 guides back to back. For LR circuits, practice writing I(t) for growth and decay and reading values off exponential graphs. For LC circuits, identify the SHM analogy, calculate ω and T, and use energy conservation to find I_max. Use available practice questions and FRQ practice to test both circuit types under timed conditions.

More ways to review

Topic study guides

Open the individual guides for Unit 13 when you want a closer review of one topic.

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Practice questions

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FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

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Official unit cheatsheet

Open the Fiveable one-page unit review, then explore visual cheatsheets for a quick refresher.

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Score calculator

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Unit 13 printables

Print the unit cheatsheets ($3) for Unit 13. Yours to keep, no subscription needed.

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Frequently Asked Questions

What topics are covered in AP Physics E&M Unit 13?

AP Physics E&M Unit 13 covers electromagnetic induction across 6 topics: Magnetic Flux (13.1), Electromagnetic Induction (13.2), Induced Currents and Magnetic Forces (13.3), Inductance (13.4), Circuits with Resistors and Inductors or LR Circuits (13.5), and Circuits with Capacitors and Inductors or LC Circuits (13.6). These topics build on each other, so magnetic flux and Faraday's law come first, then you apply those ideas to real circuit behavior with inductors. See AP Physics E&M Unit 13 for matched practice on each topic.

How much of the AP Physics E&M exam is Unit 13?

Electromagnetic induction makes up 10-20% of the AP Physics E&M exam, making it one of the heavier-weighted units. That range covers everything from magnetic flux and Faraday's law to inductance and the behavior of LR and LC circuits. Expect both multiple-choice and free-response questions that test these concepts. Because the weight is that significant, it's worth spending real time on the calculus-based derivations in this unit, not just the conceptual ideas.

What's on the AP Physics E&M Unit 13 progress check (MCQ and FRQ)?

The AP Physics E&M Unit 13 progress check in AP Classroom includes both MCQ and FRQ parts drawn from all six topics in the unit. The MCQ section tests conceptual and quantitative understanding of magnetic flux, electromagnetic induction, induced currents, and inductance. The FRQ part typically asks you to analyze LR or LC circuit behavior, derive expressions using Faraday's law, or calculate induced EMF. The progress check is one of the best low-stakes ways to find gaps before the real exam. Head to AP Physics E&M Unit 13 for practice that mirrors the same topic breakdown.

How do I practice AP Physics E&M Unit 13 FRQs?

The best way to practice AP Physics E&M Unit 13 FRQs is to focus on the topics that show up most often: electromagnetic induction, inductance, and LR and LC circuit analysis. FRQs in this unit typically ask you to derive an expression for induced EMF using Faraday's law, sketch or interpret current vs. time graphs for LR circuits, or analyze energy storage in an LC circuit. For each problem, write out your setup equation before plugging in numbers, and show the calculus steps clearly since AP graders award method points. Visit AP Physics E&M Unit 13 to find FRQ practice sets organized by topic.

Where can I find AP Physics E&M Unit 13 practice questions?

For AP Physics E&M Unit 13 practice questions, including multiple-choice and practice test sets, go to AP Physics E&M Unit 13. That page has MCQ and FRQ practice covering all six topics: magnetic flux, electromagnetic induction, induced currents, inductance, LR circuits, and LC circuits with capacitors and inductors. When you work through MCQs, flag any question involving magnetic flux or inductance that trips you up, then review the matching topic before moving on to a full practice test.

How should I study AP Physics E&M Unit 13?

To study AP Physics E&M Unit 13 on electromagnetic induction, start with magnetic flux (13.1) and make sure you can set up and evaluate the flux integral before moving on. Faraday's law and Lenz's law in topic 13.2 are the backbone of the whole unit, so spend extra time there. Here's a concrete plan:
- Topics 13.1-13.3: Practice drawing field diagrams, calculating magnetic flux, and applying Lenz's law to find induced current direction.
- Topic 13.4: Work through inductance derivations and understand the energy stored in an inductor.
- Topics 13.5-13.6: Solve LR and LC circuit differential equations step by step. Connecting LC circuits to capacitors and oscillatory behavior is a common FRQ angle. After each topic, do a short timed problem set, then check your work before moving forward. Visit AP Physics E&M Unit 13 for topic-by-topic practice to structure your review.

Ready to review Unit 13?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.