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💡AP Physics C: E&M
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💡AP Physics C: E&M

FRQ 1 – Mathematical Routines
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Unit 8: Electric Charges, Fields, and Gauss's Law
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Practice FRQ 1 of 201/20

1. A nonconducting solid sphere of radius R=0.30 mR = 0.30\ \text{m}R=0.30 m is centered at the origin. The sphere contains a spherical cavity of radius a=0.10 ma = 0.10\ \text{m}a=0.10 m that is also centered at the origin. The material of the sphere (for a<r<Ra < r < Ra<r<R) has a uniform volume charge density ρ=+6.0×10−6 C/m3\rho = +6.0\times10^{-6}\ \text{C/m}^3ρ=+6.0×10−6 C/m3. The cavity region r<ar < ar<a is vacuum. A thin, conducting spherical shell of inner radius RRR and outer radius Rout=0.32 mR_\text{out} = 0.32\ \text{m}Rout​=0.32 m is concentric with the sphere. The conducting shell has a net charge Qshell=−1.0×10−7 CQ_\text{shell} = -1.0\times10^{-7}\ \text{C}Qshell​=−1.0×10−7 C. The entire configuration is electrostatic and isolated, as shown in Figure 1.

Figure 1. Concentric spherical cavity, uniformly charged insulating material, and conducting spherical shell (cross-sectional view through a diameter).

Figure 1

Figure 2. Axes for sketching electric field magnitude E as a function of radial distance r.

Figure 2
A.
i.

Using Gauss's law, derive an expression for the magnitude EEE of the electric field as a function of the radial distance rrr for the region a<r<Ra < r < Ra<r<R. Express your answer in terms of ρ\rhoρ, aaa, rrr, and physical constants, as appropriate.

ii.

Derive an expression for the magnitude EEE of the electric field as a function of the radial distance rrr for the region r>Routr > R_\text{out}r>Rout​. Your expression must be in terms of ρ\rhoρ, aaa, RRR, QshellQ_\text{shell}Qshell​, rrr, and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

iii.

On the axes shown in Figure 2, sketch a graph of EEE as a function of rrr from r=0r = 0r=0 to a position that is outside the conducting shell.

Figure 3. Same geometry as Figure 1, but the cavity (r < a) is filled with a linear dielectric of relative permittivity κ.

Figure 3
B.

Derive an expression for the magnitude of the electric field EEE in the dielectric-filled cavity region r<ar < ar<a. Express your answer in terms of ρ\rhoρ, aaa, κ\kappaκ, and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information. The cavity region r<ar < ar<a is filled with a linear dielectric material of relative permittivity κ=4.0\kappa = 4.0κ=4.0, as shown in Figure 3. The charge density in the insulating material for a<r<Ra < r < Ra<r<R remains ρ=+6.0×10−6 C/m3\rho = +6.0\times10^{-6}\ \text{C/m}^3ρ=+6.0×10−6 C/m3, and the conducting shell still has net charge Qshell=−1.0×10−7 CQ_\text{shell} = -1.0\times10^{-7}\ \text{C}Qshell​=−1.0×10−7 C.







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Free Response Question Practice

This practice environment simulates the AP AP Physics C: E&M Free Response Questions section. Here are some guidelines:

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