Two conservation laws govern ideal fluid flow. Conservation of mass gives the continuity equation: A1v1 = A2v2. Where a pipe narrows, the fluid speeds up to keep the flow rate constant. Conservation of mechanical energy gives Bernoulli's equation, which relates pressure, gravitational potential energy per unit volume, and kinetic energy per unit volume at any two points along a streamline. Torricelli's theorem is a direct application of Bernoulli to a fluid exiting an opening.
- Continuity equation: A1v1 = A2v2. The volume flow rate Q = Av is constant for an incompressible fluid. A smaller cross-section means a higher speed.
- Volume flow rate: Q = Av, in m^3/s. It equals the volume of fluid passing a cross-section per unit time.
- Bernoulli's equation: P1 + rhogy1 + (1/2)rhov1^2 = P2 + rhogy2 + (1/2)rhov2^2. Expresses conservation of mechanical energy per unit volume along a streamline.
- Bernoulli's principle (qualitative): Where fluid speed increases, pressure decreases, and vice versa. This follows directly from Bernoulli's equation when height is constant.
- Torricelli's theorem: v = sqrt(2gdelta_y). The speed of fluid exiting an opening at the base of a tank equals the speed a free-falling object would reach after falling the same height delta_y. Derived from Bernoulli's equation.
Water flows through a pipe that narrows from area 0.02 m^2 to 0.005 m^2. If the speed in the wide section is 1 m/s, what is the speed in the narrow section? If the pressure in the wide section is 200,000 Pa and both sections are at the same height, what is the pressure in the narrow section? (rho = 1000 kg/m^3)
| Law | Equation | What is conserved |
|---|
| Continuity equation | A1v1 = A2v2 | Mass flow rate (volume flow rate for incompressible fluids) |
| Bernoulli's equation | P + rho*g*y + (1/2)*rho*v^2 = constant | Mechanical energy per unit volume |
| Torricelli's theorem | v = sqrt(2*g*delta_y) | Mechanical energy (special case of Bernoulli) |