AP exam review verified for 2027

AP Chem Unit 9 Review: Thermodynamics and Electrochemistry

Review AP Chem Unit 9 to understand how entropy, Gibbs free energy, and electrochemistry connect energy changes to the direction and extent of chemical processes. This unit ties together thermodynamic favorability, equilibrium, and redox reactions in electrochemical cells.

Use the topic guides, key terms, and practice questions available for every topic in this unit to build a complete review.

What is AP Chem unit 9?

Unit 9 asks you to predict and explain energy changes in chemical systems using two connected frameworks: thermodynamics and electrochemistry. You will calculate entropy changes, evaluate thermodynamic favorability using Gibbs free energy, connect ΔG° to equilibrium constants, and then apply all of that reasoning to galvanic and electrolytic cells.

Unit 9 is about predicting whether chemical processes are thermodynamically favored (ΔG° < 0), how that connects to equilibrium constants and cell potentials, and how to use Faraday's law to relate charge, current, and mass in electrochemical cells.

Entropy and Gibbs Free Energy

Entropy (S) measures dispersal of matter and energy. The sign of ΔS° tells you whether disorder increases or decreases. Gibbs free energy combines enthalpy and entropy: ΔG° = ΔH° - TΔS°. When ΔG° < 0, the process is thermodynamically favored. Temperature determines which sign of ΔH° and ΔS° combinations are favored.

Free Energy, Equilibrium, and Coupled Reactions

ΔG° and K are linked by ΔG° = -RT ln K. A negative ΔG° means K > 1 and products are favored at equilibrium. Thermodynamically unfavorable processes can be driven by coupling them to favorable reactions (shared intermediates) or by supplying external energy such as electricity or light.

Electrochemical Cells and Calculations

Galvanic cells convert thermodynamically favored redox reactions into electrical energy; electrolytic cells use external power to drive unfavorable reactions. Standard cell potential E°cell = E°cathode - E°anode, and ΔG° = -nFE°. The Nernst equation describes how cell potential changes under nonstandard conditions, and Faraday's law connects charge, current, time, and mass deposited.

Energy drives the direction of change

Every topic in Unit 9 returns to one question: will this process occur, and how much energy is involved? Entropy measures dispersal, Gibbs free energy combines enthalpy and entropy into a single favorability criterion, and electrochemistry translates that criterion into measurable voltage and calculable mass. The equation ΔG° = -nFE° = -RT ln K is the backbone of the entire unit, linking thermodynamics, equilibrium, and electrochemistry into one coherent framework.

AP Chem unit 9 topics

9.1

Introduction to Entropy

Predict the sign and relative magnitude of ΔS for phase changes, volume changes, and reactions based on dispersal of matter and energy and changes in moles of gas.

open guide
9.2

Absolute Entropy and Entropy Change

Calculate ΔS°reaction using ΔS°reaction = ΣS°products - ΣS°reactants with tabulated standard molar entropy values. Remember units are J/(mol·K) and physical states matter.

open guide
9.3

Gibbs Free Energy and Thermodynamic Favorability

Use ΔG° = ΔH° - TΔS° or ΔG°reaction = ΣΔG°f products - ΣΔG°f reactants to determine whether a process is thermodynamically favored. ΔG° < 0 means favored.

open guide
9.4

Thermodynamic and Kinetic Control

A thermodynamically favored reaction (ΔG° < 0) may not occur at a measurable rate if activation energy is high. Distinguish thermodynamic favorability from reaction rate in your explanations.

open guide
9.5

Free Energy and Equilibrium

Connect ΔG° to K using ΔG° = -RT ln K. Negative ΔG° means K > 1 (products favored); positive ΔG° means K < 1 (reactants favored). Estimate K magnitude qualitatively from the size of ΔG° relative to RT.

open guide
9.6

Free Energy of Dissolution

Explain salt solubility using the three contributions to ΔG° of dissolution: lattice breaking (endothermic), solvent reorganization, and ion-dipole interactions. Predictions are difficult because these contributions partially cancel.

open guide
9.7

Coupled Reactions

Drive unfavorable reactions by coupling them to favorable ones through a shared intermediate. Add ΔG° values to determine overall favorability. External energy sources (electricity, light) can also drive unfavorable processes.

open guide
9.8

Galvanic (Voltaic) and Electrolytic Cells

Identify the anode (oxidation) and cathode (reduction) in both cell types. Galvanic cells produce energy (ΔG° < 0); electrolytic cells consume energy (ΔG° > 0). Track electron flow, ion flow through the salt bridge, and electrode mass changes.

open guide
9.9

Cell Potential and Free Energy

Calculate E°cell = E°cathode - E°anode using standard reduction potentials. Connect to thermodynamics using ΔG° = -nFE°. Positive E°cell means thermodynamically favored; negative means unfavored.

open guide
9.10

Cell Potential Under Nonstandard Conditions

Cell potential changes when concentrations deviate from standard conditions. The cell moves toward equilibrium as it operates; E approaches zero when Q = K. Reason qualitatively using Q relative to 1 and K.

open guide
9.11

Electrolysis and Faraday's Law

Use I = q/t and the Faraday constant (96,485 C/mol e-) to convert between current, time, charge, moles of electrons, and mass deposited or removed at an electrode. Set up the dimensional analysis chain carefully.

open guide
practice snapshot

Hardest AP Chemistry unit 9 topics

This snapshot uses Fiveable practice activity to show where students tend to miss questions and which review moves are worth prioritizing first.

61%average MCQ accuracy

Across 9.0k multiple-choice practice attempts for this unit.

9.0kMCQ attempts

Practice activity included in this snapshot.

50%average FRQ score

Across 28 scored free-response attempts for this unit.

Hardest topics in unit 9

MCQ miss rate
9.3

Review Gibbs Free Energy and Thermodynamic Favorability with attention to how the concept appears in AP-style source and evidence questions.

44%995 tries
9.9

Review Cell Potential and Free Energy with attention to how the concept appears in AP-style source and evidence questions.

38%960 tries
9.8

Review Galvanic (Voltaic) and Electrolytic Cells with attention to how the concept appears in AP-style source and evidence questions.

38%829 tries
9.2

Review Absolute Entropy and Entropy Change with attention to how the concept appears in AP-style source and evidence questions.

30%1,267 tries

Unit 9 review notes

9.1

Introduction to Entropy

Entropy (S) measures how dispersed matter and energy are in a system. You need to predict the sign and relative magnitude of ΔS for physical and chemical processes without calculating exact values. Focus on the direction of change: does the process increase or decrease disorder?

  • Matter dispersal: Entropy increases when particles gain freedom of movement: solid to liquid to gas, or a gas expanding into a larger volume.
  • Moles of gas rule: For reactions involving gases, ΔS° is positive when the total moles of gaseous products exceed the total moles of gaseous reactants.
  • Energy dispersal: Entropy increases with temperature because the distribution of kinetic energy among particles broadens, creating more microstates.
  • Microstates: Entropy is related to the number of distinct molecular arrangements available to a system; more microstates means higher entropy.
  • Phase change direction: Melting and vaporization increase entropy; freezing and condensation decrease entropy.
For the reaction 2H2(g) + O2(g) → 2H2O(g), predict the sign of ΔS° and explain your reasoning using moles of gas.
ProcessΔS signReason
Solid melting to liquidPositiveParticles gain translational freedom
Liquid vaporizing to gasPositive (large)Large increase in volume and freedom
Gas compressed to smaller volumeNegativeFewer accessible positions
3 mol gas → 1 mol gas (reaction)NegativeFewer moles of gas means fewer microstates
Increasing temperature of a gasPositiveBroader kinetic energy distribution
9.2

Absolute Entropy and Entropy Change

Unlike enthalpy, entropy has a true absolute value anchored at zero for a perfect crystal at 0 K (Third Law). Standard molar entropy values S° are tabulated and used to calculate ΔS° for reactions using a products-minus-reactants summation, just like Hess's law for enthalpy.

  • ΔS°reaction = ΣS°products - ΣS°reactants: Multiply each S° by its stoichiometric coefficient, sum the products, then subtract the sum of the reactants.
  • Units: Standard molar entropy S° has units of J/(mol·K), not kJ. Watch for unit mismatches when combining with ΔH° in kJ.
  • State matters: Always include the physical state when using tabulated S° values; S°(H2O, g) is much larger than S°(H2O, l).
  • Absolute reference: Because entropy has an absolute zero, S° values are always positive for real substances above 0 K.
Using tabulated S° values, calculate ΔS° for N2(g) + 3H2(g) → 2NH3(g) and explain whether the sign matches your prediction from moles of gas.
9.3

Gibbs Free Energy and Kinetic vs. Thermodynamic Control

Gibbs free energy (ΔG°) combines enthalpy and entropy into a single criterion for thermodynamic favorability. A negative ΔG° means the process is thermodynamically favored under standard conditions. However, a favorable ΔG° does not guarantee the reaction occurs at a measurable rate. When a high activation energy prevents a favorable reaction from proceeding, the system is under kinetic control.

  • ΔG° = ΔH° - TΔS°: Temperature determines which sign combinations of ΔH° and ΔS° produce a negative ΔG°. When ΔH° and ΔS° have opposite signs, temperature controls favorability.
  • Thermodynamically favored: ΔG° < 0 means products are favored; ΔG° > 0 means reactants are favored. Avoid the word spontaneous on the AP exam.
  • ΔG°reaction = ΣΔG°f products - ΣΔG°f reactants: An alternative calculation route using standard free energies of formation from a data table.
  • Kinetic control: A thermodynamically favored reaction with a high activation energy will not proceed at a measurable rate. The system is not at equilibrium; it is kinetically trapped.
  • Activation energy: The energy barrier that must be overcome for a reaction to proceed. A catalyst lowers activation energy without changing ΔG°.
A reaction has ΔH° = +50 kJ/mol and ΔS° = +200 J/(mol·K). At what temperature does the reaction become thermodynamically favored? If the reaction still does not occur at that temperature, what explains this?
ΔH°ΔS°Favored at...
NegativePositiveAll temperatures
PositiveNegativeNo temperature (never favored)
NegativeNegativeLow temperatures only
PositivePositiveHigh temperatures only
9.5

Free Energy, Equilibrium, and Dissolution

ΔG° and K describe the same equilibrium position from two different angles. A large negative ΔG° corresponds to a large K (products strongly favored); a large positive ΔG° corresponds to a small K (reactants strongly favored). Dissolution applies this framework to salts, where ΔG° of dissolution reflects competing enthalpy and entropy contributions.

  • ΔG° = -RT ln K: Negative ΔG° gives K > 1; positive ΔG° gives K < 1; ΔG° near zero gives K near 1.
  • K = e^(-ΔG°/RT): Equivalent form; useful for estimating K magnitude when ΔG° is much larger or smaller than RT (~2.5 kJ/mol at 298 K).
  • Qualitative estimation: When |ΔG°| >> RT, K deviates strongly from 1. When ΔG° is near zero, K is close to 1 and neither products nor reactants are strongly favored.
  • Free energy of dissolution: ΔG° for dissolving a salt reflects three factors: breaking the lattice (endothermic), reorganizing the solvent (entropy cost), and forming ion-dipole interactions (exothermic). These often partially cancel, making predictions difficult.
  • Solubility and temperature: If dissolution is endothermic overall, solubility increases with temperature. If exothermic, solubility decreases with temperature.
A reaction has ΔG° = -17.1 kJ/mol at 298 K. Estimate K qualitatively and then calculate it using ΔG° = -RT ln K.
9.7

Coupled Reactions

A thermodynamically unfavorable reaction (ΔG° > 0) can be driven by coupling it to a favorable reaction (ΔG° < 0) that shares a common intermediate. The total ΔG° is the sum of the individual ΔG° values. If the sum is negative, the overall coupled process is thermodynamically favored.

  • Common intermediate: Coupled reactions must share at least one intermediate so that the individual reactions add to give the desired overall reaction.
  • ATP coupling: In biological systems, ATP hydrolysis (ΔG° < 0) is coupled to unfavorable biosynthetic reactions. The shared phosphate intermediate links the two processes.
  • External energy sources: Electrical energy drives electrolytic cells; light drives photosynthesis (CO2 to glucose). Both are examples of external energy making unfavorable processes occur.
  • Adding ΔG° values: Write out both reactions, confirm they share an intermediate, add them to get the net reaction, and add their ΔG° values to determine overall favorability.
Reaction A has ΔG° = +25 kJ/mol and reaction B has ΔG° = -40 kJ/mol. If they share a common intermediate, is the coupled process thermodynamically favored? What is the overall ΔG°?
9.8

Electrochem­ical Cells and Cell Potential

Galvanic cells use thermodynamically favored redox reactions to generate voltage. Electrolytic cells use an external power source to drive unfavorable reactions. In both cell types, oxidation occurs at the anode and reduction occurs at the cathode. Standard cell potential E°cell connects directly to ΔG° through ΔG° = -nFE°.

  • Galvanic vs. electrolytic: Galvanic cells: ΔG° < 0, E°cell > 0, no external power needed. Electrolytic cells: ΔG° > 0, E°cell < 0, external power required.
  • Anode and cathode: Oxidation always occurs at the anode; reduction always occurs at the cathode. Electrons flow through the external wire from anode to cathode.
  • Salt bridge: Maintains electrical neutrality by allowing ion flow between half-cells without mixing the solutions. Without it, the cell stops working.
  • E°cell = E°cathode - E°anode: Use tabulated standard reduction potentials. The half-reaction with the higher reduction potential is the cathode.
  • ΔG° = -nFE°: n is the moles of electrons transferred in the balanced redox equation; F is 96,485 C/mol. A positive E°cell gives a negative ΔG°, confirming thermodynamic favorability.
For a Zn-Cu galvanic cell (E°(Zn2+/Zn) = -0.76 V, E°(Cu2+/Cu) = +0.34 V), identify the anode and cathode, calculate E°cell, and determine ΔG° for the transfer of 2 moles of electrons.
FeatureGalvanic CellElectrolytic Cell
ΔG°NegativePositive
E°cellPositiveNegative
Energy flowProduces electrical energyConsumes electrical energy
Anode chargeNegativePositive
ExampleZn-Cu Daniell cellElectroplating, charging a battery
9.10

Nonstandard Conditions and Faraday's Law

Under nonstandard conditions, cell potential shifts from E°cell depending on the reaction quotient Q. The cell is always moving toward equilibrium, so E approaches zero as Q approaches K. Faraday's law connects the charge passed through an electrolytic cell to the mass of material deposited or removed at an electrode.

  • Nernst equation (qualitative): When Q < 1 (reactants favored), the cell is farther from equilibrium than standard conditions and |E| > |E°|. When Q > 1, |E| < |E°|. At Q = K, E = 0.
  • Le Chatelier does not apply: Electrochemical systems are not at equilibrium, so Le Chatelier's principle cannot be used to predict shifts. Use Q vs. K reasoning instead.
  • Concentration cell: A cell where both electrodes are the same material but differ in electrolyte concentration. Electrons flow from the lower-concentration side (anode) to the higher-concentration side (cathode) to reach equilibrium.
  • I = q/t: Current (amperes) equals charge (coulombs) divided by time (seconds). Rearrange to find charge from current and time.
  • Faraday's law calculation chain: Convert current and time to charge (q = I x t), then to moles of electrons (divide by 96,485 C/mol), then use stoichiometry of the half-reaction to find moles of substance, then convert to mass using molar mass.
A current of 2.00 A is passed through a solution of CuSO4 for 965 seconds. How many grams of copper are deposited at the cathode? (Cu2+ + 2e- → Cu, M = 63.55 g/mol)

Practice AP Chem unit 9 questions

Try stimulus-based AP practice questions and written prompts after you review the notes.

Example stimulus-based MCQs

open all practice
bar_chart

Stimulus-based practice question

Standard cell potentials are measured for the reaction M2+(aq)+H2(g)M(s)+2H+(aq)M^{2+}(aq) + H_2(g) \rightarrow M(s) + 2H^+(aq) with several unknown metals paired with a standard hydrogen electrode. The bar chart shows EcellE^\circ_{\text{cell}} values for M1, M2, M3, and M4.

Question

Which claim is best supported by the experimental data?

Reaction with M2 is favored because its EcellE^\circ_{\text{cell}} is +0.80 V, so ΔG\Delta G^\circ is negative.

Reaction with M4 is favored because its EcellE^\circ_{\text{cell}} is -0.76 V, so ΔG\Delta G^\circ is negative.

Reaction with M1 is unfavored because its EcellE^\circ_{\text{cell}} is +0.45 V, so ΔG\Delta G^\circ is positive.

Reaction with M3 is unfavored because its EcellE^\circ_{\text{cell}} is -0.25 V, so ΔG\Delta G^\circ is negative.

bar_chart

Stimulus-based practice question

A galvanic cell is constructed with Cu(s) and Ag(s) electrodes in 1.0 M solutions of their nitrate salts. The mass of each electrode is measured after the cell operates for 30 minutes. A claim is made that the copper electrode is the anode.

Question

Which reasoning best justifies the claim?

Solid Cu atoms lose electrons to form aqueous ions, causing the mass to decrease.

Aqueous Cu ions gain electrons to form solid atoms, causing the mass to decrease.

Solid Cu atoms gain electrons to form aqueous ions, causing the mass to decrease.

Aqueous Cu ions lose electrons to form solid atoms, causing the mass to decrease.

Example FRQs

open all FRQs
SAQ

Galvanic cell electron flow and electrode identification

4. A student constructs a galvanic cell to investigate the thermodynamic properties of the reaction between aluminum and nickel. The experimental setup is shown in Figure 1, and the relevant standard reduction potentials are provided in Table 1.

Table 1. Standard Reduction Potentials at 25°C

Half-Reaction

Standard Reduction Potential E° (V)

Al³⁺(aq) + 3e⁻ → Al(s)

−1.66

Ni²⁺(aq) + 2e⁻ → Ni(s)

−0.25

A.

Based on the data in Table 1, identify the metal used for the electrode that acts as the cathode in the galvanic cell.

Figure 1. Galvanic cell setup (Al/Al³⁺ || Ni²⁺/Ni) with 1.0 M solutions and KNO₃ salt bridge; voltmeter shows a positive reading.

Figure 1
B.

In Figure 1, draw a SINGLE arrow on the wire connecting the electrodes to indicate the direction of electron flow as the cell operates.

C.

The student operates the cell at 298 K and observes the cell potential.

i.

Propose a change to the concentration of Ni²⁺(aq) (increase or decrease relative to 1.0 M) that would result in a cell potential greater than the standard cell potential.

ii.

Calculate the standard Gibbs free energy change, ΔG\Delta G^\circ, in kJ/mol, for the thermodynamically favored reaction that occurs in the cell. (Assume Faraday's constant F=96,485 C/mol eF = 96,485 \text{ C/mol e}^-)

FRQ

Zinc-nickel galvanic cell potential and spontaneity

2. Answer the following questions about an electrochemical cell involving zinc and nickel.

A student constructs a galvanic cell at 298 K using a zinc electrode immersed in a 1.0 M Zn(NO₃)₂ solution and a nickel electrode immersed in a 1.0 M Ni(NO₃)₂ solution, as shown in Figure 1. A salt bridge containing KNO₃(aq) connects the two half-cells.

Table 1. Standard Reduction Potentials at 25°C

Half-Reaction

Standard Reduction Potential, E° (V)

Zn²⁺(aq) + 2e⁻ → Zn(s)

−0.76

Ni²⁺(aq) + 2e⁻ → Ni(s)

−0.25

A.

Write the balanced net ionic equation for the thermodynamically favored reaction that occurs in the galvanic cell. Refer to the standard reduction potentials in Table 1.

Figure 1. Galvanic cell at 298 K: Zn(s)|Zn2+(1.0 M) || Ni2+(1.0 M)|Ni(s) with a KNO3(aq) salt bridge and an external voltmeter

Figure 1
B.

Calculate the standard cell potential, E°cell, for the reaction in Figure 1.

C.

Calculate the value of the standard change in Gibbs free energy, ΔG°, for the reaction in kJ/molrxn.

The student prepares a second galvanic cell at 298 K with the same electrodes but different ion concentrations. In this new cell, [Zn²⁺] = 1.50 M and [Ni²⁺] = 0.010 M.

D.

Calculate the value of the cell potential, Ecell, for this second cell at 298 K.

E.

Calculate the value of the equilibrium constant, K, for the reaction at 298 K.

The original galvanic cell (with 1.0 M concentrations) is allowed to operate for 45.0 minutes. During this time, the cell produces a constant average current of 0.750 A.

F.
i.

Calculate the mass, in grams, of solid nickel deposited on the cathode during this 45.0-minute period.

ii.

Does the mass of the zinc electrode increase, decrease, or remain the same during this operation? Justify your answer.

FRQ

Silver and chromium electrochemical cell

1. Answer the following questions about an electrochemical cell constructed using silver and chromium electrodes.

The standard reduction potentials for the half-reactions related to the cell are given in the table in Figure 1.

Figure 1. Standard Reduction Potentials at 25°C

Table 1
A.
i.

Write the balanced net ionic equation for the thermodynamically favored reaction that occurs in the cell.

ii.

Calculate the standard cell potential, E°cell, for the reaction.

B.

Calculate the standard Gibbs free energy change, ΔG°, for the reaction in kJ/molrxn.

The galvanic cell is constructed as shown in Figure 2.

Figure 2. Galvanic cell setup

Figure 2
C.

In the salt bridge shown in Figure 2, do the nitrate ions, NO₃⁻, migrate toward the beaker containing the chromium electrode or toward the beaker containing the silver electrode? Justify your answer.

The cell operates for a period of time, and the concentrations of the ions change. The new concentration of Ag⁺(aq) is 0.010 M, and the concentration of Cr³⁺(aq) is 1.0 M.

D.
i.

Calculate the value of the reaction quotient, Q, under these new conditions.

ii.

Is the cell potential, Ecell, under these conditions greater than, less than, or equal to the standard cell potential, E°cell, calculated in part A? Justify your answer.

E.

Calculate the value of the equilibrium constant, K, for the reaction at 25°C.

In a separate experiment, a student uses an external power source to plate silver metal onto an object from a solution of AgNO₃(aq). The student applies a constant current of 2.00 amperes for 30.0 minutes.

F.
i.

Calculate the mass, in grams, of silver metal deposited on the object.

ii.

If the student used a solution of Cu(NO₃)₂ instead of AgNO₃ and applied the same current for the same amount of time to plate copper metal, would the mass of copper produced be greater than, less than, or equal to the mass of silver calculated in part F(i)? Justify your answer.

Key terms

TermDefinition
ΔG° = ΔH° − TΔS°The fundamental equation relating Gibbs free energy change to enthalpy change, entropy change, and absolute temperature. When ΔG° < 0, the process is thermodynamically favored.
ΔG° = -RT ln KRelates standard free energy change to the equilibrium constant. Negative ΔG° gives K > 1 (products favored); positive ΔG° gives K < 1 (reactants favored).
ΔG° = -nFE°Connects standard Gibbs free energy change to standard cell potential, where n is moles of electrons transferred and F is the Faraday constant (96,485 C/mol).
ΔS°reaction = ΣS°products - ΣS°reactantsCalculates standard entropy change of a reaction from tabulated standard molar entropy values. Units are J/(mol·K).
microstatesThe number of distinct molecular arrangements available to a system. Entropy increases as the number of accessible microstates increases.
Standard Cell PotentialE°cell = E°cathode - E°anode, calculated from standard reduction potentials. A positive E°cell indicates a thermodynamically favored redox reaction.
Galvanic CellAn electrochemical cell that converts a thermodynamically favored redox reaction (ΔG° < 0, E°cell > 0) into electrical energy. Also called a voltaic cell.
Electrolytic CellAn electrochemical cell that uses an external power source to drive a thermodynamically unfavorable redox reaction (ΔG° > 0, E°cell < 0).
AnodeThe electrode where oxidation occurs in any electrochemical cell. Electrons leave the cell through the anode into the external circuit.
CathodeThe electrode where reduction occurs in any electrochemical cell. Electrons arrive at the cathode from the external circuit.
Faraday constant96,485 coulombs per mole of electrons. Used to convert between charge passed and moles of electrons in Faraday's law calculations.
I = q/tCurrent (amperes) equals charge (coulombs) divided by time (seconds). The starting equation for all Faraday's law stoichiometry problems.
Nonstandard ConditionsAny conditions where concentrations, pressures, or temperature differ from standard state (1 M, 1 atm, 298 K). Cell potential shifts from E°cell based on the reaction quotient Q.
Activation EnergyThe energy barrier a reaction must overcome to proceed. A high activation energy can prevent a thermodynamically favored reaction from occurring at a measurable rate, placing it under kinetic control.
Salt BridgeConnects the two half-cells of a galvanic cell, allowing ion flow to maintain electrical neutrality without mixing the electrode solutions.

Common unit 9 mistakes

Confusing thermodynamic favorability with reaction rate

A negative ΔG° means a process is thermodynamically favored, not that it is fast. Diamond converting to graphite has ΔG° < 0 but does not occur at a measurable rate at room temperature because of a very high activation energy. Always separate these two ideas in your explanations.

Mixing up units for ΔS° and ΔH°

Standard molar entropy S° is in J/(mol·K), but ΔH° and ΔG°f are typically in kJ/mol. When using ΔG° = ΔH° - TΔS°, convert ΔS° to kJ/(mol·K) by dividing by 1000 before substituting.

Applying Le Chatelier's principle to electrochemical cells

Electrochemical cells are not at equilibrium while operating, so Le Chatelier's principle does not apply. Use Q vs. K reasoning to explain how concentration changes affect cell potential.

Reversing anode and cathode in electrolytic cells

In galvanic cells the anode is negative; in electrolytic cells the anode is positive (connected to the positive terminal of the power supply). The rule that oxidation occurs at the anode and reduction at the cathode never changes, but the charge on the electrode does.

Forgetting to account for stoichiometric coefficients in Faraday's law

The number of electrons transferred (n) comes from the balanced half-reaction, not from the overall reaction. For Cu2+ + 2e- → Cu, n = 2 per mole of copper. Using n = 1 here would double the calculated mass.

How this unit shows up on the AP exam

Justify thermodynamic favorability with multiple lines of reasoning

AP Chemistry questions frequently ask you to explain whether a process is thermodynamically favored and to support your answer using ΔG°, ΔH°, ΔS°, K, or E°cell. Practice connecting these quantities explicitly: state the sign of ΔG°, explain which enthalpy and entropy contributions produce that sign, and confirm with K > 1 or E°cell > 0 as appropriate. A complete justification uses at least two connected pieces of evidence.

Distinguish thermodynamic and kinetic arguments in written responses

A common task in AP Chemistry is to explain why a thermodynamically favored process does not occur at a measurable rate. Your response must name activation energy as the kinetic barrier and explicitly state that ΔG° < 0 does not determine rate. Mixing up these two concepts in a written explanation is a frequent source of lost points.

Set up and execute multi-step electrochemistry calculations

Electrochemistry problems often chain several calculations: identify half-reactions and assign anode/cathode, calculate E°cell, convert to ΔG° using ΔG° = -nFE°, and then apply Faraday's law to find mass deposited or time required. On the AP exam, show each conversion step clearly and include units throughout. Errors in identifying n (moles of electrons from the balanced half-reaction) are the most common source of incorrect answers in these problems.

Final unit 9 review checklist

  • Predict ΔS° sign and magnitudeFor any process, identify whether matter or energy becomes more or less dispersed. Apply the moles-of-gas rule for reactions and the phase-change rule for physical processes.
  • Calculate ΔS° and ΔG° from tabulated valuesUse ΔS°reaction = ΣS°products - ΣS°reactants and ΔG°reaction = ΣΔG°f products - ΣΔG°f reactants. Watch units: S° is in J/(mol·K) and ΔG°f is in kJ/mol.
  • Apply ΔG° = ΔH° - TΔS° across temperature scenariosUse the four-case sign table (ΔH° and ΔS° combinations) to determine at which temperatures a process is thermodynamically favored. Identify the crossover temperature when ΔG° = 0.
  • Connect ΔG° to K using ΔG° = -RT ln KGiven ΔG°, determine whether K > 1 or K < 1 and estimate its magnitude. Given K, determine the sign and approximate magnitude of ΔG°.
  • Analyze electrochemical cellsFor any cell, identify the anode and cathode, the direction of electron flow, the role of the salt bridge, and whether the cell is galvanic or electrolytic. Calculate E°cell and ΔG° using ΔG° = -nFE°.
  • Reason about nonstandard cell potentialExplain qualitatively how Q relative to 1 and K affects cell potential. Know that E = 0 at equilibrium and that Le Chatelier's principle does not apply to electrochemical systems.
  • Solve Faraday's law problemsChain the calculation: current and time to charge (q = I x t), charge to moles of electrons (divide by 96,485 C/mol), moles of electrons to moles of substance via half-reaction stoichiometry, then to mass.

How to study unit 9

Step 1: Build entropy intuition (9.1-9.2)Read the topic guides for 9.1 and 9.2. Practice predicting ΔS° sign for phase changes, gas expansions, and reactions by counting moles of gas. Then practice the ΔS°reaction = ΣS°products - ΣS°reactants calculation with tabulated values, paying attention to physical states and units.
Step 2: Work through Gibbs free energy and its limits (9.3-9.4)Use the four-case ΔH°/ΔS° sign table to predict thermodynamic favorability at different temperatures. Practice calculating ΔG° both from ΔG° = ΔH° - TΔS° and from formation values. Then practice writing explanations that separate thermodynamic favorability from kinetic control using activation energy.
Step 3: Connect ΔG° to K and dissolution (9.5-9.6)Practice converting between ΔG° and K using ΔG° = -RT ln K. Focus on qualitative estimation: large negative ΔG° means very large K. Apply this framework to dissolution problems, identifying the enthalpy and entropy contributions to ΔG° of dissolution and explaining why predictions can be difficult.
Step 4: Analyze coupled reactions and electrochemical cells (9.7-9.9)Practice adding ΔG° values for coupled reactions and identifying common intermediates. Then work through galvanic and electrolytic cell diagrams: label anode, cathode, electron flow, and salt bridge. Calculate E°cell from standard reduction potentials and convert to ΔG° using ΔG° = -nFE°.
Step 5: Apply nonstandard conditions and Faraday's law (9.10-9.11)Practice qualitative Nernst reasoning: determine whether a concentration change increases or decreases |E| relative to E°cell. Then work Faraday's law problems from start to finish using the full dimensional analysis chain from current and time to mass deposited. Use available practice questions to check your setup before solving.

More ways to review

Topic study guides

Open the individual guides for Unit 9 when you want a closer review of one topic.

browse guides

FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

practice FRQs

Cram archive videos

Watch past review streams filtered to Unit 9 when you want a video walkthrough.

open videos

Cheatsheets

Use unit cheatsheets for a quick visual review after you work through the notes.

open cheatsheets

Score calculator

Estimate your broader AP score goal after you review the course and exam format.

open calculator

Frequently Asked Questions

What topics are covered in AP Chem Unit 9?

AP Chem Unit 9 covers 11 topics across thermodynamics and electrochemistry: entropy (9.1, 9.2), Gibbs free energy and thermodynamic favorability (9.3), thermodynamic vs. kinetic control (9.4), free energy and equilibrium (9.5), free energy of dissolution (9.6), coupled reactions (9.7), galvanic and electrolytic cells (9.8), cell potential and free energy (9.9), cell potential under nonstandard conditions (9.10), and electrolysis and Faraday's Law (9.11). The unit connects energy changes at the molecular level to macroscopic outcomes, so you'll see how entropy, Gibbs free energy, and electrochemical cells all tie together. Check out AP Chem Unit 9 for topic-by-topic breakdowns.

How much of the AP Chem exam is Unit 9?

AP Chem Unit 9 makes up 7-9% of the AP exam. That weight covers thermodynamics and electrochemistry, including entropy, Gibbs free energy, equilibrium relationships, galvanic and electrolytic cells, and Faraday's Law. It's a focused unit, but the concepts show up in calculation-heavy multiple-choice and free-response questions. Because the percentage is on the smaller side, students sometimes underestimate this unit. The math-intensive topics like cell potential and Gibbs free energy calculations tend to appear on the FRQ section, so solid practice here pays off.

What's on the AP Chem Unit 9 progress check (MCQ and FRQ)?

The AP Chem Unit 9 progress check includes both MCQ and FRQ parts drawn from all 11 topics in the unit. The MCQ section tests conceptual understanding of entropy, Gibbs free energy, thermodynamic favorability, and cell potential. The FRQ part typically asks you to calculate delta-G, interpret equilibrium relationships using free energy, or analyze electrochemical cells including electrolysis. For the progress check FRQ, expect to show your work on Gibbs free energy calculations, connect free energy to equilibrium constants, and explain how electrolysis and Faraday's Law apply to a given scenario. Practicing those question types on AP Chem Unit 9 before you submit the progress check is a smart move.

How do I practice AP Chem Unit 9 FRQs?

AP Chem Unit 9 FRQs most often focus on Gibbs free energy calculations, the relationship between free energy and equilibrium, cell potential under nonstandard conditions, and electrolysis with Faraday's Law. To practice, work through problems that ask you to calculate delta-G from delta-H and delta-S, connect delta-G to the equilibrium constant K, and determine the amount of substance produced during electrolysis. A few tips that help: - Write out every step of your calculation, since partial credit is awarded for correct setup even if the final answer is wrong. - Practice interpreting the sign of delta-G to predict thermodynamic favorability. - For electrochemistry FRQs, make sure you can draw and label a galvanic cell and explain the direction of electron flow. You can find FRQ-style practice matched to these topics at AP Chem Unit 9.

Where can I find AP Chem Unit 9 practice questions?

For AP Chem Unit 9 multiple-choice and practice test questions, AP Chem Unit 9 is the best starting point, with MCQ and FRQ practice organized by topic across all 11 topics in the unit. Look for questions covering entropy, Gibbs free energy, electrolysis, and cell potential, since those are the highest-yield areas for both MCQ and the full practice test. When you work through MCQs, focus on questions that ask you to predict thermodynamic favorability, interpret free energy and equilibrium relationships, and calculate cell potential. Mixing conceptual MCQs with calculation-based practice gives you the best coverage of what shows up on the real exam.

How should I study AP Chem Unit 9?

Start AP Chem Unit 9 by building a strong foundation in entropy before moving to Gibbs free energy, since delta-G ties together delta-H, delta-S, and temperature in one equation you'll use constantly. Once that relationship clicks, connecting free energy to equilibrium constants and cell potential becomes much more straightforward. A concrete study plan that works: 1. Learn the entropy rules (9.1-9.2): predict whether delta-S is positive or negative from the reaction. 2. Practice Gibbs free energy calculations (9.3) until the sign conventions feel automatic. 3. Work through the free energy and equilibrium connection (9.5) using real K values. 4. Study galvanic vs. electrolytic cells (9.8) side by side so you don't mix them up. 5. Finish with electrolysis and Faraday's Law (9.11), which is very calculation-driven. Review topic by topic at AP Chem Unit 9, then test yourself with progress check-style questions to find gaps before the exam.

Ready to review Unit 9?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.