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Honors Chemistry Unit 8 Review: Thermochemistry

Thermochemistry tracks the energy that flows in and out of chemical reactions and physical changes as heat and work. By the end of this unit you should be able to tell exothermic from endothermic processes by sign, calculate ΔH using Hess's law or formation enthalpies, and turn calorimeter temperature data into a heat of reaction.

Read the overview first, then work through each topic note and try the checkpoint question before moving on.

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What is Honors Chemistry unit 8?

This unit connects the particle picture of matter to energy you can actually measure. You'll define the system and surroundings, follow heat and work across that boundary, and use enthalpy to describe how much energy a reaction releases or absorbs.

Honors Chemistry Unit 8 covers thermochemistry, the study of energy changes during chemical reactions and physical changes. It starts with the forms of energy and the difference between heat, work, and temperature. Next comes the first law of thermodynamics (ΔU = q + w) and enthalpy change (ΔH), including how to calculate ΔH with Hess's law, standard enthalpies of formation, and bond enthalpies. It ends with calorimetry, where you use q = mcΔT and temperature data from a coffee cup or bomb calorimeter to find the heat of a reaction.

Energy moves between a system and its surroundings, and the signs always describe the system.

The system is the reaction you're studying, and the surroundings are everything else, including the water and the beaker. A positive q means heat flows into the system. A negative q means the system releases heat and the surroundings warm up.

Enthalpy change is the heat of a reaction at constant pressure.

Most lab reactions open to the air occur at approximately constant pressure. When pressure-volume work is the only work involved, ΔH equals the heat exchanged at constant pressure. Exothermic reactions have ΔH < 0, and endothermic reactions have ΔH > 0. Because enthalpy is a state function, you can find ΔH by adding reaction steps with Hess's law or by using tabulated formation values.

Calorimetry turns a temperature change into an energy value.

You measure the temperature change of the surroundings rather than the reaction's heat itself. Use q = mcΔT to calculate the heat gained or lost by the solution or water. If the calorimeter's heat capacity and heat loss are negligible, the reaction's heat has the same magnitude with the opposite sign.

Energy is conserved, so every joule a reaction gives off shows up somewhere else.

The first law says the energy lost by the system equals the energy gained by the surroundings. That single idea explains the sign conventions, lets Hess's law work, and makes calorimetry possible. If you can track where the energy goes, you can solve almost every problem in this unit.

Honors Chemistry unit 8 topics

8.3

Calorimetry

Calorimetry determines a reaction's heat from the temperature change of its surroundings, such as a solution, water bath, and calorimeter.

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Unit 8 review notes

8.1

Energy, Work, and Heat

Energy is the ability to do work or transfer heat, and it's measured in joules (J). Kinetic energy is energy of motion, and potential energy comes from position or arrangement. Chemical energy is potential energy associated with the arrangement and electrostatic interactions of atoms and electrons. Breaking bonds requires energy, while forming bonds releases energy.

Heat and temperature are not the same thing. Temperature measures the average kinetic energy of the particles in a sample. Heat (q) is energy that moves from a hotter object to a cooler one because of a temperature difference. A full bathtub at 40°C holds far more thermal energy than a cup of tea at 90°C, even though the tea has the higher temperature.

Work (w) is energy transferred when a force moves something. In chemistry this is usually pressure-volume work. At constant external pressure, w=−PextΔVw = -P_{ext}\Delta V. When a gas expands against the atmosphere, ΔV\Delta V is positive, so w is negative and the system transfers energy to the surroundings as work.

In an exothermic process the system releases heat, so the surroundings get warmer. In an endothermic process the system absorbs heat, so the surroundings get cooler. An instant cold pack feels cold because dissolving ammonium nitrate pulls heat out of your hand.

For units, 1 cal = 4.184 J, and the Calorie on a food label is a kilocalorie, or 4184 J.

  • Heat (q): Heat is energy transferred between objects because they are at different temperatures.
  • Temperature: Temperature is a measure of the average kinetic energy of the particles in a substance.
  • Pressure-volume work: Pressure-volume work is energy transferred when a gas expands or is compressed against a constant external pressure, and it is calculated with w = -P_extΔV.
  • Chemical energy: Chemical energy is potential energy associated with the arrangement and electrostatic interactions of atoms and electrons in a substance.

Check yourself. You dissolve a salt in water and the beaker gets colder. Is the dissolving process exothermic or endothermic, and what is the sign of q for the system? (Answer: The process is endothermic. The system absorbed heat from the water, so q is positive.)

FeatureExothermicEndothermic
Direction of heatSystem to surroundingsSurroundings to system
Sign of q and ΔHNegativePositive
Surroundings temperatureRisesFalls
ExampleBurning methane, ΔH = -890 kJ/molDissolving NH₄NO₃ in a cold pack
8.2

First Law of Thermodynamics and Enthalpy Changes

The first law of thermodynamics says energy can't be created or destroyed. For a system, ΔU=q+w\Delta U = q + w, where ΔU\Delta U is the change in internal energy. If a system absorbs 250 J of heat and does 100 J of work on its surroundings, ΔU=+250+(−100)=+150\Delta U = +250 + (-100) = +150 J.

Enthalpy (H) is defined as H=U+PVH = U + PV. At constant pressure, when pressure-volume work is the only work involved, the enthalpy change equals the heat exchanged, so ΔH=qp\Delta H = q_p. ΔH depends on the physical states involved and scales with the coefficients. Doubling a reaction doubles ΔH, and reversing it flips the sign.

You can calculate ΔH three ways. Hess's law adds the ΔH values of steps that sum to the overall reaction. Standard enthalpies of formation use ΔHrxn∘=∑nΔHf∘(products)−∑nΔHf∘(reactants)\Delta H^\circ_{rxn} = \sum n\Delta H^\circ_f(\text{products}) - \sum n\Delta H^\circ_f(\text{reactants}), where any element in its standard state has ΔHf∘=0\Delta H^\circ_f = 0. Bond enthalpies give an estimate, ΔH≈∑(bonds broken)−∑(bonds formed)\Delta H \approx \sum(\text{bonds broken}) - \sum(\text{bonds formed}).

Worked example. Find ΔH° for CH4(g)+2O2(g)→CO2(g)+2H2O(l)CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l). Use ΔHf∘\Delta H^\circ_f values of -74.8 kJ/mol for CH₄, -393.5 for CO₂, -285.8 for H₂O(l), and 0 for O₂. Products give −393.5+2(−285.8)=−965.1-393.5 + 2(-285.8) = -965.1 kJ. Reactants give −74.8+2(0)=−74.8-74.8 + 2(0) = -74.8 kJ. So ΔH∘=−965.1−(−74.8)=−890.3\Delta H^\circ = -965.1 - (-74.8) = -890.3 kJ, which is strongly exothermic.

  • Internal energy (U): Internal energy is the total kinetic and potential energy of all the particles in a system.
  • State function: A state function is a property, such as H or U, whose change depends only on the starting and ending states rather than the path.
  • Hess's law: The ΔH of an overall reaction equals the sum of the ΔH values of any set of steps that add up to it.
  • Standard enthalpy of formation: Standard enthalpy of formation is the enthalpy change when one mole of a substance forms from its elements in their standard states at a specified temperature and a standard pressure of 1 bar. Tables commonly report values at 25°C.

Check yourself. The reaction A → 2B has ΔH = +40 kJ. What is ΔH for 4B → 2A? (Answer: -80 kJ. Reversing the reaction changes the sign to -40 kJ, and doubling the coefficients doubles ΔH.)

8.3

Calorimetry

Calorimetry determines a reaction's heat from the temperature change of its surroundings, such as a solution, water bath, and calorimeter. Because energy is conserved, qrxn=−qsurroundingsq_{rxn} = -q_{surroundings}. You may use qrxn=−qwaterq_{rxn} = -q_{water} when the water is treated as the only part of the surroundings that absorbs or releases heat.

The heat gained or lost by a substance is q=mcΔTq = mc\Delta T, where m is mass in grams, c is specific heat in J/g·°C, and ΔT=Tfinal−Tinitial\Delta T = T_{final} - T_{initial}. Water's specific heat is a high 4.18 J/g·°C, so water absorbs a lot of heat with a small temperature change.

A coffee cup calorimeter usually consists of nested foam cups with a lid and thermometer. It operates at approximately constant pressure, so you use the temperature change to infer the reaction's ΔH, assuming pressure-volume work is the only work involved. Heat leaking to the room and heat absorbed by the cup are common sources of error. A bomb calorimeter keeps volume constant, so its calibrated temperature change gives qvq_v and therefore ΔU for reactions such as combustion.

Worked example. You mix 50.0 mL of 1.0 M HCl with 50.0 mL of 1.0 M NaOH, and the temperature rises from 22.0°C to 28.7°C. Treat the solution as 100.0 g of water and ignore heat absorbed by the cup. qwater=(100.0)(4.18)(6.7)=2.8×103q_{water} = (100.0)(4.18)(6.7) = 2.8 \times 10^3 J, so qrxn=−2.8q_{rxn} = -2.8 kJ. The reaction formed 0.0500 mol of water, so ΔH=−2.8÷0.0500=−56\Delta H = -2.8 \div 0.0500 = -56 kJ/mol.

  • Specific heat capacity (c): Specific heat capacity is the heat needed to raise 1 gram of a substance by 1°C, such as 4.18 J/g·°C for water.
  • Thermal equilibrium: Thermal equilibrium occurs when two objects in contact reach the same temperature and net heat transfer stops.
  • Coffee cup calorimeter: A coffee cup calorimeter is an insulated container open to the air that works at approximately constant pressure, so its data can be used to find ΔH.
  • Bomb calorimeter: A bomb calorimeter is a sealed steel container surrounded by water that works at constant volume, so its data can be used to find ΔU.

Check yourself. How much heat does 200.0 g of water absorb when it warms from 20.0°C to 25.0°C? (Answer: q = (200.0)(4.18)(5.0) = 4.2 × 10³ J, or 4.2 kJ.)

FeatureCoffee cup calorimeterBomb calorimeter
Condition held constantPressure (approximately)Volume
Quantity determinedΔH, inferred from q at constant pressureΔU, from q at constant volume
Typical useDissolving, neutralization, aqueous reactionsCombustion of fuels and foods
PrecisionLower, some heat escapesHigher, well insulated and sealed

Key terms

TermDefinition
SystemThe system is the part of the universe you are studying, usually the reacting chemicals.
SurroundingsThe surroundings are everything outside the system, such as the water, container, and air around a reaction.
ExothermicAn exothermic process releases heat to the surroundings and has a negative ΔH.
EndothermicAn endothermic process absorbs heat from the surroundings and has a positive ΔH.
First law of thermodynamicsEnergy is conserved, so a system's energy change equals the heat plus work it exchanges, ΔU = q + w.
Enthalpy change (ΔH)When pressure-volume work is the only work involved, enthalpy change is the heat absorbed or released by a reaction at constant pressure.
Hess's lawThe total ΔH for a reaction is the same no matter which set of steps you use to get from reactants to products.
Bond enthalpyBond enthalpy is the energy needed to break one mole of a particular bond in the gas phase, and it can be used to estimate ΔH.
Specific heat capacitySpecific heat capacity is the heat required to raise the temperature of 1 gram of a substance by 1°C.
CalorimeterA calorimeter is a device that measures the heat of a reaction by tracking the temperature change of its surroundings.

Mistakes to avoid in Thermochemistry

Using the water's heat as the reaction's heat without flipping the sign

When the water warms up because of a reaction, q for the water is positive, so it's tempting to call the reaction positive too. The water gained heat because the reaction lost it, so q_rxn = -q_surroundings. In a constant-pressure calorimeter, a surroundings temperature rise caused by the reaction indicates an exothermic reaction with a negative ΔH.

Treating heat and temperature as the same thing

Temperature is an average particle energy, while heat is energy in transit. A large mass at a lower temperature can hold more thermal energy than a small hot one. Keep them separate by remembering that q depends on mass and specific heat, not just ΔT.

Forgetting coefficients in formation-enthalpy problems

ΔH°f values are per mole, so each one has to be multiplied by its coefficient in the balanced equation. Also remember that elements in their standard states, like O₂(g) or Fe(s), have ΔH°f = 0, not a missing value.

Changing a Hess's law step without adjusting its ΔH

If you reverse a step to match the target reaction, change the sign of its ΔH. If you multiply a step by 2 or 3, multiply its ΔH by the same number. Check your work by confirming the intermediates cancel and the steps add up to exactly the target equation.

Study unit 8 other ways

Ready to review Unit 8?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.