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AP Physics 1 Unit 3 practice questions

Try 10 multiple-choice questions from Unit 3 here. Pick an answer to see why it's right or wrong, then take the timed test above for a full AP-style set.

  1. Question 1

    An object of mass mm moves with speed vv and translational kinetic energy KK. If the object accelerates to a speed of 3v3v while its mass remains constant, which expression represents its new translational kinetic energy?

    3K3K

    6K6K

    9K9K

    27K27K

    Show answer

    Answer: (C)

    Translational kinetic energy depends on the square of the velocity (K∝v2K \propto v^2). Tripling the speed results in a factor of 32=93^2 = 9 change in kinetic energy.

  2. Question 2

    A block of mass mm travels at speed vv with kinetic energy K0K_0. A second block has mass 0.5m0.5m and travels at speed 2v2v. What is the kinetic energy of the second block in terms of K0K_0?

    0.5K00.5 K_0

    1.0K01.0 K_0

    2.0K02.0 K_0

    4.0K04.0 K_0

    Show answer

    Answer: (C)

    Kinetic energy is proportional to mm and v2v^2. The new energy is proportional to (0.5)(22)=(0.5)(4)=2(0.5)(2^2) = (0.5)(4) = 2, resulting in 2.0K02.0 K_0.

  3. Question 3

    A vehicle traveling at speed vv requires a braking distance dd to stop. Assuming the braking force is constant, what braking distance is required if the vehicle is traveling at speed 2v2v?

    dd

    2d\sqrt{2}d

    2d2d

    4d4d

    Show answer

    Answer: (D)

    Stopping distance is proportional to kinetic energy (W=Fd=ΔKW = Fd = \Delta K). Since K∝v2K \propto v^2, doubling speed quadruples kinetic energy, requiring four times the distance to stop.

  4. Question 4

    A stone dropped from height hh reaches the ground with kinetic energy KK. If the stone is instead dropped from height 2h2h and air resistance is negligible, what is its kinetic energy upon reaching the ground?

    2K\sqrt{2}K

    2K2K

    4K4K

    8K8K

    Show answer

    Answer: (B)

    Gravitational potential energy (Ug=mghU_g = mgh) converts directly to kinetic energy. Since Ug∝hU_g \propto h, doubling the height doubles the final kinetic energy.

  5. Question 5

    An observer standing on the ground measures the kinetic energy of a car moving at velocity vv as KK. A second observer is moving in the same direction as the car at velocity v/2v/2. What value does the second observer measure for the car's kinetic energy?

    K/4K/4

    K/2K/2

    KK

    2K2K

    Show answer

    Answer: (A)

    The relative velocity of the car to the observer is v−v/2=v/2v - v/2 = v/2. Since K∝v2K \propto v^2, the measured energy is proportional to (1/2)2=1/4(1/2)^2 = 1/4 of the original value.

  6. Question 6

    A satellite of mass mm orbits a planet in a circular path of radius RR with kinetic energy KK. If the satellite is moved to a circular orbit of radius 2R2R, what is the new kinetic energy? (Note: For a circular orbit, v=GM/Rv = \sqrt{GM/R}).

    K/4K/4

    K/2K/2

    KK

    2K2K

    Show answer

    Answer: (B)

    Orbital velocity squared is inversely proportional to radius (v2∝1/Rv^2 \propto 1/R). Since K∝v2K \propto v^2, doubling the radius halves the kinetic energy.

  7. Question 7

    A cart moves along a track with kinetic energy KK. As it passes under a hopper, sand is dropped into the cart, tripling its total mass while its speed remains constant. What is the new kinetic energy of the cart?

    K/3K/3

    KK

    3K3K

    9K9K

    Show answer

    Answer: (C)

    Translational kinetic energy is directly proportional to mass (K∝mK \propto m). Tripling the mass while keeping speed constant triples the kinetic energy.

  8. Question 8

    Object A has mass mm and speed vv. Object B has mass 4m4m. If both objects have the same translational kinetic energy, what is the speed of Object B?

    v/4v/4

    v/2v/2

    2v2v

    4v4v

    Show answer

    Answer: (B)

    For kinetic energies to be equal (12mv2=12(4m)vB2\frac{1}{2}mv^2 = \frac{1}{2}(4m)v_B^2), v2=4vB2v^2 = 4v_B^2. Taking the square root gives vB=v/2v_B = v/2.

  9. Question 9

    An object has momentum pp and kinetic energy KK. If the object's momentum is doubled while its mass remains constant, what is the new kinetic energy?

    K/2K/2

    2K2K

    4K4K

    8K8K

    Show answer

    Answer: (C)

    Kinetic energy is related to momentum by K=p2/2mK = p^2/2m. Doubling momentum (p→2pp \to 2p) results in a factor of 22=42^2 = 4 increase in kinetic energy.

  10. Question 10

    A block launched by a spring compressed by distance xx has exit kinetic energy KK. If the spring is compressed by distance 3x3x, what is the exit kinetic energy?

    3K3K

    6K6K

    9K9K

    27K27K

    Show answer

    Answer: (C)

    Elastic potential energy (Us=12kx2U_s = \frac{1}{2}kx^2) converts to kinetic energy. Since Us∝x2U_s \propto x^2, tripling the compression increases the energy by a factor of 32=93^2 = 9.

What's on the AP Physics 1 Unit 3 practice test

The standard version takes about 88 minutes and follows the timing and directions of the AP exam, sized to one unit:

  • 20 Multiple Choice Questions (40 minutes)
  • 1 FRQ – FRQ 1 – Mathematical Routines (24 minutes)
  • 1 FRQ – FRQ 2 – Translation Between Representations (24 minutes)

Questions are drawn from 1070 multiple-choice questions and 41 FRQs written for Unit 3, Work, Energy, and Power.

Practice AP Physics 1 Unit 3 FRQs

Answer the unit's free-response questions one at a time and get a score on every part.

Review Unit 3 before you start

Other AP Physics 1 unit tests