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AP Bio Unit 5 Review: Heredity

  • 8–11% of AP multiple choice
  • 6 topics
  • AP exam review verified for 2027

Heredity is the transmission of genetic information from parents to offspring through chromosomes. Meiosis halves the chromosome number to form gametes, fertilization restores it, and the rules of segregation and independent assortment predict how alleles are distributed. When those rules break down, non-Mendelian patterns like linkage, codominance, or sex-linked inheritance appear instead.

Fiveable's AP Biology Unit 5 review covers 6 topics, with guided practice questions for the unit.

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AP Bio unit 5 topics

5.1

Meiosis

Meiosis produces four haploid gametes from one diploid cell through two divisions. Meiosis I separates homologous chromosomes; meiosis II separates sister chromatids. Know each phase, what moves where, and how meiosis differs from mitosis in outcome and genetic content.

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5.2

Meiosis and Genetic Diversity

Crossing over in prophase I, independent assortment in metaphase I, and random fertilization are the three sources of genetic diversity from meiosis and reproduction. Nondisjunction is the error case that produces aneuploid gametes when chromosomes fail to separate correctly.

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5.3

Mendelian Genetics

Mendel's laws of segregation and independent assortment predict inheritance ratios for genes on different chromosomes. Use Punnett squares, the product rule, and pedigree analysis to determine genotypes, phenotypes, and the probability of specific offspring outcomes.

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5.4

Non-Mendelian Genetics

Linked genes, codominance, incomplete dominance, sex-linked traits, pleiotropy, and mitochondrial inheritance all produce ratios that deviate from Mendel's predictions. Calculate map units from recombination frequency and use pedigrees to identify sex-linked versus autosomal patterns.

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5.5

Environmental Effects on Phenotype

Environmental conditions such as soil pH, temperature, and UV exposure can change how genes are expressed, producing different phenotypes from the same genotype. This phenotypic plasticity does not change allele frequencies and is distinct from evolutionary change.

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Chromosomal Inheritance Review

AP Biology chromosomal inheritance explained: meiosis, segregation, independent assortment, crossing over, Punnett squares, nondisjunction, and genetic disorders.

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Practice AP Bio unit 5 questions

Try AP-style questions on unit 5, then use the review notes below for anything you miss.

Example stimulus-based MCQs

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Stimulus-based practice question

Genetically identical animal skin cells were exposed to four UV intensities (control, low, medium, high), and melanin concentration was measured in each culture.

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Question

Which statement best describes the null hypothesis for the experiment?

Higher UV intensity increases melanin concentration in the skin cells.

UV intensity does not affect melanin concentration in the skin cells.

Melanin concentration decreases as UV intensity increases in the cells.

Incubation temperature does not affect melanin concentration in the cells.

pedigree

Stimulus-based practice question

A pedigree tracks herbicide resistance in a weed across three generations to test whether the trait is inherited through the chloroplast genome.

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Question

The independent variable in this investigation is best described as

The survival rate of the offspring exposed to herbicide

The specific nuclear alleles inherited from each parent

The sex of the parent possessing the resistance trait

The generation number in which the offspring are born

Example FRQs

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FRQ

Genetic recombination and homologous chromosome crossing over

2. Meiosis is a specialized type of cell division that reduces the chromosome number by half to produce haploid gametes or spores (see Figure 2). In the yeast Saccharomyces cerevisiae, proper chromosome segregation during meiosis is essential for the production of viable spores. Scientists are investigating the role of the protein Msh4 in this process.

To determine the effect of Msh4 on meiotic outcomes, researchers compared a wild-type yeast strain, a mutant strain lacking the gene encoding Msh4 (msh4 mutant), and a msh4 mutant strain transformed with a plasmid containing a functional MSH4 gene (Rescue). The scientists induced meiosis in all three strains and determined the average spore viability, defined as the percentage of spores that successfully germinated and formed colonies. The results are shown in Table 1.

During Prophase I of meiosis, homologous chromosomes pair and exchange genetic material. The scientists hypothesize that Msh4 stabilizes the connections between homologous chromosomes, ensuring they segregate correctly (Figure 1). Figure 2 illustrates the proposed mechanism.

Figure 1. Model of Msh4-mediated meiotic recombination and chromosome segregation (with vs. without Msh4)

Figure 2
A.

Describe the process in Prophase I of meiosis that results in the exchange of genetic material between homologous chromosomes.

B.
i.

Using the template in the space provided for your response, construct an appropriate type of graph that represents the data in Table 1. Your graph should be appropriately plotted and labeled.

ii.

Based on the data in Table 1, determine the effect of the msh4 mutation on spore viability compared to the wild type.

Table 1. Average Spore Viability in Different Yeast Strains (percent ± 2SE)

Table 1
C.
i.

Based on Table 1, identify the treatment group that demonstrates rescue of the mutant phenotype.

ii.

Spo11 is the protein responsible for creating the double-strand breaks shown in Step 1 of Figure 1. Based on Figure 1, predict the effect of a spo11 mutation (which prevents double-strand breaks) on the formation of crossovers.

Aneuploidy refers to an abnormal number of chromosomes in a cell, such as having an extra chromosome or missing a chromosome. In yeast, spores with aneuploidy are typically inviable and fail to develop into colonies. The scientists claim that the reduced spore viability in the msh4 mutant is caused by errors in chromosome segregation during Meiosis I.

D.
i.

Use evidence from the information provided to support the scientists' claim.

ii.

Based on Figure 1, explain why the spores produced in the absence of Msh4 are inviable.

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FRQ

Homologous chromosome recombination and MEI-2 protein levels

6. During prophase I of meiosis, homologous chromosomes pair and exchange genetic material through a process called crossing over. This process requires the formation of double-strand breaks in the DNA, which are initiated by the MEI-2 protein. The formation of chiasmata (physical links between homologous chromosomes) is the visible result of successful crossing over.

Scientists identified a gene encoding the MEI-2 protein in a model organism. To investigate the relationship between MEI-2 protein levels and recombination frequency, they generated several yeast strains with different genotypes involving the wild-type allele (WT), a deletion allele where the gene is missing (del), and a mutant allele with a single amino acid substitution (mut1).

The scientists analyzed four genotypes: homozygous wild-type (WT/WT), heterozygous for the deletion (WT/del), hemizygous for the mutant allele (mut1/del), and homozygous for the deletion (del/del). They measured the average number of chiasmata per meiotic cell (Figure 1A) and quantified the relative amount of MEI-2 protein present in the cells using Western blot analysis (Figure 1B).

Figure 1. Two-panel bar graph comparing (A) mean chiasmata per meiotic cell during prophase I and (B) mean relative MEI-2 protein abundance for four yeast genotypes (WT/WT, WT/del, mut1/del, del/del). Error bars show ±SEM and must be symmetric above and below the bar top (except where SEM is explicitly absent).

Figure 1
A.

Based on Figure 1A, identify the genotype that produces an average of approximately 3 chiasmata per cell.

B.

Based on Figure 1B, describe the difference in MEI-2 protein production between the WT/WT genotype and the WT/del genotype.

C.

Scientists hypothesize that meiotic cells can maintain normal levels of recombination even when MEI-2 protein levels are reduced by half. Use the data in Figures 1A and 1B to support the scientists' hypothesis.

D.

For the WT/del and mut1/del genotypes, explain why the average number of chiasmata (Figure 1A) differs drastically despite the cells producing the same amount of MEI-2 protein (Figure 1B).

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FRQ

Genetic recombination through chromosome exchange during meiosis.

1. Meiosis is a specialized type of cell division that reduces the chromosome number by half to produce haploid gametes. This process ensures genetic diversity in sexually reproducing organisms through mechanisms such as the exchange of genetic material between homologous chromosomes.

Researchers are investigating the role of the protein Rec8, a component of the meiotic cohesin complex, in the formation of crossovers during meiosis in the yeast Saccharomyces cerevisiae. Crossovers are physical linkages between homologous chromosomes that are essential for their proper alignment and segregation. The researchers utilized a wild-type yeast strain and a mutant strain lacking the gene encoding Rec8 (rec8-).

To determine the effect of the Rec8 protein on crossing over, the researchers measured the recombination frequency between two linked genes, ARG4 and THR1, located on chromosome VIII. They analyzed the offspring from crosses involving either the wild-type strain or the rec8- mutant strain. The average recombination frequency for each strain was calculated (Figure 1).

Following the analysis of recombination frequencies, the researchers investigated the reproductive success of the yeast strains. In yeast, meiosis results in the formation of four haploid spores (gametes) packaged together in a sac called an ascus. The researchers induced meiosis in both the wild-type and rec8- mutant strains and determined the percentage of spores that were viable and able to grow into colonies (Figure 2).

A.

Describe the process of crossing over during meiosis.

Figure 1. Recombination frequency between ARG4 and THR1 in yeast

Figure 1
B.
i.

Identify the dependent variable in the experiment shown in Figure 1.

ii.

Justify why the researchers determined the recombination frequency in the Wild Type strain.

iii.

Based on Figure 1, describe the effect of the rec8 mutation on the frequency of crossing over between the ARG4 and THR1 genes.

Figure 2. Spore viability in wild-type vs. rec8− yeast strains

Figure 2
C.
i.

Identify the independent variable in the researchers' second experiment (data shown in Figure 2).

ii.

Based on Figure 2, identify the strain that produced the lowest percentage of viable spores.

iii.

The researchers collected 500 spores from the Wild Type strain and 500 spores from the rec8- mutant strain. Based on the data in Figure 2, calculate the difference in the number of viable spores between the two groups.

D.
i.

The researchers claim that the Rec8 protein is required for the production of viable gametes in S. cerevisiae. Using data from Figure 2, support the researchers' claim.

ii.

Researchers hypothesize that the reduced spore viability in the rec8- mutant is due to an increase in nondisjunction events during Meiosis I. Justify this hypothesis based on the function of crossovers in chromosome alignment.

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AP Bio unit 5 practice test

A timed, AP-style test built only from unit 5 questions — multiple choice plus free response, scored with AI feedback. Use the standard format or build your own.

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Unit 5 review notes

5.1

Meiosis: Stages and Chromosome Transmission

Meiosis converts one diploid (2n) cell into four haploid (n) gametes through two sequential divisions after a single round of DNA replication. Meiosis I is the reductional division: homologous chromosomes pair up and then separate. Meiosis II is the equational division: sister chromatids separate, similar to mitosis. The key distinction is what separates in each division.

  • Prophase I: Homologous chromosomes pair (synapsis), chiasmata form where crossing over occurs, the nuclear envelope breaks down, and the meiotic spindle begins to form.
  • Metaphase I: Homologous pairs (tetrads) align at the metaphase plate with each homolog facing an opposite pole, not sister chromatids as in mitosis.
  • Anaphase I: Homologous chromosomes separate and move to opposite poles; sister chromatids remain attached at the centromere.
  • Meiosis II: Proceeds like mitosis: sister chromatids separate in anaphase II, yielding four haploid cells each with one copy of each chromosome.
  • Mitosis vs. meiosis: Mitosis produces two genetically identical diploid cells for growth and repair; meiosis produces four genetically unique haploid gametes for sexual reproduction.

Can you state what separates in anaphase I versus anaphase II, and explain why the chromosome number is halved after meiosis I but not after meiosis II?

FeatureMitosisMeiosis
Number of divisions12
Daughter cells produced24
Chromosome number in daughters2n (diploid)n (haploid)
Genetic identity of daughtersIdentical to parentGenetically unique
Crossing over occursNoYes, in prophase I
5.2

Meiosis and Genetic Diversity

Three mechanisms during meiosis and fertilization generate genetic diversity. Crossing over in prophase I exchanges segments between non-sister chromatids of homologous chromosomes, creating new allele combinations. Independent assortment in metaphase I randomly orients each homologous pair, so maternal and paternal chromosomes are distributed independently. Random fertilization then combines two unique gametes. Nondisjunction is a failure of these processes: homologs fail to separate in meiosis I, or sister chromatids fail to separate in meiosis II, producing aneuploid gametes.

  • Crossing over: Non-sister chromatids of homologous chromosomes exchange segments at chiasmata during prophase I, producing recombinant chromosomes with new allele combinations.
  • Independent assortment: Each homologous pair orients randomly at metaphase I, so the maternal or paternal chromosome of one pair goes to a pole independently of every other pair.
  • Random fertilization: Any sperm can fertilize any egg, multiplying the number of possible allele combinations in offspring beyond what meiosis alone produces.
  • Nondisjunction: Failure of chromosomes to separate correctly in meiosis I or II, producing gametes with an extra or missing chromosome and potentially aneuploid offspring.

Given a cell with three pairs of homologous chromosomes, how many chromosome combinations are possible from independent assortment alone? How does crossing over increase that number further?

MechanismWhen it occursEffect on diversity
Crossing overProphase INew allele combinations on single chromosomes
Independent assortmentMetaphase IRandom mix of maternal and paternal chromosomes in gametes
Random fertilizationAt fertilizationCombines two independently generated haploid genomes
NondisjunctionAnaphase I or IIProduces aneuploid gametes, reduces viability
5.3

Mendelian Genetics

Mendel's two laws describe how alleles for single genes and genes on different chromosomes are inherited. The law of segregation states that the two alleles for a gene separate during gamete formation so each gamete carries one allele. The law of independent assortment states that alleles of different genes on different chromosomes sort independently. Punnett squares and probability rules (product rule for independent events, sum rule for mutually exclusive events) let you predict genotypic and phenotypic ratios. Pedigree analysis applies these rules to family inheritance data.

  • Monohybrid cross (Aa x Aa): Produces a 3:1 phenotypic ratio and a 1:2:1 genotypic ratio (AA : Aa : aa) in offspring.
  • Dihybrid cross (AaBb x AaBb): Produces a 9:3:3:1 phenotypic ratio when the two genes are on different chromosomes and assort independently.
  • Test cross: Crossing an organism of unknown genotype with a homozygous recessive individual to determine whether the unknown is homozygous dominant or heterozygous.
  • Pedigree analysis: Tracing a trait through a family tree to determine whether inheritance is autosomal or sex-linked, and dominant or recessive, based on which individuals are affected.
  • Product rule: The probability of two independent events both occurring equals the product of their individual probabilities; used to calculate the chance of a specific multi-gene genotype.

A dihybrid cross gives offspring in a 9:3:3:1 ratio. What does that ratio tell you about the dominance relationships and chromosomal locations of the two genes?

Cross typeParental genotypesExpected phenotypic ratio
MonohybridAa x Aa3 dominant : 1 recessive
DihybridAaBb x AaBb9:3:3:1
Test crossAa x aa1 dominant : 1 recessive
Test crossAA x aaAll dominant phenotype
5.4

Non-Mendelian Genetics

When observed phenotypic ratios differ from Mendel's predictions, a non-Mendelian pattern is at work. Genetic linkage occurs when two genes sit on the same chromosome and tend to be inherited together; recombination frequency between them is used to calculate map distance in map units (cM). Codominance produces a heterozygote phenotype that shows both alleles simultaneously (ABO blood types). Incomplete dominance produces an intermediate blended phenotype in heterozygotes (snapdragon flower color). Sex-linked traits are carried on the X chromosome and show different expression rates in males (hemizygous) versus females. Pleiotropy means one gene affects multiple phenotypic traits. Non-nuclear inheritance through mitochondrial DNA follows maternal inheritance because mitochondria come from the egg.

  • Genetic linkage and map units: Genes on the same chromosome do not assort independently; recombination frequency (recombinants / total offspring x 100) gives map distance in centiMorgans.
  • Codominance: Both alleles are fully expressed in the heterozygote; ABO blood type IA and IB alleles both produce their antigens in IAIB individuals.
  • Incomplete dominance: Neither allele masks the other; a red-flowered snapdragon crossed with a white-flowered one produces pink heterozygotes.
  • Sex-linked inheritance: X-linked recessive traits like red-green color blindness appear more often in males (XY) because males have only one X chromosome and no second allele to mask the recessive.
  • Mitochondrial inheritance: Traits encoded by mitochondrial DNA are passed from mother to all offspring regardless of sex, because the egg contributes virtually all cytoplasmic organelles.

Two genes show a recombination frequency of 22%. What is the map distance between them, and does this mean they assort independently?

PatternHeterozygote phenotypeClassic example
Complete dominanceIdentical to dominant homozygoteMendel's pea traits
Incomplete dominanceIntermediate blendPink snapdragon flowers
CodominanceBoth alleles expressedABO blood type IAIB
Sex-linked recessiveExpressed in hemizygous malesRed-green color blindness
5.5

Environmental Effects on Phenotype

The same genotype can produce different phenotypes when environmental conditions change how genes are expressed. This is phenotypic plasticity. It does not alter the DNA sequence; it alters gene expression. AP Biology uses several illustrative examples: hydrangea flower color shifts with soil pH because pH affects pigment production, arctic animals change fur color seasonally in response to photoperiod, reptile sex is determined by incubation temperature rather than sex chromosomes in some species, and UV exposure increases melanin production in animals. Phenotypic plasticity is not evolution because allele frequencies in the population do not change.

  • Phenotypic plasticity: The ability of one genotype to produce different phenotypes in response to different environmental conditions, without any change to the DNA sequence.
  • Soil pH and flower color: Hydrangea flower color (blue vs. pink) depends on soil pH, which affects aluminum ion availability and anthocyanin expression from the same genotype.
  • Temperature-dependent sex determination: In some reptiles, incubation temperature rather than sex chromosomes determines whether offspring develop as male or female.
  • UV and melanin production: Increased UV exposure upregulates melanin synthesis in animals, darkening skin or fur from the same underlying genotype.
  • Plasticity vs. evolution: Phenotypic plasticity changes an individual's expressed traits within its lifetime; evolution changes allele frequencies across generations in a population.

Two hydrangea plants with identical genotypes are grown in acidic versus alkaline soil and produce blue versus pink flowers. What does this demonstrate about the relationship between genotype and phenotype?

Key terms

TermDefinition
Meiosis IThe first division of meiosis, which separates homologous chromosomes and reduces the cell from diploid to haploid. Includes crossing over in prophase I and independent assortment in metaphase I.
Meiosis IIThe second division of meiosis, which separates sister chromatids to produce four haploid daughter cells, each genetically distinct from the parent cell.
Crossing OverExchange of genetic material between non-sister chromatids of homologous chromosomes during prophase I, creating recombinant chromosomes with new allele combinations.
Independent AssortmentRandom orientation of homologous chromosome pairs at metaphase I, so each gamete receives a random mix of maternal and paternal chromosomes independently for each pair.
NondisjunctionFailure of homologous chromosomes (meiosis I) or sister chromatids (meiosis II) to separate correctly, producing gametes with abnormal chromosome numbers.
Mendel's law of segregationThe two alleles for a gene separate during gamete formation so each gamete carries exactly one allele, which recombines randomly at fertilization.
Punnett SquareA diagram used to predict the genotypic and phenotypic ratios of offspring by mapping all possible gamete combinations from two parents.
GenotypeThe specific combination of alleles an organism carries for one or more genes, which may be homozygous or heterozygous.
PhenotypesThe observable traits of an organism resulting from the interaction of its genotype with environmental conditions.
genetic linkageThe tendency of genes located on the same chromosome to be inherited together rather than assorting independently, violating Mendel's second law.
Incomplete DominanceAn inheritance pattern where neither allele fully masks the other, producing an intermediate blended phenotype in heterozygotes, such as pink flowers from red and white parents.
Sex-Linked TraitsTraits encoded by genes on the X chromosome that show different inheritance patterns in males and females because males are hemizygous for X-linked genes.
Phenotypic PlasticityThe ability of a single genotype to produce different phenotypes in response to different environmental conditions, without any change to the DNA sequence.
Homologous ChromosomesPaired chromosomes of the same length and gene content, one inherited from each parent, that pair up and separate during meiosis I.
pedigreeA diagram tracing the inheritance of a trait through multiple generations of a family, used to determine whether inheritance is autosomal or sex-linked and dominant or recessive.

How to review unit 5

Topics students miss most

Miss rates come from Fiveable multiple-choice practice.

5.2
Meiosis and Genetic Diversity
45%10,563 tries
5.5
Environmental Effects on Phenotype
35%3,517 tries
5.1
Meiosis
34%7,699 tries

Common unit 5 mistakes

Confusing what separates in meiosis I versus meiosis II

In anaphase I, homologous chromosomes separate and sister chromatids stay joined. In anaphase II, sister chromatids separate. Mixing these up leads to wrong answers about ploidy and chromosome number at each stage.

Treating nondisjunction as a source of genetic diversity

Crossing over, independent assortment, and random fertilization generate beneficial diversity. Nondisjunction is a chromosome-separation error that typically produces inviable or aneuploid offspring. Keep these categories separate.

Applying independent assortment to linked genes

Mendel's law of independent assortment applies only to genes on different chromosomes. Linked genes on the same chromosome violate this law and produce recombination frequencies below 50%, which is used to calculate map distance.

Confusing incomplete dominance with codominance

Incomplete dominance produces a blended intermediate phenotype in heterozygotes (pink snapdragons). Codominance produces a phenotype where both alleles are fully and simultaneously expressed (ABO blood type IAIB shows both A and B antigens).

Claiming phenotypic plasticity is evolution

Phenotypic plasticity changes gene expression within an individual in response to the environment. It does not change allele frequencies in a population across generations, which is what evolution requires.

How this unit shows up on the AP exam

Predicting and explaining inheritance ratios

AP Biology questions frequently present a genetic cross or pedigree and ask you to predict offspring ratios, identify the inheritance pattern, or explain why an observed ratio deviates from Mendel's predictions. Be ready to set up Punnett squares, apply the product rule, calculate recombination frequency as map distance, and justify whether a pattern is Mendelian or non-Mendelian based on the data.

Connecting meiosis mechanics to genetic outcomes

Questions may ask you to explain how a specific stage of meiosis produces a particular genetic result, such as how crossing over in prophase I increases allele diversity or how nondisjunction in anaphase I produces a trisomic offspring. Expect to trace chromosome behavior through specific phases and link that behavior to the inheritance pattern observed.

Distinguishing genetic change from environmental phenotype change

Free-response questions in AP Biology often ask you to evaluate a scenario and determine whether a phenotypic difference between individuals results from different genotypes, non-Mendelian inheritance, or environmental effects on gene expression. You need to clearly distinguish phenotypic plasticity from mutation or allele frequency change, using specific examples like soil pH effects on flower color or temperature-dependent sex determination.

More ways to review

Topic study guides

Open the individual guides for Unit 5 when you want a closer review of one topic.

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Practice questions

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FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

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Cram archive videos

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Official unit cheatsheet

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Score calculator

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Unit 5 printables

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Frequently Asked Questions

What's on the AP Bio Unit 5 progress check (MCQ and FRQ)?

The AP Bio Unit 5 progress check in AP Classroom has both MCQ and FRQ parts drawn from all five unit topics: meiosis, genetic variation, Mendelian genetics, non-Mendelian genetics, and environmental effects on phenotype. MCQ questions test your ability to interpret Punnett squares, predict inheritance patterns, and explain how nondisjunction affects chromosomes. The FRQ portion typically asks you to design or analyze crosses and justify deviations from expected ratios using non-Mendelian patterns. Practice with matched questions at /ap-bio/unit-5.

How do I practice AP Bio Unit 5 FRQs?

AP Bio Unit 5 FRQs most often pull from meiosis, Mendelian genetics, and non-Mendelian inheritance. Expect questions that ask you to predict phenotype ratios using Punnett squares, explain how nondisjunction disrupts normal chromosome segregation, or describe how environmental factors modify gene expression. To practice, work through past FRQs topic by topic, write out full justifications (not just answers), and check that your reasoning connects genotype to phenotype explicitly. Find practice FRQs organized by topic at /ap-bio/unit-5.

Where can I find AP Bio Unit 5 practice questions?

For AP Bio Unit 5 practice questions, including multiple-choice and practice test sets, head to /ap-bio/unit-5. You'll find MCQ questions covering meiosis, chromosomes, Punnett squares, and inheritance patterns, plus FRQ practice organized by topic. Working through unit-specific MCQ sets is one of the fastest ways to spot gaps before the full exam.

How should I study AP Bio Unit 5?

Start AP Bio Unit 5 by building a solid understanding of meiosis, since Topics 5.1 and 5.2 are the foundation for everything else in the unit. From there, work through Mendelian genetics and Punnett squares until predicting ratios feels automatic, then move to non-Mendelian patterns like incomplete dominance, codominance, and sex-linkage. Finish with Topic 5.5 to understand how environment shifts phenotype even when the genotype stays the same. A few concrete steps that help:
- Draw and label meiosis I and II from memory, focusing on where genetic variation comes from.
- Practice Punnett squares for monohybrid, dihybrid, and sex-linked crosses until the patterns click.
- Make a comparison chart of non-Mendelian inheritance types so you can tell them apart quickly.
- Do timed MCQ sets, then review any question involving chromosomes or inheritance that tripped you up. All five topics with practice are at /ap-bio/unit-5.

Ready to review Unit 5?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.
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