Skip to main content
course review

Honors Physics Unit 9 Review: Work, Energy, and Simple Machines

Unit 9 shows how forces move energy around: work puts energy into or takes it out of an object, and that energy shifts between kinetic and potential forms without ever disappearing. By the end, you should be able to calculate work and power, solve speed and height problems with energy conservation, and explain why a simple machine can lower the force you need without lowering the work you do.

Read the overview first, then work through each topic note and try its checkpoint question before you check the answer.

start unit practicereview topicsReview with a tutorFree, 24/7, real people, from UPchieve

What is Honors Physics unit 9?

This unit swaps the force-and-acceleration approach from earlier units for an energy approach. Many problems that take several kinematics steps become one line when you compare energy at the start and the end. The same ideas show up in the energy unit of AP Physics 1 if you take that course later.

Honors Physics Unit 9 covers work by a constant force (W=Fdcos⁡θW = Fd\cos\theta), average power (P=W/tP = W/t), kinetic energy (12mv2\frac{1}{2}mv^2), and gravitational and elastic potential energy (mghmgh near Earth's surface and 12kx2\frac{1}{2}kx^2 for an ideal spring), the work-energy theorem (Wnet=ΔKEW_{net} = \Delta KE), conservation of mechanical energy, and simple machines. You learn to find how fast something moves after falling or being pushed, how much energy friction turns into heat, and how mechanical advantage and efficiency describe levers, pulleys, ramps, and other machines.

Work is energy transferred by a force acting along a displacement.

Only the part of a force that lines up with the motion does work, which is why the formula includes cos⁡θ\cos\theta. A force perpendicular to the motion, like the normal force on a level floor, does zero work. Net work on an object equals its change in kinetic energy.

Total energy stays constant, even when mechanical energy does not.

With only gravity and springs doing work, kinetic plus potential energy stays the same at every point. Friction and air resistance drain mechanical energy, but that energy becomes thermal energy and sound instead of vanishing. You account for it with the work done by those nonconservative forces.

Simple machines trade force for distance.

A ramp, lever, or pulley system can let you use a smaller force over a longer distance, or it can change the direction of the force. In an ideal machine, work in equals work out. Real machines lose some energy to friction, so their efficiency is always below 100%.

Energy is a quantity you can track, and work is how it moves.

Every problem in this unit is an energy budget. Figure out how much energy the system has at the start, what forces add or remove energy through work, and what form the energy takes at the end. Once you set up that budget, the algebra is usually short.

Honors Physics unit 9 topics

Unit 9 review notes

9.1

Work, Power, and the Work-Energy Theorem

Work is energy transferred by a force acting through a displacement. For a constant force, W=Fdcos⁡θW = Fd\cos\theta, where θ\theta is the angle between the force and the displacement. A force along the motion does positive work. A force opposite the motion, like kinetic friction, does negative work. A force perpendicular to the motion does zero work.

The work-energy theorem links work to speed. The net work done by all forces equals the change in kinetic energy, Wnet=ΔKE=12mvf2−12mvi2W_{net} = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2. Positive net work speeds an object up, and negative net work slows it down.

Power measures how fast work gets done. Average power is Pavg=W/tP_{avg} = W/t, measured in watts (1 W = 1 J/s). When the force points along the velocity, you can also use P=FvP = Fv.

Worked example. A 2.0 kg box starts at rest. You push it 5.0 m with a 10 N horizontal force while friction pulls back with 4.0 N. Your work is (10)(5.0)=50(10)(5.0) = 50 J. Friction's work is (4.0)(5.0)cos⁡180∘=−20(4.0)(5.0)\cos 180^\circ = -20 J, so Wnet=30W_{net} = 30 J. Then 30=12(2.0)vf230 = \frac{1}{2}(2.0)v_f^2, which gives vf2=30v_f^2 = 30 and vf≈5.5v_f \approx 5.5 m/s. The push took about 1.83 s, so your average power output was 50/1.83≈2750/1.83 \approx 27 W.

  • Work: Energy transferred by a force acting through a displacement, measured in joules. For a constant force, work equals Fdcos⁡θFd\cos\theta.
  • Net work: The sum of the work done by every force on an object, which equals the object's change in kinetic energy.
  • Power: The rate of doing work or transferring energy, measured in watts.

Try this. You carry a 10 kg backpack 20 m across a level hallway at constant speed. How much work does your upward holding force do on the backpack? (Answer: Zero, because your force points up and the displacement is horizontal, so θ=90∘\theta = 90^\circ and cos⁡90∘=0\cos 90^\circ = 0.)

Angle between force and displacementSign of workEffect on speed (if it were the only force)Example
0°PositiveSpeeds upPushing a cart forward
90°ZeroNo changeNormal force on a level floor
180°NegativeSlows downKinetic friction on a sliding box
9.2

Mechanical Energy and Conservation of Energy

Mechanical energy is kinetic plus potential energy, ME=KE+PEME = KE + PE. Kinetic energy is 12mv2\frac{1}{2}mv^2. Near Earth's surface, gravitational potential energy is mghmgh, measured from a reference height you choose. Elastic potential energy in an ideal spring is 12kx2\frac{1}{2}kx^2, where xx is the stretch or compression from the spring's natural length.

Energy is never created or destroyed. When only conservative forces like gravity and springs do work, mechanical energy stays constant, so KEi+PEi=KEf+PEfKE_i + PE_i = KE_f + PE_f. A pendulum or a frictionless roller coaster trades PE for KE and back without losing any.

Friction and air resistance often reduce mechanical energy, converting some into thermal energy and sound. Track nonconservative work with KEi+PEi+Wnc=KEf+PEfKE_i + PE_i + W_{nc} = KE_f + PE_f. The work WncW_{nc} can be negative or positive, depending on how the force acts.

Worked example. A 50 kg skateboarder starts from rest at the top of a 5.0 m ramp. Ignoring friction, mgh=12mv2mgh = \frac{1}{2}mv^2, so the mass cancels and v=2gh=2(9.8)(5.0)≈9.9v = \sqrt{2gh} = \sqrt{2(9.8)(5.0)} \approx 9.9 m/s at the bottom. Suppose she actually reaches the bottom at 8.0 m/s. Her starting energy was (50)(9.8)(5.0)=2450(50)(9.8)(5.0) = 2450 J and her final KE is 12(50)(8.0)2=1600\frac{1}{2}(50)(8.0)^2 = 1600 J. Friction converted the difference, 850 J, into thermal energy.

  • Mechanical energy: The total of an object's kinetic energy and potential energy.
  • Conservative force: A force like gravity or a spring force whose work depends only on the start and end positions. A potential energy can be defined for the system.
  • Nonconservative force: A force whose work can depend on the path. Friction and air resistance often convert mechanical energy into thermal energy and sound, but nonconservative forces can also add mechanical energy.

Try this. A spring with k=500k = 500 N/m is compressed 0.20 m and launches a 0.50 kg block across a frictionless floor. How fast does the block move? (Answer: Stored energy is 12(500)(0.20)2=10\frac{1}{2}(500)(0.20)^2 = 10 J. Setting 10=12(0.50)v210 = \frac{1}{2}(0.50)v^2 gives v2=40v^2 = 40, so v≈6.3v \approx 6.3 m/s.)

FeatureConservative forcesNonconservative forces
ExamplesGravity, spring forceFriction, air resistance, drag
Does work depend on path?No, only start and end pointsYes, work can differ between paths
Effect on mechanical energyKeeps KE + PE constantCan raise or lower KE + PE
Where the energy goesCan shift between kinetic and potential energyCan transfer energy into or out of mechanical forms
9.3

Simple Machines

A simple machine changes the size or direction of a force. For a passive machine, useful work out cannot exceed work in. With constant forces along their displacements, work in is FindinF_{in}d_{in}, and an ideal machine gives back the same amount as work out. If the input force is smaller than the output force, the input distance is longer.

Ideal mechanical advantage (IMA) comes from the machine's geometry, usually din/doutd_{in}/d_{out}. Actual mechanical advantage (AMA) comes from measured forces, Fout/FinF_{out}/F_{in}. Friction makes AMA smaller than IMA. Efficiency is WoutWin×100%\frac{W_{out}}{W_{in}} \times 100\%. For constant forces along the input and output displacements, it also equals AMAIMA×100%\frac{AMA}{IMA} \times 100\%.

The six simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw. A single fixed pulley has an IMA of 1, so it only changes the direction of your pull. Third-class levers like tweezers or a fishing rod have a mechanical advantage below 1, which means they give up force to gain distance and speed at the output.

Worked example. You push a 600 N crate up a 4.0 m ramp onto a 1.0 m platform. The IMA is 4.0/1.0=44.0/1.0 = 4, so a frictionless ramp would need only 150 N. You actually need 200 N, so the AMA is 600/200=3600/200 = 3. Work out is (600)(1.0)=600(600)(1.0) = 600 J and work in is (200)(4.0)=800(200)(4.0) = 800 J, so the efficiency is 600/800=75%600/800 = 75\%, which matches 3/43/4.

  • Ideal mechanical advantage (IMA): The force multiplication a machine would give with no friction, calculated from distances or radii.
  • Actual mechanical advantage (AMA): The measured ratio of output force to input force, which is lower than the IMA in real machines.
  • Efficiency: The percent of input work that comes out as useful output work.

Try this. A pulley system has 4 rope segments supporting a 400 N load. With no friction, what force do you need, and how far must you pull the rope to lift the load 0.50 m? (Answer: The IMA is 4, so you need 100 N, and you pull 4 × 0.50 m = 2.0 m of rope. Work in and work out are both 200 J.)

MachineIMA formulaEveryday example
LeverEffort arm ÷ load armCrowbar, wheelbarrow
Wheel and axleWheel radius ÷ axle radiusDoorknob, screwdriver
Pulley systemNumber of supporting rope segmentsBlock and tackle
Inclined planeRamp length ÷ heightWheelchair ramp
WedgeLength ÷ thickness of wide endAxe head, doorstop
Screw$2\pi r$ ÷ pitchJar lid, wood screw

Key terms

TermDefinition
WorkEnergy transferred by a force acting through a displacement, measured in joules. For a constant force, $W = Fd\cos\theta$.
JouleThe SI unit of work and energy. One joule is the work done by a one-newton force acting along a one-meter displacement.
PowerThe rate at which work is done or energy is transferred, measured in watts, where 1 W equals 1 J/s.
Kinetic energyThe energy of motion, $KE = \frac{1}{2}mv^2$, which is never negative.
Gravitational potential energyEnergy associated with an object's position in a gravitational field. Near Earth's surface, $PE_g = mgh$, where $h$ is measured relative to a chosen reference level.
Elastic potential energyEnergy stored in a stretched or compressed ideal spring, $PE_e = \frac{1}{2}kx^2$.
Work-energy theoremThe rule that the net work done on an object equals its change in kinetic energy.
Conservation of energyThe principle that total energy is conserved. The energy of an isolated system stays constant, even as it changes form.
Mechanical advantageThe factor by which a machine multiplies the input force, found from geometry (IMA) or measured forces (AMA).
EfficiencyThe ratio of useful output work to input work, expressed as a percentage and always below 100% for real machines.

Mistakes to avoid in Work, Energy, and Simple Machines

Thinking any force on a moving object does work

Work only counts the part of the force along the displacement. Holding a box while walking across a level room, or the normal force on a sliding block, does zero work because the force is perpendicular to the motion. Check the angle before you multiply.

Believing a machine reduces the work you do

A ramp makes the push easier, so it feels like less work, but you push over a longer distance. Ideal machines keep work in equal to work out, and friction makes real machines need more input work than they give back. A machine can reduce the force needed by increasing the distance over which it acts.

Forgetting that speed is squared in kinetic energy

Doubling speed doesn't double KE. It multiplies KE by 4, since (2v)2=4v2(2v)^2 = 4v^2. A car going 40 m/s has four times the kinetic energy of the same car at 20 m/s, which is why stopping distance grows so fast with speed.

Plugging in mass when it cancels

For an object starting from rest and dropping through a vertical height hh without friction, mgh=12mv2mgh = \frac{1}{2}mv^2 simplifies to v=2ghv = \sqrt{2gh}. A heavy and a light object reach the same speed after the same drop. If a problem leaves out the mass, that's often the reason. Write the energy equation with symbols first and cancel before you calculate.

Study unit 9 other ways

Ready to review Unit 9?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.