The 1.5×IQR rule is the AP Stats method for identifying outliers: compute the interquartile range (IQR = Q3 − Q1), then flag any value below the lower fence Q1 − 1.5×IQR or above the upper fence Q3 + 1.5×IQR as an outlier.
The 1.5×IQR rule turns "that point looks weird" into an actual calculation. Per the CED, outliers are data points that are unusually small or large relative to the rest of the data, and this rule is how you back that up with numbers instead of vibes.
Here's the recipe. First find the quartiles Q1 and Q3, then the interquartile range, IQR = Q3 − Q1. Multiply the IQR by 1.5 and build two fences. The lower fence is Q1 − 1.5×IQR, and the upper fence is Q3 + 1.5×IQR. Any data value outside those fences is an outlier. Think of the fences as a tolerance zone built around the middle 50% of the data. Because the rule is built entirely from quartiles, it's resistant to extreme values, which is exactly why it pairs with the median and IQR rather than the mean and standard deviation. This is also the rule behind every boxplot you'll draw: the whiskers stop at the most extreme values inside the fences, and outliers get plotted as individual dots.
This lives in Topic 1.6 (Describing the Distribution of a Quantitative Variable) in Unit 1, supporting learning objective 1.6.A. Every full description of a distribution needs shape, center, variability, and unusual features, and outliers are the headline unusual feature. The 1.5×IQR rule is the CED's standard tool for justifying an outlier claim. It also feeds directly into bigger Unit 1 decisions, like why you'd report the median and IQR instead of the mean and standard deviation for a skewed dataset. An outlier yanks the mean toward it but barely touches the median, so spotting outliers tells you which summary statistics to trust.
Keep studying AP® Statistics Unit 1
Interquartile Range (IQR) (Unit 1)
The rule is literally built on the IQR. If you can't compute Q3 − Q1, you can't build the fences. The IQR measures the spread of the middle 50%, and the rule asks whether a point strays more than 1.5 of those middle-spreads beyond the quartiles.
Median vs. Mean (Unit 1)
Outliers found by this rule explain why the median is called resistant and the mean isn't. One huge salary drags the mean way up but leaves the median alone, so once the 1.5×IQR rule confirms an outlier, the median + IQR combo becomes the better summary.
Skewness (Unit 1)
Skewed distributions and outliers travel together. A long right tail often produces points past the upper fence, and the rule helps you decide whether that tail contains genuine outliers or just stretched-out data. Either way, you describe both when summarizing the distribution.
Quartile (Q1, Q3) (Unit 1)
The fences are anchored at Q1 and Q3, not at the median or the mean. A classic mistake is building fences from the median; remember the rule protects the middle 50%, so it starts at the edges of that box.
Multiple choice questions hand you a five-number summary or a stemplot and ask you to (1) compute a fence, (2) decide whether a specific value is an outlier, or (3) identify which statistics you'd need to apply the rule (answer: Q1 and Q3, so you can get the IQR). For example, with Q1 = 65,000, the IQR is 95,000, making a $350,000 salary a clear outlier. No released FRQ has used the phrase verbatim, but FRQ describe-the-distribution prompts expect you to address unusual features, and citing the 1.5×IQR calculation is how you earn full credit for an outlier claim instead of just eyeballing it. Always show the arithmetic: state the IQR, show the fence calculation, then compare the suspect value to the fence.
Both flag unusually extreme values, but they're built from different toolkits. The 1.5×IQR rule uses quartiles, so it's resistant to the very outliers it's hunting, which makes it the go-to for skewed data and boxplots. A rule based on the mean and standard deviation is itself distorted by outliers, since one extreme value inflates both the mean and the SD. On the exam, if you're given a five-number summary, the 1.5×IQR rule is the rule you're meant to use.
A value is an outlier if it falls below Q1 − 1.5×IQR or above Q3 + 1.5×IQR, where IQR = Q3 − Q1.
The fences are anchored at the quartiles, not the median or the mean, so you only need Q1 and Q3 to apply the rule.
Because it's built from quartiles, the rule is resistant to extreme values, unlike rules based on the mean and standard deviation.
Boxplot whiskers extend to the most extreme data values inside the fences, and points beyond the fences get plotted individually as outliers.
Finding an outlier with this rule is your evidence for choosing median and IQR over mean and standard deviation when summarizing the data.
On FRQs, show the full calculation (IQR, then the fence, then the comparison) rather than just declaring a value an outlier.
It's the standard method for identifying outliers in Topic 1.6. Compute IQR = Q3 − Q1, then any value below Q1 − 1.5×IQR or above Q3 + 1.5×IQR counts as an outlier.
No. The max is only an outlier if it lands above the upper fence. For a dataset with Q1 = 18 and Q3 = 31, the IQR is 13 and the upper fence is 31 + 19.5 = 50.5, so a max of 45 is not an outlier.
The 1.5×IQR rule uses quartiles, which outliers can't distort, so it works well for skewed data. A mean ± 2 SD rule gets pulled around by the very outliers it's trying to detect. If a problem gives you a five-number summary, use the 1.5×IQR rule.
The IQR (Q3 − Q1), not the range (max − min). The range includes the potential outliers themselves, which would defeat the purpose. The fences are built from the spread of the middle 50% only.
No, the fences aren't on the formula sheet, so memorize them: lower fence = Q1 − 1.5×IQR, upper fence = Q3 + 1.5×IQR. The good news is it's just one multiplication and one addition or subtraction once you have the quartiles.
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