The spring constant k is the proportionality constant in Hooke's Law (F = -kx) that measures a spring's stiffness in newtons per meter; a larger k means more force is needed per meter of stretch or compression, and it sets both elastic potential energy (½kx²) and oscillation frequency (ω = √(k/m)).
The spring constant, symbol k, tells you how stiff a spring is. It lives inside Hooke's Law, F = -kx, where F is the restoring force the spring exerts and x is the displacement from the spring's natural (equilibrium) length. The units are newtons per meter. A k of 500 N/m means you need 500 N of force to stretch that spring one full meter. Big k means a stiff spring (think car suspension); small k means a floppy one (think Slinky). The negative sign in Hooke's Law isn't about k itself. It just says the force always points back toward equilibrium, which is what makes it a restoring force.
In AP Physics C: Mechanics, k is rarely the star of the problem. It's the constant that connects three big ideas. It sets the spring force (F = -kx), the elastic potential energy stored in the spring (U = ½kx²), and the angular frequency of a mass-spring oscillator (ω = √(k/m), so T = 2π√(m/k)). Notice what's missing from that last formula: amplitude. The period of a mass-spring system depends only on k and m, which is a classic exam trap.
The spring constant threads through three separate units of AP Physics C: Mechanics. In force and dynamics problems, F = -kx is one of the few non-constant forces you'll work with, which means F = ma turns into a differential equation instead of simple kinematics. In work and energy, integrating the spring force gives U = ½kx², and that quadratic dependence on x is why energy-conservation problems with springs feel different from gravity problems. In oscillations, k (with mass m) completely determines the motion of a simple harmonic oscillator. The same constant that tells you how hard a spring pushes also tells you how fast a block bounces back and forth on it. That's the kind of cross-unit connection the exam loves to test, often in a single multi-part FRQ that starts with energy conservation and ends with a period calculation.
Keep studying AP Physics C: Mechanics Unit Ro4fvf7uNKWRj5Zi
Hooke's Law (Units 2 & 7)
Hooke's Law, F = -kx, is where k is defined. The spring constant is literally the slope of a force-versus-displacement graph for an ideal spring, so if an FRQ hands you F-vs-x data, the slope is your k.
Elastic Potential Energy (Unit 3)
Integrate the spring force over displacement and you get U = ½kx². Because energy goes as x squared, doubling the compression quadruples the stored energy. Most spring FRQs are really energy-conservation problems where ½kx² trades off with ½mv² and mgh.
Simple Harmonic Motion (Unit 7)
Attach a mass m to a spring and Newton's second law gives ma = -kx, the defining equation of SHM. The ratio k/m sets everything about the motion's timing, while the initial stretch only sets the amplitude.
Angular Frequency (Unit 7)
For a mass-spring oscillator, ω = √(k/m). Stiffer spring means faster oscillation; heavier mass means slower. Quadruple k and you only double ω, because of the square root. That proportionality reasoning shows up constantly in MCQs.
The spring constant is a workhorse in released FRQs. The 2017 FRQ had a block slide down an incline into a spring, asking you to use energy conservation to relate mgh to ½kx². The 2021 FRQ went further and defined k symbolically as mg/(2R) in a loop-the-loop problem, so you had to carry k through energy equations algebraically, not numerically. The 2018 FRQ used a spring-tipped cart in a collision, connecting k to force-sensor data and momentum. Expect to do four things with k: read it off the slope of an F-vs-x graph, plug it into ½kx² for energy conservation, solve for maximum compression by setting kinetic energy to zero, and use ω = √(k/m) or T = 2π√(m/k) for oscillation questions. In MCQs, watch for proportional-reasoning stems like "if the spring constant doubles, the period changes by what factor?" (Answer: it drops by √2.)
The spring constant k is a property of the spring alone; it never changes no matter what mass you attach or how far you stretch it. Angular frequency ω = √(k/m) is a property of the whole oscillating system, so it depends on both the spring and the mass. Students mix these up when a problem changes the mass: k stays fixed, but ω and the period T shift. Also keep the units straight. k is in N/m, ω is in rad/s.
The spring constant k measures stiffness in newtons per meter, and it appears in Hooke's Law as F = -kx.
A larger k means a stiffer spring, so more force is required for the same stretch and the spring stores more energy per meter of displacement.
Elastic potential energy is U = ½kx², so doubling the compression quadruples the stored energy.
For a mass on a spring, ω = √(k/m) and T = 2π√(m/k), and neither depends on amplitude.
On a force-versus-displacement graph for an ideal spring, the slope equals k, which is a common way FRQs ask you to find it experimentally.
Released FRQs (2017, 2018, 2021) embed k in energy-conservation and collision setups, often requiring symbolic answers in terms of k rather than numbers.
It's the constant k in Hooke's Law, F = -kx, measuring how much force a spring exerts per meter of stretch or compression. Units are N/m, and it feeds directly into elastic potential energy (½kx²) and SHM frequency (ω = √(k/m)).
No, it's the opposite. A bigger k means a stiffer spring, so the same applied force produces less stretch. For a fixed force F, the stretch is x = F/k, so stretch and k are inversely related.
No. The spring constant is a property of the spring itself, set by its material and geometry. Adding mass changes the equilibrium stretch and the oscillation period, but k stays the same.
The restoring force is the actual force the spring exerts, F = -kx, which changes as the spring stretches. The spring constant k is the fixed proportionality constant telling you how strong that force is per meter of displacement.
On a force-versus-displacement graph, k is the slope of the line. On an elastic-potential-energy-versus-x² graph, the slope is k/2. Lab-based FRQs often ask you to extract k this way rather than handing you a number.
Connect this key term to the AP exam workflow: review the course, practice questions, and check related study tools.
Review units, study guides, and course resources.
Check this vocabulary in multiple-choice context.
Apply key concepts in written AP responses.
Estimate the exam score you are working toward.
Review the highest-yield facts before practice.
Put the full course together before test day.