AP Chemistry Unit 9 practice questions
Try 10 multiple-choice questions from Unit 9 here. Pick an answer to see why it's right or wrong, then take the timed test above for a full AP-style set.
Question 1
A researcher plots the standard Gibbs free energy change (ΔG°) on the y-axis versus temperature (T) on the x-axis for a chemical reaction. The resulting line has a negative slope and a positive y-intercept. Based on the linear relationship ΔG° = ΔH° − TΔS°, which statement correctly identifies the signs of the enthalpy and entropy changes indicated by the graph?
The enthalpy change is positive and the entropy change is positive.
The enthalpy change is positive and the entropy change is negative.
The enthalpy change is negative and the entropy change is positive.
The enthalpy change is negative and the entropy change is negative.
Show answer
Answer: (A)
Connecting the linear equation y = mx + b to the thermodynamic function shows that the y-intercept corresponds to ΔH° and the slope corresponds to −ΔS°. A positive intercept indicates ΔH° > 0, and a negative slope indicates −ΔS° < 0, meaning ΔS° must be positive.
Question 2
A heating curve plots temperature versus heat added for a pure substance. The horizontal segment representing vaporization is significantly longer than the horizontal segment representing melting. Which conclusion about the standard entropy of vaporization (ΔS°vap) compared to the standard entropy of fusion (ΔS°fus) is best supported by this graphical difference?
ΔS°vap > ΔS°fus because the gas phase has greater matter dispersal than the liquid.
ΔS°vap < ΔS°fus because the higher temperature reduces the calculated entropy change.
ΔS°vap = ΔS°fus because the mass of the substance remains constant during heating.
ΔS°vap ≈ 0 because the temperature remains constant throughout the phase transition.
Show answer
Answer: (A)
Interpreting the graph shows that vaporization requires more energy (longer segment) than fusion. Since ΔS = q/T, the large heat input combined with the massive increase in disorder (dispersal of matter) when forming a gas results in ΔS°vap being significantly larger than ΔS°fus.
Question 3
A graph of ln K versus 1/T for the reaction 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) yields a straight line with a negative y-intercept. Based on the relationship ln K = (−ΔH°/R)(1/T) + (ΔS°/R), what does the y-intercept indicate about the entropy change of the system?
The entropy change is negative, consistent with the decrease in moles of gas.
The entropy change is negative, consistent with the increase in moles of gas.
The entropy change is positive, consistent with the decrease in moles of gas.
The entropy change is positive, consistent with the increase in moles of gas.
Show answer
Answer: (A)
Identifying the y-intercept as ΔS°/R allows for the determination of the sign of ΔS°. A negative intercept means ΔS° is negative, which aligns with the reaction stoichiometry showing a reduction from 3 moles of gas reactants to 2 moles of gas products.
Question 4
A student constructs a Nernst plot ( versus ) for a reaction between metal M and metal ion . The slope of the line is determined to be V at 298 K. Given that the theoretical slope is V, what is the balanced net ionic equation represented by this data?
Show answer
Answer: (A)
Solving for using the slope relationship () yields , indicating a total transfer of 6 electrons, which corresponds to the balanced equation involving two trivalent and three divalent ions.
Question 5
A graph of current (A) versus time (s) for the electrolysis of a molten chloride salt is a rectangle with a height of 10.0 A and width of 965 s. If 0.90 g of metal X is deposited, what is the balanced reduction half-reaction? (F = 96,500 C/mol)
Show answer
Answer: (A)
Calculating total charge (9650 C) and moles of electrons (0.10 mol) allows determination of the equivalent mass (9 g/mol e-), which identifies Aluminum (27 g/mol) as the metal requiring 3 electrons per atom.
Question 6
In a galvanic cell, a graph of the mass of the anode (Metal A) lost versus the mass of the cathode (Metal B) gained is linear with a slope of 0.30. The atomic mass of A is 65.4 g/mol and B is 107.9 g/mol. What is the balanced cell reaction?
Show answer
Answer: (A)
Using the slope (mass ratio) and atomic masses reveals a mole ratio of 1:2 (), which corresponds to the stoichiometry of a divalent metal displacing a monovalent metal.
Question 7
A model of a galvanic cell anode shows cadmium atoms () becoming cadmium ions (). Which combination correctly describes the half-reaction components and the quantitative flow of electrons for every 10 atoms oxidized?
20 electrons flow from the anode to the cathode
10 electrons flow from the anode to the cathode
20 electrons flow from the cathode to the anode
5 electrons flow from the cathode to the anode
Show answer
Answer: (A)
Analyzing the oxidation state change shows that each Cd atom loses 2 electrons (). Therefore, oxidizing 10 atoms releases electrons, which flow from the anode.
Question 8
A reaction vessel initially contains a mixture of molecules and ions. Based on standard reduction potentials ( for is +2.87 V, for is +0.54 V), which statement describes the correct final particulate representation?
The initial and particles remain unchanged
The initial F⁻ ions are oxidized to F₂ molecules while I₂ remains unchanged
The initial I₂ molecules are reduced to I⁻ ions while F⁻ remains unchanged
The initial I₂ and F⁻ particles react to form IF₅ molecules and electrons
Show answer
Answer: (A)
Comparing reduction potentials indicates that is a stronger oxidant than , meaning is a weaker reductant than . Therefore, cannot oxidize spontaneously, and no reaction occurs.
Question 9
A galvanic cell operates using the reaction . The atomic mass of Zn is 65.38 g/mol and Cu is 63.55 g/mol. Which statement best explains the change in electrode mass based on particulate electron transfer?
For every mole of reaction, 2 moles of electrons transfer, causing the anode to lose slightly more mass than the cathode gains.
For every mole of reaction, 1 mole of electrons transfers, causing the anode to gain mass while the cathode loses mass.
The transfer of electrons from Cu to Zn causes the zinc electrode to increase in mass due to electron accumulation.
The stoichiometry is 1:1, so the mass lost by the zinc electrode must be exactly equal to the mass gained by the copper electrode.
Show answer
Answer: (A)
Connecting the 1:1 molar ratio (derived from the 2-electron transfer in both half-reactions) to atomic masses explains the mass difference. Since Zn (anode) is heavier than Cu (cathode), the mass loss exceeds the mass gain.
Question 10
Electrolysis of a molten metal chloride using a current of 5.00 A for 386 seconds deposits 0.010 mol of metal M at the cathode. (Faraday's constant = 96,500 C/mol ). Which half-reaction represents the reduction of M consistent with this data?
Show answer
Answer: (A)
Calculating charge ( C) and converting to moles of electrons ( mol ) reveals a 2:1 ratio of electrons to metal moles ( mol / mol M), indicating a +2 charge.
What's on the AP Chemistry Unit 9 practice test
The standard version takes about 60 minutes and follows the timing and directions of the AP exam, sized to one unit:
- 20 Multiple Choice Questions (30 minutes)
- 1 FRQ – FRQ 1 – Long Answer (15 minutes)
- 1 FRQ – FRQ 4 – Short Answer (15 minutes)
Questions are drawn from 3268 multiple-choice questions and 100 FRQs written for Unit 9, Thermodynamics and Electrochemistry.
Practice AP Chemistry Unit 9 FRQs
Answer the unit's free-response questions one at a time and get a score on every part.
- FRQ 1 – Long Answer (11 questions)
- FRQ 2 – Long Answer (13 questions)
- FRQ 3 – Long Answer (1 question)
- FRQ 4 – Short Answer (15 questions)
- FRQ 5 – Short Answer (16 questions)
- FRQ 6 – Short Answer (29 questions)
- FRQ 7 – Short Answer (15 questions)
Review Unit 9 before you start
- 9.1 Introduction to Entropy
- 9.2 Absolute Entropy and Entropy Change
- 9.3 Gibbs Free Energy and Thermodynamic Favorability
- 9.4 Thermodynamic and Kinetic Control
- 9.5 Free Energy and Equilibrium
- 9.6 Free Energy of Dissolution
- 9.7 Coupled Reactions
- 9.8 Galvanic (Voltaic) and Electrolytic Cells
- 9.9 Cell Potential and Free Energy
- 9.10 Cell Potential Under Nonstandard Conditions
- 9.11 Electrolysis and Faraday's Law