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Honors Geometry Unit 10 Review: Circles

Unit 10 is about circles, from their equations on the coordinate plane to the angles, arcs, and segments that show up inside and around them. By the end, you should be able to write and read circle equations, find any angle or arc using the right formula, and solve for missing lengths with tangents, secants, and chords.

Read the overview for the big picture, then work through each topic's notes and test yourself with the checkpoint questions before checking the common mistakes.

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What is Honors Geometry unit 10?

This unit pulls together algebra and classic geometry. You'll use the distance formula to describe circles on a grid, then use theorems about arcs, angles, and segments to solve multi-step problems and write proofs.

Honors Geometry Unit 10 covers circles. You learn the standard form (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2 and how to complete the square to find a circle's center and radius. You learn how central, inscribed, and other angles relate to their intercepted arcs depending on where the vertex sits. You study tangent and secant lines, including the tangent-radius right angle and the segment product theorems. You also work with the parts of a circle, chord properties, arc length, and sector area.

A circle's equation is the distance formula applied to every point on the circle.

Any point (x,y)(x, y) on the circle is exactly rr units from the center (h,k)(h, k). Squaring the distance formula gives (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2. When the equation is expanded, completing the square puts it back in this form so you can read off the center and radius.

Where an angle's vertex sits decides how it relates to its arcs.

A central angle has the same degree measure as its intercepted arc. An inscribed angle or tangent-chord angle measures half its intercepted arc. For two chords crossing inside a circle, use half the sum of the arcs intercepted by the angle and its vertical angle. For secants or tangents meeting outside, use half the difference of the far and near arcs.

Tangents create right angles, and intersecting segments create equal products.

A tangent is perpendicular to the radius at the point of tangency, which sets up the Pythagorean theorem. When chords, secants, or tangents meet, multiplying the right segment lengths gives equal products you can solve for an unknown.

Equal distance from the center drives everything.

Because every radius has the same length, you get the circle equation, isosceles triangles inside circles, and the inscribed angle theorem. When a circle problem feels stuck, draw a radius to a point you care about and see what congruent segments or right angles appear.

Honors Geometry unit 10 topics

Unit 10 review notes

10.1

Equations of circles

A circle's equation is the distance formula in disguise. Every point (x,y)(x, y) on a circle with center (h,k)(h, k) and radius rr sits exactly rr units from the center, so the Pythagorean theorem gives the standard form (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2.

Reading the center takes care with signs. The equation subtracts hh and kk, so (x+3)2(x + 3)^2 means h=−3h = -3. The right side is r2r^2, not rr, so take a square root to get the radius.

If the equation is expanded, like x2+y2+8x−2y−8=0x^2 + y^2 + 8x - 2y - 8 = 0, complete the square to get back to standard form.

Worked example. Find the center and radius of x2+y2+8x−2y−8=0x^2 + y^2 + 8x - 2y - 8 = 0. Group the terms and move the constant to get (x2+8x)+(y2−2y)=8(x^2 + 8x) + (y^2 - 2y) = 8. Half of 8 is 4, and 42=164^2 = 16. Half of −2-2 is −1-1, and (−1)2=1(-1)^2 = 1. Add 16 and 1 to both sides to get (x+4)2+(y−1)2=25(x + 4)^2 + (y - 1)^2 = 25. The center is (−4,1)(-4, 1) and the radius is 5.

To test whether a point is on the circle, plug it in. The point (−1,5)(-1, 5) gives 32+42=253^2 + 4^2 = 25, so it lies on the circle.

  • Standard form: The equation (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) is the center and rr is the radius.
  • General form: The expanded version of a circle equation, such as x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0, which hides the center and radius.
  • Completing the square: Adding the square of half the linear coefficient to both sides so each group factors into a perfect square.

Check yourself. What are the center and radius of (x−2)2+(y+5)2=49(x - 2)^2 + (y + 5)^2 = 49? (Answer: The center is (2,−5)(2, -5) and the radius is 7.)

10.2

Angles and segments in circles

Circle-angle formulas depend on the location of the vertex and how the angle's sides meet the circle. Find the vertex and identify the configuration before picking a formula.

A central angle has its vertex at the center and equals its intercepted arc. An inscribed angle has its vertex on the circle and sides that pass through the circle. It measures half its intercepted arc, so a 100° arc gives a 50° inscribed angle. A tangent-chord angle also has its vertex on the circle and follows the same half-the-arc rule.

Three corollaries come up constantly. Inscribed angles that intercept the same arc are congruent. An inscribed angle that intercepts a semicircle is a right angle. Opposite angles of a quadrilateral inscribed in a circle are supplementary.

When the vertex is inside the circle, as with two crossing chords, the angle is half the sum of the arc it intercepts and the arc its vertical angle intercepts. When the vertex is outside, with two secants, two tangents, or one of each, the angle is half the difference of the far arc and the near arc.

Worked example. Two chords cross inside a circle. The angle intercepts a 100° arc and its vertical angle intercepts a 40° arc. The angle is 12(100+40)=70°\frac{1}{2}(100 + 40) = 70°. Now suppose two secants meet outside a circle, cutting off a far arc of 130° and a near arc of 50°. That angle is 12(130−50)=40°\frac{1}{2}(130 - 50) = 40°.

  • Intercepted arc: The arc that lies in the interior of an angle, between the points where the angle's sides meet the circle.
  • Inscribed Angle Theorem: An inscribed angle measures half of its intercepted arc, which is also half of the central angle on that arc.
  • Cyclic quadrilateral: A quadrilateral with all four vertices on a circle, so each pair of opposite angles adds to 180°.

Check yourself. Quadrilateral ABCD is inscribed in a circle and angle A measures 72°. What is the measure of angle C? (Answer: 108°, because opposite angles of an inscribed quadrilateral are supplementary.)

Vertex locationAngles that fitAngle measure
At the centerCentral angleEqual to the intercepted arc
On the circleInscribed angle, tangent-chord angleHalf the intercepted arc
Inside the circleTwo chords crossingHalf the sum of the two intercepted arcs
Outside the circleTwo secants, two tangents, or a secant and a tangentHalf the difference of the far arc and the near arc
10.3

Tangents and secants

Tangents and secants give you two kinds of facts, right angles and segment products.

A tangent touches the circle at exactly one point and is perpendicular to the radius at that point. That right angle lets you use the Pythagorean theorem. It also lets you write a tangent line's equation on the coordinate plane. When the radius has a nonzero slope, the tangent's slope is its negative reciprocal. A horizontal radius has a vertical tangent, and a vertical radius has a horizontal tangent. Two tangent segments drawn from the same outside point are congruent.

The segment theorems all multiply lengths. When two chords cross inside a circle, the two pieces of one chord multiply to the same product as the two pieces of the other. For segments from an outside point, multiply each whole segment by its outside part. A tangent counts as both its own whole and its own outside part, so it gets squared.

Worked example. From point PP, a secant has an outside part of 4 and an inside part of 5, and a tangent from PP touches the circle at AA. The whole secant is 4+5=94 + 5 = 9, so PA2=9⋅4=36PA^2 = 9 \cdot 4 = 36 and PA=6PA = 6. A common slip is writing 4⋅54 \cdot 5, but the inside part alone never goes into this equation.

For a radius-and-tangent problem, if the radius is 5 and the center is 13 units from PP, the tangent segment from PP is 132−52=12\sqrt{13^2 - 5^2} = 12.

  • Tangent: A line in the plane of a circle that intersects the circle at exactly one point, called the point of tangency.
  • Secant: A line that intersects a circle at exactly two points.
  • External segment: The part of a secant segment from the outside point to the nearer point where the secant meets the circle.
  • Tangent-radius theorem: A tangent line is perpendicular to the radius drawn to the point of tangency.

Check yourself. Two chords intersect inside a circle. One chord is split into pieces of 3 and 8, and the other into pieces of 4 and xx. What is xx? (Answer: 3⋅8=4x3 \cdot 8 = 4x, so x=6x = 6.)

SetupWhere the segments meetEquation
Two chordsInside the circlepart × part = part × part
Two secantsOutside the circlewhole × outside = whole × outside
Tangent and secantOutside the circletangent² = whole × outside
Two tangentsOutside the circleThe two tangent segments are equal
10.4

Parts of circles and their relationships

A circle is every point in a plane at a fixed distance, the radius, from one center point. Radii connect the center to the circle, and chords connect two points on the circle. A diameter is a chord through the center, so d=2rd = 2r and it's the longest chord.

Arcs come in three sizes. A minor arc is less than 180°, a semicircle is exactly 180°, and a major arc is more than 180° and gets named with three letters, like arc ACBACB. Arc measure is in degrees and matches the corresponding central angle. For a major arc, use the reflex central angle, which measures more than 180°. Arc length is a distance, a fraction of the circumference.

Chords have their own rules. A radius or diameter perpendicular to a chord bisects that chord. Congruent chords sit the same distance from the center and cut off congruent arcs.

Worked example. In a circle with radius 6, a central angle measures 120°. The arc measure is 120°. The arc length is 120360⋅2π(6)=13⋅12π=4π\frac{120}{360} \cdot 2\pi(6) = \frac{1}{3} \cdot 12\pi = 4\pi. The sector area is 120360⋅π(6)2=13⋅36π=12π\frac{120}{360} \cdot \pi(6)^2 = \frac{1}{3} \cdot 36\pi = 12\pi.

A polygon is inscribed in a circle when all its vertices lie on the circle. A polygon is circumscribed about a circle when every side is tangent to the circle.

  • Chord: A segment whose endpoints both lie on the circle.
  • Arc length: The distance along an arc, found with θ360⋅2πr\frac{\theta}{360} \cdot 2\pi r when the central angle is θ\theta degrees.
  • Sector: The pie-slice region bounded by two radii and their arc, with area θ360⋅πr2\frac{\theta}{360} \cdot \pi r^2.

Check yourself. A circle has radius 10. What is the area of a sector with a 72° central angle? (Answer: 72360⋅100π=20π\frac{72}{360} \cdot 100\pi = 20\pi square units.)

Key terms

TermDefinition
RadiusA segment from the center of a circle to any point on the circle, or the length of that segment.
DiameterA chord that passes through the center, equal to twice the radius.
Central angleAn angle with its vertex at the center of a circle whose measure equals its intercepted arc.
Inscribed angleAn angle with its vertex on a circle and sides that are chords, measuring half its intercepted arc.
Point of tangencyThe single point where a tangent line touches a circle.
Minor arcAn arc measuring less than 180°, named with its two endpoints.
Major arcAn arc measuring more than 180°, named with three points to show which way around the circle it goes.
Circumscribed angleAn angle formed by two tangents from the same outside point, equal to 180° minus the minor arc it intercepts.
Concentric circlesCircles in the same plane that share a center but have different radii.

Mistakes to avoid in Circles

Getting the sign of the center backwards

Standard form subtracts the center coordinates, so (x+4)2+(y−1)2=25(x + 4)^2 + (y - 1)^2 = 25 has center (−4,1)(-4, 1), not (4,−1)(4, -1). Rewrite each plus as minus a negative, like x−(−4)x - (-4), before reading off hh and kk.

Treating $r^2$ as the radius

The number on the right side of standard form is the radius squared. If it's 25, the radius is 5. The same idea applies after completing the square, where you also have to add the new constants to both sides or the radius comes out wrong.

Using the inside piece instead of the whole secant

For segments from an outside point, the product is whole × outside, where the whole runs from the outside point all the way to the far side of the circle. Add the outside and inside parts first, then multiply. The part × part rule only applies to chords crossing inside the circle.

Mixing up half the sum and half the difference

Both formulas use two arcs, so they're easy to swap. Vertex inside the circle means half the sum, and vertex outside means half the difference. Locate the vertex before you write anything down.

Study unit 10 other ways

Ready to review Unit 10?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.