Tangent, cotangent, secant, and cosecant are all built from sine and cosine, so their graphs break wherever the denominator is zero. Those breaks are vertical asymptotes.
Since tanx=cosxsinx, tangent has asymptotes where cosx=0, at x=±2π,±23π, and so on. Between asymptotes it rises from −∞ to ∞ and crosses zero at multiples of π. Its period is π, not 2π. Cotangent, sinxcosx, has asymptotes at multiples of π and falls from left to right instead of rising.
Secant and cosecant are reciprocals, secx=cosx1 and cscx=sinx1. To sketch one, lightly draw the cosine or sine curve, put asymptotes at its zeros, and then draw U-shaped branches that touch each peak and valley and open away from the x-axis. Their range is (−∞,−1]∪[1,∞) and their period is 2π.
Transformations work as in 6.1. For nonzero a and b, the period of y=atan(bx) or y=acot(bx) is ∣b∣π. For y=asec(bx) or y=acsc(bx), it is ∣b∣2π.
Worked example. Find the period and asymptotes of y=tan(2x). The period is 2π. Asymptotes occur where 2x=2π+kπ, so x=4π+2kπ. That gives x=±4π,±43π, and so on.
- Vertical asymptote: A line x=cx = cx=c where the function approaches positive or negative infinity as xxx approaches ccc from at least one side. For the four parent functions in this section, these lines occur where the denominator is zero.
- Reciprocal function: A function equal to 1 divided by another, such as secx=1cosx\sec x = \frac{1}{\cos x}secx=cosx1.
- Cotangent: The ratio cosxsinx\frac{\cos x}{\sin x}sinxcosx, with period π\piπ and a graph that decreases between asymptotes.
Try this. Where are the vertical asymptotes of y=cscx, and why? (Answer: At x=kπ, such as 0,±π,±2π, because cscx=sinx1 and sinx=0 at those points.)
| Function | Period | Vertical asymptotes | Range |
|---|
| $\tan x$ | $\pi$ | $x = \frac{\pi}{2} + k\pi$ | All real numbers |
| $\cot x$ | $\pi$ | $x = k\pi$ | All real numbers |
| $\sec x$ | $2\pi$ | $x = \frac{\pi}{2} + k\pi$ | $(-\infty, -1] \cup [1, \infty)$ |
| $\csc x$ | $2\pi$ | $x = k\pi$ | $(-\infty, -1] \cup [1, \infty)$ |