Every description of motion depends on a reference frame, which means an origin, a positive direction, and an observer. If you change the observer, the motion changes too. A passenger sitting on a train moving at 20 m/s is at rest relative to the train but moving at 20 m/s relative to the platform. In one dimension, relative velocities add with signs. If the passenger walks toward the front at 1.5 m/s, someone on the platform sees 20+1.5=21.5 m/s. If the passenger walks toward the back, the platform observer sees 20−1.5=18.5 m/s.
Once you have a frame, you can give an object's position x and describe how it moved. Distance is the total path length. It is a scalar and is never negative. Displacement is the change in position, Δx=xf−xi. It is a vector, and its sign gives the direction.
Worked example. A hiker walks 2 km north, then 1.5 km south, then 3 km north. Take north as positive. For distance, add the size of every leg: 2+1.5+3=6.5 km. For displacement, add the signed legs: (+2)+(−1.5)+(+3)=+3.5 km, so the hiker ends up 3.5 km north.
Distance is always greater than or equal to the size of the displacement. The two are equal only when the object never reverses. A runner who travels 200 m along a straight path and returns to the start has covered 400 m of distance but has zero displacement.
- Reference frame: The viewpoint and coordinate system, with an origin and a positive direction, that you use to measure motion.
- Position: An object's location relative to the origin, written as xxx. It can be positive, negative, or zero at the origin.
- Distance: The total length of the path an object travels, a scalar that is never negative.
- Displacement: The change in position, Δx=xf−xi\Delta x = x_f - x_iΔx=xf−xi, a vector that can be positive, negative, or zero.
Check yourself: A car drives 5 km east, then 8 km west. What are its distance and displacement? (Answer: The distance is 13 km. The displacement is 3 km west, or -3 km if east is positive.)