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3.3 Graphical methods for rate law analysis

3.3 Graphical methods for rate law analysis

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
⚗️Chemical Kinetics
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Graphical Methods for Rate Law Analysis

Graphical methods let you determine the order of a reaction and extract the rate constant kk directly from experimental data. The core idea is straightforward: if you plot concentration-vs.-time data in the right way, the correct reaction order will produce a straight line. The order that gives you linearity is the order of the reaction.

This section covers the integrated rate laws for zero-, first-, and second-order reactions, how to linearize each one, and how half-life behavior can also reveal reaction order.

Integrated Rate Laws and Linearization

Each reaction order has its own integrated rate law. When you rearrange these into the form y=mx+by = mx + b, each one suggests a specific plot that will be linear only if the data actually follow that order.

Zero-order reactions:

  • Integrated rate law: [A]t=kt+[A]0[A]_t = -kt + [A]_0
  • Plot [A][A] vs. tt
  • Slope = k-k, y-intercept = [A]0[A]_0

This is already in y=mx+by = mx + b form with no transformation needed. If raw concentration vs. time is a straight line, the reaction is zero-order.

First-order reactions:

  • Integrated rate law: ln[A]t=kt+ln[A]0\ln[A]_t = -kt + \ln[A]_0
  • Plot ln[A]\ln[A] vs. tt
  • Slope = k-k, y-intercept = ln[A]0\ln[A]_0

You take the natural log of each concentration value before plotting. A straight line on this plot means first-order.

Second-order reactions:

  • Integrated rate law: 1[A]t=kt+1[A]0\frac{1}{[A]_t} = kt + \frac{1}{[A]_0}
  • Plot 1[A]\frac{1}{[A]} vs. tt
  • Slope = kk (positive), y-intercept = 1[A]0\frac{1}{[A]_0}

You take the reciprocal of each concentration value. A straight line here means second-order.

Graphical methods for kinetic data, Integrated Rate Laws | General Chemistry

How to Determine Reaction Order from Plots

When you're given concentration-vs.-time data and need to find the reaction order, follow this process:

  1. Make three plots from the same data set: [A][A] vs. tt, ln[A]\ln[A] vs. tt, and 1[A]\frac{1}{[A]} vs. tt.
  2. Check which plot produces a straight line (or the best linear fit if working with real, slightly noisy data).
  3. The linear plot tells you the order: linear [A][A] vs. tt = zero-order, linear ln[A]\ln[A] vs. tt = first-order, linear 1[A]\frac{1}{[A]} vs. tt = second-order.
  4. Read kk from the slope of the linear plot. Remember that for zero- and first-order, the slope is k-k (so kk is the absolute value), while for second-order, the slope equals kk directly.

Only one of the three plots should be linear. If ln[A]\ln[A] vs. tt is straight but the other two curve, you've confirmed first-order behavior.

Graphical methods for kinetic data, Concentration–Time Relationships: Integrated Rate Laws – Introductory Chemistry- 1st Canadian ...

Half-Life and Reaction Order

Half-life (t1/2t_{1/2}) is the time it takes for the reactant concentration to drop to half its current value. The relationship between half-life and initial concentration is different for each order, which gives you another way to identify reaction order.

First-order:

t1/2=ln2kt_{1/2} = \frac{\ln 2}{k}

Half-life is constant regardless of concentration. If you notice that it always takes the same amount of time for the concentration to halve (say, 20 s to go from 1.0 M to 0.5 M, and another 20 s to go from 0.5 M to 0.25 M), that's a signature of first-order kinetics.

Second-order:

t1/2=1k[A]0t_{1/2} = \frac{1}{k[A]_0}

Half-life is inversely proportional to the initial concentration. As the reaction proceeds and [A][A] decreases, each successive half-life gets longer. A reaction that starts fast and slows down dramatically may be second-order.

Zero-order:

t1/2=[A]02kt_{1/2} = \frac{[A]_0}{2k}

Half-life is directly proportional to the initial concentration. As [A][A] decreases, each successive half-life gets shorter. The reaction runs at a steady rate until the reactant is nearly gone, then finishes quickly.

Quick check: If doubling the initial concentration doesn't change the half-life, the reaction is first-order. If doubling [A]0[A]_0 cuts the half-life in half, it's second-order. If doubling [A]0[A]_0 doubles the half-life, it's zero-order.

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