The period T, frequency f, and angular frequency ω are always related by T = 2π/ω = 1/f. For a mass-spring system, substituting ω = √(k/m) gives T_s = 2π√(m/k). For a simple pendulum at small angles, the restoring force component along the arc is -mg sinθ ≈ -mgθ, which produces ω = √(g/l) and T_p = 2π√(l/g). A critical exam point: period does not depend on amplitude for ideal SHM. Increasing mass increases T for a spring but has no effect on T for a simple pendulum.
A pendulum on the Moon (g smaller) compared to Earth: does T increase, decrease, or stay the same? Justify using T_p = 2π√(l/g).