Oxymercuration–demercuration
Oxymercuration-demercuration is a two-step Organic Chemistry reaction that adds water across an alkene to form a Markovnikov alcohol. It uses mercury(II) acetate first, then demercuration replaces mercury with hydrogen.
What is oxymercuration–demercuration?
Oxymercuration-demercuration is a clean way to turn an alkene into an alcohol in Organic Chemistry. The reaction adds the elements of water across the double bond, and the OH group ends up on the more substituted carbon, which is the Markovnikov product.
The process happens in two steps. First, the alkene reacts with mercury(II) acetate, Hg(OAc)2, to form a bridged mercurinium ion. That bridge matters because it keeps the positive charge from becoming a free carbocation. Since there is no open carbocation floating around, the molecule does not rearrange the way it can in acid-catalyzed hydration.
Next, water attacks the mercurinium ion, opens the ring, and gives an organomercury alcohol intermediate. The attack happens from the side opposite the mercury bridge, so the addition is anti in the first step. After that, demercuration uses a reducing agent such as sodium borohydride to replace the mercury-containing group with hydrogen, leaving the alcohol behind.
A good way to picture the reaction is this: the alkene is being hydrated, but in a controlled way. Instead of letting the alkene form a messy carbocation and risk rearrangements, oxymercuration uses mercury to hold the intermediate in place long enough for water to add correctly. That is why it is so often chosen when you want the alcohol in the Markovnikov position and you want a single main product.
For example, if you start with an internal alkene, oxymercuration-demercuration gives the alcohol at the more substituted carbon of the double bond. With an unsymmetrical alkene, this regioselectivity is usually the main thing your instructor wants you to predict. The reaction is less about memorizing a name and more about recognizing a pattern: alkene in, Markovnikov alcohol out, rearrangements avoided.
Why oxymercuration–demercuration matters in Organic Chemistry
Oxymercuration-demercuration shows up anytime Organic Chemistry asks you to choose the best alkene-to-alcohol route. It gives you a reliable Markovnikov hydration without the rearrangement problems that make acid-catalyzed hydration unpredictable. That makes it a favorite in synthesis questions where the exact position of the OH group matters.
It also helps you compare reaction mechanisms instead of treating hydration methods like random recipes. Once you know why the mercurinium ion forms, you can explain why the product is regioselective and why the reaction avoids a carbocation rearrangement. That logic comes up again when you study other alkene additions, especially ones that depend on bridged intermediates or anti addition.
This term also builds your reaction-mechanism vocabulary. If you can identify the alkene, the mercurinium ion, nucleophilic attack by water, and the final reduction step, you can follow the whole sequence instead of just memorizing the product. That skill transfers to problem sets where you need to predict products from reagents, justify major products, or compare two hydration methods side by side.
Keep studying Organic Chemistry Unit 8
Visual cheatsheet
view galleryHow oxymercuration–demercuration connects across the course
Acid-Catalyzed Hydration
Both reactions add water to an alkene to make an alcohol, but they do not behave the same way. Acid-catalyzed hydration goes through a carbocation, so rearrangements can happen. Oxymercuration-demercuration avoids that by using a bridged mercurinium ion, which gives you a cleaner Markovnikov product when rearrangement would cause the wrong alcohol.
Hydroboration-Oxidation
This is the main comparison students make with oxymercuration-demercuration. Hydroboration-oxidation gives the anti-Markovnikov alcohol, while oxymercuration-demercuration gives the Markovnikov alcohol. If a synthesis problem asks for the OH group on the less substituted carbon, hydroboration-oxidation is usually the better match.
Mercuration
Mercuration is the first stage of the process, where the alkene reacts with mercury(II) acetate and forms the mercurinium ion. If you know what mercuration does, demercuration makes more sense because it is just the cleanup step that removes mercury and replaces it with hydrogen.
Anti-Addition
The opening of the mercurinium ion happens from the backside, so the first step is anti. That does not always show up as the final stereochemical rule students focus on, but it matters for understanding how the intermediate is attacked. It also connects oxymercuration-demercuration to other reactions that add across double bonds with anti geometry.
Is oxymercuration–demercuration on the Organic Chemistry exam?
A quiz or problem set will usually give you an alkene and ask for the product after oxymercuration-demercuration, so you need to place the OH group on the more substituted carbon and add H to the other carbon. If the alkene is unsymmetrical, check which carbon would form the more substituted alcohol before you answer. If the options include a rearranged product, that is usually a trap, because this reaction does not go through a free carbocation.
You may also be asked to compare reagents. When you see Hg(OAc)2 followed by NaBH4, think oxymercuration-demercuration and Markovnikov hydration. On longer mechanism questions, label the mercurinium ion, show water attacking from the opposite side, and then show demurcuration replacing the mercury group with hydrogen.
Oxymercuration–demercuration vs Acid-Catalyzed Hydration
These two both hydrate alkenes to make alcohols, but acid-catalyzed hydration uses a carbocation intermediate and can rearrange. Oxymercuration-demercuration uses a bridged mercurinium ion instead, so the product is usually cleaner and still Markovnikov. If a question mentions rearrangements, that is your clue to separate the two.
Key things to remember about oxymercuration–demercuration
Oxymercuration-demercuration turns an alkene into a Markovnikov alcohol in two steps.
The reaction uses mercury(II) acetate first, then a reducing step to remove mercury and leave hydrogen behind.
A bridged mercurinium ion keeps the mechanism from going through a free carbocation, so rearrangements do not usually happen.
If the alkene is unsymmetrical, the OH group ends up on the more substituted carbon.
When you see Hg(OAc)2 followed by NaBH4, think clean alkene hydration, not anti-Markovnikov addition.
Frequently asked questions about oxymercuration–demercuration
What is oxymercuration-demercuration in Organic Chemistry?
It is a two-step alkene hydration reaction that produces an alcohol. The alkene first forms a mercurinium ion with mercury(II) acetate, then water adds, and the mercury is removed in the second step. The usual result is a Markovnikov alcohol without carbocation rearrangements.
Does oxymercuration-demercuration give Markovnikov or anti-Markovnikov products?
It gives Markovnikov products. The OH group ends up on the more substituted carbon of the alkene. That is one reason this reaction is so useful when you want a specific alcohol and do not want rearrangements.
Why doesn't oxymercuration-demercuration rearrange?
Because it does not form a free carbocation. The positive charge is held in a bridged mercurinium ion, which is much more controlled than a carbocation intermediate. That makes the product more predictable than acid-catalyzed hydration.
How is oxymercuration-demercuration different from hydroboration-oxidation?
They both add water across an alkene, but they put the OH group in different places. Oxymercuration-demercuration gives the Markovnikov alcohol, while hydroboration-oxidation gives the anti-Markovnikov alcohol. If you mix them up, your final product will be on the wrong carbon.