Skip to main content
The new Teacher Workspace is here. Your first 3 assignments are free. Try it →

Platinum(ii)

Platinum(II) is platinum in the +2 oxidation state, usually a d8 square planar metal center in Inorganic Chemistry II. It shows up most often in ligand substitution and coordination chemistry.

Last updated July 2026

What is platinum(ii)?

Platinum(II) is the +2 oxidation state of platinum, written Pt(II) or Pt2+, and in Inorganic Chemistry II you usually meet it as a coordination complex rather than as a free ion. Because Pt(II) is a d8 metal center, it strongly favors square planar geometry in many common complexes.

That geometry matters a lot. A square planar Pt(II) complex has four ligands arranged in one plane, with open space above and below the plane. Those open axial sites make the complex accessible to an incoming ligand, which is why Pt(II) compounds are such a useful model for ligand substitution reactions.

In many Pt(II) substitutions, the incoming ligand starts to bind before the old ligand leaves, so the pathway is often associative. You can think of it as a temporary five-coordinate intermediate or transition state forming first, then the leaving group exits. This is different from a simple swap happening in one isolated step, and it is one reason Pt(II) chemistry is studied so closely in kinetics.

The ligands attached to platinum(II) change everything about the complex. Ammines, phosphines, and halides can shift the rate of substitution, alter the trans effect, and change which products form most easily. A chloro ligand, for example, often makes a complex more substitution-labile than one with a stronger donor ligand, so the identity of each ligand is part of the mechanism, not just decoration.

A classic example is cisplatin, a Pt(II) complex used in medicinal chemistry. In the body, its chloride ligands are eventually substituted by water and then by DNA bases, which is why the substitution chemistry of Pt(II) is not just theoretical. In class, Pt(II) is usually the metal ion you use to explain square planar bonding, kinetic behavior, and how ligand identity controls reactivity.

Why platinum(ii) matters in Inorganic Chemistry II

Platinum(II) is one of the clearest examples of how oxidation state, electron count, and geometry work together in coordination chemistry. If you can predict why Pt(II) prefers square planar geometry, you can make better sense of its spectra, its substitution rates, and the products it forms in reactions.

It also gives you a concrete way to connect structure to mechanism. In substitution problems, Pt(II) is often the metal center that points you toward an associative pathway instead of a dissociative one. That means you are not just naming a species, you are predicting how the reaction proceeds and which factors speed it up or slow it down.

Pt(II) also shows up in real chemical applications, especially catalysis and bioinorganic chemistry. Cisplatin is the familiar case because its Pt(II) center is reactive enough to exchange ligands inside the body, but stable enough to be delivered as a drug. That balance between inertness and reactivity is a theme that comes up again and again in Inorganic Chemistry II.

Keep studying Inorganic Chemistry II Unit 4

Official unit cheatsheet

open one-pager

How platinum(ii) connects across the course

Square Planar Geometry

Pt(II) commonly sits in a square planar arrangement because its d8 electron count makes that geometry especially stable. When you see Pt(II), you should immediately think about four ligands in one plane and the open axial positions that affect how substitution happens. That geometry is the reason associative attack is so common.

Substitution Reaction

Platinum(II) is a classic metal center for ligand substitution problems. The key question is not just which ligand leaves, but whether the incoming ligand starts bonding before the old one departs. Pt(II) complexes often substitute in a stepwise, associative way, so they are a standard example for reaction mechanism analysis.

trans Effect

The trans effect is especially useful in Pt(II) chemistry because it helps explain why one ligand ends up leaving faster when it sits opposite a strong trans-directing ligand. In practice, this controls product distribution in square planar complexes. If you are predicting a synthesis or mechanism, the trans effect can tell you which position is most reactive.

Palladium(II)

Palladium(II) and platinum(II) are often compared because both are d8, square planar, and common in substitution chemistry. The details are not identical, though. Pd(II) is usually more kinetically labile, while Pt(II) is often slower and easier to study by mechanism, which makes the comparison useful in organometallic and coordination questions.

Is platinum(ii) on the Inorganic Chemistry II exam?

A quiz or problem set will usually ask you to identify Pt(II) from its charge, electron count, or geometry, then predict how it reacts with incoming ligands. You might be given a square planar complex and asked whether substitution is more likely associative or dissociative, or which ligand is most likely to leave first.

You may also have to connect Pt(II) to real examples like cisplatin, explain why its geometry is square planar, or use the trans effect to justify a product. In mechanism questions, look for the incoming ligand binding first, a five-coordinate intermediate or transition state, and then departure of the leaving group. If a prompt asks about reactivity, answer with both structure and kinetics, not just the oxidation state.

Platinum(ii) vs Palladium(II)

Both Pt(II) and Pd(II) are d8, square planar, and common in substitution chemistry, so they are easy to mix up. The big difference in class problems is usually reactivity: Pd(II) is often more labile, while Pt(II) is typically slower and more kinetically informative. If you are asked about mechanism or product control, that difference matters.

Key things to remember about platinum(ii)

  • Platinum(II) means platinum in the +2 oxidation state, usually written as Pt(II) in coordination compounds.

  • Pt(II) is usually d8 and square planar, so geometry is one of the first clues you use when identifying it in a problem.

  • Its substitution chemistry is often associative, which means the new ligand begins bonding before the old one fully leaves.

  • Ligands like amines, phosphines, and halides change both the stability and the reactivity of Pt(II) complexes.

  • Pt(II) shows up in real systems like cisplatin, where ligand substitution controls how the complex reacts with biological targets.

Frequently asked questions about platinum(ii)

What is platinum(II) in Inorganic Chemistry II?

Platinum(II) is platinum in the +2 oxidation state, usually found in coordination complexes rather than as a bare ion. In Inorganic Chemistry II, it is most often discussed as a square planar d8 metal center with distinctive ligand substitution behavior.

Why does platinum(II) form square planar complexes?

Pt(II) has a d8 electron configuration, and square planar geometry gives a stable arrangement for many of its complexes. The geometry also leaves open space above and below the plane, which affects how ligands approach during substitution.

Is platinum(II) substitution associative or dissociative?

Pt(II) substitution is often associative, meaning the incoming ligand starts bonding before the leaving group fully departs. In mechanism questions, that usually means you should look for a five-coordinate intermediate or transition state.

How is platinum(II) different from palladium(II)?

They are similar because both are d8 and often square planar, but Pt(II) is usually less labile and slower to substitute. Pd(II) tends to react faster, so the two metals can behave differently even when the structures look almost the same.

Platinum(II) in Inorganic Chemistry II | Fiveable