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🏃🏽‍♀️Galois Theory Unit 5 Review

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5.2 Fixed fields and the Fundamental Theorem of Galois Theory

5.2 Fixed fields and the Fundamental Theorem of Galois Theory

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025
🏃🏽‍♀️Galois Theory
Unit & Topic Study Guides

Fixed fields and the Fundamental Theorem of Galois Theory are key concepts in understanding field extensions. They link automorphisms, subfields, and subgroups, providing a powerful framework for analyzing field structures.

This correspondence allows us to translate problems between group theory and field theory. By studying subgroups of the Galois group, we can uncover properties of subfields and vice versa, simplifying complex algebraic questions.

Fixed fields of automorphisms

Definition and properties

  • The fixed field of a group of automorphisms GG of a field extension K/FK/F consists of all elements of KK fixed by every automorphism in GG
  • If GG is a group of automorphisms of a field KK, the fixed field of GG, denoted by Fix(G)Fix(G) or KGK^G, forms a subfield of KK
  • The fixed field equals the intersection of all fields fixed by each individual automorphism in GG
  • The degree of the extension K/Fix(G)K/Fix(G) matches the order of the group GG, expressed as [K:Fix(G)]=G[K:Fix(G)] = |G|
  • The Galois group of the extension K/Fix(G)K/Fix(G) is isomorphic to the group GG

Characterization and examples

  • For a cyclic group G=σG = \langle \sigma \rangle generated by an automorphism σ\sigma, the fixed field Fix(G)Fix(G) consists of elements aKa \in K satisfying σ(a)=a\sigma(a) = a
  • In the extension Q(2,i)/Q\mathbb{Q}(\sqrt{2}, i)/\mathbb{Q}, the fixed field of the automorphism σ:22,ii\sigma: \sqrt{2} \mapsto -\sqrt{2}, i \mapsto i is Q(i)\mathbb{Q}(i)
  • For the extension Q(24)/Q\mathbb{Q}(\sqrt[4]{2})/\mathbb{Q}, the fixed field of the Galois group G={id,σ,σ2,σ3}G = \{\text{id}, \sigma, \sigma^2, \sigma^3\}, where σ:24i24\sigma: \sqrt[4]{2} \mapsto i\sqrt[4]{2}, is Q\mathbb{Q}
  • In the extension Q(2,3)/Q\mathbb{Q}(\sqrt{2}, \sqrt{3})/\mathbb{Q}, the fixed field of the subgroup H={id,σ}H = \{\text{id}, \sigma\}, where σ:22,33\sigma: \sqrt{2} \mapsto -\sqrt{2}, \sqrt{3} \mapsto \sqrt{3}, is Q(3)\mathbb{Q}(\sqrt{3})

Fundamental Theorem of Galois Theory

Statement and interpretation

  • The Fundamental Theorem of Galois Theory establishes a one-to-one correspondence between subfields of a Galois extension and subgroups of its Galois group
  • For a Galois extension K/FK/F with Galois group GG, there exists a bijection between subfields of KK containing FF and subgroups of GG, given by HFix(H)H \mapsto Fix(H) and EGal(K/E)E \mapsto Gal(K/E)
  • The correspondence reverses inclusions: for subgroups H1H_1 and H2H_2 of GG with H1H2H_1 \subseteq H_2, we have Fix(H2)Fix(H1)Fix(H_2) \subseteq Fix(H_1)
  • The degree of the extension K/EK/E equals the index of the corresponding subgroup Gal(K/E)Gal(K/E) in GG, expressed as [K:E]=[G:Gal(K/E)][K:E] = [G:Gal(K/E)]
  • A subfield EE is a Galois extension of FF if and only if the corresponding subgroup Gal(K/E)Gal(K/E) is a normal subgroup of GG, in which case the Galois group of E/FE/F is isomorphic to the quotient group G/Gal(K/E)G/Gal(K/E)

Examples and consequences

  • In the extension Q(2,i)/Q\mathbb{Q}(\sqrt{2}, i)/\mathbb{Q}, the subgroup H={id,σ}H = \{\text{id}, \sigma\}, where σ:22,ii\sigma: \sqrt{2} \mapsto -\sqrt{2}, i \mapsto i, corresponds to the subfield Q(i)\mathbb{Q}(i)
  • For the extension Q(24)/Q\mathbb{Q}(\sqrt[4]{2})/\mathbb{Q} with Galois group G={id,σ,σ2,σ3}G = \{\text{id}, \sigma, \sigma^2, \sigma^3\}, the subgroup H={id,σ2}H = \{\text{id}, \sigma^2\} corresponds to the subfield Q(2)\mathbb{Q}(\sqrt{2})
  • The Fundamental Theorem implies that for a Galois extension K/FK/F, the subfield FF corresponds to the entire Galois group GG, while the field KK corresponds to the trivial subgroup {id}\{\text{id}\}
  • As a consequence of the Fundamental Theorem, a finite extension K/FK/F is Galois if and only if Aut(K/F)=[K:F]|Aut(K/F)| = [K:F]
Definition and properties, Absolute Galois group - Wikipedia

Galois correspondence

Finding corresponding subfields and subgroups

  • To find the subfield corresponding to a given subgroup HH of the Galois group GG, calculate the fixed field Fix(H)Fix(H) by identifying elements of KK fixed by every automorphism in HH
  • To find the subgroup corresponding to a given subfield EE of KK containing FF, calculate the Galois group Gal(K/E)Gal(K/E) by finding automorphisms of KK that fix every element of EE
  • The Galois correspondence preserves the lattice structure of subgroups and subfields: the intersection of subgroups corresponds to the compositum of subfields, and the join of subgroups corresponds to the intersection of subfields
  • The Galois correspondence helps determine the lattice of subfields of a Galois extension by studying the lattice of subgroups of its Galois group

Examples and applications

  • In the extension Q(2,3)/Q\mathbb{Q}(\sqrt{2}, \sqrt{3})/\mathbb{Q}, the subgroup H={id,σ}H = \{\text{id}, \sigma\}, where σ:22,33\sigma: \sqrt{2} \mapsto -\sqrt{2}, \sqrt{3} \mapsto \sqrt{3}, corresponds to the subfield Q(3)\mathbb{Q}(\sqrt{3})
  • For the extension Q(23)/Q\mathbb{Q}(\sqrt[3]{2})/\mathbb{Q} with Galois group G={id,σ,σ2}G = \{\text{id}, \sigma, \sigma^2\}, where σ:23ω23\sigma: \sqrt[3]{2} \mapsto \omega\sqrt[3]{2} and ω\omega is a primitive cube root of unity, the subfield Q(ω)\mathbb{Q}(\omega) corresponds to the subgroup {id,σ}\{\text{id}, \sigma\}
  • The Galois correspondence can be used to prove that for a Galois extension K/FK/F with Galois group GG, the number of subfields of KK containing FF equals the number of subgroups of GG
  • In cryptography, the Galois correspondence is applied to construct finite fields with desired properties for use in encryption and error correction codes

Applying the Fundamental Theorem

Solving problems in field theory

  • Use the Fundamental Theorem to determine the existence and uniqueness of subfields with specific properties, such as degree or Galois group
  • Apply the Galois correspondence to construct field extensions with desired properties by finding appropriate subgroups of the Galois group
  • Utilize the Fundamental Theorem to prove theorems about the structure of field extensions, such as the existence of intermediate fields or the solvability of polynomial equations
  • Employ the Galois correspondence to simplify the computation of Galois groups by working with subfields instead of automorphisms
  • Use the Fundamental Theorem to study relationships between different field extensions and their Galois groups, such as compositums, intersections, and quotients

Examples and applications

  • Prove that for a Galois extension K/FK/F with Galois group GG, there exists a unique subfield EE of KK containing FF with [E:F]=n[E:F] = n if and only if GG has a unique subgroup of index nn
  • Construct a field extension K/QK/\mathbb{Q} with Galois group isomorphic to the dihedral group D4D_4 by finding a polynomial whose splitting field has D4D_4 as its Galois group and applying the Galois correspondence
  • Use the Fundamental Theorem to prove that a polynomial f(x)F[x]f(x) \in F[x] is solvable by radicals if and only if its Galois group over FF is a solvable group
  • Determine the Galois group of the splitting field of x42x^4 - 2 over Q\mathbb{Q} by studying the lattice of subfields and applying the Galois correspondence
  • Investigate the relationship between the splitting fields of polynomials f(x)f(x) and g(x)g(x) over a field FF by examining the subgroups of the Galois group of the compositum of their splitting fields