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AP Physics C: Mechanics Unit 7 practice questions

Try 10 multiple-choice questions from Unit 7 here. Pick an answer to see why it's right or wrong, then take the timed test above for a full AP-style set.

  1. Question 1

    A block of mass m oscillates vertically on a spring with constant k inside an elevator accelerating upward at a. Which claim about the period T is correct based on the spring-mass model?

    T remains 2π√(m/k) because the uniform inertial force only shifts the equilibrium position.

    T decreases because the effective gravity g+a increases the restoring force on the mass.

    T increases because the effective gravity g-a decreases the restoring force on the mass.

    T changes because the amplitude of oscillation is reduced by the upward acceleration force.

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    Answer: (A)

    Analyzing the differential equation for a spring-mass system with a constant external force reveals that the period depends only on mass and stiffness. The upward acceleration adds a constant term to the force but does not change the restoring force coefficient k or the inertial mass m.

  2. Question 2

    A simple pendulum of length L hangs in a cart accelerating horizontally at a. Which claim about the new period T is justified by the pendulum model?

    T decreases because the effective gravitational acceleration magnitude increases to √(g²+a²).

    T increases because the effective gravitational acceleration magnitude increases to √(g²+a²).

    T increases because the effective gravitational acceleration magnitude decreases to √(g²-a²).

    T stays constant because the period depends only on the vertical component of acceleration.

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    Answer: (A)

    Applying the pendulum model in a non-inertial frame requires replacing g with the effective gravitational field magnitude. The vector sum of gravity and the fictitious inertial force results in a larger effective g, which appears in the denominator of the period equation, reducing T.

  3. Question 3

    An ideal spring of constant k is cut into two equal lengths, and a mass m is suspended from one half. Which claim describes the new period T_new compared to the original period T_old?

    T_new = T_old/√(2) because the spring constant doubles when the length is halved.

    T_new = T_old/2 because the spring constant quadruples when the length is halved.

    T_new = T_old√(2) because the spring constant halves when the length is halved.

    T_new = 2T_old because the spring constant quarters when the length is halved.

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    Answer: (A)

    Applying the model of spring stiffness reveals that k is inversely proportional to length; halving the length doubles the spring constant to 2k. Substituting 2k into the period equation results in the period decreasing by a factor of 1/√(2).

  4. Question 4

    A particle of mass m moves such that its acceleration a is given by a = -Cx, where C is a positive constant. Which claim about the period T is justified by this relationship?

    T = 2π/√(C) because the constant C represents the square of the angular frequency.

    T = 2π√(C) because the constant C represents the inverse square of angular frequency.

    T = 2π/C because the constant C represents the angular frequency of the motion directly.

    T = 2πC because the constant C represents the inverse of the angular frequency directly.

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    Answer: (A)

    Comparing the given equation of motion to the definition of simple harmonic motion (a = -ω²x) allows for the identification of the constant C as ω². Solving for the period T = 2π/ω yields T = 2π/√(C).

  5. Question 5

    A block of mass mm attached to a spring with constant kk oscillates with amplitude AA. How does the magnitude of the block's acceleration at position x=Ax = A compare to its acceleration at position x=A/2x = A/2?

    It is four times greater at x=Ax = A

    It is two times greater at x=Ax = A

    It is the same at both positions

    It is half as large at x=Ax = A

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    Answer: (B)

    Comparing the restoring forces using F=−kxF = -kx and Newton's second law F=maF = ma shows that acceleration is directly proportional to displacement (a=−kmxa = -\frac{k}{m}x). Since AA is twice as large as A/2A/2, the acceleration at AA is double the acceleration at A/2A/2.

  6. Question 6

    Two identical springs are attached to blocks of mass mm and 4m4m. Both systems oscillate with the same amplitude AA. How does the maximum speed v1v_1 of the block with mass mm compare to the maximum speed v2v_2 of the block with mass 4m4m?

    v1v_1 is one-fourth of v2v_2

    v1v_1 is one-half of v2v_2

    v1v_1 is twice as large as v2v_2

    v1v_1 is four times as large as v2v_2

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    Answer: (C)

    Analyzing the maximum speed vmax=Aωv_{max} = A\omega where ω=k/m\omega = \sqrt{k/m} reveals the relationship. Since mass mm is in the denominator under a square root, the system with mass 4m4m has half the frequency (1/4=1/2\sqrt{1/4} = 1/2), making v1v_1 twice v2v_2.

  7. Question 7

    A spring with constant kk and mass mm oscillates horizontally. The same system is then hung vertically. How do the period TT and equilibrium position xeqx_{eq} of the vertical system compare to the horizontal system?

    TT is the same; xeqx_{eq} is different

    TT is greater; xeqx_{eq} is different

    TT is smaller; xeqx_{eq} is the same

    TT is the same; xeqx_{eq} is the same

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    Answer: (A)

    Evaluating the period equation T=2πm/kT = 2\pi\sqrt{m/k} shows it depends only on mass and spring constant, not gravity or orientation. However, the vertical system has a new equilibrium position where the spring force balances gravity (kΔx=mgk\Delta x = mg), unlike the unstretched equilibrium of the horizontal system.

  8. Question 8

    A particle undergoes simple harmonic motion. If the amplitude of oscillation is doubled from AA to 2A2A, how does the new period TnewT_{new} compare to the original period ToldT_{old}?

    T_{new} = 0.5 T_{old}

    T_{new} = 1.0 T_{old}

    T_{new} = 1.4 T_{old}

    T_{new} = 2.0 T_{old}

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    Answer: (B)

    Applying the formula for the period of a simple harmonic oscillator T=2πm/kT = 2\pi\sqrt{m/k} reveals that period is independent of amplitude. The increased distance is exactly compensated by the higher average speed resulting from larger restoring forces.

  9. Question 9

    A block oscillates on a horizontal spring. How does the magnitude of acceleration aeqa_{eq} at the equilibrium position compare to the magnitude of acceleration aturna_{turn} at the turning points?

    aeqa_{eq} is zero while aturna_{turn} is maximum

    aeqa_{eq} is maximum while aturna_{turn} is zero

    aeqa_{eq} and aturna_{turn} are both zero

    aeqa_{eq} and aturna_{turn} are both maximum

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    Answer: (A)

    Connecting acceleration to force via Newton's second law (F=maF=ma) and the spring force law (F=−kxF=-kx) shows that at equilibrium (x=0x=0), force and acceleration are zero. At turning points (x=±Ax=\pm A), displacement is maximum, making force and acceleration maximum.

  10. Question 10

    Two blocks with masses mm and 3m3m are attached to identical springs with constant kk and extended to the same amplitude AA. How does the magnitude of acceleration a1a_1 of the lighter block compare to a2a_2 of the heavier block at the moment of release?

    a1a_1 is one-third the magnitude of a2a_2

    a1a_1 is equal to the magnitude of a2a_2

    a1a_1 is three times the magnitude of a2a_2

    a1a_1 is nine times the magnitude of a2a_2

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    Answer: (C)

    Using Newton's second law a=F/ma = F/m, and recognizing that the restoring force F=kAF = kA is identical for both blocks at release, the acceleration is inversely proportional to mass. The block with mass mm therefore has three times the acceleration of the block with mass 3m3m.

What's on the AP Physics C: Mechanics Unit 7 practice test

The standard version takes about 88 minutes and follows the timing and directions of the AP exam, sized to one unit:

  • 20 Multiple Choice Questions (40 minutes)
  • 1 FRQ – FRQ 1 – Mathematical Routines (24 minutes)
  • 1 FRQ – FRQ 2 – Translation Between Representations (24 minutes)

Questions are drawn from 730 multiple-choice questions and 24 FRQs written for Unit 7, Oscillations.

Practice AP Physics C: Mechanics Unit 7 FRQs

Answer the unit's free-response questions one at a time and get a score on every part.

Review Unit 7 before you start

Other AP Physics C: Mechanics unit tests