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LiAlH4

LiAlH4, or lithium aluminum hydride, is a strong reducing agent in Organic Chemistry. It donates hydride to reduce carbonyl compounds, esters, and amides into more reduced products.

Last updated July 2026•Fiveable Content Team

What is LiAlH4?

LiAlH4, short for lithium aluminum hydride, is a very strong hydride donor used in Organic Chemistry when you want to reduce a functional group. It is not a gentle reagent. It reacts fast, and it can reduce several carbonyl-derived compounds that weaker reagents cannot touch.

In practice, LiAlH4 delivers hydride ions, which act like a source of H- for a carbonyl carbon. That matters because carbonyl carbons are electrophilic, so they are ready to accept electron density. After the hydride attack, the reaction is usually finished with a separate water or acid workup step, which protonates the oxygen and gives the neutral alcohol or amine product.

The most common pattern is reduction of aldehydes and ketones to alcohols. Aldehydes become primary alcohols, while ketones become secondary alcohols. If you see a carbonyl on an exam question and the product has fewer oxygen-to-carbon bonding features than the starting material, LiAlH4 may be the reagent that made the change.

LiAlH4 goes further than many other reducing agents because it can also reduce more stable carbonyl derivatives. Esters are converted to alcohols, usually giving two alcohol fragments after the ester bond is broken and the carbonyl carbon is reduced. Amides are reduced to amines, which is especially useful in amine synthesis because the carbonyl oxygen is removed from the molecule while the nitrogen stays attached.

A big practical detail is that LiAlH4 must be kept away from water, alcohols, and other protic solvents until the workup step. Those solvents would quench it immediately, often with a vigorous reaction. So in lab-style problems, the reagent choice usually signals an anhydrous first step followed by a separate aqueous workup.

Why LiAlH4 matters in Organic Chemistry

LiAlH4 shows up anywhere you need to move a molecule to a lower oxidation state in a controlled way. In Organic Chemistry, that usually means changing a carbonyl-containing functional group into an alcohol or amine, which is a common move in synthesis problems.

It is especially useful because it reaches farther than sodium borohydride. If you only needed to reduce an aldehyde or ketone, a milder reagent might be enough. But if the starting material is an ester or amide, LiAlH4 is one of the standard answers because those groups are less reactive and need a stronger hydride source.

The term also ties together several units that can feel separate at first. Carbonyl reactivity, nucleophilic addition, acyl derivatives, and amine synthesis all connect through LiAlH4. Once you recognize what it does, you can predict the product faster and avoid mixing up reduction with hydrolysis or substitution.

It also shows up in mechanism questions because the reagent choice tells you the reaction path. If LiAlH4 is present, you should think hydride attack on an electrophilic carbon, followed by protonation in the workup. That mental model makes it easier to trace what changed in the molecule and what stayed the same.

Keep studying Organic Chemistry Unit 24

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How LiAlH4 connects across the course

Reducing Agent

LiAlH4 is a reducing agent, which means it lowers the oxidation state of the substrate by delivering hydride. In Organic Chemistry, that label tells you to look for products with fewer bonds to oxygen or more bonds to hydrogen. The reagent is much stronger than many common reducers, so the type of functional group matters when you predict the outcome.

Nucleophilic Addition

The first step in reducing aldehydes and ketones with LiAlH4 is a nucleophilic addition to the carbonyl carbon. The hydride attacks the electrophilic carbon, and the C=O pi bond shifts onto oxygen. That is why carbonyl chemistry and reduction are linked, even though the final product is an alcohol.

Ester Hydrolysis

Ester hydrolysis and ester reduction can look similar at a glance because both start from an ester, but they give very different products. Hydrolysis breaks the ester with water or base and keeps the carbonyl carbon oxidized. LiAlH4 instead reduces the ester all the way to alcohols, so the product set is completely different.

Acid-Catalyzed Hydrolysis

Acid-catalyzed hydrolysis is a reaction pathway for breaking functional groups using water under acidic conditions, while LiAlH4 is used in a reduction pathway. The two reagents do opposite jobs, so spotting which one is present tells you whether to expect bond cleavage by hydrolysis or oxidation-state change by reduction.

Is LiAlH4 on the Organic Chemistry exam?

A problem-set question may give you a starting material such as an ester, amide, aldehyde, or ketone and ask for the product after LiAlH4, then workup. Your job is to recognize which functional group can be reduced and draw the correct alcohol or amine product, not just label the reagent as "strong."

In mechanism questions, you may need to show hydride attack on the carbonyl carbon, then protonation during workup. If the substrate is an ester, remember that the carbonyl portion is reduced to an alcohol and the alkoxy group is not simply "left alone" in the final product. If the substrate is an amide, the carbonyl oxygen is removed from the picture and the nitrogen-containing product is an amine.

You may also be asked to compare LiAlH4 with a milder reducing agent or explain why a reaction has to be done without water until the final quench. That is where the solvent sensitivity matters.

LiAlH4 vs NaBH4

LiAlH4 and NaBH4 are both hydride reducing agents, but they are not equally strong. NaBH4 is usually used for aldehydes and ketones, while LiAlH4 can also reduce esters and amides. If a question includes a tougher carbonyl derivative, LiAlH4 is usually the better fit.

Key things to remember about LiAlH4

  • LiAlH4 is a strong hydride reducing agent used to push organic molecules to a lower oxidation state.

  • In aldehydes and ketones, it gives alcohols after hydride attack and protonation during workup.

  • It can also reduce esters to alcohols and amides to amines, which makes it more powerful than many milder reducers.

  • LiAlH4 must stay away from water and other protic solvents until the workup step because it reacts violently with them.

  • If you see LiAlH4 in a mechanism problem, think hydride addition first and protonation second.

Frequently asked questions about LiAlH4

What is LiAlH4 in Organic Chemistry?

LiAlH4 is lithium aluminum hydride, a strong reducing agent used to add hydride to carbonyl-containing compounds. It commonly converts aldehydes and ketones into alcohols, and it can also reduce esters and amides. The final product depends on the starting functional group.

What does LiAlH4 reduce?

LiAlH4 reduces several common functional groups, especially aldehydes, ketones, esters, and amides. Aldehydes and ketones become alcohols, esters usually become alcohols, and amides become amines. It is chosen when a milder reagent would not be strong enough.

Is LiAlH4 stronger than NaBH4?

Yes. LiAlH4 is much stronger and can reduce functional groups that NaBH4 usually cannot, like esters and amides. NaBH4 is more selective and is often limited to aldehydes and ketones. If you are unsure which reagent fits, the starting material usually gives the clue.

Why can't LiAlH4 be used with water?

LiAlH4 reacts violently with water and other protic solvents because the hydride is very reactive. That means the reaction is usually run in dry ether-type solvents first, then quenched with water or acid at the end. On a mechanism or lab question, that solvent choice is a big clue that LiAlH4 is being used.