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Honors Physics Unit 16 Review: Mirrors and Lenses

This unit is about how light changes direction when it bounces off a surface or passes into a new material, and how mirrors and lenses use that to form images. By the end, you should be able to draw ray diagrams, use Snell's law, and predict where an image forms, how big it is, and whether it is real or virtual.

Read the big ideas first, then work through each topic note and try the checkpoint question before you look at its answer.

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What is Honors Physics unit 16?

In this unit, light is modeled as rays that travel in straight lines until they hit a boundary. At a boundary, light can both reflect back and refract into the new material. Curved mirrors and lenses can make rays from one point meet, or appear to come from one point, to form an image.

Honors Physics Unit 16 covers geometric optics in three parts. Reflection covers the law of reflection, plane mirrors, and concave and convex mirrors. Refraction covers the index of refraction, Snell's law, critical angle, and total internal reflection. Lenses covers converging and diverging lenses and the human eye. Across all three, you use ray diagrams, the mirror and thin lens equation 1do+1di=1f\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}, and the magnification equation M=hiho=−didoM = \frac{h_i}{h_o} = -\frac{d_i}{d_o} to locate and describe images.

Light reflects off a surface at the same angle it comes in.

The law of reflection says θi=θr\theta_i = \theta_r, with both angles measured from the normal. A flat mirror gives a virtual, upright, same-size image. Curved mirrors focus or spread light, so they can make images that are larger, smaller, or flipped.

Light can bend when it changes speed crossing into a new material.

A material's index of refraction is n=cvn = \frac{c}{v}, so a larger nn means slower light. Snell's law, n1sin⁡θ1=n2sin⁡θ2n_1 \sin\theta_1 = n_2 \sin\theta_2, tells you how much the ray bends. If light tries to leave a slow material at too steep an angle, none of it gets out, and you get total internal reflection.

Lenses use refraction to form images, and one equation describes them.

A converging lens can form a real image or a virtual one, depending on where the object sits relative to the focal point. For a real object, a diverging lens forms a virtual, upright, smaller image. The thin lens equation and the magnification equation give you the image location, size, and orientation.

Images form where light rays meet, or where they appear to come from.

A real image forms where rays actually converge, so you can project it on a screen. A virtual image forms where rays only seem to come from when you trace them backward, like the image behind a bathroom mirror. Ray diagrams show this geometry, and the equations turn it into numbers. Sign conventions keep track of which kind of image you have.

Honors Physics unit 16 topics

16.1

Reflection

Light hitting a mirror leaves at the same angle it arrived, \theta_i = \theta_r.

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16.2

Refraction

Refraction is the change in direction of light as it crosses into a material where it moves at a different speed.

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16.3

Lenses

A lens refracts light at both of its surfaces to form an image.

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Unit 16 review notes

16.1

Reflection

Light hitting a mirror leaves at the same angle it arrived, θi=θr\theta_i = \theta_r. Measure both angles from the normal, the line perpendicular to the surface, and not from the surface itself. Smooth surfaces give specular reflection and a clear image. Rough surfaces like paper give diffuse reflection, which scatters light in many directions.

A plane mirror makes a virtual, upright image that is the same size as the object and as far behind the mirror as the object is in front. A concave mirror curves inward and focuses rays parallel to the principal axis near a focal point in front of it. A convex mirror curves outward and spreads rays, so it makes a virtual, upright, smaller image of a real object. For spherical mirrors and rays close to the principal axis, f=R2f = \frac{R}{2}, where RR is positive for concave mirrors and negative for convex mirrors.

Use 1do+1di=1f\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f} with ff positive for concave and negative for convex. A positive did_i means a real image in front of the mirror. A negative did_i means a virtual image behind it.

Worked example. A concave mirror has f=10f = 10 cm, and an object sits at do=30d_o = 30 cm. Then 1di=110−130=230\frac{1}{d_i} = \frac{1}{10} - \frac{1}{30} = \frac{2}{30}, so di=15d_i = 15 cm. Magnification is M=−1530=−0.5M = -\frac{15}{30} = -0.5. The image is real, inverted, and half the object's height.

  • Normal: The imaginary line perpendicular to a surface at the point where a ray hits, used as the reference for all angles.
  • Focal point: The point where rays close and parallel to the principal axis approximately meet after reflecting, or appear to come from for a convex mirror.
  • Center of curvature: The center of the sphere from which a spherical mirror is formed, located a distance ∣R∣=2∣f∣|R| = 2|f| from the mirror.

Try this question. A convex mirror has f=−12f = -12 cm and an object is 12 cm away. Where is the image and what is it like? (Answer: 1di=−112−112=−16\frac{1}{d_i} = -\frac{1}{12} - \frac{1}{12} = -\frac{1}{6}, so di=−6d_i = -6 cm. The image is virtual, 6 cm behind the mirror, upright, and half size since M=+0.5M = +0.5.)

Mirror and object positionImage typeOrientationSize
Plane mirror, any positionVirtualUprightSame size
Concave, object beyond CRealInvertedSmaller
Concave, object between C and FRealInvertedLarger
Concave, object inside FVirtualUprightLarger
Convex, any positionVirtualUprightSmaller
16.2

Refraction

Refraction is the change in direction of light as it crosses into a material where it moves at a different speed. A ray entering along the normal changes speed but does not change direction. The index of refraction n=cvn = \frac{c}{v} measures how much a material slows light. Some values are air at about 1.00, water at 1.33, glass at about 1.50, and diamond at 2.42. In water, light moves at 3.00×1081.33≈2.26×108\frac{3.00 \times 10^8}{1.33} \approx 2.26 \times 10^8 m/s.

Light bends toward the normal when it enters a higher-nn material and away from the normal when it enters a lower-nn material. Snell's law gives the exact angle, n1sin⁡θ1=n2sin⁡θ2n_1 \sin\theta_1 = n_2 \sin\theta_2.

Worked example. Light in air hits water at 45∘45^\circ. Then 1.00sin⁡45∘=1.33sin⁡θ21.00 \sin 45^\circ = 1.33 \sin\theta_2, so sin⁡θ2=0.7071.33=0.532\sin\theta_2 = \frac{0.707}{1.33} = 0.532 and θ2≈32.1∘\theta_2 \approx 32.1^\circ. The ray bent toward the normal because it entered a slower material.

Going the other way, from high nn to low nn, the refracted ray bends farther from the normal as you increase the incident angle. At the critical angle, the refracted ray skims along the surface at 90∘90^\circ, so sin⁡θc=n2n1\sin\theta_c = \frac{n_2}{n_1}. For water to air, θc≈48.8∘\theta_c \approx 48.8^\circ. Beyond that angle all the light reflects back. This is total internal reflection, which keeps light trapped inside fiber optic cables.

  • Index of refraction: The ratio n=cvn = \frac{c}{v} that tells how much slower light moves in a material than in a vacuum.
  • Critical angle: The incident angle, measured from the normal, at which light leaving a higher-nn material refracts at exactly 90∘90^\circ.
  • Total internal reflection: Complete reflection of light back into a higher-nn material when its incident angle is larger than the critical angle.

Try this question. What is the critical angle for light going from glass (n=1.50n = 1.50) into air? (Answer: sin⁡θc=1.001.50=0.667\sin\theta_c = \frac{1.00}{1.50} = 0.667, so θc≈41.8∘\theta_c \approx 41.8^\circ.)

16.3

Lenses

A lens refracts light at both of its surfaces to form an image. For a typical glass lens in air, a converging (convex) lens is thicker in the middle and brings rays parallel to the principal axis together near a focal point, so ff is positive. A diverging (concave) lens is thinner in the middle and spreads rays out, so ff is negative.

To draw a lens ray diagram, start with two rays. A ray parallel to the axis refracts through the far focal point, or for a diverging lens it seems to come from the near one. For a thin lens, a ray through the center goes approximately straight. The image is where the rays cross, or where their backward extensions cross.

The thin lens equation is 1do+1di=1f\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}, and magnification is M=hiho=−didoM = \frac{h_i}{h_o} = -\frac{d_i}{d_o}. A positive did_i means a real image on the far side of the lens. A negative did_i means a virtual image on the same side as the object.

Worked example. A magnifying glass has f=20f = 20 cm, and you hold a bug 1515 cm away. Then 1di=120−115=3−460=−160\frac{1}{d_i} = \frac{1}{20} - \frac{1}{15} = \frac{3 - 4}{60} = -\frac{1}{60}, so di=−60d_i = -60 cm. Magnification is M=−−6015=+4M = -\frac{-60}{15} = +4. You see a virtual, upright image 4 times larger.

Your eye is a lens system. The cornea does most of the bending, and the lens changes shape to focus on near or far objects.

  • Converging lens: A lens thicker in the center that bends parallel rays to a real focal point and has a positive focal length.
  • Diverging lens: A lens that spreads parallel rays and forms a virtual, upright, smaller image of a real object. A typical glass diverging lens in air is thinner in the center.
  • Accommodation: The eye's ability to change the shape of its lens so it can focus on objects at different distances.

Try this question. An object sits 10 cm from a diverging lens with f=−10f = -10 cm. Find the image. (Answer: 1di=−110−110=−15\frac{1}{d_i} = -\frac{1}{10} - \frac{1}{10} = -\frac{1}{5}, so di=−5d_i = -5 cm. The image is virtual, on the object's side, upright, and half size since M=+0.5M = +0.5.)

Lens and object positionImage typeOrientationEveryday use
Converging, object beyond FRealInvertedCamera, projector
Converging, object inside FVirtualUpright, enlargedMagnifying glass
Diverging, any positionVirtualUpright, smallerGlasses for nearsightedness

Key terms

TermDefinition
Law of reflectionThe rule that the angle of incidence equals the angle of reflection, with both measured from the normal.
Snell's lawThe equation $n_1 \sin\theta_1 = n_2 \sin\theta_2$ that relates the angles and indices of refraction at a boundary.
Focal lengthThe distance from a mirror or lens to its focal point, positive for converging devices and negative for diverging ones.
Real imageAn image formed where light rays actually meet, which can be projected onto a screen.
Virtual imageAn image located where rays only appear to come from, which cannot be projected onto a screen.
MagnificationThe ratio $M = \frac{h_i}{h_o} = -\frac{d_i}{d_o}$. A negative value means the image is inverted, and $|M| > 1$ means it is enlarged.
Thin lens equationThe relationship $\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}$ that connects object distance, image distance, and focal length for a thin lens. The same relationship is called the mirror equation for a spherical mirror, using rays close to the principal axis.
Principal axisThe main symmetry axis of a mirror or lens. For a spherical mirror, it passes through the mirror's center of curvature.

Mistakes to avoid in Mirrors and Lenses

Measuring angles from the surface instead of the normal

Problems often show the angle between the ray and the mirror or glass surface. Snell's law and the law of reflection both use angles from the normal. If you're given the angle to the surface, subtract it from 90∘90^\circ before plugging it in.

Thinking a negative image distance means a mistake

A negative did_i is a real answer. It means the image is virtual: behind the mirror, or on the same side of a lens as the object. Keep the sign and use it to describe the image instead of dropping it.

Expecting total internal reflection when light enters a denser material

Light going from air into water or glass always refracts in, because it bends toward the normal and never reaches 90∘90^\circ. Total internal reflection only happens going from higher nn to lower nn, and only past the critical angle.

Mixing up concave mirrors and concave lenses

A concave mirror converges light and has a positive ff. A concave lens diverges light and has a negative ff. To keep them straight, think about what each one does to parallel rays instead of relying on the shape name.

Study unit 16 other ways

Ready to review Unit 16?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.