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📚SAT (Digital) Unit 2 Review

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Probability and Conditional Probability

Probability and Conditional Probability

Written by the Fiveable Content Team • Last updated August 2025
Written by the Fiveable Content Team • Last updated August 2025

Probability and conditional probability questions appear on the Digital SAT within the Problem-Solving and Data Analysis domain. You can expect roughly 2–4 questions on this topic across the math section. These questions test whether you can pull the right numbers from a table or description, identify the correct total to divide by, and express your answer as a fraction, decimal, or percentage. The math itself is straightforward division, but the real challenge is reading carefully to know which numbers to use.

Probability Basics

Probability measures how likely an event is to occur. It always falls between 0 (impossible) and 1 (certain). The fundamental formula is:

P(event)=number of favorable outcomestotal number of possible outcomesP(\text{event}) = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}

On the SAT, "favorable outcomes" just means the count of whatever the question asks about, and "total" means the full group you're choosing from.

Example: A bag contains 8 red marbles, 5 blue marbles, and 7 green marbles. If one marble is selected at random, what is the probability that it is blue?

Total marbles: 8+5+7=208 + 5 + 7 = 20

P(blue)=520=14P(\text{blue}) = \frac{5}{20} = \frac{1}{4}

Relative frequency works the same way but uses observed data rather than a theoretical setup. If a factory inspects 400 items and finds 18 defective, the relative frequency of a defective item is:

18400=0.045\frac{18}{400} = 0.045

That 0.045 serves as an estimate of the probability that any given item is defective. Relative frequency is just probability calculated from real data.

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Two-Way Tables

Two-way tables are the most common format for SAT probability questions. They organize data by two categories (one across the top, one down the side) and include row totals, column totals, and a grand total. Your entire job is picking the right cell and the right total.

Here's a sample table you might see:

FictionNonfictionTotal
Hardcover305080
Paperback9030120
Total12080200

Question 1: If a book is selected at random, what is the probability that it is a paperback?

You're selecting from all 200 books, and 120 are paperback:

P(paperback)=120200=35P(\text{paperback}) = \frac{120}{200} = \frac{3}{5}

Question 2: What is the relative frequency of hardcover nonfiction books among all books?

The cell for hardcover nonfiction is 50, and the grand total is 200:

50200=14\frac{50}{200} = \frac{1}{4}

Notice that both of these use the grand total (200) as the denominator because the question asks about all books with no restrictions.

Conditional Probability

Conditional probability is where most students make errors, and it's heavily tested. A conditional probability question restricts the group you're looking at before you calculate. The giveaway language is "given that" or phrases like "among those who," "of the students who," or "if it is known that."

The formula is:

P(AB)=number in both A and Btotal number in BP(A \mid B) = \frac{\text{number in both A and B}}{\text{total number in B}}

The denominator is NOT the grand total. It's the total for whatever condition is specified.

Using the same table:

FictionNonfictionTotal
Hardcover305080
Paperback9030120
Total12080200

Question 3: Given that a book is fiction, what is the probability that it is paperback?

"Given that a book is fiction" means you only look at the Fiction column. The total for fiction is 120. Of those, 90 are paperback:

P(paperbackfiction)=90120=34P(\text{paperback} \mid \text{fiction}) = \frac{90}{120} = \frac{3}{4}

Question 4: If a paperback book is selected at random, what is the probability that it is nonfiction?

"A paperback book is selected" restricts you to the Paperback row. The total for paperback is 120. Of those, 30 are nonfiction:

P(nonfictionpaperback)=30120=14P(\text{nonfiction} \mid \text{paperback}) = \frac{30}{120} = \frac{1}{4}

Compare this to the overall probability of nonfiction: 80200=25\frac{80}{200} = \frac{2}{5}. The conditional restriction changes the answer significantly.

Area Models and Independent Events

An area model represents probability visually as a rectangle where the total area equals 1. Each region's area represents the probability of a combined outcome. You might see a square split into sections where one dimension represents one category and the other dimension represents a second category.

For example, suppose 60% of customers order coffee and 40% order tea. Of the coffee drinkers, 30% add sugar; of the tea drinkers, 50% add sugar. An area model would partition a rectangle accordingly, and the area of each section gives the probability of that combination.

Two events are independent events if the occurrence of one doesn't change the probability of the other. Mathematically, A and B are independent if:

P(AB)=P(A)P(A \mid B) = P(A)

On the SAT, you won't typically need to prove independence, but you should recognize that when events are independent, you can multiply their individual probabilities to get the probability of both occurring:

P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)

In the table examples above, being paperback and being fiction are not independent events because P(fictionpaperback)=90120=0.75P(\text{fiction} \mid \text{paperback}) = \frac{90}{120} = 0.75, which differs from P(fiction)=120200=0.60P(\text{fiction}) = \frac{120}{200} = 0.60.

Working Backward from a Given Probability

Some SAT questions give you a probability and ask you to find a missing number in a table or description. These are less common but do appear.

Example: A survey of 150 people recorded whether they preferred cats or dogs. The results are partially shown:

CatsDogsTotal
Adults??3560
Teens40??90
Total????150

The probability that a randomly selected person is an adult who prefers cats is 16\frac{1}{6}. How many adults prefer cats?

Set up the equation using the probability formula:

x150=16\frac{x}{150} = \frac{1}{6}

x=1506=25x = \frac{150}{6} = 25

So 25 adults prefer cats. From there you could fill in the rest of the table: adults who prefer dogs = 35 (already given), teens who prefer cats = total cats minus 25, and so on.

Another type: Given that a selected person is a teen, the probability they prefer cats is 49\frac{4}{9}. How many teens prefer cats?

x90=49\frac{x}{90} = \frac{4}{9}

x=90×49=40x = \frac{90 \times 4}{9} = 40

The key is identifying whether the given probability uses the grand total or a subgroup total as its denominator, then solving the resulting equation.

What to Watch For on Test Day

  1. Read the denominator carefully. The single biggest mistake is dividing by the grand total when the question specifies a subgroup (or vice versa). Words like "given that," "among," and "of those who" signal conditional probability with a restricted denominator.

  2. Don't confuse rows and columns. Before calculating, trace your finger along the table to confirm you're reading the correct cell. A question about "nonfiction paperbacks" and one about "paperback nonfiction" point to the same cell, but the totals you divide by may differ depending on the condition.

  3. Check whether the answer should be a fraction, decimal, or percentage. Some student-produced response questions accept any equivalent form, but make sure you're giving what's asked.

  4. For "working backward" problems, set up the equation first. Write xcorrect total=given probability\frac{x}{\text{correct total}} = \text{given probability}, then solve. Don't guess and check when algebra is faster.

  5. Probability can never be greater than 1. If your answer comes out above 1 (or above 100%), you've divided by the wrong number. Use this as a quick sanity check.