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AP Physics C: E&M Unit 11 Review: Electric Circuits

Review AP Physics C: E&M Unit 11 to build fluency with electric current, resistance, power, Kirchhoff's Rules, and RC circuit behavior. This unit carries 15-25% of the exam weight and connects directly to capacitors from Unit 10 and electromagnetic induction in Unit 13.

Use the topic guides, key terms, and FRQ practice available for this unit to work through every concept from drift velocity to RC time constants.

What is AP Physics C: E&M unit 11?

Electric circuits describe how charge flows through connected components to transfer and dissipate energy. Unit 11 builds from the microscopic picture of drifting charge carriers all the way to multi-loop DC networks and time-dependent RC behavior.

Unit 11 is about analyzing electric circuits: how current flows, how resistance and power are related, how to apply Kirchhoff's Rules to find unknown currents and voltages, and how capacitors charge and discharge through resistors over time.

Current and resistance

Current is defined as I = dq/dt and arises from charge carriers drifting with average velocity v_d. Resistance depends on material resistivity and geometry through R = rho*l/A. Ohm's law I = delta-V/R connects these to potential difference.

Kirchhoff's Rules

The loop rule (sum of delta-V = 0) enforces conservation of energy around any closed path. The junction rule (sum I_in = sum I_out) enforces conservation of charge at every node. Together they let you solve any DC resistor network.

RC circuits

When a capacitor charges or discharges through a resistor, charge and current follow exponential functions governed by the time constant tau = R_eq * C_eq. At t = 0 the capacitor acts like a short circuit; at t >> tau it acts like an open circuit.

Conservation laws drive circuit analysis

Every major tool in Unit 11 is a conservation law in disguise. Kirchhoff's loop rule is conservation of energy; the junction rule is conservation of charge. Even the exponential behavior of RC circuits comes from applying the loop rule to a circuit where charge accumulates on a capacitor. Recognizing which conservation principle applies in a given situation is the core skill of this unit.

AP Physics C: E&M unit 11 topics

11.1

Electric Current

Defines current as I = dq/dt and connects it to microscopic drift velocity through I = nqv_d*A and current density J = nqv_d. Introduces emf as the driving potential difference.

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11.2

Simple Circuits

Covers closed, open, and short circuits; circuit schematic symbols; series and parallel connections; and how a single element can belong to multiple loops.

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11.3

Resistance, Resistivity, and Ohm's Law

Derives R = rho*l/A for uniform conductors and extends to variable resistivity with integration. Applies Ohm's law I = delta-V/R and distinguishes ohmic from non-ohmic materials using I-V graphs.

open guide
11.4

Electric Power

Introduces P = I*delta-V and derived forms P = I^2*R and P = delta-V^2/R. Uses power to predict lightbulb brightness and analyze energy dissipation as Joule heating.

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11.5

Compound Direct Current Circuits

Reduces series-parallel resistor networks to equivalent resistance. Models real batteries with internal resistance r and terminal voltage emf - I*r. Covers correct placement and ideal properties of ammeters and voltmeters.

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11.6

Kirchhoff's Loop Rule

States sum delta-V = 0 around any closed loop as a consequence of energy conservation. Establishes sign conventions for voltage rises and drops and uses potential-versus-position graphs.

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11.7

Kirchhoff's Junction Rule

States sum I_in = sum I_out at any node as a consequence of charge conservation. Combines with the loop rule to solve multi-loop DC networks with multiple unknown branch currents.

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11.8

Resistor-Capacitor (RC) Circuits

Combines capacitor combination rules with Kirchhoff's loop rule to derive the RC differential equation. Solves charging and discharging behavior using exponential functions with time constant tau = R_eq*C_eq.

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practice snapshot

Hardest AP Physics C: E&M unit 11 topics

This snapshot uses Fiveable practice activity to show where students tend to miss questions and which review moves are worth prioritizing first.

54%average MCQ accuracy

Across 1.5k multiple-choice practice attempts for this unit.

1.5kMCQ attempts

Practice activity included in this snapshot.

0%average FRQ score

Across 1 scored free-response attempts for this unit.

Hardest topics in unit 11

MCQ miss rate
11.1

Review Electric Current with attention to how the concept appears in AP-style source and evidence questions.

56%210 tries
11.8

Review Resistor-Capacitor (RC) Circuits with attention to how the concept appears in AP-style source and evidence questions.

48%291 tries
11.5

Review Compound Direct Current Circuits with attention to how the concept appears in AP-style source and evidence questions.

45%390 tries
11.3

Review Resistance, Resistivity, and Ohm's Law with attention to how the concept appears in AP-style source and evidence questions.

42%169 tries

Unit 11 review notes

11.1

Electric Current and Current Density

Current is the rate of charge flow through a cross-sectional area: I = dq/dt. Inside a conductor, positive charge carriers drift with average velocity v_d, giving I = nqv_d*A. Current density J = nqv_d is a vector, and the total current through a surface is I = integral of J dot dA. Microscopic Ohm's law connects field and density: J = sigma*E, where sigma is conductivity. Even when net current is zero, individual carriers still move randomly; only the net drift stops.

  • I = dq/dt: Current equals the rate at which charge passes through a cross-section; units are amperes (C/s).
  • I = nqv_d A: Relates macroscopic current to carrier number density n, charge q, drift velocity v_d, and wire cross-section A.
  • Current density J: Vector quantity equal to nqv_d; integrates over area to give total current.
  • Conventional current: Defined in the direction positive charges would move, opposite to electron flow in metal conductors.
  • Electromotive force (emf): The potential difference that drives charge around a circuit; supplied by a battery or other source.
If a wire carries 3 A and has 5 x 10^28 free electrons per cubic meter with cross-section 2 x 10^-6 m^2, what is the drift velocity? Use v_d = I / (nqA).
QuantitySymbolEquationUnits
CurrentIdq/dtA
Current densityJnqv_dA/m^2
Drift velocityv_dI / (nqA)m/s
11.2

Simple Circuits and Schematics

A circuit is a set of closed loops containing elements such as batteries, resistors, capacitors, inductors, and switches. A closed circuit allows charge to flow; an open circuit has a break that stops flow; a short circuit provides a zero-resistance path with no potential difference change. Circuit schematics use standard symbols for each element. Series and parallel are the two fundamental connection types, and a single element can belong to multiple loops simultaneously.

  • Closed circuit: A complete loop through which charge can flow continuously.
  • Open circuit: A broken loop where no charge flows; current is zero throughout that branch.
  • Short circuit: A path with negligible resistance that bypasses a circuit element, leaving no potential difference across it.
  • Circuit schematic: A diagram using standard symbols to represent circuit elements and their connections.
  • Switch: A circuit element that opens or closes a loop to start or stop current flow.
Draw a schematic with a battery, two resistors in series, and a voltmeter placed correctly across the second resistor. Identify which loop the voltmeter belongs to.
Circuit typeCharge flow?Potential difference across break
ClosedYesN/A
OpenNoNonzero
ShortYes (bypassed)Zero
11.3

Resistance, Resistivity, and Ohm's Law

Resistance quantifies how strongly an object opposes current. For a uniform conductor, R = rho*l/A, where rho is resistivity, l is length, and A is cross-sectional area. If resistivity varies along the length, integrate: R = integral of rho(l) dl / A. Ohm's law, I = delta-V / R, applies to ohmic materials that maintain constant resistance regardless of current. On an I-V graph, ohmic materials produce a straight line through the origin; the slope equals conductance 1/R. Resistivity in metals typically increases with temperature.

  • R = rho*l/A: Resistance is proportional to resistivity and length, inversely proportional to cross-sectional area.
  • Ohm's law: I = delta-V / R; applies to ohmic materials where R is constant.
  • Ohmic vs non-ohmic: Ohmic materials show a linear I-V graph; non-ohmic materials (e.g., diodes, filament bulbs at high temperature) do not.
  • Resistivity rho: A material property (units ohm-meter) that quantifies opposition to charge flow at the atomic level.
  • Temperature dependence: Resistivity of metals increases with temperature, so resistance rises as a conductor heats up.
A wire of resistivity 1.7 x 10^-8 ohm-m, length 2 m, and diameter 1 mm carries a current. Calculate its resistance using R = rho*l/A.
PropertySeries resistorsParallel resistors
CurrentSame through eachSplits among branches
VoltageDivides proportionallySame across each
Equivalent RR_eq = sum R_i1/R_eq = sum 1/R_i
11.4

Electric Power

Power is the rate of energy transfer by a circuit element: P = I * delta-V. Substituting Ohm's law gives two derived forms: P = I^2 * R (useful when current is known) and P = delta-V^2 / R (useful when voltage is known). Energy dissipated in a resistor appears as thermal energy, called Joule heating. Lightbulb brightness increases with power, so comparing P values lets you rank brightness without calculating exact temperatures. In series circuits, the largest resistor dissipates the most power; in parallel circuits, the smallest resistor dissipates the most power.

  • P = I * delta-V: Fundamental power equation; applies to any circuit element.
  • P = I^2 * R: Power dissipated in a resistor when current is the known quantity.
  • P = delta-V^2 / R: Power dissipated in a resistor when voltage is the known quantity.
  • Joule heating: Thermal energy generated in a resistor by current flow; rate equals I^2 R.
  • Brightness comparison: A bulb is brighter when it dissipates more power; use P formulas to rank bulbs in a circuit.
Two resistors, 4 ohms and 8 ohms, are connected in parallel across a 12 V battery. Which dissipates more power, and by how much? Use P = delta-V^2 / R for each.
ConfigurationWhich R has highest P?Formula to use
SeriesLargest R (same I)P = I^2 R
ParallelSmallest R (same V)P = V^2 / R
11.5

Compound DC Circuits, Internal Resistance, and Meters

Compound circuits mix series and parallel connections. Simplify by finding equivalent resistances step by step: R_eq,series = sum R_i and 1/R_eq,parallel = sum 1/R_i. A real battery has internal resistance r modeled as a resistor in series with an ideal emf source. Terminal voltage is delta-V_terminal = emf - I*r, so it drops below emf when current flows. Ammeters (zero resistance, placed in series) measure current; voltmeters (infinite resistance, placed in parallel) measure potential difference. Nonideal meters alter the circuit they measure.

  • Series equivalent resistance: R_eq = R_1 + R_2 + ... ; same current flows through each resistor.
  • Parallel equivalent resistance: 1/R_eq = 1/R_1 + 1/R_2 + ... ; same voltage appears across each branch.
  • Internal resistance: Resistance r inside a real battery; modeled as a series resistor that reduces terminal voltage.
  • Terminal voltage: Potential difference at battery terminals: emf - I*r when current flows.
  • Ammeter vs voltmeter placement: Ammeters go in series (zero R); voltmeters go in parallel (infinite R).
A battery with emf 9 V and internal resistance 1 ohm drives a 4-ohm external resistor. Find the current, terminal voltage, and power lost to internal resistance.
MeterConnectionIdeal resistanceMeasures
AmmeterSeriesZeroCurrent at a point
VoltmeterParallelInfinitePotential difference across element
11.6

Kirchhoff's Loop Rule

Kirchhoff's loop rule states that the sum of all potential differences around any closed loop equals zero: sum delta-V = 0. This is conservation of energy applied to circuits. To use it, choose a loop direction, assign a voltage rise to each battery traversed from minus to plus terminal, and assign a voltage drop of I*R to each resistor traversed in the direction of current. Write one equation per independent loop. You can also graph electric potential versus position around the loop to visualize where energy is gained and lost.

  • sum delta-V = 0: Kirchhoff's loop rule; the net potential change around any closed loop is zero.
  • Voltage rise: Potential increases when traversing a battery from its negative to positive terminal.
  • Voltage drop: Potential decreases by I*R when traversing a resistor in the direction of conventional current.
  • Conservation of energy basis: The loop rule follows from the fact that electric potential energy is path-independent; a complete loop returns to the starting potential.
  • Potential vs position graph: A plot showing how electric potential rises and falls as you move around a circuit loop; useful for visualizing loop-rule equations.
Write the loop equation for a single loop containing a 12 V battery, a 3-ohm resistor, and a 5-ohm resistor all in series. Solve for the current.
11.7

Kirchhoff's Junction Rule

Kirchhoff's junction rule states that the total current entering any junction equals the total current leaving it: sum I_in = sum I_out. This is conservation of electric charge applied to circuit nodes. In a multi-loop circuit, label each branch with its own current variable, apply the junction rule at each independent node, and combine with loop equations to solve the system. The junction rule is especially important when parallel branches carry different currents.

  • sum I_in = sum I_out: Kirchhoff's junction rule; charge cannot accumulate at a node in steady state.
  • Conservation of charge basis: The junction rule follows from the fact that charge is neither created nor destroyed at a circuit node.
  • Branch current: The current in a single path between two junctions; each branch gets its own variable in multi-loop analysis.
  • Independent node equation: For N junctions, only N-1 junction equations are independent; the last is redundant.
  • Combined Kirchhoff analysis: Use junction equations plus loop equations together to solve for all unknown currents in a network.
At a junction, currents of 2 A and 3 A enter. Two branches leave. If one carries 1 A, what does the other carry? Apply sum I_in = sum I_out.
RuleConservation lawEquationApplied at
Loop ruleConservation of energysum delta-V = 0Any closed loop
Junction ruleConservation of chargesum I_in = sum I_outAny circuit node
11.8

RC Circuits

Capacitors in series combine as 1/C_eq = sum 1/C_i; capacitors in parallel combine as C_eq = sum C_i (opposite rules from resistors). In an RC circuit, applying Kirchhoff's loop rule gives the differential equation emf = R(dq/dt) + q/C. The solution for charging is q(t) = C*emf*(1 - e^(-t/RC)) and for discharging q(t) = Q_0 * e^(-t/RC). The time constant tau = R_eq * C_eq sets the timescale: after one tau, a charging capacitor reaches about 63% of its final charge; a discharging capacitor retains about 37%. At t = 0, a capacitor acts like a wire (short circuit); at t >> tau, it acts like an open circuit with no current flowing through its branch.

  • tau = R_eq * C_eq: The RC time constant; controls how quickly the capacitor charges or discharges.
  • Charging equation: q(t) = C*emf*(1 - e^(-t/tau)); current starts at emf/R and decays to zero.
  • Discharging equation: q(t) = Q_0 * e^(-t/tau); charge and current both decay exponentially.
  • Steady state: At t >> tau, the capacitor is fully charged (or discharged) and no current flows through its branch.
  • Transient response: The time-dependent behavior between t = 0 and steady state, described by the exponential solutions.
A 10-microfarad capacitor charges through a 5-kilohm resistor from a 20 V source. Find tau, the charge at t = tau, and the current at t = 0.
CombinationCapacitorsResistors
Series1/C_eq = sum 1/C_iR_eq = sum R_i
ParallelC_eq = sum C_i1/R_eq = sum 1/R_i

Practice AP Physics C: E&M unit 11 questions

Try AP-style multiple-choice questions and written prompts after you review the notes.

Example AP-style MCQs

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MCQ

AP-style practice question

Question

Two resistors, each with resistance 60Ω60 \, \Omega, are connected in series. This series combination is connected in parallel with a third resistor of resistance 120Ω120 \, \Omega. What is the equivalent resistance of the entire circuit?

60 ohms

24 ohms

100 ohms

240 ohms

MCQ

AP-style practice question

Question

A resistor RR and capacitor CC are connected in series to a battery of emf E\mathcal{E}. A student calculates that the total energy supplied by the battery during charging is CE2C\mathcal{E}^2, but the energy stored in the capacitor is only 12CE2\frac{1}{2}C\mathcal{E}^2. The student claims the remaining energy is dissipated as heat in the resistor. Is this claim valid, and why?

Valid; the battery does work W=CE2W = C\mathcal{E}^2, and the capacitor stores U=12CE2U = \frac{1}{2}C\mathcal{E}^2, so the difference must be dissipated as heat.

Valid; the battery does work W=CE2W = C\mathcal{E}^2, and the capacitor stores U=CE2U = C\mathcal{E}^2, so the difference must be dissipated as heat.

Invalid; the battery does work W=12CE2W = \frac{1}{2}C\mathcal{E}^2, and the capacitor stores U=12CE2U = \frac{1}{2}C\mathcal{E}^2, so no energy is dissipated as heat.

Invalid; the battery does work W=CE2W = C\mathcal{E}^2, and the capacitor stores U=14CE2U = \frac{1}{4}C\mathcal{E}^2, so the difference must be dissipated as heat.

Example FRQs

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FRQ

RC circuit charging with capacitor and wire resistance

2. A circuit consists of an ideal switch S, a battery of emf E=12.0 V\mathcal{E} = 12.0\ \text{V} with internal resistance r=1.50 Ωr = 1.50\ \Omega, two identical resistive leads (wires) each of length L=2.00 mL = 2.00\ \text{m} and cross-sectional area A=1.00 mm2A = 1.00\ \text{mm}^2 made of a material with resistivity ρ=1.70×108 Ωm\rho = 1.70× 10^{-8}\ \Omega·\text{m}, a resistor R=12.0 ΩR = 12.0\ \Omega, and a capacitor C=250 μFC = 250\ \mu\text{F}. The capacitor is initially uncharged. At time t=0t=0 the switch is closed, connecting all elements in series as shown in Figure 1.

Figure 1. Series RC charging circuit with internal resistance and two identical resistive leads (each lead has length L = 2.00 m and cross-sectional area A = 1.00 mm², resistivity ρ = 1.70×10⁻⁸ Ω·m). Battery emf is ℰ = 12.0 V with internal resistance r = 1.50 Ω. Resistor R = 12.0 Ω. Capacitor C = 250 μF. Switch closes at t = 0 to connect all elements in a single series loop. Voltmeter measures V_C across the capacitor; ammeter measures the series current I.

Figure 1

Figure 2. Bar chart template for current I at four times (t = 0, 1.00 s, 3.00 s, 5.00 s), with the t = 0 bar provided as the reference.

Figure 2
A.

In Figure 2, draw bars to represent the current II at times t=1.00 st=1.00\ \text{s}, 3.00 s3.00\ \text{s}, and 5.00 s5.00\ \text{s} relative to the current shown at t=0t=0. If I=0I=0, write a "0" in that column. The current in the circuit is I(t)I(t). The partially completed bar chart in Figure 2 shows a bar that represents II at t=0t=0.

B.

Derive an expression for the current I(t)I(t) for t0t≥ 0 in terms of E\mathcal{E}, rr, RR, ρ\rho, LL, AA, CC, tt, and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

Figure 3. Axes for plotting capacitor potential difference V_C versus time t for 0 ≤ t ≤ 5.00 s.

Figure 3
C.

On the axes shown in Figure 3, sketch a graph of the capacitor potential difference VC(t)V_C(t) as a function of time during the time interval 0t5.00 s0≤ t≤ 5.00\ \text{s}.

D.

Indicate whether the sketch you drew in part C is or is not consistent with the behavior of Vterm(t)V_{\text{term}}(t) during the same interval. Briefly justify your answer by referencing a functional dependence between VtermV_{\text{term}} and II and between VCV_C and II. A student uses a voltmeter to measure the terminal potential difference of the battery, Vterm(t)V_{\text{term}}(t), while the capacitor is charging. Use the following given values: E=12.0 V\mathcal{E}=12.0\ \text{V}, r=1.50 Ωr=1.50\ \Omega, R=12.0 ΩR=12.0\ \Omega, ρ=1.70×108 Ωm\rho=1.70× 10^{-8}\ \Omega·\text{m}, L=2.00 mL=2.00\ \text{m} (each lead), A=1.00 mm2A=1.00\ \text{mm}^2, C=250 μFC=250\ \mu\text{F}. The leads are the only resistive wires in the circuit. Assume the switch and meters are ideal.

FRQ

Circuit with resistive leads, capacitor charging

4. A student builds the circuit shown in Figure 1. The battery has emf E=12.0 V\mathcal{E}=12.0\ \text{V} and internal resistance r=1.50 Ωr=1.50\ \Omega. The connecting leads are made of a uniform resistive wire with resistivity ρ=1.60×108 Ωm\rho = 1.60× 10^{-8}\ \Omega·\text{m} and circular cross-sectional area A=0.80 mm2A=0.80\ \text{mm}^2. Lead 1 has length L1=0.60 mL_1=0.60\ \text{m} and Lead 2 has length L2=0.30 mL_2=0.30\ \text{m}. A resistor R=6.00 ΩR=6.00\ \Omega and an initially uncharged capacitor C=200 μFC=200\ \mu\text{F} are connected as shown. At time t=0t=0 the switch SS is closed. Conventional current is defined to be the direction of positive charge flow.

Figure 1. Series circuit with battery internal resistance and two resistive leads; switch closes at t = 0; current defined clockwise.

Figure 1
A.

Let I1I_1 be the magnitude of the current in the circuit at t=0+t=0^+ through Lead 1, and let I2I_2 be the magnitude of the current in the circuit at t=0+t=0^+ through Lead 2.

Indicate whether I2I_2 is greater than, less than, or equal to I1I_1 by writing one of the following.

  • I2>I1I_2 > I_1
  • I2<I1I_2 < I_1
  • I2=I1I_2 = I_1

Justify your answer.

B.

Derive an expression for the initial current I0I_0 in the circuit at t=0+t=0^+ in terms of E, r, R,ρ, L1, L2,\mathcal{E},\ r,\ R,\rho,\ L_1,\ L_2, and AA and physical constants, as appropriate. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

Figure 2. Same circuit as Figure 1, but the single resistor is replaced by two resistors in parallel (R and 2R) between the same two nodes; capacitor remains in series.

Figure 2
C.

Indicate whether InewI_{\text{new}} is greater than, less than, or equal to I0I_0 by writing one of the following. The circuit is modified as shown in Figure 2: the resistor is replaced by two resistors RR and 2R2R in parallel. The switch is open for a long time so the capacitor is uncharged, and then the switch is closed at t=0t=0. Let InewI_{\text{new}} be the magnitude of the current at t=0+t=0^+ in the modified circuit.

  • Inew>I0I_{\text{new}} > I_0
  • Inew<I0I_{\text{new}} < I_0
  • Inew=I0I_{\text{new}} = I_0

Briefly justify your answer by referencing your derivation in part B.

FRQ

Capacitor charging in resistive circuit networks

1. A student builds a circuit using an ideal battery of emf E\mathcal{E} with internal resistance rr, a uniform cylindrical wire of length LL and radius aa made of a material with resistivity ρ\rho, a resistor RR, and two capacitors C1C_1 and C2C_2. The circuit is arranged as shown in Figure 1. The switch SS is initially open, and the capacitors are initially uncharged. When the switch is closed at time t=0t=0, current begins to flow and the capacitors begin to charge.

Figure 1. Circuit with two capacitors in parallel that begin charging when switch S is closed at t = 0.

Figure 1

Figure 2. Axes for sketching the circuit current I as a function of time t after the switch is closed at t = 0.

Figure 2
A.
i.

Using fundamental definitions of resistance and current in a material, derive an expression for the resistance RwireR_\text{wire} of the uniform cylindrical wire in terms of ρ\rho, LL, and aa. Begin your derivation by writing a fundamental physics principle or an equation from the reference information.

ii.

When the switch is first closed at t=0t=0, the capacitors act like wires. Using Kirchhoff's loop rule and junction rule, derive an expression for the initial current I0I_0 in terms of E\mathcal{E}, rr, RR, and RwireR_\text{wire}.

iii.

On the axes shown in Figure 2, sketch a graph of the current I(t)I(t) in the circuit from t=0t=0 to a time long after the switch is closed. Indicate and label I0I_0 and the long-time current value on your graph.

Figure 3. Same circuit as Figure 1, but capacitors C1 and C2 are connected in series.

Figure 3
B.

Derive an expression for the time constant τ\tau of the circuit shown in Figure 3 (with capacitors in series) in terms of rr, RR, RwireR_\text{wire}, C1C_1, and C2C_2. Your derivation must include determining the equivalent capacitance of the capacitor combination and the appropriate equivalent resistance seen by the capacitors. At long times after the switch is closed, the capacitors are fully charged. The potential difference across the parallel capacitor combination equals the terminal potential difference of the battery. Consider energy transfer in the circuit during charging. Figure 3 shows the same circuit but with the capacitors connected in series instead of parallel.

Key terms

TermDefinition
drift velocityThe average velocity at which charge carriers move through a conductor in response to an applied electric field; appears in I = nqv_d*A.
conventional currentThe direction of current defined as the direction positive charges would move, opposite to electron flow in metal conductors.
electromotive forceThe energy per unit charge provided by a source (such as a battery) to drive charge around a circuit; symbol emf or epsilon.
Joule heatingThermal energy generated in a resistor by current flow at a rate equal to I^2*R; represents conversion of electrical energy to heat.
series connectionA circuit configuration where charge must pass through all elements in sequence; current is the same through each element.
parallel connectionA circuit configuration where charge can take multiple paths; the same potential difference appears across each branch.
internal resistanceResistance r inside a real battery modeled as a series resistor; causes terminal voltage to equal emf - I*r when current flows.
terminal voltageThe potential difference measured across a battery's terminals; equals emf minus the voltage drop across internal resistance.
conservation of electric chargeThe principle that charge is neither created nor destroyed at a circuit junction; the basis of Kirchhoff's junction rule.
equivalent capacitanceA single capacitance representing multiple capacitors: sum C_i for parallel, reciprocal sum for series (opposite of resistor rules).
steady stateThe condition in an RC circuit after t >> tau when the capacitor is fully charged or discharged and no current flows through its branch.
transient responseThe time-dependent exponential behavior of charge and current in an RC circuit between t = 0 and steady state.
open circuitA circuit with a break in the loop so no charge flows; a fully charged capacitor in an RC circuit behaves as an open circuit at steady state.
short circuitA path with negligible resistance and no potential difference change; an uncharged capacitor behaves as a short circuit at t = 0.

Common unit 11 mistakes

Mixing up series and parallel combination rules for capacitors

Capacitor combination rules are the reverse of resistor rules. Capacitors in series use the reciprocal formula; capacitors in parallel add directly. Applying resistor rules to capacitors is one of the most frequent errors on RC circuit problems.

Using the wrong power formula for the known quantities

P = I^2*R and P = delta-V^2/R give different answers if you substitute inconsistent values. In parallel circuits, voltage is the same across branches, so P = delta-V^2/R is the cleaner choice. In series circuits, current is the same, so P = I^2*R avoids extra steps.

Ignoring internal resistance when finding terminal voltage

The terminal voltage of a real battery is emf - I*r, not just emf. Forgetting the I*r drop leads to incorrect currents and power calculations throughout the circuit.

Inconsistent sign conventions in Kirchhoff's loop equations

You must choose a loop direction and apply it consistently. A resistor traversed against the current direction gives a voltage rise of +I*R, not a drop. Switching conventions mid-loop produces wrong equations.

Treating a capacitor as an open circuit at t = 0 in an RC circuit

At the instant a switch closes, an uncharged capacitor has zero voltage across it and acts like a short circuit, allowing maximum current. The open-circuit behavior only applies at steady state (t >> tau).

How this unit shows up on the AP exam

Deriving and solving the RC differential equation

Free-response questions in AP Physics C: E&M frequently ask you to apply Kirchhoff's loop rule to an RC circuit, write the resulting differential equation emf = R(dq/dt) + q/C, and solve it to obtain q(t) or I(t). You may also be asked to sketch the exponential graph, identify tau, and describe initial and steady-state conditions in words.

Multi-loop circuit analysis using both Kirchhoff's Rules

Expect problems that require setting up a system of equations from loop and junction rules simultaneously. Skills tested include assigning current directions, writing consistent sign-convention loop equations, and solving for multiple unknown branch currents or voltages. Graphing potential versus position around a loop is another common task.

Comparing circuit configurations qualitatively and quantitatively

Questions often ask you to predict how adding or removing a resistor changes current, voltage, and power throughout a circuit, or to rank lightbulb brightness before and after a switch opens or closes. These tasks require you to reason about equivalent resistance changes and apply power formulas without necessarily solving the full circuit numerically.

Final unit 11 review checklist

  • Unit 11 final review checklistUse this list to confirm you can handle every major skill in Unit 11 before exam day.
  • Calculate current and current densityApply I = dq/dt and I = nqv_d*A to find current or drift velocity. Integrate J over a cross-section when current density is non-uniform.
  • Use R = rho*l/A and Ohm's lawCompute resistance from material and geometry. Apply I = delta-V/R and identify ohmic behavior from a linear I-V graph.
  • Calculate and compare powerUse P = I*delta-V, P = I^2*R, and P = delta-V^2/R. Rank lightbulb brightness by comparing power dissipated in each branch.
  • Reduce compound resistor networksCombine series and parallel resistors step by step to find equivalent resistance. Account for internal resistance and compute terminal voltage.
  • Apply both Kirchhoff's Rules to multi-loop circuitsWrite independent loop equations using sum delta-V = 0 and junction equations using sum I_in = sum I_out. Solve the resulting system for all unknown currents and voltages.
  • Analyze RC circuit behaviorFind tau = R_eq*C_eq. Write and interpret charging and discharging equations. Identify initial (short-circuit) and steady-state (open-circuit) capacitor behavior.

How to study unit 11

Step 1: Current, current density, and circuit basics (Topics 11.1-11.2)Read the topic guides for 11.1 and 11.2. Practice converting between I = dq/dt and I = nqv_d*A. Draw and label circuit schematics with correct symbols. Identify closed, open, and short circuits in diagrams.
Step 2: Resistance, resistivity, and power (Topics 11.3-11.4)Work through R = rho*l/A problems including variable-resistivity integrals. Sketch I-V graphs for ohmic and non-ohmic elements. Practice all three power formulas and rank bulb brightness in series and parallel examples.
Step 3: Compound circuits and equivalent resistance (Topic 11.5)Reduce multi-resistor networks step by step. Include internal resistance in battery problems and compute terminal voltage. Practice placing ammeters and voltmeters correctly in circuit diagrams.
Step 4: Kirchhoff's Rules for multi-loop circuits (Topics 11.6-11.7)Write loop equations using sum delta-V = 0 with consistent sign conventions. Write junction equations using sum I_in = sum I_out. Set up and solve systems of equations for two- and three-loop circuits. Sketch potential-versus-position graphs for a loop.
Step 5: RC circuits and time-dependent behavior (Topic 11.8)Combine capacitors in series and parallel. Derive the RC differential equation from Kirchhoff's loop rule. Practice writing q(t) and I(t) for charging and discharging. Identify initial and steady-state conditions and calculate tau for given circuits. Use the AP score calculator to estimate your overall exam score as you complete practice.

More ways to review

Topic study guides

Open the individual guides for Unit 11 when you want a closer review of one topic.

browse guides

FRQ practice

Practice free-response reasoning and compare your answer with scoring guidance.

practice FRQs

Cheatsheets

Use unit cheatsheets for a quick visual review after you work through the notes.

open cheatsheets

Score calculator

Estimate your broader AP score goal after you review the course and exam format.

open calculator

Frequently Asked Questions

What topics are covered in AP Physics E&M Unit 11?

AP Physics E&M Unit 11 covers 8 topics centered on resistance and electric circuits: Electric Current, Simple Circuits, Resistance/Resistivity and Ohm's Law, Electric Power, Compound Direct Current Circuits, Kirchhoff's Loop Rule, Kirchhoff's Junction Rule, and Resistor-Capacitor (RC) Circuits. The unit builds from basic current and resistance up to analyzing multi-loop circuits with Kirchhoff's Rules, then finishes with RC circuits where capacitors charge and discharge over time. See AP Physics E&M Unit 11 for matched practice on each topic.

How much of the AP Physics E&M exam is Unit 11?

Unit 11 makes up 15-25% of the AP Physics E&M exam, making it one of the most heavily weighted units. That weight reflects how central resistance and electric circuits are to the course. Topics like Ohm's Law, Kirchhoff's Rules, and RC circuits all appear regularly on both the multiple-choice and free-response sections.

What's on the AP Physics E&M Unit 11 progress check (MCQ and FRQ)?

The AP Physics E&M Unit 11 progress check includes both MCQ and FRQ parts drawn from all 8 topics in the unit. The MCQ section tests resistance, Ohm's Law, electric power, and circuit analysis with Kirchhoff's Rules. The FRQ part typically asks you to analyze a compound DC circuit or an RC circuit, set up equations, and interpret results. College Board designs the progress check to mirror real exam difficulty, so it's one of the best checkpoints before test day. Head to AP Physics E&M Unit 11 for practice questions matched to each progress check topic.

How do I practice AP Physics E&M Unit 11 FRQs?

The best way to practice AP Physics E&M Unit 11 FRQs is to focus on the topics that generate the most free-response questions: Compound DC Circuits, Kirchhoff's Loop and Junction Rules, and RC Circuits. FRQs in this unit typically ask you to derive an expression for resistance or current, apply Kirchhoff's Rules to a multi-loop circuit, or sketch and interpret a charge-vs-time graph for an RC circuit. For each practice problem, write out every step explicitly, because College Board awards points for correct setup even if your final answer is off. You can find FRQ-style problems organized by topic at AP Physics E&M Unit 11.

Where can I find AP Physics E&M Unit 11 practice questions?

For AP Physics E&M Unit 11 practice questions, including multiple-choice and practice test sets, go to AP Physics E&M Unit 11. That page organizes MCQ and FRQ practice by topic, covering resistance and Ohm's Law, Kirchhoff's Rules, electric power, and RC circuits. For the best results, mix MCQ drills with full practice test sections so you get comfortable with both the calculation-heavy multiple-choice questions and the longer free-response format this unit is known for.

How should I study AP Physics E&M Unit 11?

Start with resistance and Ohm's Law (Topic 11.3) before anything else, since that relationship underpins every other topic in the unit. From there, build up to series and parallel circuits (11.5), then tackle Kirchhoff's Loop Rule (11.6) and Junction Rule (11.7) together since they work as a system for solving multi-loop problems. Finish with RC circuits (11.8), which add a time-dependent layer on top of everything before. A few concrete steps that help: - Draw every circuit diagram yourself rather than just reading the textbook's version. - Practice setting up Kirchhoff's equations before solving them, since setup is where most points are lost on FRQs. - For RC circuits, make sure you can sketch charge and current vs. time graphs and explain what the time constant means physically. Check AP Physics E&M Unit 11 for topic-by-topic practice to test your understanding as you go.

Ready to review Unit 11?Start with the notes, check the topic cards, and use the practice or resource links when they are available for this course.