Kₐ (the acid dissociation constant) is the equilibrium constant for a weak acid ionizing in water, HA + H₂O ⇌ H₃O⁺ + A⁻, so Kₐ = [H₃O⁺][A⁻]/[HA]. A larger Kₐ means more ionization and a stronger weak acid; it's often reported as pKₐ = −log(Kₐ).
Kₐ is just an equilibrium constant with a job title. When a weak acid HA sits in water, only a small fraction of its molecules actually donate a proton: HA + H₂O ⇌ H₃O⁺ + A⁻. Kₐ measures where that equilibrium settles. Write it like any other K expression: Kₐ = [H₃O⁺][A⁻]/[HA]. Because weak acids barely ionize (CED 8.3.A.1), Kₐ values for weak acids are small, often 10⁻⁵ or tinier, and most of the acid stays as un-ionized HA.
The bigger the Kₐ, the more the acid ionizes, and the stronger it is. Since the numbers are awkwardly small, you'll usually see pKₐ = −log(Kₐ) instead. That flips the scale, so a smaller pKₐ means a stronger acid. Per the CED (8.3.A.2), you can find the pH of a weak acid solution from just two things, the initial acid concentration and the Kₐ (or pKₐ). That's the classic ICE-table calculation, and it shows up everywhere in Unit 8.
Kₐ is the backbone of Unit 8 (Acids and Bases). It directly supports learning objective 8.3.A, relating pH, pOH, and species concentrations in a weak acid solution. But it doesn't stop there. The Henderson-Hasselbalch equation (8.9.A) is literally the Kₐ expression rearranged into log form, so buffer pH problems are Kₐ problems in disguise. Titration analysis (8.5.A) uses Kₐ too, since the pH at the half-equivalence point of a weak acid titration equals the pKₐ. And buffer reasoning in 8.4.A and 8.10.A all flows from the same equilibrium. If you genuinely understand the Kₐ expression, you've unlocked about half of Unit 8.
Keep studying AP Chemistry Unit 8
pKₐ and the Henderson-Hasselbalch Equation (Unit 8)
Henderson-Hasselbalch, pH = pKₐ + log([A⁻]/[HA]), is not a new idea. It's the Kₐ expression with a logarithm taken on both sides. When [A⁻] = [HA], the log term is zero and pH = pKₐ, which is why buffers work best near the acid's pKₐ.
Equilibrium Constants and ICE Tables (Unit 7)
Kₐ is a regular Unit 7 equilibrium constant applied to one specific reaction, acid ionization in water. Every skill transfers: writing the K expression, setting up an ICE table, and using the small-x approximation because weak acids barely dissociate.
Acid-Base Titrations and the Half-Equivalence Point (Unit 8)
On a weak acid titration curve, the half-equivalence point is where exactly half the HA has been converted to A⁻. At that moment pH = pKₐ, which lets you read Kₐ straight off a graph. This is one of the most common FRQ moves in Unit 8.
Conjugate Base Strength (Unit 8)
Kₐ tells you about both partners in a conjugate pair. A weak acid with a tiny Kₐ holds its proton tightly, which means its conjugate base is relatively good at grabbing protons. Stronger acid, weaker conjugate base, and vice versa.
Kₐ shows up on both multiple choice and FRQs, usually asking you to use it rather than define it. Expect to: write the Kₐ expression for a given weak acid, calculate pH from initial concentration and Kₐ using an ICE table, compare acid strengths from a table of Kₐ or pKₐ values, plug into Henderson-Hasselbalch for buffer pH, and pull pKₐ off a titration curve at the half-equivalence point. Released FRQs lean on this constantly; the 2025 long FRQ on ascorbic acid (vitamin C) is a classic example of a weak-acid question built around Kₐ reasoning. A frequent trap is treating a strong acid like a weak one (strong acids ionize completely, so no Kₐ math needed) or forgetting that water is not included in the Kₐ expression.
Kₐ and pKₐ carry the same information in opposite directions. Kₐ is the raw equilibrium constant, and pKₐ = −log(Kₐ). A STRONGER weak acid has a LARGER Kₐ but a SMALLER pKₐ. Mixing up which scale you're reading is one of the easiest ways to rank acids backwards on an MCQ, so always check whether the table gives Kₐ or pKₐ before comparing.
Kₐ is the equilibrium constant for a weak acid ionizing in water: Kₐ = [H₃O⁺][A⁻]/[HA], with water left out of the expression.
A larger Kₐ means more ionization and a stronger acid, while a smaller pKₐ means a stronger acid, because pKₐ = −log(Kₐ).
You can calculate the pH of a weak acid solution from just the initial concentration and Kₐ, usually with an ICE table and the small-x approximation.
The Henderson-Hasselbalch equation is the Kₐ expression in log form, so buffer pH problems are really Kₐ problems.
At the half-equivalence point of a weak acid titration, pH = pKₐ, which lets you find Kₐ from a titration curve.
Strong acids ionize completely, so Kₐ math only applies to weak acids.
Kₐ is the acid dissociation constant, the equilibrium constant for a weak acid donating a proton to water (HA + H₂O ⇌ H₃O⁺ + A⁻). It equals [H₃O⁺][A⁻]/[HA] and measures how much the acid ionizes.
Stronger. A bigger Kₐ means the ionization equilibrium lies further toward products, so more H₃O⁺ forms. Just remember the flip with pKₐ, where a stronger acid has a smaller pKₐ.
pKₐ = −log(Kₐ), so they're the same information on flipped scales. An acid with Kₐ = 1 × 10⁻⁵ has pKₐ = 5. Stronger acid means larger Kₐ but smaller pKₐ.
On the AP exam, you treat strong acids (like HCl and HNO₃) as ionizing 100%, so you never do Kₐ equilibrium math with them. If a problem gives you a Kₐ value, that's your signal you're dealing with a weak acid.
Find the half-equivalence point, the volume halfway to the equivalence point. There, [HA] = [A⁻], so pH = pKₐ. Read the pH off the curve at that volume, then Kₐ = 10^(−pKₐ).
Connect this key term to the AP exam workflow: review the course, practice questions, and check related study tools.
Review units, study guides, and course resources.
Check this vocabulary in multiple-choice context.
Apply key concepts in written AP responses.
Estimate the exam score you are working toward.
Review the highest-yield facts before practice.
Put the full course together before test day.